I have the following question, I really can't compile from all the questions and articles researched:
In C++, is it possible to have a method with variadic template arguments that specify types of arguments (as a meta-description type for parameters of in, out, in/out of a certain type, to be passed by value, by address etc.), to loop through these variadic arguments in order to instantiate variables of specified types, and be passed these variables to functions specified by a pointer in a template parameter, but these functions not having variadic parameters?
EDIT 1
I try here to detail, as pseudocode:
template <decltype(*Type::*Method), typename... Parameters>
static bool ExecuteMethod(JSContext *cx, unsigned argc, JS::Value *vp)
{
JS::CallArgs args = CallArgsFromVp(argc, vp);
loop through Parameters
{
Parameters[i]::Type p[i] <-- args[i];
}
ReturnType r = Method(p[0], p[1], p[2] .. p[n]); // the method does not have variadic parameters
...
}
where Method might be like:
int(*GetColor) ( int16 *color);
int(*GetFile) ( FilePath &file );
int(*WriteDocument) ( const FilePath &file, const char *fileFormatName, bool askForParms);
etc.
This comes out of wrapping needs.
The challenge is something missing in C++, reflection as in .net.
It is possible to instance an array of heterogeneous objects by looping through the variadic arguments somehow? Probably.
But how pass them to methods having no variadic arguments? I think it is not possible to assign that array of objects to functions like these three above without explicit wrappers, isn't it?
EDIT 2
I've got a lot of feed-back, but it is clear I was not specific enough.
I did not detailed too much because I've got complains in the past for being too specific. Indeed, I do not have easy implementations and I am a generic guy, not lazy, but I try to make a latter development faster.
Here is the source of the problem: I need to wrap Adobe Illustrator API, which exposes hundreds if not thousands of pointers to functions grouped in structs, called suites.
I try to have a javascript engine using SpiderMonkey.
I use Visual Studio 2015 compiler.
My approach is as follows:
I have several classes to wrap the API in order to add to SpiderMonkey's engine objects for all the suites. Each SpiderMonkey class, could be called as jsData, wraps a data type of Adobe SDK, or a suite, jsSuite.
So far, I have used templates because SpiderMonkey forces me to add each function to its custom objects with a specific signature, like this:
bool jsAIDocumentSuite::WriteDocument(JSContext *cx, unsigned argc, JS::Value *vp)
{
...
}
and adding it to the custom object would be done like this:
const JSFunctionSpec jsAIDocumentSuite::fFunctions[] = {
...
JS_FN("WriteDocument", jsAIDocumentSuite::WriteDocument, 3, 0),
...
}
JS_FN is a SpiderMonkeyMacro.
Actually, this is, so far, less than 10% of the Adobe SDK.
The most are getters and setters with one parameter, passed by value or address or pointer, so I have replaced them by a generic function, like this:
template <typename jsType, typename jsReturnType, typename ReturnPrivateType = jsReturnType::PrivateType, typename jsParamType, typename ParamPrivateType = jsParamType::PrivateType, ReturnPrivateType(*Type::*Method)(ParamPrivateType&)>
static bool GetByRefMethod(JSContext *cx, unsigned argc, JS::Value *vp)
{
JS::CallArgs args = CallArgsFromVp(argc, vp);
try
{
ReturnPrivateType result;
ParamPrivateType ppt;
if (jsType::Suite() && (jsType::Suite()->*Method))
result = (jsType::Suite()->*Method)(ppt);
else
return false; // TODO throw a meaningful error
if ((jsReturnType::IsNoError(result)) && (argc > 0) && (args[0].isObject()))
{
JSObject *obj = &args[0].toObject();
JSObject *value = NULL;
if (!jsParamType::FromAIObject<jsParamType>(cx, &ppt, value))
return false;
if (!value)
return false;
jsProperty::SetProperty(cx, &obj, "value", value, true);
}
JSObject *obj = JS_NewObject(cx, &jsDataClass<jsReturnType>::fClass);
JS_SetPrivate(obj, new ReturnPrivateType(result));
args.rval().setObject(*obj);
}
EXCEPTION_CATCH_CONVERT();
return true;
}
A bit complicated, isn't it?
What is relevant, above, is:
The args variable holds the SpiderMonkey parameters passed in by its engine
Only one argument is passed here, ppt
The return type is one value, so it is easy to be handled
I use macros to inject the method in its variants (several short forms too, not so interesting here):
JS_FN(#GET_METHOD, (js##TYPE::GetByRefMethod<js##TYPE, RETURN_JS_TYPE, RETURN_PRIVATE_TYPE, PARAM_JS_TYPE, PARAM_PRIVATE_TYPE, &TYPE::GET_METHOD>), 1, 0)
I wish to be able to handle variable arguments, according to the statistics more philosophical, but interesting. The idea would be opposite to the C++, probably, and not as expected.
How would I expect it:
I wish to add variadic parameters meta-information, like:
template
static bool Method(JSContext *cx, unsigned argc, JS::Value *vp)
{
JS::CallArgs args = CallArgsFromVp(argc, vp);
try
{
ReturnPrivateType result;
*1st challenge: Loop through the variadic list of meta-parameters and create their corresponding object instances here and initialize the IN ones with values from the *args* collection passed by the SpiderMonkey engine*
if (jsType::Suite() && (jsType::Suite()->*Method))
result = (jsType::Suite()->*Method)(*2nd challenge: pass arguments here: probably by using a variadic macro?*);
else
return false; // TODO throw a meaningful error
if ((jsReturnType::IsNoError(result)) && (argc > 0) && (args[0].isObject()))
{
JSObject *obj = &args[0].toObject();
JSObject *value = NULL;
if (!jsParamType::FromAIObject<jsParamType>(cx, &ppt, value))
return false;
if (!value)
return false;
jsProperty::SetProperty(cx, &obj, "value", value, true);
}
JSObject *obj = JS_NewObject(cx, &jsDataClass<jsReturnType>::fClass);
JS_SetPrivate(obj, new ReturnPrivateType(result));
args.rval().setObject(*obj);
}
EXCEPTION_CATCH_CONVERT();
return true;
}
As you can see, it is not as C++ expected, it is a bit reversed, by trying to avoid writing templates to deduct the parameters, here, I know the parameters first and try to write a code to generate the right parameters by knowing their meta-information first and I have a clear set of types and I promise to write the right code to generate the correct wrappers. I don't need to validate much regarding the data of the parameters, as things are mostly passed without a huge business logic in the process.
