If constexpr ternary operator - c++

I have a simple snipped below:
template<typename>
struct function_traits;
template<typename Rv, typename... Args>
struct function_traits<Rv(Args...)>
{
static constexpr const char _signature[] = {GetTypeChar<Rv>, '(', GetTypeChar<Args>()..., ')', '\0'};
}
where GetTypeChar returns character representing a type (i for integer, d for double et cetra).
This works really well for simple types, eg function_traits<int(float,double)>::_signature returns i(f,d) as expected.
Now Imagine I would have the ability to see whether it is an array or not by adding '[]' after the array, eg double[] would result in d[].
I tried changing the signature to
static constexpr const char _signature[] = {GetTypeChar<Rv>(), '(', (std::is_array_v<Args> ? GetTypeChar<Args>(), '[', ']' : GetTypeChar<Args>())..., ')', '\0'};
but that seems to be completely ignored, and only things after : are evaluated.
Is something like this possible?

Well, Initially I though I will be able to do this in a single array initialization, but the constexpr getter works well.
This is what I ended up with:
template<typename Tp>
constexpr void SetParamType(char*& dst)
{
if constexpr (std::is_pointer_v<Tp>)
{
*dst++ = '[';
}
*dst++ = GetTypeChar<Tp>();
}
[[nodiscard]]
constexpr auto signature() const
{
std::array<char, sizeof...(Args) * 2 + 4> out = {0};
char * ptr = out.data();
*ptr++ = GetTypeChar<return_type>();
*ptr++ = '(';
(SetParamType<Args>(ptr),...);
*ptr++ = ')';
*ptr++ = '\0';
return out;
}
Please note that it would be wise to calculate the size of an array to exactly match the required length (which would not be hard after all, but for sake of simplicity I'll leave it as it is for now)

Related

How to get index from fold expression

I'm making a simple constexpr string encoder, see below.
template<char...Chars>
struct encoder
{
constexpr static char encode(char c)
{
return c ^ size;
}
constexpr static size_t size = sizeof...(Chars);
constexpr static const char value[size + 1] = {encode(Chars)...,0};
};
template<typename T,T...Chars>
constexpr auto operator""_encode()
{
return encoder<Chars...>::value;
}
useage:
"aab"_encode
"123"_encode
i want to get char index from encode function,like this
constexpr static char encode(char c,uint32_t index)
{
return c ^ (size + index);
}
or like this
template<uint32_t index>
constexpr static char encode(char c)
{
return c ^ (size + index);
}
But I don't know how. Any one show me how to do that?
You can write the whole thing in a single constexpr function in C++17:
template<typename T, T...Chars>
constexpr auto operator""_encode()
{
constexpr std::size_t size = sizeof...(Chars);
std::array<char, size+1> ret = {}; // Maybe T instead of char?
int i = 0;
((ret[i] = Chars ^ (size + i), i++), ...);
ret[size] = 0;
return ret;
}
(I made it return a std::array instead of a builtin array for everyone's sanity.)
Here's a godbolt link, including one of your test inputs (it helps if you include the desired output, nobody likes poring over ASCII tables and xoring stuff by hand, even if I did that here):
https://godbolt.org/z/P8ABHM
Also, please don't use this to encrypt anything.

C++ compile-time substring

I have very big code-base, which uses __FILE__ extensively for logging. However, it includes full path, which is (1) not needed, (2) might case security violations.
I'm trying to write compile-time sub-string expression. Ended up with this solution
static constexpr cstr PastLastSlash(cstr str, cstr last_slash)
{
return *str == '\0' ? last_slash : *str == '/' ? PastLastSlash(str + 1, str + 1) : PastLastSlash(str + 1, last_slash);
}
static constexpr cstr PastLastSlash(cstr str)
{
return PastLastSlash(str, str);
}
// usage
PastLastSlash(__FILE__);
This works good, I've checked assembly code, line is trimmed in compile time, only file name is present in binary.
However, this notation is too verbose. I would like to use macro for this, but failed. Proposed example from the link above
#define __SHORT_FILE__ ({constexpr cstr sf__ {past_last_slash(__FILE__)}; sf__;})
doesn't work for MSVC compiler (I'm using MSVC 2017). Is there any other method do to so using c++17?
UPD1: clang trimmed by function https://godbolt.org/z/tAU4j7
UPD2: looks like it's possible to do trim on compile time using functions, but full string is swill be present in binary.
The idea is to create truncated array of characters, but it needs to use only compile time features. Generating data array through variadic template with pack of char forces compiler to generate data without direct relation to passed string literal. This way compiler cannot use input string literal, especially when this string is long.
