How can I use egrep to output a range of numbers? [duplicate] - regex

My input number is an int. But the input number must be in a range from -2055 to 2055 and I want to check this by using regular expression.
So is there anyway to write a regular expression to check whether a number is in (-2055, 2055) or not ?
It is easier to use if statement to check whether the number is in range or not. But I'm writing an interpreter so I should use regex to check the input number

Using regular expressions to validate a numeric range
To be clear: When a simple if statement will suffice
if(num < -2055 || num > 2055) {
throw new IllegalArgumentException("num (" + num + ") must be between -2055 and 2055");
}
using regular expressions for validating numeric ranges is not recommended.
In addition, since regular expressions analyze strings, numbers must first be translated to a string before they can be tested. An exception is when the number happens to already be a string, such as when getting user input from the console.
(To ensure the string is a number to begin with, you could use org.apache.commons.lang3.math.NumberUtils#isNumber(s))
Despite this, figuring out how to validate number ranges with regular expressions is interesting and instructive.
(The links in this answer come from the Stack Overflow Regular Expressions FAQ.)
A one number range
Rule: A number must be exactly 15.
The simplest range there is. A regex to match this is
\b15\b
Word boundaries are necessary to avoid matching the 15 inside of 8215242.
A two number range
The rule: The number must be between 15 and 16. Here are three possible regexes:
\b(15|16)\b
\b1(5|6)\b
\b1[5-6]\b
(The groups are required for the "or"-ing, but they could be non-capturing: \b(?:15|16)\b)
A number range "mirrored" around zero
The rule: The number must be between -12 and 12.
Here is a regex for 0 through 12, positive-only:
\b(\d|1[0-2])\b
Free-spaced:
\b( //The beginning of a word (or number), followed by either
\d // Any digit 0 through 9
| //Or
1[0-2] // A 1 followed by any digit between 0 and 2.
)\b //The end of a word
Making this work for both negative and positive is as simple as adding an optional dash at the start:
-?\b(\d|1[0-2])\b
(This assumes no inappropriate characters precede the dash.)
To forbid negative numbers, a negative lookbehind is necessary:
(?<!-)\b(\d|1[0-2])\b
Leaving the lookbehind out would cause the 11 in -11 to match. (The first example in this post should have this added.)
Note: \d versus [0-9]
In order to be compatible with all regex flavors, all \d-s should be changed to [0-9]. For example, .NET considers non ASCII numbers, such as those in different languages, as legal values for \d. Except for in the last example, for brevity, it's left as \d.
(With thanks to #TimPietzcker)
Three digits, with all but the first digit equal to zero
Rule: Must be between 0 and 400.
A possible regex:
(?<!-)\b([1-3]?\d{1,2}|400)\b
Free spaced:
(?<!-) //Something not preceded by a dash
\b( //Word-start, followed by either
[1-3]? // No digit, or the digit 1, 2, or 3
\d{1,2} // Followed by one or two digits (between 0 and 9)
| //Or
400 // The number 400
)\b //Word-end
Another possibility that should never be used:
\b(0|1|2|3|4|5|6|7|8|9|10|11|12|13|14|15|16|17|18|19|20|21|22|23|24|25|26|27|28|29|30|31|32|33|34|35|36|37|38|39|40|41|42|43|44|45|46|47|48|49|50|51|52|53|54|55|56|57|58|59|60|61|62|63|64|65|66|67|68|69|70|71|72|73|74|75|76|77|78|79|80|81|82|83|84|85|86|87|88|89|90|91|92|93|94|95|96|97|98|99|100|101|102|103|104|105|106|107|108|109|110|111|112|113|114|115|116|117|118|119|120|121|122|123|124|125|126|127|128|129|130|131|132|133|134|135|136|137|138|139|140|141|142|143|144|145|146|147|148|149|150|151|152|153|154|155|156|157|158|159|160|161|162|163|164|165|166|167|168|169|170|171|172|173|174|175|176|177|178|179|180|181|182|183|184|185|186|187|188|189|190|191|192|193|194|195|196|197|198|199|200|201|202|203|204|205|206|207|208|209|210|211|212|213|214|215|216|217|218|219|220|221|222|223|224|225|226|227|228|229|230|231|232|233|234|235|236|237|238|239|240|241|242|243|244|245|246|247|248|249|250|251|252|253|254|255|256|257|258|259|260|261|262|263|264|265|266|267|268|269|270|271|272|273|274|275|276|277|278|279|280|281|282|283|284|285|286|287|288|289|290|291|292|293|294|295|296|297|298|299|300|301|302|303|304|305|306|307|308|309|310|311|312|313|314|315|316|317|318|319|320|321|322|323|324|325|326|327|328|329|330|331|332|333|334|335|336|337|338|339|340|341|342|343|344|345|346|347|348|349|350|351|352|353|354|355|356|357|358|359|360|361|362|363|364|365|366|367|368|369|370|371|372|373|374|375|376|377|378|379|380|381|382|383|384|385|386|387|388|389|390|391|392|393|394|395|396|397|398|399|400)\b
Final example: Four digits, mirrored around zero, that does not end with zeros.
Rule: Must be between -2055 and 2055
This is from a question on stackoverflow.
Regex:
(-?\b(?:20(?:5[0-5]|[0-4][0-9])|1[0-9]{3}|[1-9][0-9]{0,2}|(?<!-)0+))\b
Debuggex Demo
Free-spaced:
( //Capture group for the entire number
-?\b //Optional dash, followed by a word (number) boundary
(?:20 //Followed by "20", which is followed by one of
(?:5[0-5] //50 through 55
| //or
[0-4][0-9]) //00 through 49
| //or
1[0-9]{3} //a one followed by any three digits
| //or
[1-9][0-9]{0,2} //1-9 followed by 0 through 2 of any digit
| //or
(?<!-)0+ //one-or-more zeros *not* preceded by a dash
) //end "or" non-capture group
)\b //End number capture group, followed by a word-bound
(With thanks to PlasmaPower and Casimir et Hippolyte for the debugging assistance.)
