Here is the link to the problem -> PRIME1
It asks us to print all the prime numbers between two numbers m and n
I used segmented sieve to solve the problem. Stored all the primes till sqrt(10^9) and used them to get primes in a specific range. Please help me out.
#include <iostream>
#include <vector>
using namespace std;
vector<int> v;
vector<bool> prime(32022);
void precompute()
{
int n=32000;
prime[0]=prime[1]=true;
for(int i=2;i*i<=32000;i++)
{
for(int j=i*i;j<=32000;j+=i)
prime[j]=true;
}
for(int i=0;i<=32000;i++)
if(!prime[i]) v.push_back(i);
}
int main() {
precompute();
int t; scanf("%d",&t);
while(t--)
{
int m,n; scanf("%d%d",&m,&n);
if(n<=32000)
{
for(int i:v)
{
if(i>n) break;
if(i>=m && i<=n)
printf("%d\n",i);
}
}
else
{
vector<bool> prime(n-m+1,true);
for(int i:v)
{
int st=(m/i)*i;
if(st<m) st+=i;
while(st<=n)
{
prime[st-m]=false;
st+=i;
}
}
for(int i=0;i<n-m+1;i++)
{
if(prime[i]) printf("%d\n",i+m);
}
}
printf("\n");
}
}
I know the logic how to merge two arrays but the problem is how to code.
This was my code n it is giving correct ans but my sir told me that do it again,please tell me what I have to add in this code,
#include<iostream>
using namespace std;
int mergeArrays(int array1[],int size1,int array2[],int size2);
int main()
{
const int size1=8;
const int size=12;
int arrayA[size1]={10,25,37,49,50,51,55,60};
int arrayB[size]={2,5,26,27,29,32,40,45,70,80,90,95};
mergeArrays(arrayA,size1,arrayB,size);
}
int mergeArrays(int array1[],int size1,int array2[],int size2)
{
int size3=size1+size2;
int *array3=new int[size3];
int k=0;
for(int i=0;i<size1;i++)
{
array3[k]=array1[i];
cout<<" "<<array3[k];
}
int j=0;
for(int i=size1;i<size2;i++)
{
array3[k]=array2[j];
}
for(int i=size1;i<size2;i++)
{
for(int j=0;j<size2;j++)
{
array3[i]=array2[j];
cout<<" "<<array3[i];
}
cout<<endl;
delete[]array3;
return array3[k++];
}
}
I had searched this in many places but could not corrected my code
I had written this code but it is not giving correct ans.
#include<iostream>
using namespace std;
int merge(int *a,int *b,int aSize,int bSize);
int main()
{
const int aSize={8};
const int bSize={12};
int arrayA[aSize]={10,25,37,49,50,51,55,60};
int arrayB[bSize]={2,5,26,27,29,32,40,45,70,80,90,95};
merge(arrayA,arrayB,aSize,bSize);
return 0;
}
int merge(int *a,int *b,int aSize ,int bSize)
{
int cSize=aSize+bSize;
int *c=new int[cSize];
int j=0,k=0;
int i=0;
while(i<=aSize&&j<=bSize )
{
if(a[aSize ]<=b[bSize])
{
c[k]=a[aSize];
k++;
i++;
}
else
{
c[k]=b[bSize];
k++;
j++;
}
}
for(int i=0;i<k;i++)
{
cout<<c[i]<<endl;
}
delete[]c;
return c[k++];
}
your sir request you do Merging two arrays in ascending order. so i think you should return a new array, fill with array1 and array2's element, and the elements should be ascending order. here is a implement.(suppose your input arraies is already in ascending order.)