Godbolt with clang: https://godbolt.org/z/WdKNjB.
Godbolt with msvc: https://godbolt.org/z/auMEIH.
The only problem is with template depth compiler settings.
First we define int variadic template to store sequence of indexes:
template <int... I>
struct Seq {};
Pushing int to Seq:
template <int V, typename T>
struct Push;
template <int V, int... I>
struct Push<V, Seq<I...>>
{
using type = Seq<V, I...>;
};
Creating sequence:
template <int From, int To>
struct MakeSeqImpl;
template <int To>
struct MakeSeqImpl<To, To>
{
using type = Seq<To>;
};
template <int From, int To>
using MakeSeq = typename MakeSeqImpl<From, To>::type;
template <int From, int To>
struct MakeSeqImpl : Push<From, MakeSeq<From + 1, To>> {};
Now we can make sequence of compile time ints, meaning that MakeSeq<3,7> == Seq<3,4,5,6,7>. Still we need something to store selected characters in array, but using compile time representation, which is variadic template parameter with characters:
template<char... CHARS>
struct Chars {
static constexpr const char value[] = {CHARS...};
};
template<char... CHARS>
constexpr const char Chars<CHARS...>::value[];
Next we something to extract selected characters into Chars type:
template<typename WRAPPER, typename IDXS>
struct LiteralToVariadicCharsImpl;
template<typename WRAPPER, int... IDXS>
struct LiteralToVariadicCharsImpl<WRAPPER, Seq<IDXS...> > {
using type = Chars<WRAPPER::get()[IDXS]...>;
};
template<typename WRAPPER, typename SEQ>
struct LiteralToVariadicChars {
using type = typename LiteralToVariadicCharsImpl<WRAPPER, SEQ> :: type;
};
WRAPPER is a type that contain our string literal.
Almost done. The missing part is to find last slash. We can use modified version of the code found in the question, but this time it returns offset instead of pointer:
static constexpr int PastLastOffset(int last_offset, int cur, const char * const str)
{
if (*str == '\0') return last_offset;
if (*str == '/') return PastLastOffset(cur + 1, cur + 1, str + 1);
return PastLastOffset(last_offset, cur + 1, str + 1);
}
Last util to get string size:
constexpr int StrLen(const char * str) {
if (*str == '\0') return 0;
return StrLen(str + 1) + 1;
}
Combining everything together using define:
#define COMPILE_TIME_PAST_LAST_SLASH(STR) \
[](){ \
struct Wrapper { \
constexpr static const char * get() { return STR; } \
}; \
using Seq = MakeSeq<PastLastOffset(0, 0, Wrapper::get()), StrLen(Wrapper::get())>; \
return LiteralToVariadicChars<Wrapper, Seq>::type::value; \
}()
Lambda function is to have nice, value-like feeling when using this macro. It also creates a scope for defining Wrapper structure. Generating this structure with inserted string literal using macro, leads to situation when the string literal is bounded to type.
Honestly I would not use this kind of code in production. It is killing compilers.
Both, in case of security reasons and memory usage, I would recommend using docker with custom, short paths for building.
You can using std::string_view:
constexpr auto filename(std::string_view path)
{
return path.substr(path.find_last_of('/') + 1);
}
Usage:
static_assert(filename("/home/user/src/project/src/file.cpp") == "file.cpp");
static_assert(filename("./file.cpp") == "file.cpp");
static_assert(filename("file.cpp") == "file.cpp");
See it compile (godbolt.org).
For Windows:
constexpr auto filename(std::wstring_view path)
{
return path.substr(path.find_last_of(L'\\') + 1);
}
With C++17, you can do the following (https://godbolt.org/z/68PKcsPzs):
#include <cstdio>
#include <array>
namespace details {
template <const char *S, size_t Start = 0, char... C>
struct PastLastSlash {
constexpr auto operator()() {
if constexpr (S[Start] == '\0') {
return std::array{C..., '\0'};
} else if constexpr (S[Start] == '/') {
return PastLastSlash<S, Start + 1>()();
} else {
return PastLastSlash<S, Start + 1, C..., (S)[Start]>()();
}
}
};
}
template <const char *S>
struct PastLastSlash {
static constexpr auto a = details::PastLastSlash<S>()();
static constexpr const char * value{a.data()};
};
int main() {
static constexpr char f[] = __FILE__;
puts(PastLastSlash<f>::value);
return 0;
}
With C++14, it's a bit more complicated because of the more limited constexpr (https://godbolt.org/z/bzGec5GMv):
#include <cstdio>
#include <array>
namespace details {
// Generic form: just add the character to the list
template <const char *S, char ch, size_t Start, char... C>
struct PastLastSlash {
constexpr auto operator()() {
return PastLastSlash<S, S[Start], Start + 1, C..., ch>()();
}
};
// Found a '/', reset the character list
template <const char *S, size_t Start, char... C>
struct PastLastSlash<S, '/', Start, C...> {
constexpr auto operator()() {
return PastLastSlash<S, S[Start], Start + 1>()();
}
};
// Found the null-terminator, ends the search
template <const char *S, size_t Start, char... C>
struct PastLastSlash<S, '\0', Start, C...> {
constexpr auto operator()() {
return std::array<char, sizeof...(C)+1>{C..., '\0'};
}
};
}
template <const char *S>
struct PastLastSlash {
const char * operator()() {
static auto a = details::PastLastSlash<S, S[0], 0>()();
return a.data();
}
};
static constexpr char f[] = __FILE__;
int main() {
puts(PastLastSlash<f>{}());
return 0;
}
With C++20, it should be possible to pass __FILE__ directly to the template instead of needing those static constexpr variables

How to define string literal with character type that depends on template parameter?