Final note
Depending on what you are capturing, it is likely that all sub-groups should be made into non-capture groups. For example, this:
(-?\b(?:20(?:5[0-5]|[0-4][0-9])|1?[0-9]{1,3})\b)
Instead of this:
-?\b(20(5[0-5]|[0-4][0-9])|1?[0-9]{1,3})\b
Example Java implementation
import java.util.Scanner;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
import org.apache.commons.lang.math.NumberUtils;
/**
<P>Confirm a user-input number is a valid number by reading a string an testing it is numeric before converting it to an it--this loops until a valid number is provided.</P>
<P>{#code java UserInputNumInRangeWRegex}</P>
**/
public class UserInputNumInRangeWRegex {
public static final void main(String[] ignored) {
int num = -1;
boolean isNum = false;
int iRangeMax = 2055;
//"": Dummy string, to reuse matcher
Matcher mtchrNumNegThrPos = Pattern.compile("(-?\\b(?:20(?:5[0-5]|[0-4][0-9])|1[0-9]{3}|[1-9][0-9]{0,2}|(?<!-)0+))\\b").matcher("");
do {
System.out.print("Enter a number between -" + iRangeMax + " and " + iRangeMax + ": ");
String strInput = (new Scanner(System.in)).next();
if(!NumberUtils.isNumber(strInput)) {
System.out.println("Not a number. Try again.");
} else if(!mtchrNumNegThrPos.reset(strInput).matches()) {
System.out.println("Not in range. Try again.");
} else {
//Safe to convert
num = Integer.parseInt(strInput);
isNum = true;
}
} while(!isNum);
System.out.println("Number: " + num);
}
}
Output
[C:\java_code\]java UserInputNumInRangeWRegex
Enter a number between -2055 and 2055: tuhet
Not a number. Try again.
Enter a number between -2055 and 2055: 283837483
Not in range. Try again.
Enter a number between -2055 and 2055: -200000
Not in range. Try again.
Enter a number between -2055 and 2055: -300
Number: -300
Original answer to this stackoverflow question
This is a serious answer that fits your specifications. It is similar to #PlasmaPower's answer.
(-?\b(?:20(?:5[0-5]|[0-4][0-9])|1[0-9]{3}|[1-9][0-9]{0,2}|(?<!-)0+))\b
Debuggex Demo

Don't ever use it, but this works. :)
\b(-2055|-2054|-2053|-2052|-2051|-2050|-2049|-2048|-2047|-2046|-2045|-2044|-2043|-2042|-2041|-2040|-2039|-2038|-2037|-2036|-2035|-2034|-2033|-2032|-2031|-2030|-2029|-2028|-2027|-2026|-2025|-2024|-2023|-2022|-2021|-2020|-2019|-2018|-2017|-2016|-2015|-2014|-2013|-2012|-2011|-2010|-2009|-2008|-2007|-2006|-2005|-2004|-2003|-2002|-2001|-2000|-1999|-1998|-1997|-1996|-1995|-1994|-1993|-1992|-1991|-1990|-1989|-1988|-1987|-1986|-1985|-1984|-1983|-1982|-1981|-1980|-1979|-1978|-1977|-1976|-1975|-1974|-1973|-1972|-1971|-1970|-1969|-1968|-1967|-1966|-1965|-1964|-1963|-1962|-1961|-1960|-1959|-1958|-1957|-1956|-1955|-1954|-1953|-1952|-1951|-1950|-1949|-1948|-1947|-1946|-1945|-1944|-1943|-1942|-1941|-1940|-1939|-1938|-1937|-1936|-1935|-1934|-1933|-1932|-1931|-1930|-1929|-1928|-1927|-1926|-1925|-1924|-1923|-1922|-1921|-1920|-1919|-1918|-1917|-1916|-1915|-1914|-1913|-1912|-1911|-1910|-1909|-1908|-1907|-1906|-1905|-1904|-1903|-1902|-1901|-1900|-1899|-1898|-1897|-1896|-1895|-1894|-1893|-1892|-1891|-1890|-1889|-1888|-1887|-1886|-1885|-1884|-1883|-1882|-1881|-1880|-1879|-1878|-1877|-1876|-1875|-1874|-1873|-1872|-1871|-1870|-1869|-1868|-1867|-1866|-1865|-1864|-1863|-1862|-1861|-1860|-1859|-1858|-1857|-1856|-1855|-1854|-1853|-1852|-1851|-1850|-1849|-1848|-1847|-1846|-1845|-1844|-1843|-1842|-1841|-1840|-1839|-1838|-1837|-1836|-1835|-1834|-1833|-1832|-1831|-1830|-1829|-1828|-1827|-1826|-1825|-1824|-1823|-1822|-1821|-1820|-1819|-1818|-1817|-1816|-1815|-1814|-1813|-1812|-1811|-1810|-1809|-1808|-1807|-1806|-1805|-1804|-1803|-1802|-1801|-1800|-1799|-1798|-1797|-1796|-1795|-1794|-1793|-1792|-1791|-1790|-1789|-1788|-1787|-1786|-1785|-1784|-1783|-1782|-1781|-1780|-1779|-1778|-1777|-1776|-1775|-1774|-1773|-1772|-1771|-1770|-1769|-1768|-1767|-1766|-1765|-1764|-1763|-1762|-1761|-1760|-1759|-1758|-1757|-1756|-1755|-1754|-1753|-1752|-1751|-1750|-1749|-1748|-1747|-1746|-1745|-1744|-1743|-1742|-1741|-1740|-1739|-1738|-1737|-1736|-1735|-1734|-1733|-1732|-1731|-1730|-1729|-1728|-1727|-1726|-1725|-1724|-1723|-1722|-1721|-1720|-1719|-1718|-1717|-1716|-1715|-1714|-1713|-1712|-1711|-1710|-1709|-1708|-1707|-1706|-1705|-1704|-1703|-1702|-1701|-1700|-1699|-1698|-1697|-1696|-1695|-1694|-1693|-1692|-1691|-1690|-1689|-1688|-1687|-1686|-1685|-1684|-1683|-1682|-1681|-1680|-1679|-1678|-1677|-1676|-1675|-1674|-1673|-1672|-1671|-1670|-1669|-1668|-1667|-1666|-1665|-1664|-1663|-1662|-1661|-1660|-1659|-1658|-1657|-1656|-1655|-1654|-1653|-1652|-1651