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What is wrong with my code? I try to get a line break using both \n and endl but it shows an error.
#include <iostream>
using namespace std;
int main()
{
const int MinutesPerHour = 60;
const float PI = 3.14;
cout << MinutesPerHour;endl;
cout << PI;
return 0;
}
You should place the endl after the output stream operator <<.
Like this:
cout << MinutesPerHour << endl;
Related
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Closed 5 years ago.
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I am a newbie in C++, I started to learn coding in C++ two weeks ago. Why does my code below always give me result 0 when I build and run? Please help
# include <iostream>
# include <string>
using namespace std;
int main ()
{
int input = 1;
cout << "input your number : \n";
cin >> input;
int faktorial = 1;
for(int i=1;i<=input;i++)
{
faktorial = faktorial * i;
}
cout << "factorial value from number " << input << " is " << faktorial << endl;
}
Your code works: https://ideone.com/CYFaxo
I suspect your problem is, you are looking at program exit code. When you don't return any value from main, program exit code is 0 (this is special case, and only non-void function where you may leave the return statement out), which conventionally means success (non-zero exit code usually indicates some kind of error, by convention).
Try to find the program output from your IDE, it should have the correct printout.
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Closed 7 years ago.
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I made a function that will reverse the string, but the output of the reversed string always shifts towards the right by one character.
#include <iostream>
#include <string>
using namespace std;
void reverse(string string1)
{
cout << endl;
for (int i = string1.size(); i >= 0; i--)
{
cout << string1[i];
}
cout << endl;
}
int main()
{
string string1;
getline(cin, string1);
reverse(string1);
system("pause");
return 0;
}
Your first output is of a character that does not exist.
std::string's leaky abstraction means that your first iteration is printing '\0', which apparently looks like a space in your configuration.
Begin at string1.size() - 1.
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Closed 8 years ago.
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I am learning C++ via a book. It told me to type this compile and link it in order for me to see if i can read it. But there are errors when I run this. What is the issue?
#include <iostream>
int main()
{
int x = 8;
int y = 6;
std::cout << std::end1;
std::cout << x - y << " " << x * y << " " << x + y;
std::cout << std::end1; return 0;
}
It should be std::endl; instead of std::end1;
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Closed 8 years ago.
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Whenever I try to run this program it returns an error saying:
no operator "<<" matches these operands
Also note that the program only runs into this problem in the getChoice() function.
#include <iostream>
#include "utilities.h"
using namespace std;
int getChoice(string inChoices[]){
int numOfChoices = sizeof(inChoices) / sizeof(inChoices[0]);
string x = inChoices[0];
string y = inChoices[1];
cout << x << endl << y << endl;
return numOfChoices;
}
int main()
{
string choices[2] = { "Happy Day", "Even Better Day" };
cout << utilities::getChoice(choices) << endl;
cout << endl << sizeof(choices) / sizeof(choices[0]) << endl;
}
You need also to include the string header:
#include <string>
You need to #include <string>
And your calculation of numOfChoices in getChoice() is wrong, since the parameter inChoices is actually a "pointer to string" instead of "array of strings".
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Closed 9 years ago.
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I am trying to implement the following function :
void dump() const
{
size_t it = 0;
std::cout << "[";
while (it < this->_size);
{
std::cout << (this->_arr)[it];
if ((this->_arr)[it + 1])
std::cout << ", ";
it++;
}
std::cout << "]" << std::endl;
}
This appears to cause an infinite loop, I'm guessing it comes from a bad use of std::cout, and std::endl, but I can see how to manage this. Any ideas?
As I have commented, you need to change
while (it < this->_size);
to
while (it < this->_size)
to make it a while-loop with the ability to change its condition in order to avoid infinite loop.