template<typename CharType>
class StringTraits {
public:
static const CharType NULL_CHAR = '\0';
static constexpr CharType* WHITESPACE_STR = " ";
};
typedef StringTraits<char> AStringTraits;
typedef StringTraits<wchar_t> WStringTraits;
I know I could do it with template specialization, but this would require some duplication (by defining string literals with and without L prefix).
Is there a simpler way to define const/constexpr char/wchar_t and char*/wchar_t* with same string literal in a template class?
There are several ways to do this, depending on the available version of the C++ standard.
If you have C++17 available, you can scroll down to Method 3, which is the most elegant solution in my opinion.
Note: Methods 1 and 3 assume that the characters of the string literal will be restricted to 7-bit ASCII. This requires that characters are in the range [0..127] and the execution character set is compatible with 7-bit ASCII (e. g. Windows-1252 or UTF-8). Otherwise the simple casting of char values to wchar_t used by these methods won't give the correct result.
Method 1 - aggregate initialization (C++03)
The simplest way is to define an array using aggregate initialization:
template<typename CharType>
class StringTraits {
public:
static const CharType NULL_CHAR = '\0';
static constexpr CharType WHITESPACE_STR[] = {'a','b','c',0};
};
Method 2 - template specialization and macro (C++03)
(Another variant is shown in this answer.)
The aggregate initialization method can be cumbersome for long strings. For more comfort, we can use a combination of template specialization and macros:
template< typename CharT > constexpr CharT const* NarrowOrWide( char const*, wchar_t const* );
template<> constexpr char const* NarrowOrWide< char >( char const* c, wchar_t const* )
{ return c; }
template<> constexpr wchar_t const* NarrowOrWide< wchar_t >( char const*, wchar_t const* w )
{ return w; }
#define TOWSTRING1(x) L##x
#define TOWSTRING(x) TOWSTRING1(x)
#define NARROW_OR_WIDE( C, STR ) NarrowOrWide< C >( ( STR ), TOWSTRING( STR ) )
Usage:
template<typename CharType>
class StringTraits {
public:
static constexpr CharType const* WHITESPACE_STR = NARROW_OR_WIDE( CharType, " " );
};
Live Demo at Coliru
Explanation:
The template function NarrowOrWide() returns either the first (char const*) or the second (wchar_t const*) argument, depending on template parameter CharT.
The macro NARROW_OR_WIDE is used to avoid having to write both the narrow and the wide string literal. The macro TOWSTRING simply prepends the L prefix to the given string literal.
Of course the macro will only work if the range of characters is limited to basic ASCII, but this is usually sufficient. Otherwise one can use the NarrowOrWide() template function to define narrow and wide string literals separately.
Notes:
I would add a "unique" prefix to the macro names, something like the name of your library, to avoid conflicts with similar macros defined elsewhere.
Method 3 - array initialized via template parameter pack (C++17)
C++17 finally allows us to get rid of the macro and use a pure C++ solution. The solution uses template parameter pack expansion to initialize an array from a string literal while static_casting the individual characters to the desired type.
