I have this text:
2|#Favo|Name||26.0000|50.10000|_GRE|||||City|Road||||
I want to capture anything between those special chars: ||
For example, I want to capture "Name" only or I want to capture "City"
I've spent many hours and all I came up with is this regex:
([^|].*[$|])\w+
Here are the required values:
How can I capture one of them?
Thank you.
You may split the string with | removing empty entries and also all those that are blank or consisting only of digits:
Dim strng As String = "2|#Favo|Name||26.0000|50.10000|_GRE|||||City|Road||||"
Dim reslt As List(Of String) = strng.Split(New String() {"|"}, StringSplitOptions.RemoveEmptyEntries).Where(
Function(m) m.All(AddressOf Char.IsDigit) = False And String.Equals(m.Trim(), String.Empty) = False).ToList()
Console.Write(String.Join(", ", reslt))
Output:
"\:(.*)$"
Hi all i am using above expression to remove all the string before : (colon), but it is giving me all the string before this. how can i do this. Thanks a lot.
My string is:
This is text: Hi here we go
I am getting: This is text
I want : Hi here we go
Updated code
Sub Main()
Dim input As String = "This is text with : far too much "
Dim pattern As String = "\:(.*)$"
Dim replacement As String = " "
Dim rgx As New Regex(pattern)
Dim result As String = rgx.Replace(input, replacement)
Console.WriteLine("Original String: {0}", input)
' MsgBox("Original String: {0}")
Console.WriteLine("Replacement String: {0}", result)
MsgBox("Original String: {0}")
End Sub
Try this pattern. This will help you to match string after colon
/?:(.)/
or
/: (.+)/
It should be:
Dim pattern As String = "(.*)\:"
' in vb if above one doesn't work, then try this one
' Dim pattern As String = "^(.*)\:"
' also i don't think we need to use any brackets here as well.
This regex means, anything before the colon(:), Where you were using anything after the colon(:) in your example.
If you are not dead set on RegEx then you can also use
Dim result As String
result = Strings.Split(Input, ":", 2)(1)
This splits the input into an array with two elements. First element is the text before the first ":", the second element is the text after.
First of all, I would like an opinion if using regex is even the best solution here, I'm fairly new to this area and regex is the first thing I found and it seemed somewhat easy to use, until I need to grab a long section of text out of a line lol. I'm using a vb.net environment for regex.
Basically, I'm taking this line here:
21:24:55 "READ/WRITE: ['PASS',false,'27880739',[40,[459.313,2434.11,0.00221252]],[["ItemFlashlight","ItemWatch","ItemMap","ItemKnife","ItemEtool","ItemGPS","ItemHatchet","ItemCompass","ItemMatchbox","M9SD","ItemFlashlightRed","NVGoggles","Binocular_Vector","ItemToolbox","M4A1_AIM_SD_camo"],["ItemPainkiller","ItemMorphine","ItemSodaPepsi","FoodSteakCooked",["30Rnd_556x45_StanagSD",29],"30Rnd_556x45_StanagSD","30Rnd_556x45_StanagSD","30Rnd_556x45_StanagSD","30Rnd_556x45_StanagSD","30Rnd_556x45_StanagSD",["15Rnd_9x19_M9SD",12],["15Rnd_9x19_M9SD",10],"15Rnd_9x19_M9SD","15Rnd_9x19_M9SD","ItemBandage"]],["DZ_Backpack_EP1",[["BAF_AS50_TWS"],[1]],[["FoodSteakCooked","ItemPainkiller","ItemMorphine","ItemSodaCoke","5Rnd_127x99_as50","ItemBloodbag"],[2,1,1,2,4,1]]],[316,517,517],Sniper1_DZ,0.94]"
