Solve two equations of Linear Inequality involving three different variables through code - c++

I have two linear inequality equations with me, I am trying to understand how can I solve them using the code.
2x + z <= A
3y + z <= B
I know the values of A and B. I am trying to find all the possible positive values of x , y and z that will satisfy the given equation.
I want to solve the above equation using code but I haven't been able to come up with anything.
Any pointers are helpful. Thanks.

Linear inequalities can be represented as boolean expressions. Either the inequality is true, or false. We can use a function in C++ just like a function in mathematics here.
bool equation_one(double x, double z, double A)
{
return ((2 * x) + z <= A);
}
bool equation_two(double y, double z, double A)
{
return ((3 * y) + z <= A);
}
Then, if we wanted to see if any values satisfies these equations, we can just try values.
NOTE: This is horribly inefficient. We are looking at cubic time bounds. But, this is much more straight forward then using a linear algebra technique.
for(double x = 0; x <= A/2; x++)
for(double y = 0; y <= B/3; y++)
for(double z = 0; z <= A && z <= B; z++)
if(equation_one(x, z, A) && equation_two(y, z, B))
//These are the values we want!
EDIT: My bad, you said positive values only. Fixed.
EDIT 2: Thought I'd provide some output. For A = 20 and B = 20, these are all possible positive integer values that satisfy the equations with x, y, and z respectively.
0 0 0
0 0 1
0 0 2
0 0 3
0 0 4
0 0 5
0 0 6
0 0 7
0 0 8
0 0 9
0 0 10
0 0 11
0 0 12
0 0 13
0 0 14
0 0 15
0 0 16
0 0 17
0 0 18
0 0 19
0 0 20
0 1 0
0 1 1
0 1 2
0 1 3
0 1 4
0 1 5
0 1 6
0 1 7
0 1 8
0 1 9
0 1 10
0 1 11
0 1 12
0 1 13
0 1 14
0 1 15
0 1 16
0 1 17
0 2 0
0 2 1
0 2 2
0 2 3
0 2 4
0 2 5
0 2 6
0 2 7
0 2 8
0 2 9
0 2 10
0 2 11
0 2 12
0 2 13
0 2 14
0 3 0
0 3 1
0 3 2
0 3 3
0 3 4
0 3 5
0 3 6
0 3 7
0 3 8
0 3 9
0 3 10
0 3 11
0 4 0
0 4 1
0 4 2
0 4 3
0 4 4
0 4 5
0 4 6
0 4 7
0 4 8
0 5 0
0 5 1
0 5 2
0 5 3
0 5 4
0 5 5
0 6 0
0 6 1
0 6 2
1 0 0
1 0 1
1 0 2
1 0 3
1 0 4
1 0 5
1 0 6
1 0 7
1 0 8
1 0 9
1 0 10
1 0 11
1 0 12
1 0 13
1 0 14
1 0 15