|-1650|-1649|-1648|-1647|-1646|-1645|-1644|-1643|-1642|-1641|-1640|-1639|-1638|-1637|-1636|-1635|-1634|-1633|-1632|-1631|-1630|-1629|-1628|-1627|-1626|-1625|-1624|-1623|-1622|-1621|-1620|-1619|-1618|-1617|-1616|-1615|-1614|-1613|-1612|-1611|-1610|-1609|-1608|-1607|-1606|-1605|-1604|-1603|-1602|-1601|-1600|-1599|-1598|-1597|-1596|-1595|-1594|-1593|-1592|-1591|-1590|-1589|-1588|-1587|-1586|-1585|-1584|-1583|-1582|-1581|-1580|-1579|-1578|-1577|-1576|-1575|-1574|-1573|-1572|-1571|-1570|-1569|-1568|-1567|-1566|-1565|-1564|-1563|-1562|-1561|-1560|-1559|-1558|-1557|-1556|-1555|-1554|-1553|-1552|-1551|-1550|-1549|-1548|-1547|-1546|-1545|-1544|-1543|-1542|-1541|-1540|-1539|-1538|-1537|-1536|-1535|-1534|-1533|-1532|-1531|-1530|-1529|-1528|-1527|-1526|-1525|-1524|-1523|-1522|-1521|-1520|-1519|-1518|-1517|-1516|-1515|-1514|-1513|-1512|-1511|-1510|-1509|-1508|-1507|-1506|-1505|-1504|-1503|-1502|-1501|-1500|-1499|-1498|-1497|-1496|-1495|-1494|-1493|-1492|-1491|-1490|-1489|-1488|-1487|-1486|-1485|-1484|-1483|-1482|-1481|-1480|-1479|-1478|-1477|-1476|-1475|-1474|-1473|-1472|-1471|-1470|-1469|-1468|-1467|-1466|-1465|-1464|-1463|-1462|-1461|-1460|-1459|-1458|-1457|-1456|-1455|-1454|-1453|-1452|-1451|-1450|-1449|-1448|-1447|-1446|-1445|-1444|-1443|-1442|-1441|-1440|-1439|-1438|-1437|-1436|-1435|-1434|-1433|-1432|-1431|-1430|-1429|-1428|-1427|-1426|-1425|-1424|-1423|-1422|-1421|-1420|-1419|-1418|-1417|-1416|-1415|-1414|-1413|-1412|-1411|-1410|-1409|-1408|-1407|-1406|-1405|-1404|-1403|-1402|-1401|-1400|-1399|-1398|-1397|-1396|-1395|-1394|-1393|-1392|-1391|-1390|-1389|-1388|-1387|-1386|-1385|-1384|-1383|-1382|-1381|-1380|-1379|-1378|-1377|-1376|-1375|-1374|-1373|-1372|-1371|-1370|-1369|-1368|-1367|-1366|-1365|-1364|-1363|-1362|-1361|-1360|-1359|-1358|-1357|-1356|-1355|-1354|-1353|-1352|-1351|-1350|-1349|-1348|-1347|-1346|-1345|-1344|-1343|-1342|-1341|-1340|-1339|-1338|-1337|-1336|-1335|-1334|-1333|-1332|-1331|-1330|-1329|-1328|-1327|-1326|-1325|-1324|-1323|-1322|-1321|-1320|-1319|-1318|-1317|-1316|-1315|-1314|-1313|-1312|-1311|-1310|-1309|-1308|-1307|-1306|-1305|-1304|-1303|-1302|-1301|-1300|-1299|-1298|-1297|-1296|-1295|-1294|-1293|-1292|-1291|-1290|-1289|-1288|-1287|-1286|-1285|-1284|-1283|-1282|-1281|-1280|-1279|-1278|-1277|-1276|-1275|-1274|-1273|-1272|-1271|-1270|-1269|-1268|-1267|-1266|-1265|-1264|-1263|-1262|-1261|-1260|-1259|-1258|-1257|-1256|-1255|-1254|-1253|-1252|-1251|-1250|-1249|-1248|-1247|-1246|-1245|-1244|-1243|-1242|-1241|-1240|-1239|-1238|-1237|-1236|-1235|-1234|-1233|-1232|-1231|-1230|-1229|-1228|-1227|-1226|-1225|-1224|-1223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Check out this great tool which generates a regex for numeric ranges:
http://gamon.webfactional.com/regexnumericrangegenerator/
For the range requested by OP it generates: -?([0-9]{1,3}|1[0-9]{3}|20[0-4][0-9]|205[0-5])

Analyze the problem
If you "must" use a regex, break the problem down by analysing the accepted permutations.
"a range from -2055 to 2055" can be expressed as:
an optional -
optional leading zeros
followed by a number from 0 to 2055
"A number from 0 to 2055" can be one of a finite number of specific permutations:
one digit (0-9)
two digits (10-99)
three digits (100-999)
four digits starting with a 1 (1000-1999)
four digits starting with 20 (2000-204*9)
four digits starting with 205 (2050-2055*)
Note that for the purpose of this regex, it's not necessary to distinguish between the range "0-9" and "1-9", and only the last two ranges have any restrictions on the range of accepted digits/characters (indicated with a star).
Write component regex expressions
Each of the above component parts are easy to individually express as a regular expression:
-?
0*
[0-9]
[0-9][0-9]
[0-9][0-9][0-9]
1[0-9][0-9][0-9]
20[0-4][0-9]
205[0-5]
Put the expressions together
The relevant expression for the whole match would be:
-?0*([0-9]|[0-9][0-9]|[0-9][0-9][0-9]|1[0-9][0-9][0-9]|20[0-4][0-9]|205[0-5])
Or slightly more concisely:
-?0*([0-9]{1,3}|1[0-9]{3}|20[0-4][0-9]|205[0-5])
Assuming the input contains only "the number" and nothing else, the final regex is therefore:
^-?0*([0-9]{1,3}|1[0-9]{3}|20[0-4][0-9]|205[0-5])$
If it's necessary to allow for a leading plus sign, this becomes:
^[-+]?0*([0-9]{1,3}|1[0-9]{3}|20[0-4][0-9]|205[0-5])$
Here's a js fiddle demonstrating what passes and what would fails the last regex.

So many answers, but noone reads (or cares) about the OPs side question in the comments?
