c++ generic singly linked list string print fails - c++

Question

I am implementing a generic singly linked list. It works with char and int, but not for string. What mistake have I made? I get an error:
C2679 binary '<<': no operator found which takes a right-hand operand of type 'T' (or there is no acceptable conversion)
#include <iostream>
#include <vector>
#include <cstdlib>
#include <ctime>
using namespace std;
template <typename T>
struct Node
{
T data;
Node*next;
//friend class List<T>;
};
template<typename T>
class List
{
public:
List() :headNode{ nullptr } {} // empty list constructor
~List() // destructor
{
Node<T>*current = headNode;
while (current)
{
Node<T>*temp = current;
current = current->next;
delete temp; cout << "\nDeleting Nodes!!!";
}
}
bool empty() const // is list empty?
{
return headNode == nullptr;
}
const T& front() const // get front element
{
return headNode->data;
}
void addFront(const T& e) // add to front of list
{
Node<T>* tempNode= new Node<T>;
tempNode->data = e;
tempNode->next = headNode;
headNode = tempNode;
}
void removeFront()
{
if (empty()) cout << "List is empty" << endl;
else
{
Node<T> *tempNode = headNode;
headNode = tempNode->next;
delete tempNode; cout << "\nDeleting Node!!!";
}
}
void printList()const
{
Node<T>*current = headNode;
while (current)
{
cout << current->data<<" |-> ";
current = current->next;
}
}
private:
Node<T> *headNode;
};
int main()
{
srand(time(NULL));
List<int> mylist;
for (int i = 0; i < 15; ++i)
{
mylist.addFront(rand()%200 + 20);
}
mylist.printList();
mylist.removeFront(); cout << endl;
mylist.printList();
List<string>family;
family.addFront("aaa");
family.addFront("bbb");
family.addFront("ccc");
family.addFront("ddd");
family.printList();
List<char> charlist;
charlist.addFront('a');
charlist.addFront('b');
charlist.addFront('c');
charlist.addFront('d');
charlist.printList();
return 0;
}

Answer 1

You need to include the header <string>.
#include <string>
where the operator << for streams and the class std::string is declared.