All sense in title of query, i try this:
path(r'get_turnover/<str:attributes>/\?product=(?P<product>\w+$)', views.OutputTurnover.as_view(), name='get_turnover')
but it's not work for me.
The query string [wiki] is not part of the path. This is decoded by django and passed through request.GET as a QueryDict [Django-doc] a dictionary-like object.
The path should thus be:
path(
'get_turnover/<str:attributes>/',
views.OutputTurnover.as_view(),
name='get_turnover'
)
and in the view, you can access this with:
class OutputTurnover(View):
def get(request, attributes):
product = self.request.GET.get('product')
# …
Related
I have a logging system, where users can log several symptoms for any given day. Im getting the date as slug in my url, but I need to validate it. Which one is best practice, and why?
make a validator function in the class view and use it there
add a hidden form field, and write a custom DateValidator for it?
You can define a path converter that will parse date objects. You can define a custom pattern with:
# app_name/converters.py
class DateConverter:
regex = '[0-9]{4}-[0-9]{2}-[0-9]{2}'
format = '%Y-%m-%d'
def to_python(self, value):
return datetime.strptime(value, self.format).date()
def to_url(self, value):
return value.strftime(self.format)
Next we can register that path converter [Django-doc] and work with:
from app_name.converters import DateConverter
from django.urls import path, register_converter
register_converter(DateConverter, 'date')
urlpatterns = [
# …
path('some/path/<date:date>/', some_view),
# …
]
This will pass a single date parameter to the view, which is a date object, you thus can work with:
def some_view(request, date):
# …
If you thus visit the path /some/path/2021-10-17, date will be a date(2021, 10, 17) object.
It seems like the original URL querying function has been removed from Django 3.1. Does anyone know how to do it with a new package?
The url.py:
urlpatterns = [
re_path(r'^portfolio/(?P<title>[\w-]+)/$' , BlogApp_View.displayPortfolio, name='displayPortfolio'),
path('portfolio/', BlogApp_View.selectPortfolio, name='selectPortfolio'),]
The view.py
def displayPortfolio(request):
title = request.GET.get('title')
portfolio = Article.objects.filter(articleType__name__contains = "Portfolio", title=title)
print(title)
DICT = {}
return render(request, 'Article/', DICT)
The problem is now if I visit http://127.0.0.1:8000/Blog/portfolio/?title=A_UAV_Positioning_Approach_Using_LoRa/, it will skip the re_path shows in url.py.
Instead, it goes to the path one.
I have tried str:title method but that is actually not what I want. I prefer using the question mark pattern to finish the query.
The part after the questionmark is the querystring [wiki] and is not part of the path. This thus means that regardless what patterns you write, you can not distinguish on this, since the path patterns, regardless whether it is a path or re_path, are never matched against a URL with a query string.
You thus should write a single view, and inspect the request.GET query dict (which is a dictionary-like representation of the query string and see if it contains a value for title.
Your urlpatterns thus look like:
urlpatterns = [
path('portfolio/', BlogApp_View.selectPortfolio, name='selectPortfolio'),
]
and in the view, you can see if it contains a title:
def selectPortfolio(request):
if 'title' in request.GET:
# contains a ?title=…
title = request.GET.get('title')
portfolio = Article.objects.filter(
articleType__name__contains='Portfolio',
title=title
)
data = {'portfolio': portfolio}
return render(request, 'some_template.html', data)
else:
# contains no ?title=…
# …
return …
The URL pattern having issues is:
url(r'^$', business_list, name='business_list_home'),
url(r'^(?P<param>\w+)$', business_list, name='business_list_results'),
My view is:
#render_to('app/business_list.html')
def business_list(request, param=None):
queryset = Business.objects.all()
search_form = SearchForm
print request.GET
if param in request.GET:
param = request.GET.get('param')
if queryset.filter(city__iexact=param).exists():
queryset = queryset.filter(city__iexact=param)
elif queryset.filter(category__iexact=param).exists():
queryset = queryset.filter(category__iexact=param)
print queryset
else:
queryset = None
print queryset
return {'business_list': queryset, 'search_form': search_form}
Essentially, I don't understand why when I go to /Miami I don't have access to it via request.GET['param'] in the view? print request.GET prints <QueryDict: {}>
The reason I want to do this is to have a nice URL scheme for displaying results of businesses for the city or category (and that's why I check if it's a city or category in the view too) in the url. Let me know if there's a better way to accomplish this like
url(r'^$', business_list),
url(r'^(?P<city>\w+)$', business_list),
url(r'^(?P<category>\w+)$', business_list),
url(r'^(?P<category>\w+)/(?P<city>\w+)$', business_list),
Thanks for any help!