EDIT 3
About the parameters meta-information, I could write a few types with statics to specify the data type of the parameter, whether it is a return type, whether it is an IN, an OUT or an IN/OUT parameter, its jsType etc..
They would be the variadic list of the template parameters function above.
I still am having some difficulty understanding exactly what you want to do, but this should let you call a function(without variardic parameters) using a variardic template function, getting the parameters from an array and allowing a conversion operation to apply to each parameter before being passed to the function:
#include <functional>
template<typename T, typename JST> T getParam(const JST& a)
{
//Do whatever conversion necessary
return a;
}
namespace detail
{
template<typename R, typename... Args, int... S> R jsCaller(std::function<R(Args...)> f, seq<S...>, const JS::CallArgs& args)
{
return f(getParam<Args, /*Whatever type should go here */>(args[S])...);
}
}
//Actually use this to call the function and get the result
template<typename R, typename... Args> R jsCall(std::function<R(Args...)> f, const JS::CallArgs& args)
{
return detail::jsCaller(f, GenSequence<sizeof...(Args)>(), args);
}
Where GenSequence extends seq<0, 1, 2, ... , N - 1> and can be implemented as follows:
template<int... N>
struct seq {};
template<int N, int... S>
struct gens : gens<N-1, N-1, S...> {};
template<int... S>
struct gens<0, S...>
{
typedef seq<S...> type;
};
template<int N> using GenSequence<N> = typename gens<N>::type;
This creates a parameter pack of integers, and expands the function call using them- See this question.
You can call your method using jsCall:
Result r = jsCall((Method), args);
Assuming Method can be converted to std::function- if not, you can still do it by making a lambda which conforms to std::function. Does this solve the problem?
[Continued from part 1: https://stackoverflow.com/a/35109026/5386374 ]
There is an issue, however. We had to change the way our code is written to accomodate ExecuteMethod(), which may not always be possible. Is there a way around that, so that it functions exactly the same as your previously specified ExecuteMethod(), and doesn't need to take the variable it modifies as a macro parameter? The answer is... yes!
// Variadic function-like macro to automatically create, use, and destroy functor.
// Uncomment whichever one is appropriate for the compiler used.
// (The difference being that Visual C++ automatically removes the trailing comma if the
// macro has zero variadic arguments, while GCC needs a hint in the form of "##" to tell
// it to do so.)
// Instead of a do...while structure, we can just use a temporary Executor directly.
// MSVC:
// #define ExecuteMethod(M, ...) Executor<decltype(&M), decltype(&M)>{}(M, __VA_ARGS__)
// GCC:
#define ExecuteMethod(M, ...) Executor<decltype(&M), decltype(&M)>{}(M, ##__VA_ARGS__)
// For your example function WriteDocument(), defined as
// int WriteDocument(const FilePath &file, const char *fileFormatName, bool askForParms);
bool c = ExecuteMethod(WriteDocument, file, fileFormatName, askForParams);
This is all well and good, but there is one more change we can make to simplify things without impacting performance. At the moment, this functor can only take function pointers (and maybe lambdas, I'm not familiar with their syntax), not other types of function objects. If this is intended, it means that we can rewrite it to do away with the first template parameter (the entire signature), since the second and third parameters are themselves components of the signature.
// Default functor.
template<typename... Ts>
struct Executor { };
// General case.
template<typename ReturnType, typename... Params>
struct Executor<ReturnType (*)(Params...)> {
private:
// Instead of explicitly taking M as a parameter, create it from
// the other parameters.
using M = ReturnType (*)(Params...);
public:
// Parameter match:
bool operator()(M method, Params... params) {
ReturnType r = method(params...);
// ...
}
// Parameter mismatch:
template<typename... Invalid_Params>
bool operator()(M method, Invalid_Params... ts) {
// Handle parameter type mismatch here.
}
};
// Special case to catch void return type.
template<typename... Params>
struct Executor<void (*)(Params...)> {
private:
// Instead of explicitly taking M as a parameter, create it from
// the other parameters.
using M = void (*)(Params...);
public:
// Parameter match:
bool operator()(M method, Params... params) {
method(params...);
// ...
}
// Parameter mismatch:
template<typename... Invalid_Params>
bool operator()(M method, Invalid_Params... ts) {
// Handle parameter type mismatch here.
}
};
// Variadic function-like macro to automatically create, use, and destroy functor.
// Uncomment whichever one is appropriate for the compiler used.
// (The difference being that Visual C++ automatically removes the trailing comma if the
// macro has zero variadic arguments, while GCC needs a hint in the form of "##" to tell
// it to do so.)
// Instead of a do...while structure, we can just use a temporary Executor directly.
// MSVC:
// #define ExecuteMethod(M, ...) Executor<decltype(&M)>{}(M, __VA_ARGS__)
// GCC:
#define ExecuteMethod(M, ...) Executor<decltype(&M)>{}(M, ##__VA_ARGS__)
// Note: If your compiler doesn't support C++11 "using" type aliases, replace them
// with the following:
// typedef ReturnType (*M)(Params...);
This results in cleaner code, but, as mentioned, limits the functor to only accepting function pointers.
When used like this, the functor expects parameters to be an exact match. It can handle reference-ness and cv-ness correctly, but may have issues with rvalues, I'm not sure. See here.
As to how to use this with your JSContext... I'm honestly not sure. I haven't learned about contexts yet, so someone else would be more helpful for that. I would suggest checking if one of the other answers here would be more useful in your situation, in all honesty.
Note: I'm not sure how easy it would be to modify the functor to work if its function parameter is a functor, lambda, std::function, or anything of the sort.
Note 2: As before, I'm not sure if there would be any negative effects on performance for doing something like this. There's likely a more efficient way, but I don't know what it would be.
I came up with the following C++11 solution, which gives the basic idea. It could very easily be improved, however, so I welcome suggestions. Live test here.