I'm writing an interpreter in OCaml .... how can i validate the input
number within the range without using regex ?? – Trung Nguyen Mar 2
at 17:30
As so many answers - correctly - pointed out that using regex is horrible for this scenario, lets think about other ways in OCaml! It is a while since I used OCaml, but with looking up a few constructs I was able to knock this together:
let isInRange i =
not (i < -2055 or i > 2055);;
let isIntAndInRange s =
try
let i = int_of_string s in
not (i < -2055 or i > 2055)
with
Failure "int_of_string" -> false;;
let () = print_string "type a number: " in
let s = read_line () in
isIntAndInRange s
If anything about is unclear, please read up on its syntax, type conversion functions and exception handling and input-output functions.
The user input part is only used to demonstrate. It might be more convenient to use the read_int function there. But the basic concept of handling the exception stays the same.
As of OCaml 4.02 this can be cleaned up a bit since exception handling can be done in a match.
let isIntAndInRange s =
match int_of_string s with
| i when i >= -2055 && i <= 2055 -> true
| _
| exception Failure _ -> false

As an alternate approach to the great expression offered by aliteralmind, here is one that is much longer but interesting in order to see what another approach might look like (and what not to do).
It's an interesting exercise, because you can think of two distinct method: roughly, you can either:
proceed by matching 4-char numbers, then 3-char numbers, etc.
or proceed by matching the thousands digit, then the hundreds digit, etc.
Without trying, how would you know which is best? It turns out that the first approach (aliteralmind's answer) is far more economical.
Lower, I include a series of tests in the PHP language in case you or someone else would like to check the output.
Below, I will give you the regex in "free-spacing mode", which allows comments inside the regex so you can easily understand what it does. However, not all regex engines support free-spacing mode, so before we start with the interesting part, here is the regex as a one-liner.
Note that your question mentions numbers from -2055 to 2055. I assumed that you wanted to match "normal numbers", without leading zeroes. This means that the regex will match 999 but not 0999. If you would like leading zeroes, let me know, that is a very easy tweak.
Also, if you are matching in utf-8 mode, the \d should be replaced by [0-9]. This is the more common form.
The Regex as a One-Liner
^(?!-0$)-?(?:(?=\d{4}$)[12])?(?:(?=\d{3}$)(?:(?:(?<=^)|(?<=^-)|(?<=1)|(?<=-1))\d|(?:(?<=2)|(?<=-2))0))?(?:(?=\d{2}$)(?:(?:(?<=^)|(?<=^-)|(?<=^\d)|(?<=^-\d)|(?<=^\d{2})(?<!20)|(?<=^-\d{2})(?<!-20))\d|(?:(?<=20)|(?<=-20))[0-5]))?(?:(?=\d$)(?:(?:(?<=^)|(?<=^-)|(?<=^\d)|(?<=^-\d)|(?<=^\d{2})|(?<=^-\d{2})|(?<=^\d{3})(?<!205)|(?<=^-\d{3})(?<!-205))\d|(?:(?<=205)|(?<=-205))[0-5]))$
The Regex in Free-Spacing Mode
(?x) # free-spacing mode
^ # anchor at beginning of string.
(?!-0$)-? # optional minus sign, but not for -0
(?: # OPTIONAL THOUSANDS DIGIT
(?=\d{4}$)[12] # assert that the number is 4-digit long, match 1 or 2
)? # end optional thousands digit
(?: # OPTIONAL HUNDREDS DIGIT
(?=\d{3}$) # assert that there are three digits left
(?: # non-capturing group
(?:(?<=^)|(?<=^-)|(?<=1)|(?<=-1))\d # if preceding chars are 1, -1 or head of string: value can be any digit
| # or
(?:(?<=2)|(?<=-2))0 # if preceding chars are 2 or -2: value must be 0
) # close non-capturing group
)? # end optional hundreds digits
(?: # OPTIONAL TENS DIGIT
(?=\d{2}$) # assert that there are two digits left
(?: # start non-capturing group
# if preceding char is head of string, single digit,
# or two digits that are not 20
# (with or without a minus)
# value can be any digit
(?:(?<=^)|(?<=^-)|(?<=^\d)|(?<=^-\d)|
(?<=^\d{2})(?<!20)|(?<=^-\d{2})(?<!-20))\d
| # or
(?:(?<=20)|(?<=-20))[0-5] # if preceding chars are 20 or -20: value can be from 0 to 5
) # end non-capturing group
)? # close optional tens digits
(?: # FINAL DIGIT (non optional)
(?=\d$) # assert that there is only one digit left
(?: # start non-capturing group
# if preceding char is head of string, single digit,
# two digits, or three digits that are not 205
# (with or without a minus)
# value can be any digit
(?:(?<=^)|(?<=^-)|(?<=^\d)|(?<=^-\d)|
(?<=^\d{2})|(?<=^-\d{2})|
(?<=^\d{3})(?<!205)|(?<=^-\d{3})(?<!-205))
\d
| # or
(?:(?<=205)|(?<=-205))[0-5] # if preceding chars are 205 or -205: value can be from 0 to 5
) # end non-capturing group
) # end final digit
$
Series of Tests
These tests try to match against numbers from -100000 to 100000. They produce the following output:
Successful test: matches from -2055 to 2055
Successful test: NO matches from -100000 to -2056
Successful test: NO matches from 2056 to 100000
Here is the code:
<?php
$regex="~^(?!-0$)-?(?:(?=\d{4}$)[12])?(?:(?=\d{3}$)(?:(?:(?<=^)|(?<=^-)|(?<=1)|(?<=-1))\d|(?:(?<=2)|(?<=-2))0))?(?:(?=\d{2}$)(?:(?:(?<=20)|(?<=-20))[0-5]|(?:(?<=^)|(?<=^-)|(?<=^\d)|(?<=^-\d)|(?<=^\d{2})(?<!20)|(?<=^-\d{2})(?<!-20))\d))?(?:(?=\d$)(?:(?:(?<=205)|(?<=-205))[0-5]|(?:(?<=^)|(?<=^-)|(?<=^\d)|(?<=^-\d)|(?<=^\d{2})|(?<=^-\d{2})|(?<=^\d{3})(?<!205)|(?<=^-\d{3})(?<!-205))\d))$~";
// Test 1
$success="Successful test: matches from -2055 to 2055";
for($i=-2055;$i<=2055;$i++) {
$chari = sprintf("%d",$i);
if (! preg_match($regex,$chari)) {
$success="Failed test: matches from -2055 to 2055";
echo $chari.": No Match!<br />";
}
}
echo $success."<br />";
// Test 2
$success="Successful test: NO matches from -100000 to -2056";
for($i=-100000;$i<=-2056;$i++) {
$chari = sprintf("%d",$i);
if (preg_match($regex,$chari)) {
$success="Failed test: NO matches from -100000 to -2056";
echo $chari.": Match!<br />";
}
}
echo $success."<br />";
// Test 3
$success="Successful test: NO matches from 2056 to 100000";
for($i=2056;$i<=100000;$i++) {
$chari = sprintf("%d",$i);
if (preg_match($regex,$chari)) {
$success="Failed test: NO matches from 2056 to 100000";
echo $chari.": Match!<br />";
}
}
echo $success."<br />";
?>
Speed Tests
Here is the output of my simple speed test, matching from -1M to +1M. As Casimir pointed out, if aliteralmind's expression were anchored, instead of being slower it would be faster by 25%!
