I am writing a simple program of linear search on vscode on macOS.
The code is producing an error called segmentation fault only in vscode.
But the strange thing is that code is working perfectly fine on onlinegdb compiler and Xcode IDE.
I have the default c++ compiler installed on my Mac which came after installing Xcode.
#include<iostream>
using namespace std;
int linearSearch(int arr[], int n, int key){
int i = 0;
for(i = 0; i<n;i++)
{
if(arr[i] == key){
return i;
}
} return -1;
}
int main(){
int n = 0;
int arr[n];
int key = 0;
cout<<"Enter the length of the array"<<endl;
cin>>n;
cout<<"Enter the elements of the array"<<endl;
int i = 0;
for(i = 0; i<n;i++)
{
cin>>arr[i];
}
cout<<"Enter the element to search in array"<<endl;
cin>>key;
cout<<linearSearch(arr, n, key);
}[screenshot of the error in vscode][1]
[1]: https://i.stack.imgur.com/Bo3Nu.png
Segmentation fault isn't a vscode error, its a program error, it indicates that your program is accessing a memory adress that it hasn't reserved, thus the OS kills your program to save the system from wrong or bad memory accesses.
You first initialize n with 0 and then initialize the array arr with n ints. So it makes you an array with 0 ints. If you want to make this work, push the int arr[n] below the cin >> n. You will have to convert it first from a string to a int using stoi()
libraries:
#include <string>
#include <iostream>
code:
//Create the int to store the length of the array
int n = 0;
//A string, beacause cin returns a string
std::string s;
//Get the number
std::cout << "Length of array: ";
std::cin >> s;
//Convert the string to an int
n = stoi(s);
//Create the array
int arr[n];
Related
i am running this code in online compiler showing dumped core error this program finding highest product of two pair.
#include <bits/stdc++.h>
using namespace std;
void maximumproductpair(int arr[],int n){
sort(arr,arr+n);
reverse(arr,arr+n);
int prod;
for(int i=0; i<n; i++){
cout<<arr[i];
}
prod=prod*arr[0];
prod=*arr[1];
cout<<prod;
}
int main()
{
int t,n;
int arr[n];
cin>>t;
cout<<"\n";
cin>>n;
cout<<"\n";
while(t--){
for(int i=0; i<n;i++){
cin>>arr[i];
}
}
maximumproductpair(arr,n);
return 0;
}
in code everything fine then why this error?
Mistake 1
The problem is that your t and n variables are uninitialized. This means both t and n have garbage value. And when you wrote:
int t,n;
int arr[n];//UNDEFINED BEHAVIOR because n has garbage value
You have undefined behavior because n has garbage value.
This is why it is advised that
always initialize built in types in local/block scope.
Mistake 2
Second, note that in C++ the size of an array must be a compile-time constant. So take for example the following code snippets:
int n = 10;
int array[n]; //INCORRECT
The correct way to write the above would be:
const int n = 10;
int array[n]; //CORRECT
Similarly,
int n;
cin >> n;
int array[n]; //INCORRECT becasue n is not a constant expression
Also note that some compilers provide compiler extension that lets you have variable length array. You can read more about it at Why aren't variable-length arrays part of the C++ standard?.
If you want to take the size of the array as input from the user then you should use dynamic sized containers like std::vector :
int n;
cin >>n;
std::vector<int> array(n);// CORRECT, this creates a vector of size n of elements of type int
Also see Why should I not #include <bits/stdc++.h>?.
I am trying to pass a dynamic memory allocated array and its size to a function 'sum' but it is giving error of permissive what should I do?