business_list is a function that takes a request and a parameter called "param" (should probably give it a better name as to make it a little less generic). In Django, the URL routes can define what values get passed to the parameters of the view functions.
In the situation above, when a user goes to /Miami, Django will try to match the string "Miami" with any of the regular expressions defined in the URL routes. In this case, the matching expression is ^(?P<param>\w+)$. When this match is made, the string Miami is captured into param.
Django will then call business_list(request, param="Miami"). Note that there were no query parameters passed in the URL (e.g., /Miami?color=blue).
The issue in the code you've written above is that you're checking to see not if param exists, but rather that param was passed in the query parameters. Try going to the URL /Miami?param=test and it'll probably work the way that you expected.
The real fix here is to not reference request.GET, because using GET parameters is exactly what you're trying to avoid. So, instead of
if param in request.GET:
param = request.GET.get('param')
if queryset.filter(city__iexact=param).exists():
queryset = queryset.filter(city__iexact=param)
elif queryset.filter(category__iexact=param).exists():
queryset = queryset.filter(category__iexact=param)
print queryset
Just do:
if param:
if queryset.filter(city__iexact=param).exists():
queryset = queryset.filter(city__iexact=param)
elif queryset.filter(category__iexact=param).exists():
queryset = queryset.filter(category__iexact=param)
I'm trying to setup Django Haystack to search based on some pretty urls. Here is my urlpatterns.
urlpatterns += patterns('',
url(r'^search/$', SearchView(),
name='search_all',
),
url(r'^search/(?P<category>\w+)/$', CategorySearchView(
form_class=SearchForm,
),
name='search_category',
),
)
My custom SearchView class looks like this:
class CategorySearchView(SearchView):
def __name__(self):
return "CategorySearchView"
def __call__(self, request, category):
self.category = category
return super(CategorySearchView, self).__call__(request)
def build_form(self, form_kwargs=None):
data = None
kwargs = {
'load_all': self.load_all,
}
if form_kwargs:
kwargs.update(form_kwargs)
if len(self.request.GET):
data = self.request.GET
kwargs['searchqueryset'] = SearchQuerySet().models(self.category)
return self.form_class(data, **kwargs)
I keep getting this error running the Django dev web server if I try and visit /search/Vendor/q=Microsoft
UserWarning: The model u'Vendor' is not registered for search.
warnings.warn('The model %r is not registered for search.' % model)
And this on my page
The model being added to the query must derive from Model.
If I visit /search/q=Microsoft, it works fine. Is there another way to accomplish this?
Thanks for any pointers
-Jay
There are a couple of things going on here. In your __call__ method you're assigning a category based on a string in the URL. In this error:
UserWarning: The model u'Vendor' is not registered for search
Note the unicode string. If you got an error like The model <class 'mymodel.Model'> is not registered for search then you'd know that you haven't properly created an index for that model. However this is a string, not a model! The models method on the SearchQuerySet class requires a class instance, not a string.
The first thing you could do is use that string to look up a model by content type. This is probably not a good idea! Even if you don't have models indexed which you'd like to keep away from prying eyes, you could at least generate some unnecessary errors.
