Restructure Data from Long to Wide Format - sas

Hi I am trying to use a data step and an array to convert from a long format to a wide format. Originally my table was in the wide format and I figured out how to make it in the long format but now I need to use an array to make it wide again. When I run my code of the last data step I get a table with empty Expense1, Expense2, Expense 3 etc. columns. My table needs to look like this but with nine Hotels and six Expense columns.
Resort
Expense1
Expense2
Expense3
Expense 4
HOTEL1
$165.89
$45.50
$78.00
$56.25
HOTEL2
$215.32
$64.00
$54.00
$62.50
The long table looks like this but there are nine hotels.
Resort
Expense ID
Expense
HOTEL1
1
$165.89
HOTEL1
2
$45.50
HOTEL1
3
$78.00
Here is my code but the last datastep is me attempting to convert it from long to wide.
proc import datafile="/home/u54324957/The
Files/Hotels.xlsx" out=Sheet1
dbms=xlsx replace;
data Hotels;
set Sheet1;
array TheExpense(*) Expense1-Expense6;
array Peak(6) PeakExpense1-PeakExpense6;
do i=1 to 6;
Peak(i)=TheExpense(i) * 1.25;
drop i;
drop Expense1-Expense6;
format PeakExpense1-PeakExpense6
dollar7.2;
end;
run;
title "Peak Season Resort Pricing";
proc print data=Hotels noobs;
run;
data Hotels1;
set Sheet1;
array Hotels(*) Expense1-Expense6;
do ExpenseID=1 to 6;
Expense = Hotels(ExpenseID);
drop Expense1-Expense6;
output;
end;
run;
title "Restructure Data from Wide to Long
Format";
proc print data=Hotels1 noobs;
format Expense dollar7.2;
run;
proc sort data=Hotels1;
by ExpenseID;
run;
data Hotels2;
set Hotels1;
array Hotels(*) Expense1-Expense6;
retain Expense1-Expense3;
by ExpenseID;
if first.ExpenseID then i=0;
i+1;
if last.ExpenseID then output;
run;
proc print data=Hotels2;
run;
Any ideas for how I can fill in these empty columns with values?

Array based transposition by group can be accomplished as follows:
data wide(keep=resort expense1-expense6);
if 0 then set tall (keep=resort); * prep PDV with resort variable;
array expenses expenses1-expenses6; * prep PDV with wide variables;
* reset array to zeroes, resorts without a specific expenseID will have a 0;
do index = 1 to dim(expenses);
expenses[index] = 0;
end;
* if you want missing values instead of zeroes;
* call missing (of expenses(*));
* dow loop, iterate down the by group;
do until (last.resort);
set tall;
by resort;
expenses[expenseID] = expense;
end;
*implicit output, one row per resort;
run;

Related

SaS 9.4: How to use different weights on the same variable without datastep or proc sql

