It's possible suppress output about of one function? - c++

Question

In my program I use an external function which generates output to me and I don't want it not to be generated by that function alone,
it's possible?
int main()
{
int a;
//I don't want the output of this function
a = function();
//now i want output
cout << "the result is : " << a;
}
Is it possible?
EDIT:
The function is in an external library.

Answer 1

Using only standard C++ where no dup-like functions exist, you could open a temporary std::FILE and std::swap with stdout.
#include <cerrno>
#include <cstring>
#include <cstdio>
#include <fstream>
#include <iostream>
#include <iterator>
#include <string>
#include <sstream>
// extern "C" int function(); // an assumption
// A helper class to temporarilly redirect the output to stdout to a file and to read
// the content of the file afterwards.
class BufferStdout {
public:
// the collector string is used for collecting the output to stdout
BufferStdout (std::string& collector) :
m_collector(collector),
fp(std::fopen("output.txt", "w"))
{
if(fp == nullptr) throw std::runtime_error(std::strerror(errno));
std::swap(stdout, fp); // swap stdout and the temp file
}
~BufferStdout () {
std::swap(stdout, fp); // swap back
std::fclose(fp);
// read the content of the temp file into m_collector
if(std::ifstream is("output.txt"); is) {
m_collector.append(std::istreambuf_iterator<char>(is),
std::istreambuf_iterator<char>{});
}
std::remove("output.txt"); // cleanup
}
private:
std::string& m_collector;
std::FILE* fp;
};
int main() {
std::string collector; // the string that will contain the output from function()
int a;
{
BufferStdout foo(collector);
a = function();
}
std::cout << "the result is : " << a << '\n';
std::cout << "Collected from function():\n";
std::cout << collector << '\n';
}

Answer 2

Yes it is generally possible but a bit complicated, a similar question is in Suppress output to cout from linked library
In addition to you can redirect stdout before invoking the shared library function and then redirect it again after the use of the shared library function in the however this is also a suboptimal solution. Best solution would be to adapt the shared library
// Cpp program to redirect cout to a file
#include <fstream>
#include <iostream>
#include <string>
using namespace std;
int main()
{
fstream file;
file.open("cout.txt", ios::out);
string line;
// Backup streambuffers of cout
streambuf* stream_buffer_cout = cout.rdbuf();
streambuf* stream_buffer_cin = cin.rdbuf();
// Get the streambuffer of the file
streambuf* stream_buffer_file = file.rdbuf();
// Redirect cout to file
cout.rdbuf(stream_buffer_file);
cout << "This line written to file" << endl;
// Redirect cout back to screen
cout.rdbuf(stream_buffer_cout);
cout << "This line is written to screen" << endl;
file.close();
return 0;
}
Note: The above steps can be condensed into a single step
auto cout_buf = cout.rdbuf(file.rdbuf())
// sets couts streambuffer and returns the old
streambuffer back to cout_buf
source : https://www.geeksforgeeks.org/io-redirection-c/

Answer 3

use
fclose(stdout);
with this function you will suppress any printf inside your libraries.
Of course you can not print other stuff inside your software.