#include <iostream>
using namespace std;
int mergeArrays(int array1[],int size1,int array2[],int size2, int outArray[]);
int main()
{
const int size1=8;
const int size=12;
int arrayA[size1]={10,25,37,49,50,51,55,60};
int arrayB[size]={2,5,26,27,29,32,40,45,70,80,90,95};
int outArray[size1+size];
int len = mergeArrays(arrayA,size1,arrayB,size, outArray);
cout <<" "<< len;
for (int i = 0; i< size1+size; ++i){
cout <<" " << outArray[i];
}
}
int mergeArrays(int array1[], int size1, int array2[], int size2, int outArray[])
{
int i=0, j=0, k=0;
int retSize = size1+size2;
while (k<retSize){
if (i==size1){// only left array2, copy it
for (; j<size2; ++j){
outArray[k++] = array2[j];
}
}else if (j == size2) { // only left array1, copy it
for (; i<size1; ++i){
outArray[k++] = array1[i];
}
}
else if (array1[i] > array2[j]){ // copy the min value to outArray
outArray[k++] = array2[j++];
}else{
outArray[k++] = array1[i++];
}
}
return k;
}
now, let's look at your first code:
int mergeArrays(int array1[],int size1,int array2[],int size2)
{
int size3=size1+size2;
int *array3=new int[size3];
int k=0;
for(int i=0;i<size1;i++)
{
array3[k]=array1[i]; // k is not changed, so you just assign array1's each value to array3[0]
cout<<" "<<array3[k];
}
int j=0;
// what's the purpose of this loop?
// and in loop, you don't use i, you just repeat set array3[0] = array2[0]!!
for(int i=size1;i<size2;i++)
{
array3[k]=array2[j];
}
for(int i=size1;i<size2;i++) // if array2's length bigger than array1's, will enter this loop.
{
for(int j=0;j<size2;j++)
{
array3[i]=array2[j]; // this just repeat assign array2's each value to array3[i]!!
cout<<" "<<array3[i];
}
cout<<endl;
delete[]array3;
return array3[k++]; // you delete array3, but at here you access it!! this will crash!
// also, in this for i loop, you have return, so it will only execute once.
}
// reach function end and no return if not enter for loop.
}
I haven't looked at your second code. I think you still need to do more study.
# include <iostream>
using namespace std;
class mm
{
private:
int k[1000];
int n;
int i;
int a;
int b;
int f;
public:
mm ()
{
a=0;
b=1;
f=0;
i=0;
for(int i=0; i<n;i++)
k[i]=0;
};
~mm()
{
}
void fib(int n)
{
for (int i=0;i<n;i++)
{
if (i<=1)
f=i;
else
{
f=a+b;
a=b;
b=f;
}
k[i]=f;
}
for (int j=0;j<n;j++)
cout<<k[j]<<" ";
}
int se (int n, int i)
{
if (n==1)
return 1;
else
return 1/k[i] + se (n-1, i+1);
}
};
int main()
{
int n;
cout<<"Enter n:";
cin>>n;
mm p;
cout<<"fib: "<<endl;
p.fib(n);
cout<<endl;
cout<<"se: ";
cout<<p.se(n,0);
return 0;
}
Recursion function from main is not responding. Maybe the array k[i] is not working, but I cant find the reason. Can anyone help me?
k[0] is set to 0. When you then call se(n,0) in main, it computes 1/k[0] + se(n-1,1) which is a division by zero.
After reading through the theory of Merge Sort on TopCoder, I tried to write it's implementations, but it's getting weird, and I'm more or less a beginner in programming, especially algorithms. Can somebody assist me?
