How to save the file in the server? - clojure

Question

I'm receiving the following request in the server that I'm extracting using (-> req :params):
{"_parts":[["video",{"_data":{"size":2971246,"blobId":"D002459C-47C5-4403-ABC6-A2DE6A46230A","offset":0,"type":"video/quicktime","name":"DCDE604A-954F-4B49-A1F9-1BCC2C2F37BC.mov","__collector":null}}],["key","VAL"]]}
It contains a file "video" with a name and blobId. However, I want to access the file's data and save it to a file. So far, I've tried the following:
(defn upload-shot-video [req]
(prn "uploading video")
(prn "video is! " (-> req :multipart-params))
(prn "video is " (-> req :params))
(prn "video before is " (slurp (-> req :body)))
(.reset (-> req :body))
(prn "req full" (-> req))
(prn "video after is " (-> req :body))
(prn "video is! " (-> req :multipart-params))
(clojure.java.io/copy (-> req :body) (clojure.java.io/file "./resources/public/video.mov"))
(let [filename (str (rand-str 100) ".mov")]
(s3/put-object
:bucket-name "humboi-videos"
:key filename
:file "./resources/public/video.mov"
:access-control-list {:grant-permission ["AllUsers" "Read"]})
(db/add-video {:name (-> req :params :name)
:uri (str "https://humboi-videos.s3-us-west-1.amazonaws.com/" filename)}))
(r/response {:res "okay!"}))
In which I'm trying to save the (-> req :body) into the file (which is an inputstream). This must be incorrect. What's the correct way to save this file that the server has received into a file, by saving the data into a file on the server? How to extract this data from the request?

Answer 1

If you are using Ring, you need to use wrap-multipart-params middleware.
(ns controller
(:require [ring.middleware.params :refer [wrap-params]]
[ring.middleware.multipart-params :refer [wrap-multipart-params]])
(defn upload-shot-video [req]
(let [uploaded-file (-> req :params "file" :tempfile) ;; here is a java.io.File instance of your file
(save-file uploaded-file)
{:status 201 :body "Upload complete"}))
(def app
(-> upload-shot-video
wrap-params
wrap-multipart-params))