First we declare a str_array class, which is similar to std::array but tailored for constant null-terminated string (e. g. str_array::size() returns number of characters without '\0', instead of buffer size). This wrapper class is necessary, because a plain array cannot be returned from a function. It must be wrapped in a struct or class.
template< typename CharT, std::size_t Length >
struct str_array
{
constexpr CharT const* c_str() const { return data_; }
constexpr CharT const* data() const { return data_; }
constexpr CharT operator[]( std::size_t i ) const { return data_[ i ]; }
constexpr CharT const* begin() const { return data_; }
constexpr CharT const* end() const { return data_ + Length; }
constexpr std::size_t size() const { return Length; }
// TODO: add more members of std::basic_string
CharT data_[ Length + 1 ]; // +1 for null-terminator
};
So far, nothing special. The real trickery is done by the following str_array_cast() function, which initializes the str_array from a string literal while static_casting the individual characters to the desired type:
#include <utility>
namespace detail {
template< typename ResT, typename SrcT >
constexpr ResT static_cast_ascii( SrcT x )
{
if( !( x >= 0 && x <= 127 ) )
throw std::out_of_range( "Character value must be in basic ASCII range (0..127)" );
return static_cast<ResT>( x );
}
template< typename ResElemT, typename SrcElemT, std::size_t N, std::size_t... I >
constexpr str_array< ResElemT, N - 1 > do_str_array_cast( const SrcElemT(&a)[N], std::index_sequence<I...> )
{
return { static_cast_ascii<ResElemT>( a[I] )..., 0 };
}
} //namespace detail
template< typename ResElemT, typename SrcElemT, std::size_t N, typename Indices = std::make_index_sequence< N - 1 > >
constexpr str_array< ResElemT, N - 1 > str_array_cast( const SrcElemT(&a)[N] )
{
return detail::do_str_array_cast< ResElemT >( a, Indices{} );
}
The template parameter pack expansion trickery is required, because constant arrays can only be initialized via aggregate initialization (e. g. const str_array<char,3> = {'a','b','c',0};), so we have to "convert" the string literal to such an initializer list.
The code triggers a compile time error if any character is outside of basic ASCII range (0..127), for the reasons given at the beginning of this answer. There are code pages where 0..127 doesn't map to ASCII, so this check does not give 100% safety though.
Usage:
template< typename CharT >
struct StringTraits
{
static constexpr auto WHITESPACE_STR = str_array_cast<CharT>( "abc" );
// Fails to compile (as intended), because characters are not basic ASCII.
//static constexpr auto WHITESPACE_STR1 = str_array_cast<CharT>( "Àâü" );
};
Live Demo at Coliru
Here is a refinement of the now-common template-based solution which
preserves the array[len] C++ type of the C strings rather than decaying them to pointers, which means you can call sizeof() on the result and get the size of the string+NUL, not the size of a pointer, just as if you had the original string there.
Works even if the strings in different encodings have different length in code units (which is virtually guaranteed if the strings have non-ASCII text).
Does not incur any runtime overhead nor does it attempt/need to do encoding conversion at runtime.
Credit: This refinement starts with the original template idea from Mark Ransom and #2 from zett42 and borrows some ideas from, but fixes the size limitations of, Chris Kushnir's answer.
This code does char and wchar_t but it is trivial to extend it to char8_t+char16_t+char32_t
// generic utility for C++ pre-processor concatenation
// - avoids a pre-processor issue if x and y have macros inside
#define _CPP_CONCAT(x, y) x ## y
#define CPP_CONCAT(x, y) _CPP_CONCAT(x, y)
// now onto stringlit()
template<size_t SZ0, size_t SZ1>
constexpr
auto _stringlit(char c,
const char (&s0) [SZ0],
const wchar_t (&s1) [SZ1]) -> const char(&)[SZ0]
{
return s0;
}
template<size_t SZ0, size_t SZ1>
constexpr
auto _stringlit(wchar_t c,
const char (&s0) [SZ0],
const wchar_t (&s1) [SZ1]) -> const wchar_t(&)[SZ1]
{
return s1;
}
#define stringlit(code_unit, lit) \
_stringlit(code_unit (), lit, CPP_CONCAT(L, lit))
Here we are not using C++ overloading but rather defining one function per char encoding, each function with different signatures. Each function returns the original array type with the original bounds. The selector that chooses the appropriate function is a single character in the desired encoding (value of that character not important). We cannot use the type itself in a template parameter to select because then we'd be overloading and have conflicting return types. This code also works without the constexpr. Note we are returning a reference to an array (which is possible in C++) not an array (which is not allowed in C++). The use of trailing return type syntax here is optional, but a heck of a lot more readable than the alternative, something like const char (&stringlit(...params here...))[SZ0] ugh.
I compiled this with clang 9.0.8 and MSVC++ from Visual Studio 2019 16.7 (aka _MSC_VER 1927 aka pdb ver 14.27). I had c++2a/c++latest enabled, but I think C++14 or 17 is sufficient for this code.
Enjoy!
Here's an alternative implementation based on #zett42 's answer. Please advise me.