I can't find a way to summarize the same variable using different weights.
I try to explain it with an example (of 3 records):
data pippo;
a=10;
wgt1=0.5;
wgt2=1;
wgt3=0;
output;
a=3;
wgt1=0;
wgt2=0;
wgt3=1;
output;
a=8.9;
wgt1=1.2;
wgt2=0.3;
wgt3=0.1;
output;
run;
I tried the following:
proc summary data=pippo missing nway;
var a /weight=wgt1;
var a /weight=wgt2;
var a /weight=wgt3;
output out=pluto (drop=_freq_ _type_) sum()=;
run;
Obviously it gives me a warning because I used the same variable "a" (I can't rename it!).
I've to save a huge amount of data and not so much physical space and I should construct like 120 field (a0-a6,b0-b6 etc) that are the same variables just with fixed weight (wgt0-wgt5).
I want to store a dataset with 20 columns (a,b,c..) and 6 weight (wgt0-wgt5) and, on demand, processing a "summary" without an intermediate datastep that oblige me to create 120 fields.
Due to the huge amount of data (more or less 55Gb every month) I'd like also not to use proc sql statement:
proc sql;
create table pluto
as select sum(db.a * wgt1) as a0, sum(db.a * wgt1) as a1 , etc.
quit;
There is a "Super proc summary" that can summarize the same field with different weights?
Thanks in advance,
Paolo
I think there are a few options. One is the data step view that data_null_ mentions. Another is just running the proc summary however many times you have weights, and either using ods output with the persist=proc or 20 output datasets and then setting them together.
A third option, though, is to roll your own summarization. This is advantageous in that it only sees the data once - so it's faster. It's disadvantageous in that there's a bit of work involved and it's more complicated.
Here's an example of doing this with sashelp.baseball. In your actual case you'll want to use code to generate the array reference for the variables, and possibly for the weights, if they're not easily creatable using a variable list or similar. This assumes you have no CLASS variable, but it's easy to add that into the key if you do have a single (set of) class variable(s) that you want NWAY combinations of only.
data test;
set sashelp.baseball;
array w[5];
do _i = 1 to dim(w);
w[_i] = rand('Uniform')*100+50;
end;
output;
run;
data want;
set test end=eof;
i = .;
length varname $32;
sumval = 0 ;
sum=0;
if _n_ eq 1 then do;
declare hash h_summary(suminc:'sumval',keysum:'sum',ordered:'a');;
h_summary.defineKey('i','varname'); *also would use any CLASS variable in the key;
h_summary.defineData('i','varname'); *also would include any CLASS variable in the key;
h_summary.defineDone();
end;
array w[5]; *if weights are not named in easy fashion like this generate this with code;
array vars[*] nHits nHome nRuns; *generate this with code for the real dataset;
do i = 1 to dim(w);
do j = 1 to dim(vars);
varname = vname(vars[j]);
sumval = vars[j]*w[i];
rc = h_summary.ref();
if i=1 then put varname= sumval= vars[j]= w[i]=;
end;
end;
if eof then do;
rc = h_summary.output(dataset:'summary_output');
end;
run;
One other thing to mention though... if you're doing this because you're doing something like jackknife variance estimation or that sort of thing, or anything that uses replicate weights, consider using PROC SURVEYMEANS which can handle replicate weights for you.
You can SCORE your data set using a customized SCORE data set that you can generate
with a data step.
options center=0;
data pippo;
retain a 10 b 1.75 c 5 d 3 e 32;
run;
data score;
if 0 then set pippo;
array v[*] _numeric_;
retain _TYPE_ 'SCORE';
length _name_ $32;
array wt[3] _temporary_ (.5 1 .333);
do i = 1 to dim(v);
call missing(of v[*]);
do j = 1 to dim(wt);
_name_ = catx('_',vname(v[i]),'WGT',j);
v[i] = wt[j];
output;
end;
end;
drop i j;
run;
proc print;[enter image description here][1]
run;
proc score data=pippo score=score;
id a--e;
var a--e;
run;
proc print;
run;
proc means stackods sum;
ods exclude summary;
ods output summary=summary;
run;
proc print;
run;
enter image description here

Combing/Collapsing binary variables into a single row by patient ID in SAS

I am trying to collapse my multiple rows of binary variables into a single row per patient id as depicted in my illustration. Could someone please help me with the SAS code to do this? Thanks
If the rule is that to set it to 1 if it is ever 1 then take the MAX. If the rule is to set it to one only if all of them are one then take the MIN.
proc summary data=have nway ;
by id;
output out=want max= ;
run;
Update trick
data want;
update have(obs=0) have;
by id;
run;
Or
proc sql;
create table want as
select ID, max('2018'n) as Y2018, max('2019'n) as Y2019, max('2020'n) as Y2020
from have
group by ID
order by ID;
quit;
Untested because you provided data as images, please post as text, preferably as a data step.
Here is a data step-based solution. Certainly more complex than the above answers, but it does show ways you can use arrays, first. and last. processing, and the retain statement.
Use a retained temporary array to hold the values of 2018-2020 until the last observation of each id group. On the last value of each id, check if each held value is 1 and set each value of the year to a 1 or 0.
data want;
set have;
by id;
array year[3] '2018'n--'2020'n;
array hold[3] _TEMPORARY_;
retain hold;
if(first.id) then call missing(of hold[*]);
do i = 1 to dim(year);
if(year[i] = 1) then hold[i] = 1;
end;
if(last.id) then do;
do i = 1 to dim(year);
year[i] = (hold[i] = 1);
end;
output;
end;
drop i;
run;

How do I create a SAS data view from an 'Out=' option?