zx81: 3.796217918396
aliteralmind: 3.9922280311584
difference: 5.1632998151294 percent longer
Here is the test code:
$regex="~(?x)^(?!-0$)-?(?:(?=\d{4}$)[12])?(?:(?=\d{3}$)(?:(?:(?<=^)|(?<=^-)|(?<=1)|(?<=-1))\d|(?:(?<=2)|(?<=-2))0))?(?:(?=\d{2}$)(?:(?:(?<=^)|(?<=^-)|(?<=^\d)|(?<=^-\d)|(?<=^\d{2})(?<!20)|(?<=^-\d{2})(?<!-20))\d|(?:(?<=20)|(?<=-20))[0-5]))?(?:(?=\d$)(?:(?:(?<=^)|(?<=^-)|(?<=^\d)|(?<=^-\d)|(?<=^\d{2})|(?<=^-\d{2})|(?<=^\d{3})(?<!205)|(?<=^-\d{3})(?<!-205))\d|(?:(?<=205)|(?<=-205))[0-5]))$~";
$regex2 = "~(-?\b(?:20(?:5[0-5]|[0-4][0-9])|1[0-9]{3}|[1-9][0-9]{0,2}|(?<!-)0+))\b~";
$start=microtime(TRUE);
for ($i=-1000000;$i<1000000;$i++) preg_match($regex,$i);
$zxend=microtime(TRUE);
for ($i=-1000000;$i<1000000;$i++) preg_match($regex2,$i);
$alitend=microtime(TRUE);
$zx81 = $zxend-$start;
$alit = $alitend-$zxend;
$diff = 100*($alit-$zx81)/$zx81;
echo "zx81: ".$zx81."<br />";
echo "aliteralmind: ".$alit."<br />";
echo "difference: ".$diff." percent longer<br />";

Why use Regex only to check a number?
int n = -2000;
if(n >= -2055 && n <= 2055)
//Do something
else
//Do something else

Try this:
\-?\b0*(205[0-5]|20[0-4]\d|1?\d{3}|\d{1,2})\b

Try with a very simple regex.
^([-0][0-1][0-9][0-9][0-9])$|^([-0]20[0-4][0-9])$|^([-0]205[0-5])$
Visual representation
It's very simple to understand.
group 1 [-0][0-1][0-9][0-9][0-9] will cover [-1999, 1999] values
group 2 [-0]20[0-4][0-9] will cover [-2000,-2049] and [2000,2049] values
group 3 [-0]205[0-5] will cover [-2050, -2055] and [2050, 2055] values
String.format("%05d", number) is doing very well done job here?
Sample code: (Read inline comments for more clarity.)
int[] numbers = new int[] { -10002, -3000, -2056, -2055, -2000, -1999, -20,
-1, 0, 1, 260, 1999, 2000, 2046, 2055, 2056, 2955,
3000, 10002, 123456 };
//valid range -2055 to 2055 inclusive
Pattern p = Pattern.compile("^([-0][0-1][0-9][0-9][0-9])$|^([-0]20[0-4][0-9])$|^([-0]205[0-5])$");
for (int number : numbers) {
String string = String.format("%05d", number);
Matcher m = p.matcher(string);
if (m.find()) {
System.out.println(number + " is in range.");
} else {
System.out.println(number + " is not in range.");
}
}
output:
-10002 is not in range.
-3000 is not in range.
-2056 is not in range.
-2055 is in range.
-2000 is in range.
-1999 is in range.
-20 is in range.
-1 is in range.
0 is in range.
1 is in range.
260 is in range.
1999 is in range.
2000 is in range.
2046 is in range.
2055 is in range.
2056 is not in range.
2955 is not in range.
3000 is not in range.
10002 is not in range.
123456 is not in range.

Try this:
^-?0*(1?[0-9]{1,3}|20[0-4][0-9]|205[0-5])$
The regex before the brackets matches an optional - and any leading 0s.
The first part in the brackets (1?[0-9]{1,3}) matches 0-1999.
The second part in the brackets (20[0-4][0-9]) matches 2000-2049.
The third part in the brackets (205[0-5]) matches 2050-2055.

Yet another -
# ^-?0*(?:20(?:[0-4][0-9]|5[0-5])|[0-9]{1,3})$
^
-?
0*
(?:
20
(?:
[0-4] [0-9]
|
5 [0-5]
)
|
[0-9]{1,3}
)
$

Related

Regex numbers between: [duplicate]

My input number is an int. But the input number must be in a range from -2055 to 2055 and I want to check this by using regular expression.
So is there anyway to write a regular expression to check whether a number is in (-2055, 2055) or not ?
It is easier to use if statement to check whether the number is in range or not. But I'm writing an interpreter so I should use regex to check the input number
Using regular expressions to validate a numeric range
To be clear: When a simple if statement will suffice
if(num < -2055 || num > 2055) {
throw new IllegalArgumentException("num (" + num + ") must be between -2055 and 2055");
}
using regular expressions for validating numeric ranges is not recommended.
In addition, since regular expressions analyze strings, numbers must first be translated to a string before they can be tested. An exception is when the number happens to already be a string, such as when getting user input from the console.
(To ensure the string is a number to begin with, you could use org.apache.commons.lang3.math.NumberUtils#isNumber(s))
Despite this, figuring out how to validate number ranges with regular expressions is interesting and instructive.