#include <iostream>
#include <tuple>
using namespace std;
// bar : does something with an arbitrary tuple
// (no variadic template arguments)
template <class Tuple>
void bar(Tuple t)
{
// .... do something with the tuple ...
std::cout << std::tuple_size<Tuple>::value;
}
// foo : takes a function pointer and an arbitrary number of other
// arguments
template <class Func, typename... Ts>
void foo(Func f, Ts... args_in)
{
// construct a tuple containing the variadic arguments
std::tuple<Ts...> t = std::make_tuple(args_in...);
// pass this tuple to the function f
f(t);
}
int main()
{
// this is not highly refined; you must provide the types of the
// arguments (any suggestions?)
foo(bar<std::tuple<int, const char *, double>>, 123, "foobar", 43.262);
return 0;
}
Edit: After seeing your "Edit 2", I don't believe this is the proper solution. Leaving it up for reference, though.
I believe I've found a potential solution that catches reference-ness, too. Scroll down to the bottom, to the "Edit 4" section.
If you're asking whether it's possible to dynamically check template argument types, you can. I'll start with a general example of how to use std::true_type and std::false_type to overload based on whether a specified condition is met, then move on to your problem specifically. Consider this:
#include <type_traits>
namespace SameComparison {
// Credit for the contents of this namespace goes to dyp ( https://stackoverflow.com/a/20047561/5386374 )
template<class T, class...> struct are_same : std::true_type{};
template<class T, class U, class... TT> struct are_same<T, U, TT...> :
std::integral_constant<bool, std::is_same<T, U>{} && are_same<T, TT...>{} >{};
} // namespace SameComparison
template<typename T> class SomeClass {
public:
SomeClass() = default;
template<typename... Ts> SomeClass(T arg1, Ts... args);
~SomeClass() = default;
void func(T arg1);
template<typename U> void func(U arg1);
template<typename... Ts> void func(T arg1, Ts... args);
template<typename U, typename... Ts> void func(U arg1, Ts... args);
// ...
private:
template<typename... Ts> SomeClass(std::true_type x, T arg1, Ts... args);
template<typename... Ts> SomeClass(std::false_type x, T arg1, Ts... args);
// ...
};
// Constructors:
// -------------
// Public multi-argument constructor.
// Passes to one of two private constructors, depending on whether all types in paramater pack match T.
template<typename T> template<typename... Ts> SomeClass<T>::SomeClass(T arg1, Ts... args) :
SomeClass(SameComparison::are_same<T, Ts...>{}, arg1, args...) { }
// All arguments match.
template<typename T> template<typename... Ts> SomeClass<T>::SomeClass(std::true_type x, T arg1, Ts... args) { }
// One or more arguments is incorrect type.
template<typename T> template<typename... Ts> SomeClass<T>::SomeClass(std::false_type x, T arg1, Ts... args) {
static_assert(x.value, "Arguments wrong type.");
}
/*
Note that if you don't need to use Ts... in the parameter list, you can combine the previous two into a single constructor:
template<typename T> template<bool N, typename... Ts> SomeClass<T>::SomeClass(std::integral_constant<bool, N> x, T arg1, Ts... args) {
static_assert(x.value, "Arguments wrong type.");
}
x will be true_type (value == true) on type match, or false_type (value == false) on type mismatch. Haven't thoroughly tested this, just ran a similar function through an online compiler to make sure it could determine N.
*/
// Member functions:
// -----------------
// Single argument, type match.
template<typename T> void SomeClass<T>::func(T arg1) {
// code
}
// Single argument, type mismatch.
// Also catches true_type from multi-argument functions after they empty their parameter pack, and silently ignores it.
template<typename T> template<typename U> void SomeClass<T>::func(U arg1) {
if (arg1 != std::true_type{}) {
std::cout << "Argument " << arg1 << " wrong type." << std::endl;
}
}
// Multiple arguments, argument 1 type match.
template<typename T> template<typename... Ts> void SomeClass<T>::func(T arg1, Ts... args) {
func(arg1);
func(args...);
// func(SameComparison::are_same<T, Ts...>{}, vals...);
}
// Multiple arguments, argument 1 type mismatch.
template<typename T> template<typename U, typename... Ts> void SomeClass<T>::func(U arg1, Ts... args) {
// if (arg1 != std::true_type{}) {
// std::cout << "Argument " << arg1 << " wrong type." << std::endl;
// }
func(vals...);
}
First, SameComparison::are_same there is an extension of std::is_same, that applies it to an entire parameter pack. This is the basis of the check, with the rest of the example showing how it can be used. The lines commented out of the last two functions show how it could be applied there, as well.
Now, onto your problem specifically. Since you know what the methods are, you can make similar comparison structs for them.
int (*GetColor) ( int16_t *color);
int(*GetFile) ( FilePath &file );
int(*WriteDocument) ( const FilePath &file, const char *fileFormatName, bool askForParms);
Could have...
namespace ParameterCheck {
template<typename T, typename... Ts> struct parameter_match : public std::false_type {};
// Declare (GetColor, int16_t*) valid.
template<> struct parameter_match<int (*)(int16_t*), int16_t*> : public std::true_type {};
// Declare (GetFile, FilePath&) valid.
// template<> struct parameter_match<int (*)(FilePath&), FilePath&> : public std::true_type {}; // You'd think this would work, but...
template<> struct parameter_match<int (*)(FilePath&), FilePath> : public std::true_type {}; // Nope!
// For some reason, reference-ness isn't part of the templated type. It acts as if it was "template<typename T> void func(T& arg)" instead.
// Declare (WriteDocument, const FilePath&, const char*, bool) valid.
// template<> struct parameter_match<int (*)(const FilePath&, const char*, bool), const FilePath, const char*, bool> : public std::true_type {};
// template<> struct parameter_match<int (*)(const FilePath&, const char*, bool), const FilePath&, const char*, bool> : public std::true_type {};
template<> struct parameter_match<int (*)(const FilePath&, const char*, bool), FilePath, const char*, bool> : public std::true_type {};
// More reference-as-template-parameter wonkiness: Out of these three, only the last works.
