can anyone explain the working of the following code? [closed] - c++

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more specifically can you please explain the working of following lines:
clock_t delay = secs * CLOCKS_PER_SEC;
clock_t start = clock() ;
while ( clock() - start < delay )
and the significance of semicolon in the next line.
#include<iostream>
#include<ctime>
int main () {
using namespace std;
cout << "Enter the delay time in sec: ";
float secs;
cin >> secs;
clock_t delay = secs * CLOCKS_PER_SEC;
cout << "starting \a\n" ;
clock_t start = clock() ;
while (clock() - start < delay )
;
cout << "dont \a\n" ;
return 0;
}

Answer 1

Overall, this program takes your delay in seconds, and prints output after waiting for the specified time.
Now lets break each statement:
clock_t delay = secs * CLOCKS_PER_SEC;
you can think this line as converting your input delay (which is in seconds), to the unit that c++ clock library uses (clock_t). Generally CLOCKS_PER_SEC is equal to 1,000,000.
clock_t start = clock() ;
This line returns the current processor time, in clock_t units.
while (clock() - start < delay ) ;
represent an empty while loop, to wait until the current time - start time (The time difference) becomes greater than delay.
An empty while loop can also be written as
while(condition) {}