Regex that gets a sentence containing a name - regex

Question

I am creating regexes that get the whole sentence if a piece of specific information exists. Right now I am working on my name regex, so if there is any composed name (example: "Jorge Martel", "Jorge Martel del Arnold Albuquerque") the regex should get the whole sentence that has the name.
If I have these two sentences:
(1) - "A hardworking guy is working at the supermarket. They call him Jorge Horizon, but that's not his real name."
(2) - "He has an identity document that contains the name, Jorge Martel Arnold."
The regex should return these two results from the sentences above:
(1) - "They call him Jorge Horizon, but that's not his real name."
(2) - "He has an identity document that contains the name, Jorge Martel Arnold."
This is my regex:
(?:(?(?<=[\.!?]\s([A-Z]))(.+?[^.])|))?((?:(?:[A-Z][A-zÀ-ÿ']+\s(?:(?:(?:[A-zÀ-ÿ']{1,3}\s)?(?:[A-ZÀ-Ÿ][A-zÀ-ÿ']*\s?))+))\b)(.+?[\.!?](?:\s|\n|\Z)))
Basically, it verifies if there is a dot, exclamation, or interrogation symbol with a blank space and an upper case character and tells the regex that everything must be select, else it should get all the sentence.
My else case (|) right now is empty, because using (.+?) avoids my first condition...
Regex without the else case:
Validates until the dot, but doesn't get the second sentence.
Regex with the else case:
Validates the second sentence, but overrides the first condition that appears in the first sentence.
I expect my regex to return correctly the sentences:
"They call him Jorge Horizon, but that's not his real name."
"He has an identity document that contains the name, Jorge Martel Arnold."
I have also created a text to validate the regex operations as I will be using it a lot in texts. I added a lot of conditions in this text, which will probably appear in my daily work.
Check my regex, sentence, and text here:
Does anyone know what should I change in my regex? I have tried many variations and still cannot find the solution.
P.S.: I intend to use it in my python code, but I need to fix it with the regex and not with the python code.

Answer 1

you can try this.
[\w\ \,\']+\.\ ?([\w\ \,\']+\.)|^([\w\ \,\']+\.)$
prints $1$2. I.e if group one is empty it prints blank since there is no match, then will print group 2. Visa versa, it prints group 1 when group 2 is not there.
[\w\ ,']+.\ ?([\w\ ,']+.) - as matching anything with XXX. XXX.
then
^([\w\ ,']+.)$ - must start end with only 1 sentence.
Though honestly this can easily be done with a Tokenizer of (.) that check length of 1 or 2. It' really like using a sledgehammer to hammer a nail.

Answer 2

Matching names can be a very hard job using a regex, but if you want to match at least 2 consecutive uppercase words using the specified ranges.
Assuming the names start with an uppercase char A-Z (else you can extend that character class as well with the allowed chars or if supported use \p{Lu} to match an uppercase char that has a lowercase variant):
(?<!\S)[A-Z][A-Za-zÀ-ÿ]*(?:\s+[a-zÀ-ÿ,]+)*\s+[A-Z][a-zÀ-ÿ]*\s+[A-Z][a-zÀ-ÿ,]*.*?[.!?](?!\S)
(?<!\S) Assert a whitespace boundary to the left
[A-Z][A-Za-zÀ-ÿ]* Match an uppercase char A-Z optionally followed by matching the defined ranges
(?:\s+[a-zÀ-ÿ,]*)* Optionally repeat matching 1+ whitespace chars and 1 or more of the ranges
\s+[A-Z][a-zÀ-ÿ]*\s+[A-Z][a-zÀ-ÿ,]* Match 2 times whitespace chars followed by an uppercase A-Z and optional chars defined in the character class
.*?[.!?] Match as least as possible chars followed by one of . ! or ?
(?!\S) Assert a whitspace boundary to the right
Regex demo

Answer 3

Try this:
((?:^|(?:[^\.!?]*))[^\.!?\n]*(?:(?:[A-ZÀ-Ÿ][A-zÀ-ÿ']+\s?){2,}[^\.!?]*[\.!?]))
It will capture sentences where name has at least two words, e.g. His name is John Smith.
It won't capture sentences like: John went to a concert.