1 0 16
1 0 17
1 0 18
1 1 0
1 1 1
1 1 2
1 1 3
1 1 4
1 1 5
1 1 6
1 1 7
1 1 8
1 1 9
1 1 10
1 1 11
1 1 12
1 1 13
1 1 14
1 1 15
1 1 16
1 1 17
1 2 0
1 2 1
1 2 2
1 2 3
1 2 4
1 2 5
1 2 6
1 2 7
1 2 8
1 2 9
1 2 10
1 2 11
1 2 12
1 2 13
1 2 14
1 3 0
1 3 1
1 3 2
1 3 3
1 3 4
1 3 5
1 3 6
1 3 7
1 3 8
1 3 9
1 3 10
1 3 11
1 4 0
1 4 1
1 4 2
1 4 3
1 4 4
1 4 5
1 4 6
1 4 7
1 4 8
1 5 0
1 5 1
1 5 2
1 5 3
1 5 4
1 5 5
1 6 0
1 6 1
1 6 2
2 0 0
2 0 1
2 0 2
2 0 3
2 0 4
2 0 5
2 0 6
2 0 7
2 0 8
2 0 9
2 0 10
2 0 11
2 0 12
2 0 13
2 0 14
2 0 15
2 0 16
2 1 0
2 1 1
2 1 2
2 1 3
2 1 4
2 1 5
2 1 6
2 1 7
2 1 8
2 1 9
2 1 10
2 1 11
2 1 12
2 1 13
2 1 14
2 1 15
2 1 16
2 2 0
2 2 1
2 2 2
2 2 3
2 2 4
2 2 5
2 2 6
2 2 7
2 2 8
2 2 9
2 2 10
2 2 11
2 2 12
2 2 13
2 2 14
2 3 0
2 3 1
2 3 2
2 3 3
2 3 4
2 3 5
2 3 6
2 3 7
2 3 8
2 3 9
2 3 10
2 3 11
2 4 0
2 4 1
2 4 2
2 4 3
2 4 4
2 4 5
2 4 6
2 4 7
2 4 8
2 5 0
2 5 1
2 5 2
2 5 3
2 5 4
2 5 5
2 6 0
2 6 1
2 6 2
3 0 0
3 0 1
3 0 2
3 0 3
3 0 4
3 0 5
3 0 6
3 0 7
3 0 8
3 0 9
3 0 10
3 0 11
3 0 12
3 0 13
3 0 14
3 1 0
3 1 1
3 1 2
3 1 3
3 1 4
3 1 5
3 1 6
3 1 7
3 1 8
3 1 9
3 1 10
3 1 11
3 1 12
3 1 13
3 1 14
3 2 0
3 2 1
3 2 2
3 2 3
3 2 4
3 2 5
3 2 6
3 2 7
3 2 8
3 2 9
3 2 10
3 2 11
3 2 12
3 2 13
3 2 14
3 3 0
3 3 1
3 3 2
3 3 3
3 3 4
3 3 5
3 3 6
3 3 7
3 3 8
3 3 9
3 3 10
3 3 11
3 4 0
3 4 1
3 4 2
3 4 3
3 4 4
3 4 5
3 4 6
3 4 7
3 4 8
3 5 0
3 5 1
3 5 2
3 5 3
3 5 4
3 5 5
3 6 0
3 6 1
3 6 2
4 0 0
4 0 1
4 0 2
4 0 3
4 0 4
4 0 5
4 0 6
4 0 7
4 0 8
4 0 9
4 0 10
4 0 11
4 0 12
4 1 0
4 1 1
4 1 2
4 1 3
4 1 4
4 1 5
4 1 6
4 1 7
4 1 8
4 1 9
4 1 10
4 1 11
4 1 12
4 2 0
4 2 1
4 2 2
4 2 3
4 2 4
4 2 5
4 2 6
4 2 7
4 2 8
4 2 9
4 2 10
4 2 11
4 2 12
4 3 0
4 3 1
4 3 2
4 3 3
4 3 4
4 3 5
4 3 6
4 3 7
4 3 8
4 3 9
4 3 10
4 3 11
4 4 0
4 4 1
4 4 2
4 4 3
4 4 4
4 4 5
4 4 6
4 4 7
4 4 8
4 5 0
4 5 1
4 5 2
4 5 3
4 5 4
4 5 5
4 6 0
4 6 1
4 6 2
5 0 0
5 0 1
5 0 2
5 0 3
5 0 4
5 0 5
5 0 6
5 0 7
5 0 8
5 0 9
5 0 10
5 1 0
5 1 1
5 1 2
5 1 3
5 1 4
5 1 5
5 1 6
5 1 7
5 1 8
5 1 9
5 1 10
5 2 0
5 2 1
5 2 2
5 2 3
5 2 4
5 2 5
5 2 6
5 2 7
5 2 8
5 2 9
5 2 10
5 3 0
5 3 1
5 3 2
5 3 3
5 3 4
5 3 5
5 3 6
5 3 7
5 3 8
5 3 9
5 3 10
5 4 0
5 4 1
5 4 2
5 4 3
5 4 4
5 4 5
5 4 6