#include <iostream>
#include <tuple>
#define TOWSTRING_(x) L##x
#define TOWSTRING(x) TOWSTRING_(x)
#define MAKE_LPCTSTR(C, STR) (std::get<const C*>(std::tuple<const char*, const wchar_t*>(STR, TOWSTRING(STR))))
template<typename CharType>
class StringTraits {
public:
static constexpr const CharType* WHITESPACE_STR = MAKE_LPCTSTR(CharType, "abc");
};
typedef StringTraits<char> AStringTraits;
typedef StringTraits<wchar_t> WStringTraits;
int main(int argc, char** argv) {
std::cout << "Narrow string literal: " << AStringTraits::WHITESPACE_STR << std::endl;
std::wcout << "Wide string literal : " << WStringTraits::WHITESPACE_STR << std::endl;
return 0;
}
I've just came up with a compact answer, which is similar to other C++17 versions. Similarly, it relies on implementation defined behavior, specifically on the environment character types. It supports converting ASCII and ISO-8859-1 to UTF-16 wchar_t, UTF-32 wchar_t, UTF-16 char16_t and UTF-32 char32_t. UTF-8 input is not supported, but more elaborate conversion code is feasible.
template <typename Ch, size_t S>
constexpr auto any_string(const char (&literal)[S]) -> const array<Ch, S> {
array<Ch, S> r = {};
for (size_t i = 0; i < S; i++)
r[i] = literal[i];
return r;
}
Full example follows:
$ cat any_string.cpp
#include <array>
#include <fstream>
using namespace std;
template <typename Ch, size_t S>
constexpr auto any_string(const char (&literal)[S]) -> const array<Ch, S> {
array<Ch, S> r = {};
for (size_t i = 0; i < S; i++)
r[i] = literal[i];
return r;
}
int main(void)
{
auto s = any_string<char>("Hello");
auto ws = any_string<wchar_t>(", ");
auto s16 = any_string<char16_t>("World");
auto s32 = any_string<char32_t>("!\n");
ofstream f("s.txt");
f << s.data();
f.close();
wofstream wf("ws.txt");
wf << ws.data();
wf.close();
basic_ofstream<char16_t> f16("s16.txt");
f16 << s16.data();
f16.close();
basic_ofstream<char32_t> f32("s32.txt");
f32 << s32.data();
f32.close();
return 0;
}
$ c++ -o any_string any_string.cpp -std=c++17
$ ./any_string
$ cat s.txt ws.txt s16.txt s32.txt
Hello, World!
A variation of zett42 Method 2 above.
Has the advantage of supporting all char types (for literals that can be represented as char[]) and preserving the proper string literal array type.
First the template functions:
template<typename CHAR_T>
constexpr
auto LiteralChar(
char A,
wchar_t W,
char8_t U8,
char16_t U16,
char32_t U32
) -> CHAR_T
{
if constexpr( std::is_same_v<CHAR_T, char> ) return A;
else if constexpr( std::is_same_v<CHAR_T, wchar_t> ) return W;
else if constexpr( std::is_same_v<CHAR_T, char8_t> ) return U8;
else if constexpr( std::is_same_v<CHAR_T, char16_t> ) return U16;
else if constexpr( std::is_same_v<CHAR_T, char32_t> ) return U32;
}
template<typename CHAR_T, size_t SIZE>
constexpr
auto LiteralStr(
const char (&A) [SIZE],
const wchar_t (&W) [SIZE],
const char8_t (&U8) [SIZE],
const char16_t (&U16)[SIZE],
const char32_t (&U32)[SIZE]
) -> const CHAR_T(&)[SIZE]
{
if constexpr( std::is_same_v<CHAR_T, char> ) return A;
else if constexpr( std::is_same_v<CHAR_T, wchar_t> ) return W;
else if constexpr( std::is_same_v<CHAR_T, char8_t> ) return U8;
else if constexpr( std::is_same_v<CHAR_T, char16_t> ) return U16;
else if constexpr( std::is_same_v<CHAR_T, char32_t> ) return U32;
}
Then the macros:
#define CMK_LC(CHAR_T, LITERAL) \
LiteralChar<CHAR_T>( LITERAL, L ## LITERAL, u8 ## LITERAL, u ## LITERAL, U ## LITERAL )
#define CMK_LS(CHAR_T, LITERAL) \
LiteralStr<CHAR_T>( LITERAL, L ## LITERAL, u8 ## LITERAL, u ## LITERAL, U ## LITERAL )
Then use:
template<typename CHAR_T>
class StringTraits {
public:
struct LC { // literal character
static constexpr CHAR_T Null = CMK_LC(CHAR_T, '\0');
static constexpr CHAR_T Space = CMK_LC(CHAR_T, ' ');
};
struct LS { // literal string
// can't seem to avoid having to specify the size
static constexpr CHAR_T Space [2] = CMK_LS(CHAR_T, " ");
static constexpr CHAR_T Ellipsis [4] = CMK_LS(CHAR_T, "...");
};
};
auto char_space { StringTraits<char>::LC::Space };
auto wchar_space { StringTraits<wchar_t>::LC::Space };
auto char_ellipsis { StringTraits<char>::LS::Ellipsis }; // note: const char*
auto wchar_ellipsis { StringTraits<wchar_t>::LS::Ellipsis }; // note: const wchar_t*
auto (& char_space_array) [4] { StringTraits<char>::LS::Ellipsis };
auto (&wchar_space_array) [4] { StringTraits<wchar_t>::LS::Ellipsis };
? syntax to get a local copy ?
