How to get data from model objects in django - django

Question

I am using Tweepy to post a tweet from Django admin. How can I retrieve "title" and "image" from the model object as shown in the picture, whenever I click on the tweet button it should post a tweet on my Twitter account with title as text and image.
Example: Suppose I have 4 model objects and each object has a title and an image, I want to get the title and image of only that object which I want to post on Twitter.
One thing I can do is pass a primary key or id of that particular model object
but I don't know how to pass it in my template below.
Django Admin Form page
#template
{% extends 'admin/change_form.html' %}
{% load i18n %}
{% block content %}
{{ block.super }}
<form action="{% url 'post_tweet' %}" method="POST">
{% csrf_token %}
<input type="submit" value="Tweet" name="add_tweet">
</form>
{% endblock %}
#urls.py
urlpatterns = [
path('', views.Home.as_view(), name="home"),
path('$', views.tweet, name="post_tweet"),
]
#models.py
class Movie(models.Model):
GENRE = (
('Action', 'Action'),('Adventure', 'Adventure'),('Comedy', 'Comedy'),
('Crime', 'Crime'),('Drama', 'Drama'),('Fantasy', 'Fantasy'),
('Horror', 'Horror'),('Mystery', 'Mystery'),('Science Fiction', 'Science Fiction'),
('Superhero', 'Superhero'),('Thriller', 'Thriller'),('War','War'),('Others','Others')
)
image = models.ImageField(upload_to="images/",blank=True, default="default-image.png",null=True)
title = models.CharField(max_length=50, unique=True)
slug = models.SlugField(max_length=100, allow_unicode=True, unique=True, default='',blank=True)
genre = models.CharField(max_length=30, choices=GENRE)
description = models.TextField(max_length=500, blank=True)
def __str__(self):
return self.title
def save(self, *args, **kwargs):
self.slug = slugify(self.title)
super().save(*args,**kwargs)
class Meta:
ordering = ["-title"]
# views.py
def tweet(request):
if request.method == "POST":
twitter_auth_keys = {
"consumer_key" : "XXX",
"consumer_secret" : "XXX",
"access_token" : "XXX",
"access_token_secret" : "XXX"
}
auth = tweepy.OAuthHandler(
twitter_auth_keys['consumer_key'],
twitter_auth_keys['consumer_secret']
)
auth.set_access_token(
twitter_auth_keys['access_token'],
twitter_auth_keys['access_token_secret']
)
api = tweepy.API(auth)
`Do something here`
tweet = "New"
post_result = api.update_status(status=tweet)
return HttpResponseRedirect(request.META.get('HTTP_REFERER'))

Answer 1

You can print the object_id value in your template, that value is passed by default by the change_view method, you can always override this method if you want to pass extra data to your change_view template too: https://docs.djangoproject.com/en/3.1/ref/contrib/admin/#django.contrib.admin.ModelAdmin.change_view
So one way to do what you want to do is this, you can print the object_id in a hidden input so the value will be passed to your view by the form submit:
{% extends "admin/change_form.html" %}
{% load i18n admin_urls %}
{% block content %}
{{ block.super }}
<form action="{% url 'post_tweet' %}" method="POST">
{% csrf_token %}
<input type="hidden" name="movie_id" value="{{ object_id }}">
<input type="submit" value="Tweet" name="add_tweet">
</form>
{% endblock %}
Now you can get the instance of the object and get the title and the image of a movie in your tweet view by searching by its id.