Better to use a lookup in your view to route the query to the correct model index, using conditionals or perhaps a dictionary. In your __call__ method:
self.category = category.lower()
And if you have several models:
my_querysets = {
'model1': SearchQuerySet().models(Model1),
'model2': SearchQuerySet().models(Model2),
'model3': SearchQuerySet().models(Model3),
}
# Default queryset then searches everything
kwargs['searchqueryset'] = my_querysets.get(self.category, SearchQuerySet())
I have a search page that takes a variety of parameters. I want to create a new URL by just altering one parameter in the query. Is there an easy way to do this - something like:
# example request url
http://example.com/search?q=foo&option=bar&option2=baz&change=before
# ideal template code
{% url_with change 'after' %}
# resulting url
http://example.com/search?q=foo&option=bar&option2=baz&change=after
So this would take the request url, alter one query parameter and then return the new url. Similar to what can be achieved in Perl's Catalyst using $c->uri_with({change => 'after'}).
Or is there a better way?
[UPDATED: removed references to pagination]
I did this simple tag which doesn't require any extra libraries:
#register.simple_tag
def url_replace(request, field, value):
dict_ = request.GET.copy()
dict_[field] = value
return dict_.urlencode()
Use as:
<a href="?{% url_replace request 'param' value %}">
It wil add 'param' to your url GET string if it's not there, or replace it with the new value if it's already there.
You also need the RequestContext request instance to be provided to your template from your view. More info here:
http://lincolnloop.com/blog/2008/may/10/getting-requestcontext-your-templates/
So, write a template tag around this:
from urlparse import urlparse, urlunparse
from django.http import QueryDict
def replace_query_param(url, attr, val):
(scheme, netloc, path, params, query, fragment) = urlparse(url)
query_dict = QueryDict(query).copy()
query_dict[attr] = val
query = query_dict.urlencode()
return urlunparse((scheme, netloc, path, params, query, fragment))
For a more comprehensive solution, use Zachary Voase's URLObject 2, which is very nicely done.
Note:
The urlparse module is renamed to urllib.parse in Python 3.
I improved mpaf's solution, to get request directly from tag.
#register.simple_tag(takes_context = True)
def url_replace(context, field, value):
dict_ = context['request'].GET.copy()
dict_[field] = value
return dict_.urlencode()
This worked pretty well for me. Allows you to set any number of parameters in the URL. Works nice for a pager, while keeping the rest of the query string.
from django import template
from urlobject import URLObject
register = template.Library()
#register.simple_tag(takes_context=True)
def url_set_param(context, **kwargs):
url = URLObject(context.request.get_full_path())
path = url.path
query = url.query
for k, v in kwargs.items():
query = query.set_param(k, v)
return '{}?{}'.format(path, query)
Then in the template:
<a href="{% url_set_param page=last %}">
There are a number of template tags for modifying the query string djangosnippets.org:
http://djangosnippets.org/snippets/553/
http://djangosnippets.org/snippets/826/
http://djangosnippets.org/snippets/1243/
I would say those are the most promising looking. One point in all of them is that you must be using django.core.context_processors.request in your TEMPLATE_CONTEXT_PROCESSORS.
You can try https://github.com/dcramer/django-paging
In addition to the snippets mentioned by Mark Lavin, Here's a list of other implementations I could find for a Django template tag which modifies the current HTTP GET query string.
On djangosnippets.org:
#2237 Manipulate URL query strings using context variables using a template tag by JHsaunders
#2332 Querystring Builder - create urls with GET params by jibberia
my favorite: #2413 Yet another query string template tag by atms
#2428 Add GET parameters from current request by naktinis
On PyPI:
django-spurl by Jamie Matthews
django-urltags by Calloway Project/Corey Oordt
the add_query_param filter in django-rest-framework by Tom Christie
On GitHub:
update_querystring by David Gouldin