Admittedly, the syntax to preserve the string literal array type is a bit of a burden, but not overly so.
Again, only works for literals that have the same # of code units in all char type representations.
If you want LiteralStr to support all literals for all types would likely need to pass pointers as param and return CHAR_T* instead of CHAR_T(&)[SIZE]. Don't think can get LiteralChar to support multibyte char.
[EDIT]
Applying Louis Semprini SIZE support to LiteralStr gives:
template<typename CHAR_T,
size_t SIZE_A, size_t SIZE_W, size_t SIZE_U8, size_t SIZE_U16, size_t SIZE_U32,
size_t SIZE_R =
std::is_same_v<CHAR_T, char> ? SIZE_A :
std::is_same_v<CHAR_T, wchar_t> ? SIZE_W :
std::is_same_v<CHAR_T, char8_t> ? SIZE_U8 :
std::is_same_v<CHAR_T, char16_t> ? SIZE_U16 :
std::is_same_v<CHAR_T, char32_t> ? SIZE_U32 : 0
>
constexpr
auto LiteralStr(
const char (&A) [SIZE_A],
const wchar_t (&W) [SIZE_W],
const char8_t (&U8) [SIZE_U8],
const char16_t (&U16) [SIZE_U16],
const char32_t (&U32) [SIZE_U32]
) -> const CHAR_T(&)[SIZE_R]
{
if constexpr( std::is_same_v<CHAR_T, char> ) return A;
else if constexpr( std::is_same_v<CHAR_T, wchar_t> ) return W;
else if constexpr( std::is_same_v<CHAR_T, char8_t> ) return U8;
else if constexpr( std::is_same_v<CHAR_T, char16_t> ) return U16;
else if constexpr( std::is_same_v<CHAR_T, char32_t> ) return U32;
}
It is also possible to use a simpler syntax to create variables;
for example, in StringTraits::LS can change to constexpr auto &
so
static constexpr CHAR_T Ellipsis [4] = CMK_LS(CHAR_T, "...");
becomes
static constexpr auto & Ellipsis { CMK_LS(CHAR_T, "...") };
When using CMK_LS(char, "literal") any invalid char in literal are converted to '?' by VS 2019, not sure what other compilers do.

Template code and literal strings

I am currently writing some template code where the template parameter is the char type to use. This causes a problem when referring to literal strings. I can, of course, make a struct with the strings I use but I was thinking if it would be possible to make something like:
template<typename chartype, char32_t... chars>
struct tr {
/* some magic here */
};
so that tr<char32_t,U"hello world"> would result in U"hello world"
and tr<char16_t,U"Hello world"> would result in u"hello world"
and tr<char,U"hello world"> would result in "hello world" (in UTF-8).
The magic should of course correctly translate codes above 0x10000 to lead code and follow code for char16_t and to proper 2, 3 and 4 byte codes for UTF-8
at compile time.
Problem is: how do you define a constant C-style string of a given char type using the char32_t... chars template argument? You can extract the characters
from it but how do you rebuild a new string based on the chars of the input string in template code?
Note, the preprocessor can correctly define a string such as "hello world" with suitable prefix u or U if you like but it cannot access the individual characters of the string to properly translate it.
EDIT:
Strings as template arguments are definitely possible in new C++, however,
the template argument is NOT declared as const char * or something like that:
template <char... txt>
struct foo { ... }
allows you to write foo<"hello"> as a type with the string "hello" as template argument. The problem is how to build the string from those characters.
I mean at some point you want the struct to contain a string value to return:
template <char32_t... txt>
struct foo;
template <>
struct foo<> {
static const char16_t * txt() { return ""; }
};
template <char32_t a, char32_t... rest>
struct foo<a, rest...> {
static const char16_t * txt()
{
char16_t buf[100];
int k = 0;
if (a < 0x10000) buf[k++] = a;
else {
buf[k++] = 0xd800 | ((a - 0x10000) >> 10);
buf[k++] = 0xdc00 | ((a-0x10000) & 0x3ff);
}
// copy rest of string into buf + 2..99
u16strcpy(buf + k, foo<rest...>::txt());
return buf;
}
}
Several obvious problems with this "solution", one problem is that buf only have room for 100 characters which will fail if the string is longer. but the main problem is that I wanted this to happen in compile time and this looks very much like run time code to me and is not at all what I wanted to do.