} // namespace ParameterCheck
Here, we make a general-case struct that equates to std::false_type, then specialise it so that specific cases are true_type instead. What this does is tell the compiler, "These parameter lists are good, anything else is bad," where each list starts with a function pointer and ends with the arguments to the function. Then, you can do something like this for your caller:
// The actual calling function.
template<typename Func, typename... Ts> void caller2(std::true_type x, Func f, Ts... args) {
std::cout << "Now calling... ";
f(args...);
}
// Parameter mismatch overload.
template<typename Func, typename... Ts> void caller2(std::false_type x, Func f, Ts... args) {
std::cout << "Parameter list mismatch." << std::endl;
}
// Wrapper to check for parameter mismatch.
template<typename Func, typename... Ts> void caller(Func f, Ts... args) {
caller2(ParameterCheck::parameter_match<Func, Ts...>{}, f, args...);
}
As for return type deduction... that depends on where you want to deduce it:
Determine variable type from contents: Use auto when declaring the variable.
Determine return type from passed function return type: If your compiler is C++14-compatible, that's easy. Just use auto. [VStudio 2015 and GCC 4.8.0 (with -std=c++1y) are compatible with auto return type.]
The former can be done like this:
int i = 42;
int func1() { return 23; }
char func2() { return 'c'; }
float func3() { return -0.0f; }
auto a0 = i; // a0 is int.
auto a1 = func1(); // a1 is int.
auto a2 = func2(); // a2 is char.
auto a3 = func3(); // a3 is float.
The latter, however, is more complex.
std::string stringMaker() {
return std::string("Here, have a string!");
}
int intMaker() {
return 5;
}
template<typename F> auto automised(F f) {
return f();
}
// ...
auto a = automised(stringMaker); // a is std::string.
auto b = automised(intMaker); // a is int.
If your compiler isn't compatible with auto or decltype(auto) return type... well, it's a bit more verbose, but we can do this:
namespace ReturnTypeCapture {
// Credit goes to Angew ( https://stackoverflow.com/a/18695701/5386374 )
template<typename T> struct ret_type;
template<typename RT, typename... Ts> struct ret_type<RT (*)(Ts...)> {
using type = RT;
};
} // namespace ReturnTypeCapture
// ...
std::string f1() {
return std::string("Nyahaha.");
}
int f2() {
return -42;
}
char f3() {
return '&';
}
template<typename R, typename F> auto rtCaller2(R r, F f) -> typename R::type {
return f();
}
template<typename F> void rtCaller(F f) {
auto a = rtCaller2(ReturnTypeCapture::ret_type<F>{}, f);
std::cout << a << " (type: " << typeid(a).name() << ")" << std::endl;
}
// ...
rtCaller(f1); // Output (with gcc): "Nyahaha. (type: Ss)"
rtCaller(f2); // Output (with gcc): "-42 (type: i)"
rtCaller(f3); // Output (with gcc): "& (type: c)"
Furthermore, we can simplify it even more, and check the return type without a separate wrapper.
template<typename F> auto rtCaller2(F f) -> typename ReturnTypeCapture::ret_type<F>::type {
return f();
}
template<typename F> void rtCaller(F f) {
auto a = rtCaller2(f);
std::cout << a << " (type: " << typeid(a).name() << ")" << std::endl;
}
// ...
rtCaller(f1); // Output (with gcc): "Nyahaha. (type: Ss)"
rtCaller(f2); // Output (with gcc): "-42 (type: i)"
rtCaller(f3); // Output (with gcc): "& (type: c)"
// Same output.
Having that sticking off the end there is really ugly, though, so can't we do better than that? The answer is... yes! We can use an alias declaration to make a typedef, leaving a cleaner name. And thus, the final result here is:
namespace ReturnTypeCapture {
// Credit goes to Angew ( https://stackoverflow.com/a/18695701/5386374 )
template<typename T> struct ret_type;
template<typename RT, typename... Ts> struct ret_type<RT (*)(Ts...)> {
using type = RT;
};
} // namespace ReturnTypeCapture
template <typename F> using RChecker = typename ReturnTypeCapture::ret_type<F>::type;
std::string f1() { return std::string("Nyahaha."); }
int f2() { return -42; }
char f3() { return '&'; }
template<typename F> auto rtCaller2(F f) -> RChecker<F> {
return f();
}
template<typename F> void rtCaller(F f) {
auto a = rtCaller2(f);
std::cout << a << " (type: " << typeid(a).name() << ")" << std::endl;
}
So now, if we combine parameter checking & return type deduction...
// Parameter match checking.
namespace ParameterCheck {
template<typename T, typename... Ts> struct parameter_match : public std::false_type {};
// Declare (GetColor, int16_t*) valid.
template<> struct parameter_match<int (*)(int16_t*), int16_t*> : public std::true_type {};
// Declare (GetFile, FilePath&) valid.
template<> struct parameter_match<int (*)(FilePath&), FilePath> : public std::true_type {};
// Declare (WriteDocument, const FilePath&, const char*, bool) valid.
template<> struct parameter_match<int (*)(const FilePath&, const char*, bool), FilePath, const char*, bool> : public std::true_type {};
// Declare everything without a parameter list valid.
template<typename T> struct parameter_match<T (*)()> : public std::true_type { };
} // namespace ParameterCheck
// Discount return type deduction:
namespace ReturnTypeCapture {
// Credit goes to Angew ( https://stackoverflow.com/a/18695701/5386374 )
template<typename T> struct ret_type;
template<typename RT, typename... Ts> struct ret_type<RT (*)(Ts...)> {
using type = RT;
};
} // namespace ReturnTypeCapture
// Alias declarations:
template<typename F, typename... Ts> using PChecker = ParameterCheck::parameter_match<F, Ts...>;
template<typename F> using RChecker = typename ReturnTypeCapture::ret_type<F>::type;
// ---------------
int GetColor(int16_t* color);
int GetFile(FilePath& file);
int WriteDocument(const FilePath& file, const char* fileFormatName, bool askForParams);
std::string f1() { return std::string("Nyahaha."); }
int f2() { return -42; }
char f3() { return '&'; }
// ---------------
// Calling function (C++11):
// The actual calling function.
template<typename Func, typename... Ts> auto caller2(std::true_type x, Func f, Ts... args) -> RChecker<Func> {
std::cout << "Now calling... ";
return f(args...);
}
// Parameter mismatch overload.
template<typename Func, typename... Ts> auto caller2(std::false_type x, Func f, Ts... args) -> RChecker<Func> {
std::cout << "Parameter list mismatch." << std::endl;
return static_cast<RChecker<Func> >(0); // Just to make sure we don't break stuff.
