XLT 1.0 Comparing nodes to a loop - xslt

Question

I need to copy all nodes and then change one element according to the following conditions.
If all nodes ship are 0, then replace = Rejected
If all node qty are ship, then replace = Accepted
If otherwise, then replace = Changed
No error occurs with 0 values, but if the second option does not work.
Input XML
<?xml version="1.0" encoding="utf-8"?>
<root>
<a>123</a>
<b>231</b>
<c>
<xxx>
<qty>5</qty>
<ship>5</ship>
</xxx>
<xxx>
<qty>8</qty>
<ship>8</ship>
</xxx>
<xxx>
<qty>13</qty>
<ship>13</ship>
</xxx>
<xxx>
<qty>10</qty>
<ship>10</ship>
</xxx>
</c>
</root>
My XSLT
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="/root/a">
<a>
<xsl:choose>
<xsl:when test="not(/root/c/xxx/ship != '0')">Rejected</xsl:when>
<xsl:when test="not(/root/c/xxx/ship != /root/c/xxx/qty)">Accepted</xsl:when>
<xsl:otherwise>Changed</xsl:otherwise>
</xsl:choose>
</a>
</xsl:template>
</xsl:stylesheet>
UPD.
I begged xml, because I didn't think that the result would be through predicates
Now the structure of the input file is like this and I already use predicates
<?xml version="1.0" encoding="utf-8"?>
<root>
<a>123</a>
<b>231</b>
<c>
<xxx>
<yyy>
<what>1</what>
<qty>5</qty>
</yyy>
<yyy>
<what>2</what>
<qty>5</qty>
</yyy>
</xxx>
<xxx>
<yyy>
<what>1</what>
<qty>24</qty>
</yyy>
<yyy>
<what>2</what>
<qty>24</qty>
</yyy>
</xxx>
...
</c>
</root>

Answer 1

I suppose you want <xsl:when test="not(/root/c/xxx[ship != qty])">Accepted</xsl:when>.