5 4 7
5 4 8
5 5 0
5 5 1
5 5 2
5 5 3
5 5 4
5 5 5
5 6 0
5 6 1
5 6 2
6 0 0
6 0 1
6 0 2
6 0 3
6 0 4
6 0 5
6 0 6
6 0 7
6 0 8
6 1 0
6 1 1
6 1 2
6 1 3
6 1 4
6 1 5
6 1 6
6 1 7
6 1 8
6 2 0
6 2 1
6 2 2
6 2 3
6 2 4
6 2 5
6 2 6
6 2 7
6 2 8
6 3 0
6 3 1
6 3 2
6 3 3
6 3 4
6 3 5
6 3 6
6 3 7
6 3 8
6 4 0
6 4 1
6 4 2
6 4 3
6 4 4
6 4 5
6 4 6
6 4 7
6 4 8
6 5 0
6 5 1
6 5 2
6 5 3
6 5 4
6 5 5
6 6 0
6 6 1
6 6 2
7 0 0
7 0 1
7 0 2
7 0 3
7 0 4
7 0 5
7 0 6
7 1 0
7 1 1
7 1 2
7 1 3
7 1 4
7 1 5
7 1 6
7 2 0
7 2 1
7 2 2
7 2 3
7 2 4
7 2 5
7 2 6
7 3 0
7 3 1
7 3 2
7 3 3
7 3 4
7 3 5
7 3 6
7 4 0
7 4 1
7 4 2
7 4 3
7 4 4
7 4 5
7 4 6
7 5 0
7 5 1
7 5 2
7 5 3
7 5 4
7 5 5
7 6 0
7 6 1
7 6 2
8 0 0
8 0 1
8 0 2
8 0 3
8 0 4
8 1 0
8 1 1
8 1 2
8 1 3
8 1 4
8 2 0
8 2 1
8 2 2
8 2 3
8 2 4
8 3 0
8 3 1
8 3 2
8 3 3
8 3 4
8 4 0
8 4 1
8 4 2
8 4 3
8 4 4
8 5 0
8 5 1
8 5 2
8 5 3
8 5 4
8 6 0
8 6 1
8 6 2
9 0 0
9 0 1
9 0 2
9 1 0
9 1 1
9 1 2
9 2 0
9 2 1
9 2 2
9 3 0
9 3 1
9 3 2
9 4 0
9 4 1
9 4 2
9 5 0
9 5 1
9 5 2
9 6 0
9 6 1
9 6 2
10 0 0
10 1 0
10 2 0
10 3 0
10 4 0
10 5 0
10 6 0

Related

Duplication of data entries by id if they meet a certain condition

In the original choice data set, individuals (id) are captured making purchases (choice) among all the product options possible (assortchoice is a product code). Every individual always faces the same set of products to choose from; as a result the value of choice is always either 0 or 1 ("was the product chosen or not?").
clear
input
id assortchoice choice sumchoice
2 12 1 2
2 13 0 2
2 14 0 2
2 15 0 2
2 16 0 2
2 17 0 2
2 18 0 2
2 19 0 2
2 20 0 2
2 21 0 2
2 22 0 2
2 23 1 2
3 12 1 1
3 13 0 1
3 14 0 1
3 15 0 1
3 16 0 1
3 17 0 1
3 18 0 1
3 19 0 1
3 20 0 1
3 21 0 1
3 22 0 1
3 23 0 1
4 12 1 3
4 13 0 3
4 14 1 3
4 15 1 3
4 16 0 3
4 17 0 3
4 18 0 3
4 19 0 3
4 20 0 3
4 21 0 3
4 22 0 3
4 23 0 3
end
I created the following code to understand how many choices were made by each individual:
egen sumchoice=total(choice), by(id)
In this example, an individual 3 (id=3) only chose one product (since sumchoice=1), but individual 2 made two choices (sumchoice=2). Finally, individual 4 made three choices (sumchoice=3).