I have a process flow in SAS Enterprise Guide which is comprised mainly of Data views rather than tables, for the sake of storage in the work library.
The problem is that I need to calculate percentiles (using proc univariate) from one of the data views and left join this to the final table (shown in the screenshot of my process flow).
Is there any way that I can specify the outfile in the univariate procedure as being a data view, so that the procedure doesn't calculate everything prior to it in the flow? When the percentiles are left joined to the final table, the flow is calculated again so I'm effectively doubling my processing time.
Please find the code for the univariate procedure below
proc univariate data=WORK.QUERY_FOR_SGFIX noprint;
var CSA_Price;
by product_id;
output out= work.CSA_Percentiles_Prod
pctlpre= P
pctlpts= 40 to 60 by 10;
run;
In SAS, my understanding is that procs such as proc univariate cannot generally produce views as output. The only workaround I can think of would be for you to replicate the proc logic within a data step and produce a view from the data step. You could do this e.g. by transposing your variables into temporary arrays and using the pctl function.
Here's a simple example:
data example /view = example;
array _height[19]; /*Number of rows in sashelp.class dataset*/
/*Populate array*/
do _n_ = 1 by 1 until(eof);
set sashelp.class end = eof;
_height[_n_] = height;
end;
/*Calculate quantiles*/
array quantiles[3] q40 q50 q60;
array points[3] (40 50 60);
do i = 1 to 3;
quantiles[i] = pctl(points[i], of _height{*});
end;
/*Keep only the quantiles we calculated*/
keep q40--q60;
run;
With a bit more work, you could also make this approach return percentiles for individual by groups rather than for the whole dataset at once. You would need to write a double-DOW loop to do this, e.g.:
data example;
array _height[19];
array quantiles[3] q40 q50 q60;
array points[3] _temporary_ (40 50 60);
/*Clear heights array between by groups*/
call missing(of _height[*]);
/*Populate heights array*/
do _n_ = 1 by 1 until(last.sex);
set class end = eof;
by sex;
_height[_n_] = height;
end;
/*Calculate quantiles*/
do i = 1 to 3;
quantiles[i] = pctl(points[i], of _height{*});
end;
/* Output all rows from input dataset, with by-group quantiles attached*/
do _n_ = 1 to _n_;
set class;
output;
end;
keep name sex q40--q60;
run;

