This question already has answers here:
std::cin input with spaces?
(8 answers)
Closed 1 year ago.
I am making something where you have to put your name but my string doesn't save the spaces, why?
#include <iostream>
using namespace std;
string name;
int main()
{
cout<<"<System>: Please enter your name"<<endl;
cin>>name;
cout<<name;
return 0;
}
I entered:
Test 123
And I got:
Test
the insertion operator inserts only the first string (before any whitespace) from std::cin to the string if you want to take the whole line use std::getline()
#include <iostream>
using namespace std;
string name;
int main()
{
cout<<"<System>: Please enter your name"<<endl;
std::getline(std::cin, name);
cout<<name;
return 0;
}
And see this Why is "using namespace std;" considered bad practice?
std::cin << only reads up to the next space (ie. space, tabulation or line break). If you want to read the whole line, you will have to use std::getline. Moreover, unless you have a very clear reason, you should declare the variable name as a local variable of the function main.
#include <iostream>
using namespace std;
int main()
{
string name;
cout<<"<System>: Please enter your name"<<endl;
getline(cin, name);
cout<<name;
return 0;
}
cin takes any whitespace (spaces, tabs, etc.) as a terminating character which is why you're only getting the first word.
Using getline() you can get the whole sentence until the return key is pressed:
int main()
{
cout<<"<System>: Please enter your name"<<endl;
getline(cin, name);
cout<<name;
return 0;
}
Related
This question already has answers here:
Why does std::getline() skip input after a formatted extraction?
(5 answers)
Closed 2 years ago.
#include <iostream>
#include <bits/stdc++.h>
using namespace std;
main function
int main(){
long long int T;
string s;
cin >> T;
while(T--){
getline(cin, s);
cout << s << endl;
}
}
while loop skipping input on first iteration
only printing blank lines
I want pass string as input on every iteration but on first iteration while loop is skipping input line.
cin >> T reads to the end of the number and not to the end of the line.
So with the first getline(cin, s); you read the rest of the line after the number.
You can call cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n'); right after the cin >> T; to ignore everything that is left in that line.
You need to use std::cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n'); because it ignores the rest of the line up until "\n" or EOF.
Now the std::numeric_limits<std::streamsize>::max() is basically telling cin that there is no limit to the number of characters to ignore.
Also, it might make more sense to use a for loop.
For example:
#include <iostream>
#include <string>
int main()
{
long long int T;
std::cin >> T;
std::cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
for (int i = 0; i < T; i--)
{
std::string s;
std::getline (std::cin, s);
std::cout << s << std::endl;
}
return 0;
}
Also check out why you shouldn't use using namespace std;
This question already has answers here:
equivalent of Console.ReadLine() in c++
(3 answers)
tell cin to stop reading at newline
(6 answers)
Closed 2 years ago.
i wanted to let a user input a string which has whitespaces.but my compiler seems to only take the character and does not include the whitespace.
I have entered the code below:
#include <iostream>
using namespace std;
int main ()
{
char str[100];
cout<<"Enter the value";
cin>>str;
cout<<"Value is :";cout<<str;
return 0;
}
Try using std::string instead of char array along with std::getline:
#include <iostream>
#include <string>
int main () {
std::string str;
std::cout << "Enter the value: ";
std::getline(std::cin, str);
std::cout << std::endl << "Value is :" << str;
return 0;
}
std::getline takes new line character \n as a default delimiter. Therefore, str variable will have whitespaces included.
See the below code. If i give a "space" input for variable name, another integer variable is not being stored in the file. Why?
I've posted the outputs too.
#include<iostream>
#include<fstream>
#include<cstring>
using namespace std;
int main()
{
int age;
char name[100];
ofstream obj,obj10;
obj.open("lol.dat", ios::trunc);
cout<<"Enter Name"<<endl;
cin.getline(name,100);
cin.ignore();
obj<<name<<endl;
cout<<"Enter age"<<endl;
cin>>age;
cin.ignore();
obj10<<age<<endl;
obj.close();
//read
ifstream obj2;
obj2.open("lol.dat");
obj2>>name;
cout<<"Name:"<<name<<endl;
obj2>>age;
cout<<"Age:"<<age<<endl;
obj2.close();
return 0;
}
My outputs:
Enter Name
Ankith
Enter age
1234
Name:Ankith
Age:1234
Enter Name
Ankith Prabhas
Enter age
12345
Name:Ankith
Age:0
What do i need to do to take the complete name "Ankith Prabhas" as one input and another integer?