Since this is a choice data, I need to transform all the instances of multiple choices into sets of single choices.
What I mean by that: if an individual made two purchases, I need to duplicate the choice set for that individual twice; for an individual who made 3 purchases, I need to replicate the choice set three times, so the final structure looks like the data set below.
clear
input
id transaction assortchoice choice
2 1 12 1
2 1 13 0
2 1 14 0
2 1 15 0
2 1 16 0
2 1 17 0
2 1 18 0
2 1 19 0
2 1 20 0
2 1 21 0
2 1 22 0
2 1 23 0
2 2 12 0
2 2 13 0
2 2 14 0
2 2 15 0
2 2 16 0
2 2 17 0
2 2 18 0
2 2 19 0
2 2 20 0
2 2 21 0
2 2 22 0
2 2 23 1
3 1 12 1
3 1 13 0
3 1 14 0
3 1 15 0
3 1 16 0
3 1 17 0
3 1 18 0
3 1 19 0
3 1 20 0
3 1 21 0
3 1 22 0
3 1 23 0
4 1 12 1
4 1 13 0
4 1 14 0
4 1 15 0
4 1 16 0
4 1 17 0
4 1 18 0
4 1 19 0
4 1 20 0
4 1 21 0
4 1 22 0
4 1 23 0
4 2 12 0
4 2 13 0
4 2 14 1
4 2 15 0
4 2 16 0
4 2 17 0
4 2 18 0
4 2 19 0
4 2 20 0
4 2 21 0
4 2 22 0
4 2 23 0
4 3 12 0
4 3 13 0
4 3 14 0
4 3 15 1
4 3 16 0
4 3 17 0
4 3 18 0
4 3 19 0
4 3 20 0
4 3 21 0
4 3 22 0
4 3 23 0
end
***update:
transaction indicates which transaction order this is:
bysort id assortchoice (choice): gen transaction=_n
Hence, choice=1 should appear only once per each transaction.
The answer isn't quite "use expand" as there is a twist that you don't want exact replicates.
expand sumchoice
bysort id assortchoice (choice) : replace choice = 0 if _n != _N & choice == 1
list if id == 2 , sepby(assortchoice)
+-----------------------------------+
| id assort~e choice sumcho~e |
|-----------------------------------|
1. | 2 12 0 2 |
2. | 2 12 1 2 |
|-----------------------------------|
3. | 2 13 0 2 |
4. | 2 13 0 2 |
|-----------------------------------|
5. | 2 14 0 2 |
6. | 2 14 0 2 |
|-----------------------------------|
7. | 2 15 0 2 |
8. | 2 15 0 2 |
|-----------------------------------|
9. | 2 16 0 2 |
10. | 2 16 0 2 |
|-----------------------------------|
11. | 2 17 0 2 |
12. | 2 17 0 2 |
|-----------------------------------|
13. | 2 18 0 2 |
14. | 2 18 0 2 |
|-----------------------------------|
15. | 2 19 0 2 |
16. | 2 19 0 2 |
|-----------------------------------|
17. | 2 20 0 2 |
18. | 2 20 0 2 |
|-----------------------------------|
19. | 2 21 0 2 |
20. | 2 21 0 2 |
|-----------------------------------|
21. | 2 22 0 2 |
22. | 2 22 0 2 |
|-----------------------------------|
23. | 2 23 0 2 |
24. | 2 23 1 2 |
+-----------------------------------+

How to properly iterate a 3D vector, using only iterators in C++? [closed]

Closed. This question is not reproducible or was caused by typos. It is not currently accepting answers.
This question was caused by a typo or a problem that can no longer be reproduced. While similar questions may be on-topic here, this one was resolved in a way less likely to help future readers.
Closed 3 years ago.
