How to access array elements in a struct with pointors C++ - c++

Question

I have the following function and the following struct.
void function(TestStruct *array) {
for (int i = 0; i < 3; i++){
array[i].value = 0;
array[i].remove = true;
}
}
struct TestStruct
{
int value;
bool remove;
};
int main(){
TestStruct sampleStruct[3];
sampleStruct[0].value = 1;
sampleStruct[1].value = 2;
sampleStruct[2].value = 3;
sampleStruct[0].value = false;
sampleStruct[1].value = false;
sampleStruct[2].value = false;
function(sampleStruct);
}
However, the values in sampleStruct do not change.
When I was debugging, the function had only access to the first index of the array 0x0025fb64 {Value = 1 remove = false}, but even the first index did not change.
In other words, I'm trying to access the full sampleStruct address to change the values.

Answer 1

Well, for me it works fine. The only thing I changed is .value = false to .remove = false (because this is probably how you wanted to do it). code:
#include <iostream>
using namespace std;
struct TestStruct
{
int value;
bool remove;
};
void function(TestStruct *array) {
for (int i = 0; i < 3; i++){
array[i].value = 0;
array[i].remove = true;
}
}
int main(){
TestStruct sampleStruct[3];
sampleStruct[0].value = 1;
sampleStruct[1].value = 2;
sampleStruct[2].value = 3;
sampleStruct[0].remove = false; // changed to .remove
sampleStruct[1].remove = false; // changed to .remove
sampleStruct[2].remove = false; // changed to .remove
function(sampleStruct);
for (int i = 0; i < 3; i++) // prints "0 1" 3 times
cout << sampleStruct[i].value << ' ' << sampleStruct[i].remove << '\n';
}