Using the following regex:
\[\[([\w|_|\""|,]*)\],\[([\w|_|\""|,|\[|\]]*)\]\],
To try and get the following:
[["ItemFlashlight","ItemWatch","ItemMap","ItemKnife","ItemEtool","ItemGPS","ItemHatchet","ItemCompass","ItemMatchbox","M9SD","ItemFlashlightRed","NVGoggles","Binocular_Vector","ItemToolbox","M4A1_AIM_SD_camo"],["ItemPainkiller","ItemMorphine","ItemSodaPepsi","FoodSteakCooked",["30Rnd_556x45_StanagSD",29],"30Rnd_556x45_StanagSD","30Rnd_556x45_StanagSD","30Rnd_556x45_StanagSD","30Rnd_556x45_StanagSD","30Rnd_556x45_StanagSD",["15Rnd_9x19_M9SD",12],["15Rnd_9x19_M9SD",10],"15Rnd_9x19_M9SD","15Rnd_9x19_M9SD","ItemBandage"]]
However either my regex is flawed, or my vb.net code is. It only displays the following data:
[["ItemFlashlight","ItemWatch","ItemMap","ItemKnife","ItemEtool","ItemGPS","ItemHatchet","ItemCompass","ItemMatchbox","M9SD","ItemFlashlightRed","NVGoggles","Binocular_Vector","ItemToolbox","M4A1_AIM_SD_camo"],["ItemPainkiller","ItemMorphine","ItemSodaPepsi",
My vb.net code in case you need to peek at it is:
ListView1.Clear()
Call initList(Me.ListView1)
My.Computer.FileSystem.CurrentDirectory = My.Settings.cfgPath
My.Computer.FileSystem.CopyFile("arma2oaserver.RPT", "tempRPT.txt")
Dim ScriptLine As String = ""
Dim path As String = My.Computer.FileSystem.CurrentDirectory & "\tempRPT.txt"
Dim lines As String() = IO.File.ReadAllLines(path, System.Text.Encoding.Default)
Dim que = New Queue(Of String)(lines)
ProgressBar1.Maximum = lines.Count + 1
ProgressBar1.Value = 0
Do While que.Count > 0
ScriptLine = que.Dequeue()
ScriptLine = LCase(ScriptLine)
If InStr(ScriptLine, "login attempt:") Then
Dim rtime As Match = Regex.Match(ScriptLine, ("(\d{1,2}:\d{2}:\d{2})"))
Dim nam As Match = Regex.Match(ScriptLine, "\""([^)]*)\""")
Dim name As String = nam.ToString.Replace("""", "")
Dim next_line As String = que.Peek 'Read next line temporarily 'This is where it would move to next line temporarily to read from it
next_line = LCase(next_line)
If InStr(next_line, "read/write:") > 0 Then 'Or InStr(next_line, "update: [b") > 0 Then 'And InStr(next_line, "setmarkerposlocal.sqf") < 1 Then
Dim coords As Match = Regex.Match(next_line, "\[(\d+)\,\[(-?\d+)\.\d+\,(-?\d+)\.\d+,([\d|.|-]+)\]\]")
Dim inv As Match = Regex.Match(next_line, "\[\[([\w|_|\""|,]*)\],\[([\w|_|\""|,|\[|\]]*)\]\],") '\[\[([\w|_|\""|,]*)\],\[([\w|_|\""|,|\[|\]]*)\]\],
'\[\[([\w|_|\""|,]*)\],\[([\w|_|\""|,|\[|\]]*)\]\]:\[([\w|_|\""|,|\[|\]]*)\]\:
Dim back As Match = Regex.Match(next_line, "\""([\w|_]+)\"",\[\[([\w|_|\""|,]*)\],\[([\d|,]*)\]\],\[\[([\w|_|\""|,]*)\],\[([\d|,]*)\]\]")
Dim held As Match = Regex.Match(next_line, "\[\""([\w|_|\""|,]+)\""\,\d+\]")
With Me.ListView1
.Items.Add(name.ToString)
With .Items(.Items.Count - 1).SubItems
.Add(rtime.ToString)
.Add(coords.ToString)
.Add(inv.ToString)
.Add(back.ToString)
.Add(held.ToString)
End With
End With
End If
End If
ProgressBar1.Value += 1
Loop
My.Computer.FileSystem.DeleteFile("tempRPT.txt")
ProgressBar1.Value = 0
The odd thing is, when I test my regex in Expresso it gets the full, correct match. So I don't know what I'm doing wrong.
I'm not sure what's wrong with the regex you have, but the first match off of this one seems to work fine:
\[\[.*?\]\]
Hope this helps.