Try to use getline() in strings where you expect spaces.
I have the following simple program, but the last line of code getline(cin, topicClass) is never excuted. However, if I use normal cin>>topicClass that is executed. Could you please help me out of this? Thanks
#include <iostream>
#include <string>
using namespace std;
void InfoInput()
{
string classID;
string teacherName;
int totalStudent;
string topicClass;
cout<<"Enter class ID"<<endl;
getline(cin, classID);
cout<<"Enter teacher's name"<<endl;
getline(cin, teacherName);
cout<<"Enter total number of students"<<endl;
cin>>totalStudent;
cout<<"Enter topic of class"<<endl;
getline(cin, topicClass);
//cin>>topicClass;
}
int main ()
{
InfoInput();
}
Your problem is above, with this line:
cin>>totalStudent;
This does not read a line. You enter your input and (I assume) you press ENTER. The \n remains in the buffer of std::cin and is read as an empty line with your next instruction:
getline(cin, topicClass);
To fix, use this code:
cin>>totalStudent;
while(std::isspace(cin.peek())
cin.ignore();
cout<<"Enter topic of class"<<endl;
getline(cin, topicClass);
There is \n remained in cin after reading totalStudent as integer so you need to get that \n first out of the system and then read the next string
#include <iostream>
#include <string>
using namespace std;
void InfoInput()
{
string classID;
string teacherName;
int totalStudent;
string topicClass;
cout<<"Enter class ID"<<endl;
getline(cin, classID);
cout<<"Enter teacher's name"<<endl;
getline(cin, teacherName);
cout<<"Enter total number of students"<<endl;
cin>>totalStudent;
cout<<"Enter topic of class"<<endl;
getline(cin,topicClass);
getline(cin, topicClass);
//cin>>topicClass;
}
int main ()
{
InfoInput();
}
Your classID and teacherName are local variables and disappear after execution leaves the function. You'll have to figure out some way, like passing parameters by reference, to share the variables between functions.
I'm using Visual C++ 6.0 and currently created a program that will print the output stored in string.
The problem is when I entered words with space, only the first word is visible in the output.
Example:
Enter your address: new york
new
Press any key to continue
I want this:
Enter your address: new york
new york
Press any key to continue
Also, I tried to use getline but when I entered words, It will first print blank space then stored the last output before the current one.
Here's my code:
#include <iostream>
#include <string>
using namespace std;
void main()
{
string address1;
cout<<"Enter your address:";
cin>> address1;
// getline(cin, address1); code when using getline
cout<<address1<<"\n";
}
you are doing it correct, but the main problem is that you are using cin while you should avoid it and use getline(cin,address1) because cin will only take a single word and it will not take anyhting which you type after space. On the other hand getline(cin,address1) can take a complete sentence along with spaces
Read the comments and use this code
#include <iostream>
#include <string>
using namespace std;
int main()//using int main()
{
string address1;
cout<<"Enter your address:";
//cin>> address1; Don't use it
getline(cin, address1);//use this
cout<<address1<<"\n";
return 0;//returning an integer 0
}
Use std::getline (std::cin, address1);, not cin. Because cin takes space as delimiter.
What about this one? Kind of getline concept, presuming newline character is '\n', change as required according to your platform, unix or windows etc
int main()
{
string addrpart, address1;
cout<<"Enter your address:";
cin>> addrpart;
while (addrpart != "x") {
address1 += addrpart + " ";
addrpart = "x";
cin>> addrpart;
}
cout<<address1<<"\n";
}
Here you go
#include <iostream>
#include <string>
using namespace std;
int main( int argc, char** argv )
{
string userinput;
cout << "Enter your address:";
getline ( cin, userinput );
cout << userinput;
return 0;
}
$ g++ a.cpp -o app
$ ./app
Enter your address:new york
new york