(The links in this answer come from the Stack Overflow Regular Expressions FAQ.)
A one number range
Rule: A number must be exactly 15.
The simplest range there is. A regex to match this is
\b15\b
Word boundaries are necessary to avoid matching the 15 inside of 8215242.
A two number range
The rule: The number must be between 15 and 16. Here are three possible regexes:
\b(15|16)\b
\b1(5|6)\b
\b1[5-6]\b
(The groups are required for the "or"-ing, but they could be non-capturing: \b(?:15|16)\b)
A number range "mirrored" around zero
The rule: The number must be between -12 and 12.
Here is a regex for 0 through 12, positive-only:
\b(\d|1[0-2])\b
Free-spaced:
\b( //The beginning of a word (or number), followed by either
\d // Any digit 0 through 9
| //Or
1[0-2] // A 1 followed by any digit between 0 and 2.
)\b //The end of a word
Making this work for both negative and positive is as simple as adding an optional dash at the start:
-?\b(\d|1[0-2])\b
(This assumes no inappropriate characters precede the dash.)
To forbid negative numbers, a negative lookbehind is necessary:
(?<!-)\b(\d|1[0-2])\b
Leaving the lookbehind out would cause the 11 in -11 to match. (The first example in this post should have this added.)
Note: \d versus [0-9]
In order to be compatible with all regex flavors, all \d-s should be changed to [0-9]. For example, .NET considers non ASCII numbers, such as those in different languages, as legal values for \d. Except for in the last example, for brevity, it's left as \d.
(With thanks to #TimPietzcker)
Three digits, with all but the first digit equal to zero
Rule: Must be between 0 and 400.
A possible regex:
(?<!-)\b([1-3]?\d{1,2}|400)\b
Free spaced:
(?<!-) //Something not preceded by a dash
\b( //Word-start, followed by either
[1-3]? // No digit, or the digit 1, 2, or 3
\d{1,2} // Followed by one or two digits (between 0 and 9)
| //Or
400 // The number 400
)\b //Word-end
Another possibility that should never be used:
\b(0|1|2|3|4|5|6|7|8|9|10|11|12|13|14|15|16|17|18|19|20|21|22|23|24|25|26|27|28|29|30|31|32|33|34|35|36|37|38|39|40|41|42|43|44|45|46|47|48|49|50|51|52|53|54|55|56|57|58|59|60|61|62|63|64|65|66|67|68|69|70|71|72|73|74|75|76|77|78|79|80|81|82|83|84|85|86|87|88|89|90|91|92|93|94|95|96|97|98|99|100|101|102|103|104|105|106|107|108|109|110|111|112|113|114|115|116|117|118|119|120|121|122|123|124|125|126|127|128|129|130|131|132|133|134|135|136|137|138|139|140|141|142|143|144|145|146|147|148|149|150|151|152|153|154|155|156|157|158|159|160|161|162|163|164|165|166|167|168|169|170|171|172|173|174|175|176|177|178|179|180|181|182|183|184|185|186|187|188|189|190|191|192|193|194|195|196|197|198|199|200|201|202|203|204|205|206|207|208|209|210|211|212|213|214|215|216|217|218|219|220|221|222|223|224|225|226|227|228|229|230|231|232|233|234|235|236|237|238|239|240|241|242|243|244|245|246|247|248|249|250|251|252|253|254|255|256|257|258|259|260|261|262|263|264|265|266|267|268|269|270|271|272|273|274|275|276|277|278|279|280|281|282|283|284|285|286|287|288|289|290|291|292|293|294|295|296|297|298|299|300|301|302|303|304|305|306|307|308|309|310|311|312|313|314|315|316|317|318|319|320|321|322|323|324|325|326|327|328|329|330|331|332|333|334|335|336|337|338|339|340|341|342|343|344|345|346|347|348|349|350|351|352|353|354|355|356|357|358|359|360|361|362|363|364|365|366|367|368|369|370|371|372|373|374|375|376|377|378|379|380|381|382|383|384|385|386|387|388|389|390|391|392|393|394|395|396|397|398|399|400)\b
Final example: Four digits, mirrored around zero, that does not end with zeros.
Rule: Must be between -2055 and 2055
This is from a question on stackoverflow.
Regex:
(-?\b(?:20(?:5[0-5]|[0-4][0-9])|1[0-9]{3}|[1-9][0-9]{0,2}|(?<!-)0+))\b
Debuggex Demo
Free-spaced:
( //Capture group for the entire number
-?\b //Optional dash, followed by a word (number) boundary
(?:20 //Followed by "20", which is followed by one of
(?:5[0-5] //50 through 55
| //or
[0-4][0-9]) //00 through 49
| //or
1[0-9]{3} //a one followed by any three digits
| //or
[1-9][0-9]{0,2} //1-9 followed by 0 through 2 of any digit
| //or
(?<!-)0+ //one-or-more zeros *not* preceded by a dash
) //end "or" non-capture group
)\b //End number capture group, followed by a word-bound
(With thanks to PlasmaPower and Casimir et Hippolyte for the debugging assistance.)
Final note
Depending on what you are capturing, it is likely that all sub-groups should be made into non-capture groups. For example, this:
(-?\b(?:20(?:5[0-5]|[0-4][0-9])|1?[0-9]{1,3})\b)
Instead of this:
-?\b(20(5[0-5]|[0-4][0-9])|1?[0-9]{1,3})\b
Example Java implementation
import java.util.Scanner;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
import org.apache.commons.lang.math.NumberUtils;
/**
<P>Confirm a user-input number is a valid number by reading a string an testing it is numeric before converting it to an it--this loops until a valid number is provided.</P>
<P>{#code java UserInputNumInRangeWRegex}</P>
**/
public class UserInputNumInRangeWRegex {
public static final void main(String[] ignored) {
int num = -1;
boolean isNum = false;
int iRangeMax = 2055;
//"": Dummy string, to reuse matcher
Matcher mtchrNumNegThrPos = Pattern.compile("(-?\\b(?:20(?:5[0-5]|[0-4][0-9])|1[0-9]{3}|[1-9][0-9]{0,2}|(?<!-)0+))\\b").matcher("");
do {
System.out.print("Enter a number between -" + iRangeMax + " and " + iRangeMax + ": ");
String strInput = (new Scanner(System.in)).next();
if(!NumberUtils.isNumber(strInput)) {
System.out.println("Not a number. Try again.");
} else if(!mtchrNumNegThrPos.reset(strInput).matches()) {
System.out.println("Not in range. Try again.");
} else {
//Safe to convert
num = Integer.parseInt(strInput);
isNum = true;
}
} while(!isNum);
System.out.println("Number: " + num);
}
}
Output
[C:\java_code\]java UserInputNumInRangeWRegex
Enter a number between -2055 and 2055: tuhet
Not a number. Try again.