Basically I wanted something that works this way:
foo<char, "hello"> results in something that is effectively a string literal
"hello" or u8"hello".
foo<char16_t, "hello"> results in something that is effectively a string literal u"hello" and foo<char32_t, "hello"> results in something that is effectively a string literal U"hello".
The problem is when writing template code to handle various character formats and then having string literals involved. Yes, you can write a simple struct:
template <typename ChT> struct bar;
template <>
struct bar<char32_t> {
static const char32_t * txta = U"AAAA";
static const char32_t * txtb = U"BBBB";
};
and so on and bar<char16_t> has txta = u"AAAA" etc. Then refer to the strings
in your templated code by bar<T>::txta etc. However, I wish there was a way that you could specify those strings directly in templated code and the compiler would do the right thing. A templated string literal in other words.
Maybe it should be added as a feature to the language that
T<char32_t> string-literal is the same as U string-literal etc
so that you could write
template <typename ChT>
struct foo {
static const ChT * txta = T<ChT> "AAAAA";
};
and the compiler would do the right thing.
This would appear to simply not be legal, even the following is rejected (vs2017, with standard set to latest):
template<char const * ptr>
struct test
{};
void bar()
{
test<"testing"> t;
}
with the error: invalid expression as a template argument for 'ptr', and if that's not going to work trying to convert it at compile-time is a non-starter. And honestly this doesn't seem all that surprising that a pointer-to-data isn't constant enough. to be a template argument.
Here are some tools to make it work in C++17 (might be portable to C++11 and C++14):
static constexpr data member of templated class
The output literal you wish to work with needs some "storage". I suggest to instantiate a unique class template for each literal, e.g., Literal<char, 'f', 'o', 'o', '\0'>. That class can hold the data as astatic constexpr` member.
template<class C, C... cs>
struct Literal {
static_assert(sizeof...(cs) >= 1);
static constexpr C data[] = {cs...};// or use `std::array<C, sizeof...(cs)>`
};
template<class C, C... cs>
constexpr C Literal<C, cs...>::data[];
user-defined string literal to simplify syntax
Of course you wish to avoid typing, e.g., Literal<char, 'f', 'o', 'o', '\0'>. A useful tool to achieve that is the following overload for user-defined string literals.
template<class C, C... cs>
constexpr Literal<C, cs..., C('\0')> operator""_c() {// or use `auto`
return Literal<C, cs..., C('\0')>{};
}
Note how the input literal is passed as non-type template parameters to that overload. That way, it is possible to "carry the value as a type".
constexpr algorithms for re-encoding
So far, you can type "foo"_c to obtain a Literal<char, 'f', 'o', 'o', '\0'> which has a static constexpr data member yielding the same as "foo". Next you can pass that Literal<char, 'f', 'o', 'o', '\0'> to a function which returns a const char16_t(&)[4] to data of the corresponding Literal<char16_t, ..., '\0'>. The syntax could read tr<char16_t>("foo"_c).
The code that transforms a Literal<char, ...> into the corresponding Literal<char16_t, ...> may be based on constexpr algorithms as shown below.
template<
class OutChar, class InChar, InChar... cs,
std::size_t... input_indices, std::size_t... output_indices
>
constexpr auto& tr_impl(// called by `tr` with appropriate `index_sequence`s
Literal<InChar, cs...>,
std::index_sequence<input_indices...>,
std::index_sequence<output_indices...>
) {
constexpr std::size_t outsize = sizeof...(output_indices);
using Buffer = std::array<OutChar, outsize>;
constexpr Buffer buf = encode_as<OutChar, outsize>({cs...});
return Literal<OutChar, buf[output_indices]...>::data;
}
template<class OutChar, class InChar, InChar... cs>
constexpr auto& tr(Literal<InChar, cs...> literal) {
constexpr std::size_t outsize = count_as<OutChar>({cs...});
return tr_impl<OutChar>(
literal,
std::make_index_sequence<sizeof...(cs)>{},// input indices
std::make_index_sequence<outsize>{}// output indices
);
}
The remaining part would be to implement those functions count_as and encode_as.
assign to constexpr auto& in final usage
Finally you can assign to constexpr auto& to verify that type and value are equivalent to the plain string literal based on the desired character type.