}
// Wrapper to check for parameter mismatch.
template<typename Func, typename... Ts> auto caller(Func f, Ts... args) -> RChecker<Func> {
// return caller2(ParameterCheck::parameter_match<Func, Ts...>{}, f, args...);
return caller2(PChecker<Func, Ts...>{}, f, args...);
}
// ---------------
// Calling function (C++14):
// The actual calling function.
template<typename Func, typename... Ts> auto caller2(std::true_type x, Func f, Ts... args) {
std::cout << "Now calling... ";
return f(args...);
}
// Parameter mismatch overload.
template<typename Func, typename... Ts> auto caller2(std::false_type x, Func f, Ts... args) {
std::cout << "Parameter list mismatch." << std::endl;
}
// Wrapper to check for parameter mismatch.
template<typename Func, typename... Ts> auto caller(Func f, Ts... args) {
// return caller2(ParameterCheck::parameter_match<Func, Ts...>{}, f, args...);
return caller2(PChecker<Func, Ts...>{}, f, args...);
}
You should be able to get the functionality you want out of this, I believe. The only caveat is that if you do it this way, you need to explicitly declare functions valid in ParameterCheck, by making a template specialisation for the function & its parameter list, derived from std::true_type instead of std::false_type. I'm not sure if there's a way to get true dynamic parameter list checking, but it's a start.
[I'm not sure if you can just overload caller() or if you explicitly need to use caller2() as well. All my attempts to overload caller() via template parameters ended up crashing the compiler; for some reason, it chose template<typename Func, typename... Ts> void caller(Func f, Ts... args) as a better match for caller(std::true_type, f, args...) than template<typename Func, typename... Ts> caller(std::true_type x, Func f, Ts... args), even with the latter listed before the former, and tried to recursively expand it until it ran out of memory. (Tested on two online gcc compilers: Ideone, and TutorialsPoint's compiler (with -std=c++11). I'm not sure if this is a gcc problem, or if I was a bit off about how template matching works. Unfortunately, the online VStudio compiler is down for maintenance, and the only version of VS I have available to me offline at the moment doesn't support variadic templates, so I can't check which is the case.) Unless someone says otherwise, or says how to fix that particular issue, it's probably best to just use caller() as a wrapper & caller2() to do the heavy lifting.]
Examples of pretty much everything here that would be relevant to your problem: here
Also, note that you can't easily pull individual arguments from a parameter pack. You can use recursion to strip arguments off the front a few at a time, you can use them to initialise member variables in a constructor's initialisation list, you can check how many arguments are in the pack, you can specialise it (as we did for parameter_match), & you can pass the whole pack to a function that takes the right number of arguments, but I believe that's it at the moment. This can make them a bit more awkward than C-style varargs at times, despite being more efficient. However, if your ExecuteMethod()'s argument list consists of a function and its argument list, and nothing else, this isn't an issue. As long as the parameter match succeeds, we can just give the entire pack to the passed function, no questions asked. On that note, we can rewrite ExecuteMethod() into something like...
// Not sure what cx is, leaving it alone.
// Assuming you wanted ExecuteMethod to take parameters in the order (cx, function, function_parameter_list)...
// Parameter list match.
template<typename M, typename... Parameters>
static bool ExecuteMethodWorker(std::true_type x, JSContext* cx, M method, Parameters... params)
{
auto r = method(params...);
// ...
}
// Parameter list mismatch.
template<typename M, typename... Parameters>
static bool ExecuteMethodWorker(std::false_type x, JSContext* cx, M method, Parameters... params)
{
// Handle parameter type mismatch here.
// Omit if not necessary, though it's likely better to use it to log errors, terminate, throw an exception, or something.
}
// Caller.
template<typename M, typename... Parameters>
static bool ExecuteMethod(JSContext* cx, M method, Parameters... params)
{
return ExecuteMethodWorker(PChecker<M, Parameters...>{}, cx, method, params...);
}
Make sure to either prototype or define the worker functions before ExecuteMethod(), so the compiler can resolve the call properly.
(Apologies for any typoes I may have missed anywhere in there, I'm a bit tired.)
Edit: I've located the problem with passing references to a template. It seems that using templates to determine types does indeed remove reference-ness in and of itself, hence notation like template<typename T> void func(T&) for functions that take a reference. Sadly, I'm not yet sure how to fix this issue. I did, however, come up with a new version of PChecker that dynamically reflects types for any function that doesn't use reference types. So far, however, you still need to add references manually, and non-const references probably won't work properly for now.
namespace ParameterCheck {
namespace ParamGetter {
// Based on an answer from GManNickG ( https://stackoverflow.com/a/4693493/5386374 )
// Turn the type list into a single type we can use with std::is_same.
template<typename... Ts> struct variadic_typedef { };
// Generic case, to catch passed parameter types list.
template<typename... Ts> struct variadic_wrapper {
using type = variadic_typedef<Ts...>;
};
// Special case to catch void parameter types list.
template<> struct variadic_wrapper<> {
using type = variadic_typedef<void>;
};
// Generic case to isolate parameter list from function signature.
template<typename RT, typename... Ts> struct variadic_wrapper<RT (*)(Ts...)> {
using type = variadic_typedef<Ts...>;
};
// Special case to isolate void parameter from function signature.
template<typename RT> struct variadic_wrapper<RT (*)()> {
using type = variadic_typedef<void>;
};
} // namespace ParamGetter
template<typename... Ts> using PGetter = typename ParamGetter::variadic_wrapper<Ts...>::type;
// Declare class template.
template<typename... Ts> struct parameter_match;
// Actual class. Becomes either std::true_type or std::false_type.
template<typename F, typename... Ts> struct parameter_match<F, Ts...> : public std::integral_constant<bool, std::is_same<PGetter<F>, PGetter<Ts...> >{}> {};
// Put specialisations for functions with const references here.
