How to concatenate name of variables in Cpp? - c++

Question

I have class Walls in my program. Inside of class are objects Wall1, Wall2 etc.
I want to do something like this:
class definition:
class Walls {
public:
Walls(){
nPositionX = nMapWidth - 1;
nHoleSize = 1;
nHolePosition = rand()%(nMapHeight - nHoleSize);
count++;
}
static int getCount() {
return count;
}
int getPositionX()
{
return nPositionX;
}
private:
int nPositionX;
int nHolePosition;
int nHoleSize;
static int count;
};
access to object
for (int i = 0; i < Walls::getCount(); i++) {
int nPosx = Wall"i".getPositionX();
}
}
Is that possible in c++?
Ok big thanks for everyone for help. I don't know why I didn't tried it before.

Answer 1

You can use an array or std::vector for that, eg:
std::array<Wall, MAX_WALLS> m_walls;
or
std::vector<Wall> m_walls;
...
// initialize m_walls[0], m_walls[1], etc as needed...
...
for (size_t i = 0; i < m_walls.size(); i++) {
int nPosx = m_walls[i].getPositionX();
...
}
Or, you can use a std::map, eg:
std::map<std::string, Wall> m_walls;
...
// initialize m_walls["Wall1"], m_walls["Wall2"], etc as needed...
...
for (int i = 1; i <= getCount(); i++) {
int nPosx = m_walls["Wall" + std::to_string(i)].getPositionX();
...
}

Answer 2

The code is not executed until you execute your program, but in the executable there are no variable names anymore. Hence, no.
You can use an array or vector:
struct Wall { int get_position() const { return 42; } };
using Walls = std::vector<Wall>;
Walls walls;
for (const auto& wall : walls) {
int nPosx = wall.get_position();
}
Or if you really want to map names to objects, use a std::map:
std::map<std::string,Wall> named_walls;
named_walls["stone wall"] = Wall();