Regex.IsMatch for only letters and numbers [duplicate] - regex

Question

How can I validate a string using Regular Expressions to only allow alphanumeric characters in it?
(I don't want to allow for any spaces either).

Answer 1

In .NET 4.0 you can use LINQ:
if (yourText.All(char.IsLetterOrDigit))
{
//just letters and digits.
}
yourText.All will stop execute and return false the first time char.IsLetterOrDigit reports false since the contract of All cannot be fulfilled then.
Note! this answer do not strictly check alphanumerics (which typically is A-Z, a-z and 0-9). This answer allows local characters like åäö.
Update 2018-01-29
The syntax above only works when you use a single method that has a single argument of the correct type (in this case char).
To use multiple conditions, you need to write like this:
if (yourText.All(x => char.IsLetterOrDigit(x) || char.IsWhiteSpace(x)))
{
}

Answer 2

Use the following expression:
^[a-zA-Z0-9]*$
ie:
using System.Text.RegularExpressions;
Regex r = new Regex("^[a-zA-Z0-9]*$");
if (r.IsMatch(SomeString)) {
...
}

Answer 3

You could do it easily with an extension function rather than a regex ...
public static bool IsAlphaNum(this string str)
{
if (string.IsNullOrEmpty(str))
return false;
for (int i = 0; i < str.Length; i++)
{
if (!(char.IsLetter(str[i])) && (!(char.IsNumber(str[i]))))
return false;
}
return true;
}
Per comment :) ...
public static bool IsAlphaNum(this string str)
{
if (string.IsNullOrEmpty(str))
return false;
return (str.ToCharArray().All(c => Char.IsLetter(c) || Char.IsNumber(c)));
}

Answer 4

While I think the regex-based solution is probably the way I'd go, I'd be tempted to encapsulate this in a type.
public class AlphaNumericString
{
public AlphaNumericString(string s)
{
Regex r = new Regex("^[a-zA-Z0-9]*$");
if (r.IsMatch(s))
{
value = s;
}
else
{
throw new ArgumentException("Only alphanumeric characters may be used");
}
}
private string value;
static public implicit operator string(AlphaNumericString s)
{
return s.value;
}
}
Now, when you need a validated string, you can have the method signature require an AlphaNumericString, and know that if you get one, it is valid (apart from nulls). If someone attempts to pass in a non-validated string, it will generate a compiler error.
You can get fancier and implement all of the equality operators, or an explicit cast to AlphaNumericString from plain ol' string, if you care.

Answer 5

I needed to check for A-Z, a-z, 0-9; without a regex (even though the OP asks for regex).
Blending various answers and comments here, and discussion from https://stackoverflow.com/a/9975693/292060, this tests for letter or digit, avoiding other language letters, and avoiding other numbers such as fraction characters.
if (!String.IsNullOrEmpty(testString)
&& testString.All(c => Char.IsLetterOrDigit(c) && (c < 128)))
{
// Alphanumeric.
}

Answer 6

^\w+$ will allow a-zA-Z0-9_
Use ^[a-zA-Z0-9]+$ to disallow underscore.
Note that both of these require the string not to be empty. Using * instead of + allows empty strings.

Answer 7

Same answer as here.
If you want a non-regex ASCII A-z 0-9 check, you cannot use char.IsLetterOrDigit() as that includes other Unicode characters.
What you can do is check the character code ranges.
48 -> 57 are numerics
65 -> 90 are capital letters
97 -> 122 are lower case letters
The following is a bit more verbose, but it's for ease of understanding rather than for code golf.
public static bool IsAsciiAlphaNumeric(this string str)
{
if (string.IsNullOrEmpty(str))
{
return false;
}
for (int i = 0; i < str.Length; i++)
{
if (str[i] < 48) // Numeric are 48 -> 57
{
return false;
}
if (str[i] > 57 && str[i] < 65) // Capitals are 65 -> 90
{
return false;
}
if (str[i] > 90 && str[i] < 97) // Lowers are 97 -> 122
{
return false;
}
if (str[i] > 122)
{
return false;
}
}
return true;
}

Answer 8

In order to check if the string is both a combination of letters and digits, you can re-write #jgauffin answer as follows using .NET 4.0 and LINQ:
if(!string.IsNullOrWhiteSpace(yourText) &&
yourText.Any(char.IsLetter) && yourText.Any(char.IsDigit))
{
// do something here
}

Answer 9

Based on cletus's answer you may create new extension.
public static class StringExtensions
{
public static bool IsAlphaNumeric(this string str)
{
if (string.IsNullOrEmpty(str))
return false;
Regex r = new Regex("^[a-zA-Z0-9]*$");
return r.IsMatch(str);
}
}

Answer 10

While there are many ways to skin this cat, I prefer to wrap such code into reusable extension methods that make it trivial to do going forward. When using extension methods, you can also avoid RegEx as it is slower than a direct character check. I like using the extensions in the Extensions.cs NuGet package. It makes this check as simple as:
Add the https://www.nuget.org/packages/Extensions.cs package to your project.
Add "using Extensions;" to the top of your code.
"smith23".IsAlphaNumeric() will return True whereas "smith 23".IsAlphaNumeric(false) will return False. By default the .IsAlphaNumeric() method ignores spaces, but it can also be overridden as shown above. If you want to allow spaces such that "smith 23".IsAlphaNumeric() will return True, simple default the arg.
Every other check in the rest of the code is simply MyString.IsAlphaNumeric().

Answer 11

12 years and 7 months later, if anyone comes across this article nowadays.
Compiled RegEx actually has the best performance in .NET 5 and .NET 6
Please look at the following link where I compare several different answers given on this question. Mainly comparing Compiled RegEx, For-Loops, and Linq Predicates: https://dotnetfiddle.net/WOPQRT
Notes:
As stated, this method is only faster in .NET 5 and .NET 6.
.NET Core 3.1 and below show RegEx being the slowest.
Regardless of the version of .NET, the For-Loop method is consistently faster than the Linq Predicate.

Answer 12

I advise to not depend on ready made and built in code in .NET framework , try to bring up new solution ..this is what i do..
public bool isAlphaNumeric(string N)
{
bool YesNumeric = false;
bool YesAlpha = false;
bool BothStatus = false;
for (int i = 0; i < N.Length; i++)
{
if (char.IsLetter(N[i]) )
YesAlpha=true;
if (char.IsNumber(N[i]))
YesNumeric = true;
}
if (YesAlpha==true && YesNumeric==true)
{
BothStatus = true;
}
else
{
BothStatus = false;
}
return BothStatus;
}