#include<conio.h>
#include<iostream>
using namespace std;
int sum(int n[], int *m)
{
for(int z=0;z<*m;z++)
{
cout<<"\n the output is = "<<n[z]<<"\n";
}
}
int main()
{
int *n,*m,a; //declaration is done here**strong text**
cout<<"enter the size of array = ";
m=new int;
cin>>*m;
n=new int[*m];
for(int i=0;i<*m;i++)
{
cout<<"\n enter the "<<i+1<<" array = ";
cin>>n[i];
cout<<"\n";
}
/* for(int z=0;z<*m;z++)
{
cout<<"\n the output is = "<<n[z]<<"\n";
}*/
int sum(n,&m);//here "m" is an pointer and I am trying to pass int in a function with an array
return 0;
}
Your code should, probably, look like the following (Linux Ubuntu + gcc):
#include <iostream>
using namespace std;
int sum(int n[], int m)
{
int s=0;
for(int z=0; z<m; z++)
{
cout<<"\n array["<<z<<"]= "<<n[z]<<"\n";
s+=n[z];
}
return s;
}
int main()
{
int *n,m;
cout<<"enter the size of array = ";
cin>>m;
n=new int[m];
for(int i=0; i<m; i++)
{
cout<<"\n enter array["<<i+1<<"] value = ";
cin>>n[i];
cout<<"\n";
}
int s = sum(n, m);
cout<<"s="<<s<<endl;
return 0;
}
There is no use allocating the size of the array m dynamically. It is an ordinary int variable and can be initialized as
cin>>m;
You may also write the sum prototype in the form
int sum(int * n, int m)
It is another way of passing a 1-dimensional array as a function parameter.
Speaking frankly, these questions are the very basics of the language.
You should, probably, read something like
Dynamic memory allocation/dynamic arrays
about dynamic memory allocation and dynamic arrays and
Simple cases of std::cin usage
about the simplest cases of std::cin usage in C++.
This is a syntax of a program that I made of hackerrank to reverse an array. The location of the question is Practice < Data Structures < Arrays < Arrays - DS
the program seems to work fine on an online compiler but is showing error over hackerrank.
can anyone guide me where I went wrong?
#include<iostream>
using namespace std;
int main(){
int n,i;
int arr[n];
cin>>n;
for(int i=0;i<n;i++)
{
cin>>arr[i];
}
for(int i=n-1;i>=0;i--)
{
cout<<arr[i];
}
}
You are creating an array with n elements before you read n, i.e n is having garbage value. Here is correct working code.
#include <iostream>
using namespace std;
int main(){
int n,i;
cout<<"Enter number of elements"<<endl; // Comment it if you don't want debug console outut
cin>>n;
int arr[n];
cout<<"Enter "<<n<<" elements"<<endl; // Comment it if you don't want debug console outut
for(int i=0;i<n;i++)
{
cin>>arr[i];
}
for(int i=n-1;i>=0;i--)
{
cout<<arr[i];
}
}
I changed your solution and it work fine now , i will tell you some notes for your future:
1 - You have to read size of array first before declare array as mentioned in comments by #HolyBlackCat , otherwise it will give garbage value.
2 - this command int arr[n]; won't work on all Compilers and may give you an Error. Is there a solution to declare array without specific size ? Yes , you can use Vector like that vector<int> arr(n);but you have to include library of vector first #include<vector>
3 - In C and C++ programs the main function is of type int and therefore it should return an integer value. The return value of the main function is considered the "Exit Status" of the application. On most operating systems returning 0 is a success status like saying "The program worked fine". So you have to write return 0; in the end of your program.
#include<iostream>
#include<vector> // must include to use Vectors
using namespace std;
int main(){
int n;
cin >> n; // Must read size of array first , otherwise it will give it garbude value
vector<int> arr(n); // instead of int arr[n]
for(int i = 0 ; i < n ; i++)
cin >> arr[i];
for(int i = n-1 ; i >= 0 ; i--)
cout << arr[i] << " ";
cout << endl; // to print new line as mentioned in the problem statement
return 0; // Prefer to use it always
}
Hope that helps you and Good Luck.
The exercise of Hacker Rank needs that you reverse an array of integers, might you have a problem with the variable size array, cause some compilers support this characteristic but others not.
And Hacker Rank do not support some properties in other languages like JS , Hacker Rank do not support prompt() for take an input.
In any case for fix this error you can use vector class.
