I know this is possible with other sdks (boto, js sdk) but I have no idea how to do it with Powershell (can't find a -Range param).
How do I specify a range when getting an S3 Object with AWS tools?
I have a bucket containing 60k files and some of them (zip files) are corrupted and I know the missing byte is always at the end. So I'd like to check the zip signature in all those files without downloading it in its entirety.
Is it possible with PS? Or should I just use the JS SDK?
Related
So as the title says, I have a couple of files in the VOB/BUP format that I need to convert first to .mp4 (I also have .IFO files and I don't know what that is) and then check for a public url to display them (S3 Bucket) But I don't know which one is the correct service.
I have read about MediaConvert, but I'm not quite sure this is the right service for my need.
Thanks in advance for any tips.
VOB/BUP/IFO files are typically found on a DVD where:
IFO files are an index and hold information about the disc contents
BUP files are backup versions of the IFO files
VOB files hold the video and audio content
AWS Elemental MediaConvert does not support these as an input (1).
To convert these, you can consider leveraging a different tool that is capable, for example FFMPeg.
Here is an example batch script you can reference that does this:
https://gist.github.com/andreasbotsikas/8bad3df5309dd0383f2e2c450b22481c
You can also potentially have this workflow run on AWS by using AWS Lambda to run FFMPeg (2).
References:
Supported input codecs and containers : https://docs.aws.amazon.com/mediaconvert/latest/ug/reference-codecs-containers-input.html
Processing user-generated content using AWS Lambda and FFmpeg : https://aws.amazon.com/blogs/media/processing-user-generated-content-using-aws-lambda-and-ffmpeg/
I Have a bucket with 3 million objects. I Even don't know how many folders are there in my S3 bucket and even don't know the names of folders in my bucket.I want to show only list of folders of AWS s3. Is there any way to get list of all folders ?
I would use AWS CLI for this. To get started - have a look here.
Then it is a matter of almost standard linux commands (ls):
aws s3 ls s3://<bucket_name>/path/to/search/folder/ --recursive | grep '/$' > folders.txt
where:
grep command just reads what aws s3 ls command has returned and searches for entries with ending /.
ending > folders.txt saves output to a file.
Note: grep (if I'm not wrong) is unix only utility command. But I believe, you can achieve this on windows as well.
Note 2: depending on the number of files there this operation might (will) take a while.
Note 3: usually in systems like AWS S3, term folder is there only for user to maintain visual similarity with standard file systems however inside it does treat it as a part of a key. You can see in your (web) console when you filter by "prefix".
Amazon S3 buckets with large quantities of objects are very difficult to use. The API calls that list bucket contents are limited to returning 1000 objects per API call. While it is possible to request 'folders' (by using Delimiter='/' and looking at CommonPrefixes), this would take repeated calls to obtain the hierarchy.
Instead, I would recommend using Amazon S3 Inventory, which can provide a daily or weekly CSV file listing all objects. You can then play with that CSV file from code (or possibly Excel? Might be too big?) to obtain your desired listings.
Just be aware that doing anything on that bucket will not be fast.
I have an Amazon S3 server filled with multiple buckets, each bucket containing multiple subfolders. There are easily 50,000 files in total. I need to generate an excel sheet that contains the path/url of each file in each bucket.
For eg, If I have a bucket called b1, and it has a file called f1.txt, I want to be able to export the path of f1 as b1/f1.txt.
This needs to be done for every one of the 50,000 files.
I have tried using S3 browsers like Expandrive and Cyberduck, however they require you to select each and every file to copy their urls.
I also tried exploring the boto3 library in python, however I did not come across any in built functions to get the file urls.
I am looking for any tool I can use, or even a script I can execute to get all the urls. Thanks.
Do you have access to the aws cli? aws s3 ls --recursive {bucket} will list all nested files in a bucket.
Eg this bash command will list all buckets, then recursively print all files in each bucket:
aws s3 ls | while read x y bucket; do aws s3 ls --recursive $bucket | while read x y z path; do echo $path; done; done
(the 'read's are just to strip off uninteresting columns).
nb I'm using v1 CLI.
What you should do is have a look again at boto3 documentation as it is what you are looking for. It is fairly simple to do what you are asking but may take you a bit of reading if you are new to it. Since there is multiple steps involved I will try to steer you in the right direction.
In boto3 for S3 the method you are looking for is list_objects_v2(). This will give you the 'Key' or object path of every object. You will notice that it will return the entire json blob for each object. Since you only are interested in the Key, you can target this just the same way you would access Key/Values in a dict. E.g. list_objects_v2()['Contents'][0]['Key'] should return only object path of the very first object.
If you've got that working the next step is to try to loop and get all values. You can either use a for loop to do this or there is an awesome python package I regularly use called jmespath - https://jmespath.org/
Here is how you can retrieve all object paths up to 1000 objects in one line.
import jmespath
bucket_name='im-a-bucket'
s3_client = boto3.client('s3')
bucket_object_paths = jmespath.search('Contents[*].Key', s3_client.list_objects_v2(Bucket=bucket_name))
Now since your buckets may have more than 1000 objects, you will need to use the paginator to do this. Have a look at this to understand it.
How to get more than 1000 objects from S3 by using list_objects_v2?
Basically the way it works is only 1000 objects can be returned. To overcome this we use a paginator which allows you to return the entire result and treats the limit of 1000 as a pagination so you just need to also use it within a for loop to get all the results you are looking for.
Once you get this working for one bucket, store the result in a variable which will be of type list and repeat for the rest of the buckets. Once you have all this data you could easily just copy paste it into an excel sheet or use python to do it. (Haven't tested the code snippets but they should work).
Amazon s3 inventory can help you with this use case.
Do evaluate that option. refer: https://docs.aws.amazon.com/AmazonS3/latest/userguide/storage-inventory.html
I have to compare two files in aws s3 bucket and generate a new file with only the difference.
I have tried to do using Java, NodeJs and Python, but i couldn't find way to do that.For example we have some libraries in nodejs and python, but it requires input as 'path', but when you retrieve from s3 bucket its coming in different format.
Your AWS Lambda function could:
Download the two files to /tmp/
Use the difflib — Helpers for computing deltas module to find differences
Save the results to a file in /tmp/
Upload the results file to Amazon S3
Delete temporary files that were generated (in case the container is reused, since there is a 500MB limit in /tmp/)
The question is using Lambda function is it possible to look through an S3 bucket with User folder's for a specific file name (Ex: Test1.txt and Text2.txt) Inside the file is just random number. Then basically write back a text file into the grabbed file respected folder basically saying "Test1.txt and Test2.txt has been touched.". If possible in python.
Yes! Use Amazon's AWS SDK. Here's an example for downloading a file from S3. The API for listing files and uploading files is pretty similar.