Improve this question
I have the following main() program -
int main()
{
vector<vector<vector<int> > > vec;
vector<vector<int> > vv;
vector<int> ve;
//fill vectors
for (int i = 0; i < 5; i++)
{
//vector<vector<int> > vv;
for (int j = 0; j < 10; j++)
{
//vector<int> ve;
for (int t = 0; t < 3; t++)
{
ve.push_back(t);
}
vv.push_back(ve);
}
vec.push_back(vv);
}
for (vector<vector<vector<int> > >::iterator it = vec.begin(); it != vec.end(); it++)
{
for (vector<vector<int> >::iterator it2 = vv.begin(); it2 != vv.end(); it2++)
{
for (vector<int>::iterator it3 = it2->begin(); it3 != it2->end(); it3++)
{
cout << *it3 << " ";
}
cout << endl;
}
cout << endl;
}
return 0;
}
I want to iterate through the 3D vector using iterators only (not i, j variables etc).
How can I do this correctly?
It looks like the implementation that I have is not correct, namely:
for (vector<vector<vector<int> > >::iterator it = vec.begin(); it != vec.end(); it++)
{
for (vector<vector<int> >::iterator it2 = vv.begin(); it2 != vv.end(); it2++)
{
for (vector<int>::iterator it3 = it2->begin(); it3 != it2->end(); it3++)
{
cout << *it3 << " ";
}
cout << endl;
}
cout << endl;
}
How can I implement it correctly, using iterators in the loops only?
Compiler and OS details: Microsoft Visual Studio Enterprise 2019 (Version 16.2.1). I am building x86 Debug. 64-bit Operating System, x64-based processor. Windows edition = Windows 10 Pro.
Note: I don't think that the implementation is correct, because the program produces a very lengthy output on the console (I could not paste all the characters on the console here because, of Body limit of 3000 characters. And I was at 39634). Following is the output on the console:
0 1 2
0 1 2 0 1 2
0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
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0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2
0 1 2 0 1 2
0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2 0 1 2
Press any key to continue . . .
You're basically there, you just accidentally forgot to iterate over it->begin and instead used vv:
for (auto it = vec.begin(); it != vec.end(); ++it)
{
for (auto it2 = it->begin(); it2 != it->end(); ++it2)
{
for (auto it3 = it2->begin(); it3 != it2->end(); ++it3)
Demo
Note the use of auto greatly simplifies declaring an iterator type (iterators are the primary motivating use case for auto)
As an aside, I can infer from your code snippet that you probably have the following line in your code:
using namespace std;
This is something you should avoid in general because it causes many problems.
You say that you are not sure your output is correct either, because there is so much of it.
