catch queues overflow exceptions when they occur - c++

Question

void IntQueue::enqueue(int num)
{
if (isFull())
throw std::runtime_error("The queue is full");
else
{
// Calculate the new rear position
rear = (rear + 1) % queueSize;
// Insert new item
queueArray[rear] = num;
// Update item count
numItems++;
}
}
after I throw this exception how can I rewrite the main program so that it catches overflow exceptions when they occur. The exception handler for queue overflow should print an appropriate error message and then terminate the program. here is the main program
int main()
{
IntQueue iQueue(5);
cout << "Enqueuing 5 items...\n";
// Enqueue 5 items.
for (int x = 0; x < 5; x++)
iQueue.enqueue(x);
// Attempt to enqueue a 6th item.
cout << "Now attempting to enqueue again...\n";
iQueue.enqueue(5);
// Deqeue and retrieve all items in the queue
cout << "The values in the queue were:\n";
while (!iQueue.isEmpty())
{
int value;
iQueue.dequeue(value);
cout << value << endl;
}
}

Answer 1

Wrap the part that can throw with try-block.
For example,
try
{
for (int x = 0; x < 5; x++)
iQueue.enqueue(x);
// Attempt to enqueue a 6th item.
cout << "Now attempting to enqueue again...\n";
iQueue.enqueue(5);
}
catch (const std::runtime_error& e)
{
cout << "Error: " << e.what() << endl; // Print error message
exit(1); // Terminate with non-zero exit code
}