} // namespace ParameterCheck
template<typename F, typename... Ts> using PChecker = ParameterCheck::parameter_match<F, Ts...>;
See here.
--
Edit 2: Okay, can't figure out how to grab the passed function's parameter list and use it directly. It might be possible using tuples, perhaps using the rest of GManNickG's code (the convert_in_tuple struct), but I haven't looked into them, and don't really know how to grab the entire type list from a tuple at the same time, or if it's even possible. [If anyone else knows how to fix the reference problem, feel free to comment.]
If you're only using references to minimise passing overhead, and not to actually change data, you should be fine. If your code uses reference parameters to modify the data that the parameter is pointing to, however, I'm not sure how to help you. Sorry.
--
Edit 3: It looks like RChecker might not be as necessary for C++11 function forwarding, we can apparently use decltype([function call]) for that. So...
// caller2(), using decltype. Valid, as args... is a valid parameter list for f.
template<typename Func, typename... Ts> auto caller2(std::true_type x, Func f, Ts... args) -> decltype(f(args...)) {
std::cout << "Now calling... ";
return f(args...);
}
// Parameter mismatch overload.
// decltype(f(args...)) would be problematic, since args... isn't a valid parameter list for f.
template<typename Func, typename... Ts> auto caller2(std::false_type x, Func f, Ts... args) -> RChecker<Func> {
std::cout << "Parameter list mismatch." << std::endl;
return static_cast<RChecker<Func> >(0); // Make sure we don't break stuff.
}
// Wrapper to check for parameter mismatch.
// decltype(caller2(PChecker<Func, Ts...>{}, f, args...)) is valid, but would be more verbose than RChecker<Func>.
template<typename Func, typename... Ts> auto caller(Func f, Ts... args) -> RChecker<Func> {
// return caller2(ParameterCheck::parameter_match<Func, Ts...>{}, f, args...);
return caller2(PChecker<Func, Ts...>{}, f, args...);
}
However, as noted, decltype can have issues when it can't find a function call that matches what it's passed exactly. So, for any case where the parameter mismatch version of caller2() is called, trying to use decltype(f(args...)) to determine return type would likely cause issues. However, I'm not sure if decltype(auto), introduced in C++14, would have that issue.
Also, in C++14-compatible compilers, it's apparently better to use decltype(auto) than just auto for automatic return type determination; auto doesn't preserve const-ness, volatile-ness, or reference-ness, while decltype(auto) does. It can be used either as a trailing return type, or as a normal return type.
// caller2(), using decltype(auto).
template<typename Func, typename... Ts> decltype(auto) caller2(std::true_type x, Func f, Ts... args) {
std::cout << "Now calling... ";
return f(args...);
}
decltype(auto) can also be used when declaring variables. See here for more information.
Edit 4: I believe I may have found a potential solution that preserves the passed function's parameter list properly, using functors. However, it may or may not create unwanted overhead, I'm not sure.
// Default functor.
template<typename... Ts>
struct Executor { };
// General case.
template<typename M, typename ReturnType, typename... Params>
struct Executor<M, ReturnType (*)(Params...)> {
public:
// Parameter match:
bool operator()(M method, Params... params) {
ReturnType r = method(params...);
// ...
}
// Parameter mismatch:
template<typename... Invalid_Params>
bool operator()(M method, Invalid_Params... ts) {
// Handle parameter type mismatch here.
}
};
// Special case to catch void return type.
template<typename M, typename... Params>
struct Executor<M, void (*)(Params...)> {
public:
// Parameter match:
bool operator()(M method, Params... params) {
method(params...);
// ...
}
// Parameter mismatch:
template<typename... Invalid_Params>
bool operator()(M method, Invalid_Params... ts) {
// Handle parameter type mismatch here.
}
};
// Variadic function-like macro to automatically create, use, and destroy functor.
// Uncomment whichever one is appropriate for the compiler used.
// (The difference being that Visual C++ automatically removes the trailing comma if the
// macro has zero variadic arguments, while GCC needs a hint in the form of "##" to tell
// it to do so.)
// Also note that the "do { ... } while (false)" structure is used to swallow the trailing
// semicolon, so it doesn't inadvertently break anything; most compilers will optimise it
// out, leaving just the code inside.
// (Source: https://gcc.gnu.org/onlinedocs/cpp/Swallowing-the-Semicolon.html )
// MSVC:
// #define ExecuteMethod(C, M, ...) \
// do { \
// Executor<decltype(&M), decltype(&M)> temp; \
// C = temp(M, __VA_ARGS__); \
// } while (false)
// GCC:
#define ExecuteMethod(C, M, ...) \
do { \
Executor<decltype(&M), decltype(&M)> temp; \
C = temp(M, ##__VA_ARGS__); \
} while (false)
In this case, you can use it as:
ExecuteMethod(return_value_holder, function_name, function_parameter_list);
Which expands to...
do {
Executor<decltype(&function_name), decltype(&function_name)> temp;
return_value_holder = temp(function_name, function_parameter_list);
} while (false);
With this, there's no need to manually go through the parameter pack and make sure each one matches the passed function's parameters. As the passed function's parameter list is quite literally built into Executor as Params..., we can simply overload the function call operator based on whether the arguments it was passed match Params... or not. If the parameters match the function, it calls the Parmas... overload; if they don't, it calls the Invalid_Params... overload. A bit more awkward than true reflection, IMO, but it seems to match everything properly.
Note that:
I'm not sure whether using functors liberally can cause any performance or memory use overhead. I'm... not all that familiar with them at the moment.
I don't know if it's possible to combine the general case and the "void return type" special case into a single functor. The compiler complained when I tried, but I'm not sure if it's because it isn't possible or because I was doing it wrong.
Considering #2, when modifying this version of ExecuteMethod()'s parameters, you have to modify it and both versions of Executor to match.