This is because during your "Fill" stage, you are not clearing your temporary vectors before each iteration. As a result, e.g., ve grows by 3 elements per iteration over j, per iteration over i. You can reduce the code to remove the temporary vectors altogether like so:
std::vector<std::vector<std::vector<int>>> vec(5,
std::vector<std::vector<int>>(10,
std::vector<int>(3)));
for (int i = 0; i < 5; i++)
for (int j = 0; j < 10; j++)
for (int k = 0; k < 3; k++)
vec[i][j][k] = k;
This results in output of repeating 0 1 2 in groups of 10 lines, five times

fortran read and write from file(reading from .msh and writing to dat)

I am trying to read a .msh file and want to generate .dat file in rearranged manner (node number, x1 ,y1 , z1, x2, y2, z2)
$MeshFormatv
2.2 0 8
$EndMeshFormat
$PhysicalNames
4
1 1 "inlet"
1 2 "top"
1 3 "exit"
1 4 "bottom"
$EndPhysicalNames
$Nodes
45
1 -2 -2 0
2 2 -2 0
3 2 2 0
4 -2 2 0
5 -1.666666666666667 -2 0
6 -1.333333333333333 -2 0
7 -1 -2 0
8 -0.6666666666666665 -2 0
9 -0.3333333333333335 -2 0
10 0 -2 0
11 0.3333333333333335 -2 0
12 0.666666666666667 -2 0
13 1 -2 0
14 1.333333333333333 -2 0
15 1.666666666666667 -2 0
16 2 -1.666666666666667 0
17 2 -1.333333333333333 0
18 2 -1 0
19 2 -0.6666666666666665 0
20 2 -0.3333333333333335 0
21 2 0 0
22 2 0.3333333333333335 0
23 2 0.666666666666667 0
24 2 1 0
25 2 1.333333333333333 0
26 2 1.666666666666667 0
27 1.666666666666667 2 0
28 1.333333333333333 2 0
29 1 2 0
30 0.6666666666666665 2 0
31 0.3333333333333335 2 0
32 0 2 0
33 -0.3333333333333335 2 0
34 -0.666666666666667 2 0
35 -1 2 0
36 -1.333333333333333 2 0
37 -1.666666666666667 2 0
38 -2 1.555555555555556 0
39 -2 1.111111111111111 0
40 -2 0.6666666666666667 0
41 -2 0.2222222222222223 0
42 -2 -0.2222222222222223 0
43 -2 -0.6666666666666665 0
44 -2 -1.111111111111111 0
45 -2 -1.555555555555555 0
$EndNodes
$Elements
45
1 1 2 4 1 1 5
2 1 2 4 1 5 6
3 1 2 4 1 6 7
4 1 2 4 1 7 8
5 1 2 4 1 8 9
6 1 2 4 1 9 10
7 1 2 4 1 10 11
8 1 2 4 1 11 12
9 1 2 4 1 12 13
10 1 2 4 1 13 14
11 1 2 4 1 14 15
12 1 2 4 1 15 2
13 1 2 3 2 2 16
14 1 2 3 2 16 17
15 1 2 3 2 17 18
16 1 2 3 2 18 19
17 1 2 3 2 19 20
18 1 2 3 2 20 21
19 1 2 3 2 21 22
20 1 2 3 2 22 23
21 1 2 3 2 23 24
22 1 2 3 2 24 25
23 1 2 3 2 25 26
24 1 2 3 2 26 3
25 1 2 2 3 3 27
26 1 2 2 3 27 28
27 1 2 2 3 28 29
28 1 2 2 3 29 30
29 1 2 2 3 30 31
30 1 2 2 3 31 32
31 1 2 2 3 32 33
32 1 2 2 3 33 34
33 1 2 2 3 34 35
34 1 2 2 3 35 36
35 1 2 2 3 36 37
36 1 2 2 3 37 4
37 1 2 1 4 4 38
38 1 2 1 4 38 39
39 1 2 1 4 39 40
40 1 2 1 4 40 41
41 1 2 1 4 41 42
42 1 2 1 4 42 43
43 1 2 1 4 43 44
44 1 2 1 4 44 45
45 1 2 1 4 45 1
$EndElements
I have tried with allocatable, I want to skip the lines till character '$Nodes' appear and and one more line then read it in a array and then skip the three lines of character. Read the next in another array and then rearrange the no as mentioned above.