Enter a number between -2055 and 2055: 283837483
Not in range. Try again.
Enter a number between -2055 and 2055: -200000
Not in range. Try again.
Enter a number between -2055 and 2055: -300
Number: -300
Original answer to this stackoverflow question
This is a serious answer that fits your specifications. It is similar to #PlasmaPower's answer.
(-?\b(?:20(?:5[0-5]|[0-4][0-9])|1[0-9]{3}|[1-9][0-9]{0,2}|(?<!-)0+))\b
Debuggex Demo
Don't ever use it, but this works. :)
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Check out this great tool which generates a regex for numeric ranges:
http://gamon.webfactional.com/regexnumericrangegenerator/
For the range requested by OP it generates: -?([0-9]{1,3}|1[0-9]{3}|20[0-4][0-9]|205[0-5])
Analyze the problem
If you "must" use a regex, break the problem down by analysing the accepted permutations.
"a range from -2055 to 2055" can be expressed as:
an optional -
optional leading zeros
followed by a number from 0 to 2055
"A number from 0 to 2055" can be one of a finite number of specific permutations:
one digit (0-9)
two digits (10-99)
three digits (100-999)
four digits starting with a 1 (1000-1999)
four digits starting with 20 (2000-204*9)
four digits starting with 205 (2050-2055*)
Note that for the purpose of this regex, it's not necessary to distinguish between the range "0-9" and "1-9", and only the last two ranges have any restrictions on the range of accepted digits/characters (indicated with a star).
Write component regex expressions
Each of the above component parts are easy to individually express as a regular expression:
-?
0*
[0-9]
[0-9][0-9]
[0-9][0-9][0-9]
1[0-9][0-9][0-9]
20[0-4][0-9]
205[0-5]
Put the expressions together
The relevant expression for the whole match would be:
-?0*([0-9]|[0-9][0-9]|[0-9][0-9][0-9]|1[0-9][0-9][0-9]|20[0-4][0-9]|205[0-5])
Or slightly more concisely:
-?0*([0-9]{1,3}|1[0-9]{3}|20[0-4][0-9]|205[0-5])
Assuming the input contains only "the number" and nothing else, the final regex is therefore:
^-?0*([0-9]{1,3}|1[0-9]{3}|20[0-4][0-9]|205[0-5])$
If it's necessary to allow for a leading plus sign, this becomes:
^[-+]?0*([0-9]{1,3}|1[0-9]{3}|20[0-4][0-9]|205[0-5])$
Here's a js fiddle demonstrating what passes and what would fails the last regex.
So many answers, but noone reads (or cares) about the OPs side question in the comments?
I'm writing an interpreter in OCaml .... how can i validate the input
number within the range without using regex ?? – Trung Nguyen Mar 2
at 17:30
As so many answers - correctly - pointed out that using regex is horrible for this scenario, lets think about other ways in OCaml! It is a while since I used OCaml, but with looking up a few constructs I was able to knock this together:
let isInRange i =
not (i < -2055 or i > 2055);;
let isIntAndInRange s =
try
let i = int_of_string s in
not (i < -2055 or i > 2055)
with
Failure "int_of_string" -> false;;
let () = print_string "type a number: " in
let s = read_line () in
isIntAndInRange s
If anything about is unclear, please read up on its syntax, type conversion functions and exception handling and input-output functions.
The user input part is only used to demonstrate. It might be more convenient to use the read_int function there. But the basic concept of handling the exception stays the same.
As of OCaml 4.02 this can be cleaned up a bit since exception handling can be done in a match.
let isIntAndInRange s =
match int_of_string s with
| i when i >= -2055 && i <= 2055 -> true
| _
| exception Failure _ -> false
As an alternate approach to the great expression offered by aliteralmind, here is one that is much longer but interesting in order to see what another approach might look like (and what not to do).
It's an interesting exercise, because you can think of two distinct method: roughly, you can either:
proceed by matching 4-char numbers, then 3-char numbers, etc.
or proceed by matching the thousands digit, then the hundreds digit, etc.
Without trying, how would you know which is best? It turns out that the first approach (aliteralmind's answer) is far more economical.
Lower, I include a series of tests in the PHP language in case you or someone else would like to check the output.
Below, I will give you the regex in "free-spacing mode", which allows comments inside the regex so you can easily understand what it does. However, not all regex engines support free-spacing mode, so before we start with the interesting part, here is the regex as a one-liner.
Note that your question mentions numbers from -2055 to 2055. I assumed that you wanted to match "normal numbers", without leading zeroes. This means that the regex will match 999 but not 0999. If you would like leading zeroes, let me know, that is a very easy tweak.
Also, if you are matching in utf-8 mode, the \d should be replaced by [0-9]. This is the more common form.
The Regex as a One-Liner
^(?!-0$)-?(?:(?=\d{4}$)[12])?(?:(?=\d{3}$)(?:(?:(?<=^)|(?<=^-)|(?<=1)|(?<=-1))\d|(?:(?<=2)|(?<=-2))0))?(?:(?=\d{2}$)(?:(?:(?<=^)|(?<=^-)|(?<=^\d)|(?<=^-\d)|(?<=^\d{2})(?<!20)|(?<=^-\d{2})(?<!-20))\d|(?:(?<=20)|(?<=-20))[0-5]))?(?:(?=\d$)(?:(?:(?<=^)|(?<=^-)|(?<=^\d)|(?<=^-\d)|(?<=^\d{2})|(?<=^-\d{2})|(?<=^\d{3})(?<!205)|(?<=^-\d{3})(?<!-205))\d|(?:(?<=205)|(?<=-205))[0-5]))$
The Regex in Free-Spacing Mode
(?x) # free-spacing mode
^ # anchor at beginning of string.
