This question already has answers here:
Regex Match all characters between two strings
(16 answers)
RegEx match open tags except XHTML self-contained tags
(35 answers)
Closed 2 years ago.
I would like to mark all strings between 2 strings with the regular expression.
Example:
https://regex101.com/r/Etfpol/1
I want regular expression to mark follow text:
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Thanks
You can use positive lookbehind and positive lookahead to check the tags.
(?<=<Name>Description<\/Name><Value>).*?(?=<\/Value>)
Match results
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If you prefer not to use them, this will work as well, but the full match will include the strings before and after your desired string.
(?:<Name>Description<\/Name><Value>)(.*?)(?:<\/Value>)
Related
This question already has answers here:
JavaScript regex get all matches in a string
(2 answers)
Closed 2 years ago.
I'm trying to build a regular expression that captures anything between square brackets like the following numbers.
[phone]010101[/phone] [phone]434343[/phone]
[phone]3443434[/phone]
so the matches should be 010101, 434343, 3443434
I built cow([\s\S]*?)milk to experiment, and this seems to capture multiple matches and works fine with multiple lines, achieving what I exactly need.
However when I attempted to build the actual regex using this: \[phone\]([\s\S]*?)\[\/phone\] , it would only capture the first single match.
What could be wrong with my expression?
Another approach. This will capture the numbers as you intend.
\](.*)\[
RegexDemo
The regex is correct but global and multi-line flags are missing. In JavaScript, with g (global) and m (multiline) flags added to regex, intended matches can be found.
str=`[phone]010101[/phone] [phone]434343[/phone]
[phone]3443434[/phone]`;
reg = /\[phone\]([\s\S]*?)\[\/phone\]/gm;
[...str.matchAll(reg)].map(x=> x[1]); //["010101", "434343", "3443434"]
This question already has answers here:
Regular expression to get a string between two strings in Javascript
(13 answers)
Closed 3 years ago.
Link Regex101
I am using (FD.*?)FD however I am missing every second expression - see regex. Any ideas?
The trailing "FD" in your regex matches the "FD" in the input that starts the next "item" in the input text, so the entire next "item" is skipped, until it finds another "FD".
In a case like this, instead of specify .* followed by the pattern that starts the next item, you typically want to specify anything not including a pattern of FD.
This question already has answers here:
Regex: match everything but a specific pattern
(6 answers)
Closed 4 years ago.
I am trying to find all strings not ending with the sequence -6X.
What i'm trying to do is compare the value of an xml tag with a sequence.
If it matches then do some stuff.
However I am unable to do so. I want to achieve this without any lookaheads or lookbehinds.
I've tried using .*[^-6X]
However this does not work for strings ending in - or -5 .
I want to ignore strings ending in -6X only and every other pattern should work.
Thanks in advance for your help
This matches Strings NOT ending with -6X:
.*?([^-]..|.[^6].|..[^X])$
https://regex101.com/r/omwkQ3/2
This question already has answers here:
Is it possible to check if two groups are equal?
(2 answers)
Closed 5 years ago.
I'm trying to match iff two capture groups are the same. I could manually check after the match, but I'm wondering if there is a way I can do this in the expression itself.
My expression is (\d+)\/(\d+), so I only want to accept strings where the two numbers are equal. Is there a nice way to check this in the regular expression, or do I have to manually check groups after?
EDIT: This was marked a duplicate but the supposed duplicate question is not related and does not in any way answer my question...
You can use this one in python : \b(\d+)\/+\1\b
Demo
This is the same usecase as checking for doubled words
When editing text, doubled words such as "the the" easily creep in. Using the regex \b(\w+)\s+\1\b in your text editor, you can easily find them. To delete the second word, simply type in \1 as the replacement text and click the Replace button.
Source
I assume you don't have any other capture groups, based on that:
\b(\d+)\/(\1)\b
Regex Demo
This question already has an answer here:
Reference - What does this regex mean?
(1 answer)
Closed 6 years ago.
I have a file where the application is configured to check the following Regex
[\x00-\x1F\x7F&&[^\x0A]&&[^\x0D]]
Can anyone please tell me the meaning of this regex expression exactly what it means. I do know that this regex expression ignored line feed and character feed. I even validated my file on http://regexr.com/ with the above specified regex expression and it shows no match found so not understanding why the regex is getting matched in the application.
FYI: I do not want the regex to match file as it is stopping my processing.
It could be that in Java and Ruby the regex expression && refers to character class intersection, while http://regexr.com/ doesn't support that expression and is trying to match literal & symbols. The regex you posted means match any characters from \x00 to \x1f or \x7f as long as it's not \x0A or \x0D.