program coordinates
implicit none
INTEGER:: ierror, nodeno, elementno, i, j, k , t, p, l=0, n
CHARACTER:: command
real::data(2,100)
!CHARACTER (len=5)::N!odes
!CHARACTER (len=8)::EndN!odes
!CHARACTER (len=8)::E!lements
!CHARACTER (len=11)::EndE!lements
!CHARACTER :: No*5, EndN*8, E*8, EndE*11
! CHARACTER*5 :: Nod
! CHARACTER*8 :: Ele
! real, allocatable, dimension(:,4)::node
! real, allocatable, dimension(:,7)::element
! real, allocatable, dimension(:)::n,x,y,z,a,b,c,d,g,h
!call system(l='grep -n '$Nodes' /home/user/Nitesh/Fortran/rect.msh|tail -LineNumberToStartWith|grep regEX')
! 'l = 'grep -n '$Nodes' /home/user/Nitesh/Fortran/rect.msh
command = 'grep -n $Nodes /home/user/Nitesh/Fortran/rect.msh|cut -f1 -d:'
! call system('command')
call system('grep -n '$Nodes' /home/user/Nitesh/Fortran/rect.msh|cut -f1 -d:')
! call system('l')
! print*, "enter the no. of nodes"
! read*,t
! print*, "enter the no. of elements"
! read*,p
! print*, "enter the line no. nodes data(array) starting from"
! read*,l
!allocate(node(t),element(j))
print*, "opening file"
! allocate(n(t),x(t),y(t),z(t),a(t),b(t),c(t),d(t),g(t),h(t))
OPEN (FILE='/home/user/Nitesh/Fortran/my.dat',UNIT=8, STATUS='OLD', ACTION='READ', &
IOSTAT=ierror)
if(ierror/=0)then
print*,"File rect.msh cannot be open"
stop
end if
do i=1,n
read(8,'(/)')
end do
do i=1,t+l
read(8,*) data(:,i)
!read(8,*) j,k
end do
! 8 format('',F10.6,F10.6,F10.6,F10.6)
! if(Nod == 'Nodes') then
! read*,(n(i),x(i),y(i),z(i),i=1,t)
! end if
! if(Ele == 'Elements') then
! read*,(n(j),a(j),b(j),c(j),d(j),g(j),h(j),k=1,p)
! end if
! OPEN (UNIT=10, FILE='/home/Nitesh/rect_new.msh', STATUS='NEW', ACTION='WRITE', &
! IOSTAT=ierror)
! write(*,10)
! 10 format (' ',n())
! CLOSE (UNIT=10)
CLOSE (UNIT=8)
print*, "file read"
! do i=1,n
! n(t)=g(j)
! x(t),y(t),z(t)
open(file='/home/user/Nitesh/Fortran/rect.dat', unit=24, status='replace', action='write', &
IOSTAT=ierror)
if(ierror/=0)then
print*,"File rect.msh cannot be open"
stop
end if
print*,"writing data"
do i=1,l+t
write(24,*) data(:,i)
end do
print*,"data written"
! OPEN (UNIT=10, FILE='rect_new.msh', STATUS='NEW', ACTION='WRITE', &
! IOSTAT=ierror)
! write(*,10)
! 10 format (' ','The coordinates of elements')
! CLOSE (UNIT=10)
end program coordinates

awk if-greater-than and replacement under condition

I have following data
......
6 4 4 17 154 93 309 0 11930
7 3 2 233 311 0 11936 11932 111874
8 3 1 15 0 11938 11943 211004 11449
9 3 2 55 102 0 11932 11941 111883
10 3 2 197 231 0 11925 11921 111849
11 3 2 160 777 0 11934 11928 111875
......
I hope to replace any values greater than 5000 to 0, from column 4 to column 9. How can I do this work with awk?
To print with lots of spaces like the input, something like this:
awk '{for(i=4;i<=NF;i++)if($i>5000)$i=0; for(i=1;i<=NF;i++)printf "%7d",$i;printf"\n"}' file
Output
6 4 4 17 154 93 309 0 0
7 3 2 233 311 0 0 0 0
8 3 1 15 0 0 0 0 0
9 3 2 55 102 0 0 0 0
10 3 2 197 231 0 0 0 0
11 3 2 160 777 0 0 0 0
For scrunched up together (TM) output, you can use this:
awk '{for(i=4;i<=NF;i++)if($i>5000)$i=0}1' file
6 4 4 17 154 93 309 0 0
7 3 2 233 311 0 0 0 0
8 3 1 15 0 0 0 0 0
9 3 2 55 102 0 0 0 0
10 3 2 197 231 0 0 0 0
11 3 2 160 777 0 0 0 0
An alternative approach (requires gawk4+):
{
patsplit($0, a, "[0-9]+", s)
printf s[0]
for (i=1; i<=length(a); i++){
if(i>4 && a[i]>5000) {
l=length(a[i])
a[i]=0
}
else l=0
printf "%"l"s%s", a[i], s[i]
}
printf "\n"
}
It is more flexible when the spacing would vary, as opposed to the example data. It might also be faster than the accepted answer, in case the number of fields is way bigger than 9.

