How to extract parameter names and values using regular expressions - regex

Question

I would like to know how to extract values of all this parameters.
My regular expression:
([\w]+)(\s*=\s*)(['|"|\w])(.+)['|"|\w]
Parameter names and values that should match:
name='John Doe'
name=John Doe
organization=Acme Widgets Inc.
server=192.0.2.62
port='143'
file="payroll.dat"
DOS=HIGH,UMB
DEVICE=C:\DOS\HIMEM.SYS
DEVICE=C:\DOS\EMM386.EXE RAM
DEVICEHIGH=C:\DOS\ANSI.SYS
FILES=30
SHELL=C:\DOS\COMMAND.COM C:\DOS /E:512 /P
When i run my expression in regex101.com it only finds the first parameter that matches. In this case being: name='John Doe'
Desired output is name John Doe
I am having extra trouble understanding how to find and extract parameter names and values without parantesis and equals signs.

Answer 1

Try this:
(\w+)\s*=\s*['"]?([^'"\n]+)
The keyword will be in capture group 1 (there's no need for [] around \w).
There's no need for a capture group around the equal sign.
[^"]? allows an optional quote after the equal sign. There's no need to put it in a capture group.
([^'"\n]+) then matches everything that isn't another quote or newline. So it will capture everything until either a quote or the end of the line. This value will be put into group 2.
DEMO

Answer 2

i hope this will useful for you:
/^.*?=.*?$/gm
I test the pattern in: https://regexr.com/
var str = `
name='John Doe'
name=John Doe
organization=Acme Widgets Inc.
server=192.0.2.62
port='143'
file="payroll.dat"
DOS=HIGH,UMB
DEVICE=C:\DOS\HIMEM.SYS
DEVICE=C:\DOS\EMM386.EXE RAM
DEVICEHIGH=C:\DOS\ANSI.SYS
FILES=30
SHELL=C:\DOS\COMMAND.COM C:\DOS /E:512 /P`;
console.log( str.match(/^.*?=.*?$/gm).map(str => str.replace(/("|')/g, '').replace(/=/g, ' ') ) )