How do I parameterize the django url using router.register? - django

Question

I am newbie in Django. So this might be a trivial question.
I have been been building urlpatterns as following
router = DefaultRouter()
router.register('posts', views.PostViewSet)
urlpatterns = [
path('', include(router.urls))
]
This creates URLs like api/posts and so on.
Now, I am trying to add a voting model to this.. For which I want to create URL like
api/posts/<id>/vote
But I don't want to create a path like
urlpatterns = [
path('', include(router.urls)),
path('posts/<int:pk>/vote', views.SomeView)
]
Is there a way to do this via router.register way?

Answer 1

First You will define default router same way as you defined.
router = DefaultRouter()
router.register('posts', views.PostViewSet, basename='posts')
urlpatterns = [
path('', include(router.urls))
]
Then define Serializer class as you needed.
from rest_framework import serializers
from .models import Post
class PostSerializer(serializers.ModelSerializer):
class Meta:
model = Post
fields = '__all__'
Now define the custom method of vote inside PostViewSet with Allowed HTTP methods.
from rest_framework.response import Response
from rest_framework import viewsets, status
from rest_framework.decorators import action
from .models import Post
from .serializers import PostSerializer
class PostViewSet(viewsets.ModelViewSet):
queryset = Post.objects.all()
serializer_class = PostSerializer
#action(detail=True, methods=['Get'])
def vote(self, request, pk=None):
queryset = Post.objects.filter(pk=pk)
serializer = PostSerializer(queryset, many=True)
return Response(serializer.data, status=status.HTTP_200_OK)
Now you will be able to access the vote with your desired URL as api/posts/<pk>/vote