Switch cases and getch() don't work together - c++

Question

I've done a pretty simple switch where if I press a character, the integer of it adds one to itself and prints a message, it worked pretty fine with the "cin>>" and the "getchar()", but when I added the getch, It still prints the message but it stops updating the integer "how I know"? cause I made a random value that the integer has to get to, and it's between 1 and 20, and with the getch it simply goes on without stopping itself when arrived to the value
'''
void Journ(char const *bypassto = "x")
{
int m = 4;
int VAL[m];
for (int j=0; j<m; j++)
{
VAL[j] = rand()%20 + 1;
}
char comm;
int W;
int A;
int S;
int D;
char journkey;
if (bypassto != "x" ) {
journkey = *bypassto;
} else {
cout << "Choose a direction: \n";
cout <<"[FOWARD]-[LEFT]-[RIGHT]-[BACKWARDS]\n";
cout << "w for foward - a for left - d for right - s for backwards \n";
}
while (comm!=4)
{
// cin >> comm;
comm = getch();
switch(comm)
{
case 'w':
{
cout << "You went foward. \n";
W++;
break;
}
case 'a':
{
cout << "You went left. \n";
A++;
break;
}
case 's':
{
cout << "You went backwards. \n";
S++;
break;
}
case 'd':
{
cout << "You went right. \n";
D++;
break;
}
}
if(W == VAL[0])
{
BattleIntro();
break;
}
else if(A == VAL[1])
{
BattleIntro();
break;
}
else if(S == VAL[2])
{
BattleIntro();
break;
}
else if(D == VAL[3])
{
BattleIntro();
break;
}
}
}
'''