Like so, where JSContext* cx is added to the parameter list:
template<typename M, typename ReturnType, typename... Params>
struct Executor<M, ReturnType (*)(Params...)> {
public:
bool operator()(JSContext* cx, M method, Params... params);
};
template<typename M, typename... Params>
struct Executor<M, void (*)(Params...)> {
public:
bool operator()(JSContext* cx, M method, Params... params);
};
#define ExecuteMethod(C, cx, M, ...) \
do { \
Executor<decltype(&M), decltype(&M)> temp; \
C = temp(cx, M, ##__VA_ARGS__); \
} while (false)
This may be the solution, but it requires further testing to see if it has any negative impacts on performance. At the very least, it'll make sure const-ness and reference-ness is preserved by ExecuteMethod(), and it's a lot cleaner than my old ideas.
See here.
There are further improvements that can be made, however. As I'm out of space, see here.
Notes:
int16_t (a.k.a. std::int16_t) is in the header <cstdint>.
std::true_type and std::false_type are in the header <type_traits>.
It's difficult to tell from your description, but this is my closest interpretation to what you asked:
auto foo(int) { cout << "foo int" << endl; }
auto foo(float) { cout << "foo float" << endl; }
//... other foo overloads...
template <class T>
auto uber_function(T t)
{
foo(t);
}
template <class T, class... Args>
auto uber_function(T t, Args... args)
{
foo(t);
uber_function(args...);
}
auto main() -> int
{
uber_function(3, 2.4f);
return 0;
}
Of course this can be improved to take references, to make forwarding. This is just for you to have a starting point. As you weren't more clear, I can't give a more specific answer.
Given the following code(taken from here):
#include <cstddef>
#include <type_traits>
#include <tuple>
#include <iostream>
#include <utility>
#include <functional>
template<typename ... Fs>
struct compose_impl
{
compose_impl(Fs&& ... fs) : functionTuple(std::forward_as_tuple(fs ...)) {}
template<size_t N, typename ... Ts>
auto apply(std::integral_constant<size_t, N>, Ts&& ... ts) const
{
return apply(std::integral_constant<size_t, N - 1>(), std::get<N> (functionTuple)(std::forward<Ts>(ts)...));
}
template<typename ... Ts>
auto apply(std::integral_constant<size_t, 0>, Ts&& ... ts) const
{
return std::get<0>(functionTuple)(std::forward<Ts>(ts)...);
}
template<typename ... Ts>
auto operator()(Ts&& ... ts) const
{
return apply(std::integral_constant<size_t, sizeof ... (Fs) - 1>(), std::forward<Ts>(ts)...);
}
std::tuple<Fs ...> functionTuple;
};
template<typename ... Fs>
auto compose(Fs&& ... fs)
{
return compose_impl<Fs ...>(std::forward<Fs>(fs) ...);
}
int main ()
{
auto f1 = [](std::pair<double,double> p) {return p.first + p.second; };
auto f2 = [](double x) {return std::make_pair(x, x + 1.0); };
auto f3 = [](double x, double y) {return x*y; };
auto g = compose(f1, f2, f3);
std::cout << g(2.0, 3.0) << std::endl; //prints '13', evaluated as (2*3) + ((2*3)+1)
return 0;
}
The code above works in C++14. I'm having some trouble making it work for C++11. I tried to properly provide the return types for the function templates involved but without much success e.g.:
template<typename... Fs>
struct compose_impl
{
compose_impl(Fs&&... fs) : func_tup(std::forward_as_tuple(fs...)) {}
template<size_t N, typename... Ts>
auto apply(std::integral_constant<size_t, N>, Ts&&... ts) const -> decltype(std::declval<typename std::tuple_element<N, std::tuple<Fs...>>::type>()(std::forward<Ts>(ts)...))
// -- option 2. decltype(apply(std::integral_constant<size_t, N - 1>(), std::declval<typename std::tuple_element<N, std::tuple<Fs...>>::type>()(std::forward<Ts>(ts)...)))
{
return apply(std::integral_constant<size_t, N - 1>(), std::get<N>(func_tup)(std::forward<Ts>(ts)...));
}
using func_type = typename std::tuple_element<0, std::tuple<Fs...>>::type;
template<typename... Ts>
auto apply(std::integral_constant<size_t, 0>, Ts&&... ts) const -> decltype(std::declval<func_type>()(std::forward<Ts>(ts)...))
{
return std::get<0>(func_tup)(std::forward<Ts>(ts)...);
}
template<typename... Ts>
auto operator()(Ts&&... ts) const -> decltype(std::declval<func_type>()(std::forward<Ts>(ts)...))
// -- option 2. decltype(apply(std::integral_constant<size_t, sizeof...(Fs) - 1>(), std::forward<Ts>(ts)...))
{
return apply(std::integral_constant<size_t, sizeof...(Fs) - 1>(), std::forward<Ts>(ts)...);
}
std::tuple<Fs...> func_tup;
};
template<typename... Fs>
auto compose(Fs&&... fs) -> decltype(compose_impl<Fs...>(std::forward<Fs>(fs)...))
{
return compose_impl<Fs...>(std::forward<Fs>(fs)...);
}
For the above clang(3.5.0) gives me the following error:
func_compose.cpp:79:18: error: no matching function for call to object of type 'compose_impl<(lambda at func_compose.cpp:65:15) &, (lambda at func_compose.cpp:67:15) &,
(lambda at func_compose.cpp:68:15) &>'
std::cout << g(2.0, 3.0) << std::endl; //prints '13', evaluated as (2*3) + ((2*3)+1)
^
func_compose.cpp:31:10: note: candidate template ignored: substitution failure [with Ts = <double, double>]: no matching function for call to object of type
'(lambda at func_compose.cpp:65:15)'
auto operator()(Ts&&... ts) /*const*/ -> decltype(std::declval<func_type>()(std::forward<Ts>(ts)...))
^ ~~~
1 error generated.
If I try "option 2." I get pretty much the same error.
Apart from the fact that it looks very verbose I also cannot seem to get it right. Could anyone provide some insight in what am I doing wrong?
Is there any simpler way to provide the return types?
The error message for your first option is due to the fact that in
std::declval<func_type>()(std::forward<Ts>(ts)...)
you're trying to call the f1 functor with two arguments of type double (the ones passed to operator()), but it takes a std::pair (func_type refers to the type of the first functor in the tuple).