SAS: Creating dummy variables from categorical variable

I would like to turn the following long dataset:
data test;
input Id Injury $;
datalines;
1 Ankle
1 Shoulder
2 Ankle
2 Head
3 Head
3 Shoulder
;
run;
Into a wide dataset that looks like this:
ID Ankle Shoulder Head
1 1 1 0
2 1 0 1
3 0 1 1'
This answer seemed the most relevant but was falling over at the proc freq stage (my real dataset is around 1 million records, and has around 30 injury types):
Creating dummy variables from multiple strings in the same row
Additional help: https://communities.sas.com/t5/SAS-Statistical-Procedures/Possible-to-create-dummy-variables-with-proc-transpose/td-p/235140
Thanks for the help!
Here's a basic method that should work easily, even with several million records.
First you sort the data, then add in a count to create the 1 variable. Next you use PROC TRANSPOSE to flip the data from long to wide. Then fill in the missing values with a 0. This is a fully dynamic method, it doesn't matter how many different Injury types you have or how many records per person. There are other methods that are probably shorter code, but I think this is simple and easy to understand and modify if required.
data test;
input Id Injury $;
datalines;
1 Ankle
1 Shoulder
2 Ankle
2 Head
3 Head
3 Shoulder
;
run;
proc sort data=test;
by id injury;
run;
data test2;
set test;
count=1;
run;
proc transpose data=test2 out=want prefix=Injury_;
by id;
var count;
id injury;
idlabel injury;
run;
data want;
set want;
array inj(*) injury_:;
do i=1 to dim(inj);
if inj(i)=. then inj(i) = 0;
end;
drop _name_ i;
run;
Here's a solution involving only two steps... Just make sure your data is sorted by id first (the injury column doesn't need to be sorted).
First, create a macro variable containing the list of injuries
proc sql noprint;
select distinct injury
into :injuries separated by " "
from have
order by injury;
quit;
Then, let RETAIN do the magic -- no transposition needed!
data want(drop=i injury);
set have;
by id;
format &injuries 1.;
retain &injuries;
array injuries(*) &injuries;
if first.id then do i = 1 to dim(injuries);
injuries(i) = 0;
end;
do i = 1 to dim(injuries);
if injury = scan("&injuries",i) then injuries(i) = 1;
end;
if last.id then output;
run;
EDIT
Following OP's question in the comments, here's how we could use codes and labels for injuries. It could be done directly in the last data step with a label statement, but to minimize hard-coding, I'll assume the labels are entered into a sas dataset.
1 - Define Labels:
data myLabels;
infile datalines dlm="|" truncover;
informat injury $12. labl $24.;
input injury labl;
datalines;
S460|Acute meniscal tear, medial
S520|Head trauma
;
2 - Add a new query to the existing proc sql step to prepare the label assignment.
proc sql noprint;
/* Existing query */
select distinct injury
into :injuries separated by " "
from have
order by injury;
/* New query */
select catx("=",injury,quote(trim(labl)))
into :labls separated by " "
from myLabels;
quit;
3 - Then, at the end of the data want step, just add a label statement.
data want(drop=i injury);
set have;
by id;
/* ...same as before... */
* Add labels;
label &labls;
run;
And that should do it!

SAS: Using Do/Loop in a Proc Transpose

I'm not very familiar with Do Loops in SAS and was hoping to get some help. I have data that looks like this:
Product A: 1
Product A: 2
Product A: 4
I'd like to transpose (easy) and flag that Product A: 3 is missing, but I need to do this iteratively to the i-th degree since the number of products is large.
If I run the transpose part in SAS, my first column will be 1, second column will be 2, and third column will be 4 - but I'd really like the third column to be missing and the fourth column to be 4.
Any thoughts? Thanks.
Get some sample data:
proc sort data=sashelp.iris out=sorted;
by species;
run;
Determine the largest column we will need to transpose to. Depending on your situation you may just want to hardcode this value using a %let max=somevalue; statement:
proc sql noprint;
select cats(max(sepallength)) into :max from sorted;
quit;
%put &=max;
Transpose the data using a data step:
data want;
set sorted;
by species;
retain _1-_&max;
array a[1:&max] _1-_&max;
if first.species then do;
do cnt = lbound(a) to hbound(a);
a[cnt] = .;
end;
end;
a[sepallength] = sepallength;
if last.species then do;
output;
end;
keep species _1-_&max;
run;
Notice we are defining an array of columns: _1,_2,_3,..._max. This happens in our array statement.
We then use by-group processing to populate these newly created columns for a single species at a time. For each species, on the first record, we clear the array. For each record of the species, we populate the appropriate element of the array. On the final record for the species output the array contents.
You need a way to tell SAS that you have 4 products and the values are 1-4. In this example I create dummy ID with the needed information then transpose using ID statement to name new variables using the value of product.
data product;
input id product ##;
cards;
1 1 1 2 1 4
2 2 2 3
;;;;
run;
proc print;
run;
data productspace;
if 0 then set product;
do product = 1 to 4;
output;
end;
stop;
run;
data productV / view=productV;
set productspace product;
run;
proc transpose data=productV out=wide(where=(not missing(id))) prefix=P;
by id;
var product;
id product;
run;
proc print;
run;