#include<iostream>
#include<vector>//Include library vector for dynamic size of array
using namespace std;
int main(){
int n;
cin>>n;
vector<int> arr(n);//Declare the vector with a max size n
for(int i=0;i<n;i++){
cin>>arr[i];
}
for(int i = n-1 ;i>=0;i--){
cout<<arr[i]<<" ";
}
return 0;
}
This code has passed al test cases of hackerRank
All the test on hackerRank had passed
What is wrong with my program ?
It works fine on my PC but in IDEone it gives the correct output but shows runtime error. Please help.
#include<bits/stdc++.h>
using namespace std;
struct student
{
int vote;
};
int main()
{
int t;
cin>>t;
while(t--)
{
int count=0;
int n;
cin>>n;
vector <int> a(n);
student s[n];
int k;
cin>>k;
for(int i=1;i<=n;i++)
{
s[i].vote=0;
}
for(int i=1;i<=n;i++)
{
cin>>a[i];
}
int temp=0;
for(int i=1;i<=n;i++)
{
if(a[i] != i)
{
temp=a[i];
s[temp].vote++;
}
}
for(int i=1;i<=n;i++)
{
if(s[i].vote==k)
{
count++;
}
}
printf("%d\n",count);
}
return 0;
}
This is the error shown in IDEone :-
Error in `./prog': free(): invalid next size (fast): 0x085cca10
student s[n];
This declares an array called s. It contains n values. The values are s[0] through s[n-1] (you can count them all on your fingers, if you'd like, using a small number of n, such as 5).
for(int i=1;i<=n;i++)
{
s[i].vote=0;
}
This attempts to initialize values s[1] through s[n]. The only problem is that s[n] doesn't exist. The last value in the array is s[n-1]. This code will corrupt memory on the stack, resulting in undefined behavior.
The same bug also occurs with the a array.
The index values for both vector and array are zero based and goes up to n - 1. So
for(int i = 0; i != n; ++i)
would be better.
Now you write one element too far, which free finds out later when the data after the memory block is invalid.
I want to enter n times values for c and e arrays. The following program doesn't allow me to even enter the value of 'n'. Could you tell me where is the mistake?
#include <iostream>
using namespace std;
int main()
{
int n,c[n],e[n];
cin>>n;
for(int i=0;i<n;i++){
cin>>c[i]>>e[i];
}
return 0;
}
"n" should be defined before using it to fix array size. Also, const int or constant should be used to declare array size not plain int.
In order to use plain datatype, you can initialize array dynamically like
vector<int> a(n); or
int a = new int[n]
int n,c[n],e[n];
This declaration creates arrays c and e on stack with random size, because n as an automatic variable is initialized with random value. Instead you need to dynamically create arrays on heap or use std::vector.
Example:
#include <iostream>
#include <vector>
using namespace std;
int main() {
// your code goes here
int n;
vector<int> v;
std::cin >> n;
v.resize( n);
for( int i = 0; i < n; ++i) {
cin >> v[i];
}
for( int i = 0; i < n; ++i) {
cout << v[i];
}
return 0;
}
http://ideone.com/QhgfNv
In the line of
int n,c[n],e[n];
Computer don't know the exact value of 'n', so it can't alloc memory of array.
The simplest solution is create array with fixed number, and check n after you know the value of n as follows:
int n, c[1024], e[1024];
cin >> n;
if (n > 1024) { /* error */ }
The other way is malloc memory after u know the value of n:
int n;
cin >> n;
int *c = new int[n];
int *e = new int[n];
xxxx
delete [] c;
delete [] e;
You can try something like this:
#include <iostream>
using namespace std;
int main()
{
int temp = 100; /*Random value*/
int c[temp];
int e[temp];
int n;
cin>>n;
for(int i=0;i<n;i++){
cin>>c[i]>>e[i];
}
return 0;
}
Now, I chose temp as 100, but you can do big as your int can store. Now, if n is lower than temp, your for cycle will let you save your values without troubles.