#include <iostream>
using namespace std;
int arr[] = {2, 0, 43, 12, 98};
int sizeOfarr(int a[])
{
return sizeof(a)/sizeof(a[0]);
}
int minElement(int x, int y)
{
if (x > y)
{
return y;
}
else if (x < y)
{
return x;
}
else
{
return x, y;
}
}
int main()
{
int t, z;
int n = sizeOfarr(arr);
int finalList[n];
int list1[n];
int list2[n];
for(int i = 0; i<=((n/2)-1); i++)
{
list1[i] = arr[i];
}
for(int j = n/2; j<n; j++)
{
for(int k = 0; k<=((n/2)-1); k++ )
{
list2[k] = arr[j];
}
}
for(int y = 0; y<=n; y++)
{
while(sizeOfarr(finalList)!=n)
{
t = list1[0];
z = list2[0];
finalList[y] = minElement(t, z);
if(finalList[y]==t)
{
list1[0] = list1[1];
}
else if(finalList[y]==z)
{
list2[0] = list2[1];
}
else
{
list1[0] = list1[1];
list2[0] = list2[1];
}
}
}
cout << "The sorted list is: " << finalList << endl;
return 0;
}
#include <iostream>
#include <math.h>
#include <string.h>
using namespace std;
int temp[10000];
void merge(int *A,int low,int mid,int high)
{
int i=low;
int j=mid+1;
int k=low;
int l;
while(i<=mid && j<=high)
{
if(A[i]<A[j])
{
temp[k]=A[i];
i=i+1;
}
else
{
temp[k]=A[j];
j=j+1;
}
k++;
}
for(l=i;l<=mid;l++,k++)
{
temp[k]=A[l];
}
for(l=j;l<=high;l++,k++)
{
temp[k]=A[l];
}
memcpy(A,temp,sizeof(A[0])*k);
}
void mergeSort(int *A,int low,int high)
{
int mid;
if(low<high)
{
mid=floor((low+high)/2);
mergeSort(A,low,mid);
mergeSort(A,mid+1,high);
merge(A,low,mid,high);
}
}
int main(int argc,char *argv[])
{
int n;
int array[10000];
cout<<"please enter the number numbers\n";
cin>>n;
cout<<"please enter the nubers\n";
for(int i=0;i<n;i++)
{
cin>>array[i];
}
mergeSort(array,0,n-1);
for(int i=0;i<n;i++)
{
cout<<array[i]<<" ";
}
cout<<"\n";
}
This is my implementation
mergeSort function divide recursively at middle and repeats until low lt(less than) high then a merge function is called.
I see from your code that the operator "," (return x,y) would replace x value by y value.
A few comments on the code:
return x,y // this just returns y. this is the case when x==y so it probably is OK bit not what one would write.
while(sizeOfarr(finalList)!=n) // The size of your array finalist is n elements. This is never going to change so this while condition is always false and the loop will never execute.
Well my program is working with huge digits and I should wait to much for example calculating 20! takes too much time ( calculating all permutation).
How can I output first 20 results not all 20? I tried to capture this while the program was running in icon, but I can't.
Here is my code
#include <iostream>
#include <conio.h>
#include <Windows.h>
#include <vector>
#include <fstream>
using namespace std;
int X[100];
LARGE_INTEGER start, finish, freq;
int N;
int count_number;
vector<int> numb;
vector<int> cycle;
bool search (vector<int> source, int data)
{
for (int i=0; i<source.size(); i++)
if (source[i] == data)
return true;
return false;
}
void fill(int find)
{
find++;
int data = X[find-1];
int temp = find;
while (data != find){
temp = data;
data = X[temp-1];
numb.push_back(temp);
cycle.push_back(temp);
}
if (data == find) {
numb.push_back(find);
cycle.push_back(find);
}
}
void Swap(int a,int b)
{
int t=X[a];
X[a]=X[b];
X[b]=t;
}
void Generate(int k)
{
if (k==N)
{
for(int i=0;i<N;i++)
cout<<X[i]<<" ";
cout<<"Циклы: ";
for (int i=0; i<N; i++) {
if (!search(numb, i+1)) {
fill(i);
cout<<'(';
for (int i=0; i<cycle.size(); i++) {
cout<<cycle[i];
if(i != cycle.size()-1)
cout<<',';
}
cout<<") ";
cycle.clear();
}
}
numb.clear();
cout<<"\n";
count_number++;
}
else
{
for(int j=k;j<N;j++)
{
Swap(k,j);
Generate(k+1);
Swap(k,j);
}
}
}
int main()
{
setlocale(LC_CTYPE,"English");
cout<<"N=";
cin>>N;
QueryPerformanceFrequency( &freq );
QueryPerformanceCounter( &start );
for(int i=0;i<N;i++)
X[i]=i+1;
Generate(0);
cout<<endl;
cout<<endl;
QueryPerformanceCounter( &finish );
double time = (finish.QuadPart - start.QuadPart) / (double)freq.QuadPart;
cout<<"Algorith time:"<<time<<" \t seconds"<<endl;
cout<<"All permutation:"<<count_number<<endl;
FILE myfile;
cin.get();
getch();
return 0;
}
included
created FILE mmm.
how to make?