Stop infinite loop in self-referencing models - django

I am writing a little utility which allows me to populate data models with a number of records.
I used python faker to set the values for each field based on their field-type.
What I do next, is that I use model._meta.get_fields to extract all the fields, remove all Rel types, and then populate non-relational fields with the correct values. For relational fields (where .re_relation = True) I follow the relation to the related model, then do the same for that model as well until I reach a model where there is no more relations to other models. Then create instances for each model.
Basically a recursive process.
My problem is with self-referencing models which cause an infinite loop. I thought of setting these instances to null but what about instances where null is set to False?
Is there any clean way to handle situations like this? I couldn't find anything on the net or stackoverflow.
ps: the code is pretty long so I didn't post anything. But I can if it's necessary.

Often when there's the possibility of an infinite loop, you can prevent that by setting a counter which if is reached, breaks out of the loop.
In your case, you can explicitly check if the relation references the same model and then, prevent it from following the relation.
Moreover, a model that is referencing itself, should allow for the relationship to be null.

Related

What is the most Django-appropriate way to combine multiple database columns into one model field?

I have several times come across a want to have a Django model field that comprises multiple database columns, and am wondering what the most Django way to do it would be.
Three use cases come specifically to mind.
I want to provide a field that wraps another field, keeping record of whether the wrapped field has been set or not. A use case for this particular field would be for dynamic configuration. A new configuration value is introduced, and a view marks itself as dependent upon a configuration value, redirecting if the value isn't set. Storing whether it's been set yet or not allows for easy indefinite caching of the state. This also lets the configuration value itself be not-nullable, and the application can ignore any value it might have when unset.
I want to provide a money field that combines a decimal (or integer) value, and a currency.
I want to provide a file field with a link to some manner of access rule to determine whether the request should include it/a request for it should succeed.
For each of the use cases, there exists a workaround, that in each case seems less elegant.
Define the configuration fields as nullable. This is undesirable for a few reasons: it removes the validity of NULL as a value for the configuration itself, so tristates and other use valid cases for NULL have to become a pair of fields or a different data type, or an edge case; null=True on the fields allows them to be set back to None in modelforms and the admin without writing a custom FormField for them every time; and every nullable column in a database is arguably bad design.
Define the field as a subclass of DecimalField with an argument accepting a string, and use that to contribute another field to the model. (This is what django-money does). Again, this is undesirable: fields are appearing "as if by magic" on the model; and configuring the currency field becomes not obvious.
Define the combined file+rule field instead as an entire model, and one-to-one to it from the model where you want to have the field. This is a solution to all use cases, but again comes with downsides: there's an extra JOIN required for every instance of the field - one can imagine a User with profile_picture, cv, passport, private_key etc.; there's an implicit requirement to .select_related(*fields) on every query that would ever want to access the fields; and the layout of the related model is going to have cold data interleaved with hot data all over the place given that it's reused everywhere.
In addition to solution 3., there's also the option to define a mixin factory that produces the multiple fields with matching names and whatever desired properties and methods. Again this isn't perfect because the user ends up with fields being defined in the model body, but also above that in the inheritance list.
I think the main reason this keeps sending me in circles is because custom Django model fields are always defined in terms of a single base field, because it's done by inheritance.
What is the accepted way to achieve this end?

unique=True gives already exist! Even if interchanging the values of two objects

To display objects (members) in particular order, I have made a field, order:
order = models.IntegerField(unique=True,null=True,blank=True)
so that I can do an .order_by('order') to get the required order.
In Django Admin, the table has only two objects with order 0,1. If I want to interchange it by 1,0 I get an error:
About us with this Order already exists
For ease of using Django admin, is there a better method to achieve the above?
You can remove unique=True and add a custom action to reorder objects. In this form, Django admin applies each object in a separate transaction and it causes this error. You may override the update function of your admin class and do all changes in a bulk-update transaction like this. But I don't recommend it. Because you may make a mistake in the future and want to edit other fields and this line makes a bug.

Detect duplicate inserts when adding many-to-many relation

Let's assume there are two models, A and B:
class A(models.Model):
name = models.CharField(max_length=100)
class B(models.Model):
children = models.ManyToManyField(A)
I'm using b.children.add() method to add instance of A to b:
a = A.objects.get(pk=SOMETHING)
b.children.add(a)
As far as I know, Django by default doesn't allow duplicate many-to-many relationship. So I cannot add same instance of A more than once.
But the problem is here, I fetch instances of A with another query, then loop around them and add them one by one. How can I detect a duplicate relation? Does add() method return something useful?
A look at the source code reveals that Django first checks to see if there are any entries that already exist in the database, and then only adds the new ones. It doesn't return any information to the caller, though.
It's not clear if you actually need to detect duplicates, or if you just want to make sure that they're not being added to the database? If it's the latter then everything's fine. If it's the former, there's no way around hitting the database. If you're really concerned about performance you could always perform the check and update the through table yourself (i.e. re-implement add()).

How to modify a queryset and save it as new objects?

I need to query for a set of objects for a particular Model, change a single attribute/column ("account"), and then save the entire queryset's objects as new objects/rows. In other words, I want to duplicate the objects, with a single attribute ("account") changed on the duplicates. I'm basically creating a new account and then going through each model and copying a previous account's objects to the new account, so I'll be doing this repeatedly, with different models, probably using django shell. How should I approach this? Can it be done at the queryset level or do I need to loop through all the objects?
i.e.,
MyModel.objects.filter(account="acct_1")
# Now I need to set account = "acct_2" for the entire queryset,
# and save as new rows in the database
From the docs:
If the object’s primary key attribute is not set, or if it’s set but a
record doesn’t exist, Django executes an INSERT.
So if you set the id or pk to None it should work, but I've seen conflicting responses to this solution on SO: Duplicating model instances and their related objects in Django / Algorithm for recusrively duplicating an object
This solution should work (thanks #JoshSmeaton for the fix):
models = MyModel.objects.filter(account="acct_1")
for model in models:
model.id = None
model.account = "acct_2"
model.save()
I think in my case, I have a OneToOneField on the model that I'm testing on, so it makes sense that my test wouldn't work with this basic solution. But, I believe it should work, so long as you take care of OneToOneField's.

Creating OneToOneField with base model

Sometimes in course of time model becomes too huge. There is a desire to split it on a several models and connect them with OneToOneField. Fields that uses most often, kept in primary model, other fields moves into other models.
However this approach becomes a headache when creating new instance of model. When you can initialize one model with one line:
MyModel.objects.create(foo=1, bar=2)
you needs at least two lines to initialize two models:
instance = MyModel.objects.create(foo=1, bar=2)
MyRelatedModel.objects.create(mymodel=instance, hello=3, world=4)
Is there a way to simply create two models in one line, or i should write my own auxiliary function for such problems?
I think, You should not split your models with onetooneField because of following reasons
As you said there will be some extra code to manage them.
Every time you query them you will have to make two queries instead of two.
Please don't forget that django models has two functions. The keep data related methods and they keep data model of your application. Some bussiness models have tables that have hundreds of fields. This is completely normal. If you really want to split them. you might want to check out abstract base classes. those are base classes for your model that does not have a seperate tables for themselves https://docs.djangoproject.com/en/dev/topics/db/models/#abstract-base-classes
But if you insist on going with oneToOne field you can wrap object creation code in one of the model's method like
MyMode.create(attr_for_model_A=1, attr_for_model_B=2)
Or you can overwrite default manager's create method to create two method instead of one
https://docs.djangoproject.com/en/dev/topics/db/managers/#modifying-initial-manager-querysets
In my opinion, non-of those will worth having small model code.