static_assert(std::size(U"π„žπ„ž") == 3);
static_assert(std::size(u"π„žπ„ž") == 5);
constexpr auto& test = tr<char16_t>(U"π„žπ„ž"_c);
static_assert(std::is_same<decltype(test), const char16_t(&)[5]>{});
for(std::size_t i=0; i<std::size(u"π„žπ„ž"); ++i) {
assert(test[i] == u"π„žπ„ž"[i]);
std::cout << i << ": " << test[i] << std::endl;
}

constexpr conversion of hex chars to std::string

I have a number of strings like this:
"343536"_hex
that I would like to convert into their corresponding byte strings. I am using C++11and have defined a user-defined string literals to convert these into hex strings. However, the conversion I currently have cannot be evaluated as a constexpr which is what I'm seeking. In particular I would like to use something like this, but as a constexpr:
std::string operator "" _hex(const char *s, std::size_t slen )
{
std::string str;
str.reserve(slen);
char ch[3];
unsigned long num;
ch[2] = '\0';
for ( ; slen; slen -= 2, s += 2) {
ch[0] = s[0];
ch[1] = s[1];
num = strtoul(ch, NULL, 16);
str.push_back(num);
}
return str;
}
Test driver
int main()
{
std::string src{"653467740035"_hex};
for (const auto &ch : src)
std::cout << std::hex << std::setw(2) << std::setfill('0')
<< (unsigned)ch << '\n';
}
Sample output
65
34
67
74
00
35
The question
To be very, very clear about what I'm asking, it's this:
How can I write a C++11 string literal conversion of this type that can be evaluated at compile time as a constexpr?
In order to achieve what you are trying to do, you will need to have some compile-time string class that is compatible with constexpr. There isn't such a standard thing though. I can see some things that approach it:
boost::mpl::string, but the interface is not really pretty.
boost::log::string_literal, which has the interface you want but lacks the constexpr support.
std::string_literal, which is exactly what you are looking for, but which isn't implemented. It can probably be implementable in C++11 though if you have some free time.
In order to simplify all of this, let's use an overly simplified string_literal class. Note that some of the classes described above have a trailing \0 to be closer to std::string, but we won't bother to add one.
template<std::size_t N>
struct string_literal
{
char data[N];
};
We will also provide operator+ for concatenation. It would take some time to explain how it works and it's not really relevant for the question. Let's say that it is just some template wizardry (std::integer_sequence is a C++14 utility but can be implemented in C++11):
template<std::size_t N1, std::size_t N2, std::size_t... Ind1, std::size_t... Ind2>
constexpr auto concatenate(string_literal<N1> lhs, string_literal<N2> rhs,
std::index_sequence<Ind1...>, std::index_sequence<Ind2...>)
-> string_literal<N1+N2>
{
return { lhs.data[Ind1]... , rhs.data[Ind2]... };
}
template<std::size_t N1, std::size_t N2>
constexpr auto operator+(string_literal<N1> lhs, string_literal<N2> rhs)
-> string_literal<N1+N2>
{
using Indices1 = std::make_index_sequence<N1>;
using Indices2 = std::make_index_sequence<N2>;
return concatenate(lhs, rhs, Indices1{}, Indices2{});
}
You can use the template user-defined literal (with char...) to get rid of the string literal and have a prettier literal (1234_hex instead of "1234"_hex):
template<char... Chars>
auto operator "" _hex()
-> string_literal<sizeof...(Chars)/2>
{
return process<Chars...>();
}
Now, all you need is a function that can process your characters by pairs. A generic one and an overload for the "finish" condition. Note that the enable_if_t is needed to avoid ambiguous function calls (that's C++14, but you can replace it by typename std::enable_if<...>::type in C++11). The "real" work of converting the characters to the equivalent numbers is done in the process overload that only takes two template arguments.
template<char C1, char C2>
constexpr auto process()
-> string_literal<1>
{
return { 16 * (C1 - '0') + (C2 - '0') };
}
template<char C1, char C2, char... Rest,
typename = std::enable_if_t< (sizeof...(Rest) > 0), void >>
constexpr auto process()
-> string_literal<sizeof...(Rest)/2 + 1>
{
return process<C1, C2>() + process<Rest...>();
}
You could add many more checks to ensure that there is always an even number of characters or to ensure that there aren't any bad characters. The code I provided uses some features from the C++14 standard library, but I made sure to only use features that can be easily reimplemented in C++11 if needed. Note that you could probably write a more human-readable program with C++14 thanks to the relaxed restrictions on constexpr functions.
Here is a working C++14 example with all the aforementioned functions and classes. I made sure that your test program still works (I just replaced scr by scr.data in the loop since we use an edulcorated string_literal class).