How to initialize structure to zero everytime in while loop? - c++

Question

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
#define max 200005
struct st{
ll index,freq,val;
}s[max];;
int main(){
ll t;
cin>>t;
while(t--){
ll n;
cin>>n;
ll counter[max]={0};
for(ll i=1;i<=n;i++){
ll x;
cin>>x;
s[x].val=x;
s[x].index=i;
s[x].freq++;
cout<<s[x].freq<<endl;
}
}
return 0;
}
In this code, how I will initialize struct to zero in every while loop. I have tried memset() but It is showing error. Also I created struct object in main function. But the program crashes. Please give me hints to solve the problem.

Answer 1

Try this instead, its more structured, usually less error prone.
std::fill(std::begin(s), std::end(s), st({0,0,0}));
I might even be converted to memset by the compiler.

Answer 2

Surely there will be a better solution than this but you can add this snippet at the beginning of the while loop:
for(int j=0; j<max; j++){
s[j].val=0;
s[j].index=0;
s[j].freq=0;
}
You can also consider the idea of redeclaring the struct array every time in the loop, just like this:
#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
#define max 200005
struct st{
ll index,freq,val;
};
int main(){
ll t;
cin>>t;
while(t--){
st s[max];
ll n;
cin>>n;
ll counter[max]={0};
for(ll i=1;i<=n;i++){
ll x;
cin>>x;
s[x].val=x;
s[x].index=i;
s[x].freq++;
cout<<s[x].freq<<endl;
}
}
return 0;
}

Answer 3

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
#define max 200005
struct st{
ll index,freq,val;
};
int main(){
ll t;
cin>>t;
while(t--){
st s[max]={0};
ll n;
cin>>n;
ll counter[max]={0};
for(ll i=1;i<=n;i++){
ll x;
cin>>x;
s[x].val=x;
s[x].index=i;
s[x].freq++;
cout<<s[x].freq<<endl;
}
}
return 0;
}
I did this.
The problem is solved. I used dev c++ ide, that's why the code was doing problem. Thanks all