Regarding option 2, the reason it doesn't compile is that the trailing return type is part of the function declarator and the function is not considered declared until the end of the declarator has been seen, so you can't use decltype(apply(...)) in the trailing return type of the first declaration of apply.
I'm sure you're now very happy to know why your code doesn't compile, but I guess you'd be even happier if you had a working solution.
I think there's an essential fact that needs to be clarified first: all specializations of the apply and operator() templates in compose_impl have the same return type - the return type of the first functor, f1 in this case.
There are several ways to get that type, but a quick hack is the following:
#include <cstddef>
#include <type_traits>
#include <tuple>
#include <iostream>
#include <utility>
#include <functional>
template<typename> struct ret_hlp;
template<typename F, typename R, typename... Args> struct ret_hlp<R (F::*)(Args...) const>
{
using type = R;
};
template<typename F, typename R, typename... Args> struct ret_hlp<R (F::*)(Args...)>
{
using type = R;
};
template<typename ... Fs>
struct compose_impl
{
compose_impl(Fs&& ... fs) : functionTuple(std::forward_as_tuple(fs ...)) {}
using f1_type = typename std::remove_reference<typename std::tuple_element<0, std::tuple<Fs...>>::type>::type;
using ret_type = typename ret_hlp<decltype(&f1_type::operator())>::type;
template<size_t N, typename ... Ts>
ret_type apply(std::integral_constant<size_t, N>, Ts&& ... ts) const
{
return apply(std::integral_constant<size_t, N - 1>(), std::get<N> (functionTuple)(std::forward<Ts>(ts)...));
}
template<typename ... Ts>
ret_type apply(std::integral_constant<size_t, 0>, Ts&& ... ts) const
{
return std::get<0>(functionTuple)(std::forward<Ts>(ts)...);
}
template<typename ... Ts>
ret_type operator()(Ts&& ... ts) const
{
return apply(std::integral_constant<size_t, sizeof ... (Fs) - 1>(), std::forward<Ts>(ts)...);
}
std::tuple<Fs ...> functionTuple;
};
template<typename ... Fs>
compose_impl<Fs ...> compose(Fs&& ... fs)
{
return compose_impl<Fs ...>(std::forward<Fs>(fs) ...);
}
int main ()
{
auto f1 = [](std::pair<double,double> p) {return p.first + p.second; };
auto f2 = [](double x) {return std::make_pair(x, x + 1.0); };
auto f3 = [](double x, double y) {return x*y; };
auto g = compose(f1, f2, f3);
std::cout << g(2.0, 3.0) << std::endl; //prints '13', evaluated as (2*3) + ((2*3)+1)
return 0;
}
Notes:
It compiles and works on GCC 4.9.1 and Clang 3.5.0 in C++11 mode, and on Visual C++ 2013.
As written, ret_hlp only handles function object types that declare their operator() similarly to lambda closure types, but it can be easily extended to pretty much anything else, including plain function types.
I tried to change the original code as little as possible; I think there's one important bit that needs to be mentioned regarding that code: if compose is given lvalue arguments (as in this example), functionTuple inside compose_impl will store references to those arguments. This means the original functors need to be available for as long as the composite functor is used, otherwise you'll have dangling references.
EDIT: Here's more info on the last note, as requested in the comment:
That behaviour is due to the way forwarding references work - the Fs&& ... function parameters of compose. If you have a function parameter of the form F&& for which template argument deduction is being done (as it is here), and an argument of type A is given for that parameter, then:
if the argument expression is an rvalue, F is deduced as A, and, when substituted back into the function parameter, it gives A&& (for example, this would happen if you passed a lambda expression directly as the argument to compose);
if the argument expression is an lvalue, F is deduced as A&, and, when substituted back into the function parameter, it gives A& &&, which yields A& according to the reference collapsing rules (this is what happens in the current example, as f1 and the others are lvalues).
So, in the current example, compose_impl will be instantiated using the deduced template arguments as something like (using invented names for lambda closure types)
compose_impl<lambda_1_type&, lambda_2_type&, lambda_3_type&>
which in turn will make functionTuple have the type
std::tuple<lambda_1_type&, lambda_2_type&, lambda_3_type&>
If you'd pass the lambda expressions directly as arguments to compose, then, according to the above, functionTuple will have the type
std::tuple<lambda_1_type, lambda_2_type, lambda_3_type>
So, only in the latter case will the tuple store copies of the function objects, making the composed function object type self-contained.
Now, it's not a question of whether this is good or bad; it's rather a question of what you want.
If you want the composed object to always be self-contained (store copies of the functors), then you need to get rid of those references. One way to do it here is to use std::decay, as it does more than remove references - it also handles function-to-pointer conversions, which comes in handy if you want to extend compose_impl to be able to also handle plain functions.
The easiest way is to change the declaration of functionTuple, as it's the only place where you care about references in the current implementation:
std::tuple<typename std::decay<Fs>::type ...> functionTuple;
The result is that the function objects will always be copied or moved inside the tuple, so the resulting composed function object can be used even after the original components have been destructed.
Wow, this got long; maybe you shouldn't have said 'elaborate' :-).
EDIT 2 for the second comment from the OP: Yes, the code as it is, without the std::decay (but extended to properly determine ret_type for plain function arguments, as you said) will handle plain functions, but be careful:
int f(int) { return 7; }
int main()
{
auto c1 = compose(&f, &f); //Stores pointers to function f.
auto c2 = compose(f, f); //Stores references to function f.
auto pf = f; //pf has type int(*)(int), but is an lvalue, as opposed to &f, which is an rvalue.
auto c3 = compose(pf, pf); //Stores references to pointer pf.
std::cout << std::is_same<decltype(c1.functionTuple), std::tuple<int(*)(int), int(*)(int)>>::value << '\n';
std::cout << std::is_same<decltype(c2.functionTuple), std::tuple<int(&)(int), int(&)(int)>>::value << '\n';
std::cout << std::is_same<decltype(c3.functionTuple), std::tuple<int(*&)(int), int(*&)(int)>>::value << '\n';
}
The behaviour of c3 is probably not what you want or what one would expect. Not to mention all these variants will likely confuse your code for determining ret_type.
With the std::decay in place, all three variants store pointers to function f.