-EDIT-
The problem isn't the regex, it's that ListView is truncating the display of the string. See here
Try this regular expression instead: \Q[[\E(?:(?!\Q[[\E).)+]]
http://regex101.com/r/zP1aC5
If you need a backref, use \Q[[\E((?:(?!\Q[[\E).)+)]]
Perhaps you should specify whether you are working with single line or multi line input text. Depending on your input text format, try with:
Dim variableName as Match = Regex.Match("input", "pattern", RegexOptions.SingleLine);
or
Dim variableName as Match = Regex.Match("input", "pattern", RegexOptions.Multiline);
This is my current RegEx: \[b\](.*?)\[/b\]
That works perfectly fine, it replaces exactly what I want it to. But, I'm trying to figure out how to make it replace the string between [b][/b] with a bold string, but the actual text stays the same.
Example string: [b]This is an example![/b]
Desired output: This is an example!
I'm using VB.NET and this is what I currently have:
Dim reg As New Regex("\[b\](.*?)\[/b\]")
Dim str As String = String.Empty
For Each m As Match In reg.Matches(MainBox.Text)
str = reg.Replace(MainBox.Text, "test")
Next
Preview.Show()
Preview.RichTextBox1.Text = str
Preview.Size = New Size(Preview.MaximumSize.Width, Preview.MaximumSize.Height)
You need to set the start of the selection, and set the attributes of the text before inserting it.
Preview.RichTextBox1.SelectionStart = Preview.RichTextBox1.Text.Length
Preview.RichTextBox1.SelectionFont = New Font("Tahoma", 12, FontStyle.Bold)
Preview.RichTextBox1.SelectedText = str
Just have a list of words, such as:
gram (g)
kilogram (kg)
pound (lb)
just wondering how I would get the words within the brackets for example get the "g" in "gram (g)" and dim it as a new string.
Possibly using regex?
Thanks.
Use split function ..
strArr = str.Split("(") ' splitting 'gram (g)' returns an array ["gram " , "g)"] index 0 and 1
strArr2 = strArr[1].Split(")") ' splitting 'g)' returns an array ["g " ..]
the string is in
strArr2[0]
Edit
you want getAbbrev and getAbbrev2 to be arrays
try
Dim getAbbrev As String() = Str.Split("(")
Dim getAbbrev2 as String() = getAbbrev[1].Split(")")
To do it without declaring arrays you can do
"gram (g)".Split("(")[1].Split(")")[0]
but that's unreadable
Edit
You have some very trivial errors. I would suggest you strengthen your understanding on objects and declarations first. Then you can look into invoking methods. I rather have you understand it than give it to you. Re-read the book you have or look for a basic tutorial.
Dim unit As String = 'make sure this is the actual string you are getting, not sure where you are supposed to get the string value from => ie grams (g)
Dim getAbbrev As String() = unit.Split("(") 'use unit not Str - Str does not exist
Dim getAbbrev2 As String() = getAbbrev[1].Split(")") 'As no as - case sensitive
for the last line reference getAbbrev2 instead of the unknown abbrev2
Fun with Regular Expressions (I'm really not an expert here, but tested and works)
Imports System.Text.RegularExpressions
.....
Dim charsToTrim() As Char = { "("c, ")"c }
Dim test as String = "gram (g)" + Environment.NewLine +
"kilogram (kg)" + Environment.NewLine +
"pound (lb)"
Dim pattern as String = "\([a-zA-Z0-9]*\)"
Dim r As Regex = new Regex(pattern, RegexOptions.IgnoreCase)
Dim m As Match = r.Match(test)
While(m.Success)
System.Diagnostics.Debug.WriteLine("Match" + "=" + m.Value.ToString())
Dim tempText as String = m.Value.ToString().Trim(charsToTrim)
System.Diagnostics.Debug.WriteLine("String Trimmed" + "=" + tempText)
m = m.NextMatch()
End While
You can split at the space and remove the parens from the second token (by replacing them with an empty string).
A regex is also an option, and is very simple, its pattern is
\w+\s+\((\w+)\)
Which means, a word, then at least one space, then opening parens, then in real regex parens you search for a word, and, eventually a closing paren. The inner parentheses are capturing parentheses, which make it possible to refer to the unit g, kg, lb.