Convert a string into an array of integers

I ve got a string which is white space seperated integer numbers and I want to convert it in array of vector of intergers. My string is like the:
6 9 17 5 3 4 10 12 7 3 5 10 6 5 0 10 10 10 13 3 6 10 2 11 33 9 14 7 0 8 7 6 38 2 23 8 4 52 7 3 19 12 2 22 3 6 3 1 2 1 5 17 13 5 1 6 0 12 6 9 15 2 22 0 27 2 3 4 7 2 8 2 8 6 11 22 4 9 4 1 1 2 2 16 8 3 1 8 0 4 4 2 1 10 24 15 8 2 6 9
How is it possible to convert it to array/vector??
Use std::istream_iterator. Example:
std::vector<int> vector(std::istream_iterator<int>(std::cin), std::istream_iterator<int>());
Or, with std::string:
std::string s = "6 9 17 5 3 4 10 12 7 3 5 10 6 5 0 10 10 10 13 3 6 10 2 11 33 9 14 7 0 8 7 6 38 2 23 8 4 52 7 3 19 12 2 22 3 6 3 1 2 1 5 17 13 5 1 6 0 12 6 9 15 2 22 0 27 2 3 4 7 2 8 2 8 6 11 22 4 9 4 1 1 2 2 16 8 3 1 8 0 4 4 2 1 10 24 15 8 2 6 9";
std::stringstream ss(s);
std::vector<int> vec((std::istream_iterator<int>(ss)), (std::istream_iterator<int>()));
This following code does what you need:
std::istringstream iss(my_string);
std::vector<int> v((std::istream_iterator<int>(iss)),
(std::istream_iterator<int>()));
Here is a ready to use example with all required headers
#include <iostream>
#include <sstream>
#include <vector>
#include <algorithm>
#include <iterator>
int main()
{
std::string s = "6 9 17 5 3 4 10 12 7 3 5 10 6 5 0 10 10 10 13 3 6 10 2 11 33 9 14 7 0 8 7 6 38 2 23 8 4 52 ";
std::istringstream is( s );
std::vector<int> v;
std::transform( std::istream_iterator<std::string>( is ),
std::istream_iterator<std::string>(),
std::back_inserter( v ),
[]( const std::string &s ) { return ( std::stoi( s ) ); } );
for ( int x : v ) std::cout << x << ' ';
std::cout << std::endl;
return 0;
}
Or indeed instead of algorithm std::transform you can use simply the constructor of class std::vector that accepts two iterators as for example
std::vector<int> v( ( std::istream_iterator<int>( is ) ),
std::istream_iterator<int>() );
Or
std::vector<int> v( { std::istream_iterator<int>( is ),
std::istream_iterator<int>() } );
I see some older and smarter way of doing that:
#include <stdlib.h> /* strtol */
char *numbers = "6 9 17 5 3 4 10 12 7 3 5 10 6 5 0 10 10 10 13 3 6 10 2 11 33 9 14 7 0 8 7 6 38 2 23 8 4 52 7 3 19 12 2 22 3 6 3 1 2 1 5 17 13 5 1 6 0 12 6 9 15 2 22 0 27 2 3 4 7 2 8 2 8 6 11 22 4 9 4 1 1 2 2 16 8 3 1 8 0 4 4 2 1 10 24 15 8 2 6 9"
long table[512];
char *pt;
int i=0;
pt = numbers;
while(pt != NULL)
table[i++] = strtol (pt,&pt,10);