Converting Char array to TimeStamp in C++ - c++

Question

I have char start_time[40] = "2020-04-01 12:00:00"; How can I convert the char array to timestamp in C++ without using strptime?

Answer 1

You can try this:
#include <time.h>
#include <stdio.h>
#include <stdlib.h>
#include <iostream>
int main(void) {
const char T[] = "2020-04-01 12:00:00";
time_t result = 0;
int year = 0, month = 0, day = 0, hour = 0, min = 0,sec=0;
if (sscanf(T, "%4d-%2d-%2d %2d:%2d:%2d", &year, &month, &day, &hour, &min,&sec) == 6) {
struct tm test_time = {0};
test_time.tm_year = year - 1900; /* years since 1900 */
test_time.tm_mon = month - 1;
test_time.tm_mday = day;
test_time.tm_hour = hour;
test_time.tm_min = min;
test_time.tm_sec = sec;
if ((result = mktime(&test_time)) == (time_t)-1) {
fprintf(stderr, "Cannot convert time to time_t\n");
return EXIT_FAILURE;
}
std::cout << result << '\n' ;
puts(ctime(&result));
struct tm *t_start = localtime(&result);
char date_time[30];
strftime( date_time, sizeof(date_time), "%Y-%m-%d %H:%M:%S", t_start );
std::cout << date_time << '\n' ;
return EXIT_SUCCESS;
}
else {
fprintf(stderr, "The input was not a valid time format\n");
return EXIT_FAILURE;
}
}