(?!-0$)-? # optional minus sign, but not for -0
(?: # OPTIONAL THOUSANDS DIGIT
(?=\d{4}$)[12] # assert that the number is 4-digit long, match 1 or 2
)? # end optional thousands digit
(?: # OPTIONAL HUNDREDS DIGIT
(?=\d{3}$) # assert that there are three digits left
(?: # non-capturing group
(?:(?<=^)|(?<=^-)|(?<=1)|(?<=-1))\d # if preceding chars are 1, -1 or head of string: value can be any digit
| # or
(?:(?<=2)|(?<=-2))0 # if preceding chars are 2 or -2: value must be 0
) # close non-capturing group
)? # end optional hundreds digits
(?: # OPTIONAL TENS DIGIT
(?=\d{2}$) # assert that there are two digits left
(?: # start non-capturing group
# if preceding char is head of string, single digit,
# or two digits that are not 20
# (with or without a minus)
# value can be any digit
(?:(?<=^)|(?<=^-)|(?<=^\d)|(?<=^-\d)|
(?<=^\d{2})(?<!20)|(?<=^-\d{2})(?<!-20))\d
| # or
(?:(?<=20)|(?<=-20))[0-5] # if preceding chars are 20 or -20: value can be from 0 to 5
) # end non-capturing group
)? # close optional tens digits
(?: # FINAL DIGIT (non optional)
(?=\d$) # assert that there is only one digit left
(?: # start non-capturing group
# if preceding char is head of string, single digit,
# two digits, or three digits that are not 205
# (with or without a minus)
# value can be any digit
(?:(?<=^)|(?<=^-)|(?<=^\d)|(?<=^-\d)|
(?<=^\d{2})|(?<=^-\d{2})|
(?<=^\d{3})(?<!205)|(?<=^-\d{3})(?<!-205))
\d
| # or
(?:(?<=205)|(?<=-205))[0-5] # if preceding chars are 205 or -205: value can be from 0 to 5
) # end non-capturing group
) # end final digit
$
Series of Tests
These tests try to match against numbers from -100000 to 100000. They produce the following output:
Successful test: matches from -2055 to 2055
Successful test: NO matches from -100000 to -2056
Successful test: NO matches from 2056 to 100000
Here is the code:
<?php
$regex="~^(?!-0$)-?(?:(?=\d{4}$)[12])?(?:(?=\d{3}$)(?:(?:(?<=^)|(?<=^-)|(?<=1)|(?<=-1))\d|(?:(?<=2)|(?<=-2))0))?(?:(?=\d{2}$)(?:(?:(?<=20)|(?<=-20))[0-5]|(?:(?<=^)|(?<=^-)|(?<=^\d)|(?<=^-\d)|(?<=^\d{2})(?<!20)|(?<=^-\d{2})(?<!-20))\d))?(?:(?=\d$)(?:(?:(?<=205)|(?<=-205))[0-5]|(?:(?<=^)|(?<=^-)|(?<=^\d)|(?<=^-\d)|(?<=^\d{2})|(?<=^-\d{2})|(?<=^\d{3})(?<!205)|(?<=^-\d{3})(?<!-205))\d))$~";
// Test 1
$success="Successful test: matches from -2055 to 2055";
for($i=-2055;$i<=2055;$i++) {
$chari = sprintf("%d",$i);
if (! preg_match($regex,$chari)) {
$success="Failed test: matches from -2055 to 2055";
echo $chari.": No Match!<br />";
}
}
echo $success."<br />";
// Test 2
$success="Successful test: NO matches from -100000 to -2056";
for($i=-100000;$i<=-2056;$i++) {
$chari = sprintf("%d",$i);
if (preg_match($regex,$chari)) {
$success="Failed test: NO matches from -100000 to -2056";
echo $chari.": Match!<br />";
}
}
echo $success."<br />";
// Test 3
$success="Successful test: NO matches from 2056 to 100000";
for($i=2056;$i<=100000;$i++) {
$chari = sprintf("%d",$i);
if (preg_match($regex,$chari)) {
$success="Failed test: NO matches from 2056 to 100000";
echo $chari.": Match!<br />";
}
}
echo $success."<br />";
?>
Speed Tests
Here is the output of my simple speed test, matching from -1M to +1M. As Casimir pointed out, if aliteralmind's expression were anchored, instead of being slower it would be faster by 25%!
zx81: 3.796217918396
aliteralmind: 3.9922280311584
difference: 5.1632998151294 percent longer
Here is the test code:
$regex="~(?x)^(?!-0$)-?(?:(?=\d{4}$)[12])?(?:(?=\d{3}$)(?:(?:(?<=^)|(?<=^-)|(?<=1)|(?<=-1))\d|(?:(?<=2)|(?<=-2))0))?(?:(?=\d{2}$)(?:(?:(?<=^)|(?<=^-)|(?<=^\d)|(?<=^-\d)|(?<=^\d{2})(?<!20)|(?<=^-\d{2})(?<!-20))\d|(?:(?<=20)|(?<=-20))[0-5]))?(?:(?=\d$)(?:(?:(?<=^)|(?<=^-)|(?<=^\d)|(?<=^-\d)|(?<=^\d{2})|(?<=^-\d{2})|(?<=^\d{3})(?<!205)|(?<=^-\d{3})(?<!-205))\d|(?:(?<=205)|(?<=-205))[0-5]))$~";
$regex2 = "~(-?\b(?:20(?:5[0-5]|[0-4][0-9])|1[0-9]{3}|[1-9][0-9]{0,2}|(?<!-)0+))\b~";
$start=microtime(TRUE);
for ($i=-1000000;$i<1000000;$i++) preg_match($regex,$i);
$zxend=microtime(TRUE);
for ($i=-1000000;$i<1000000;$i++) preg_match($regex2,$i);
$alitend=microtime(TRUE);
$zx81 = $zxend-$start;
$alit = $alitend-$zxend;
$diff = 100*($alit-$zx81)/$zx81;
echo "zx81: ".$zx81."<br />";
echo "aliteralmind: ".$alit."<br />";
echo "difference: ".$diff." percent longer<br />";
Why use Regex only to check a number?
int n = -2000;
if(n >= -2055 && n <= 2055)
//Do something
else
//Do something else
Try this:
\-?\b0*(205[0-5]|20[0-4]\d|1?\d{3}|\d{1,2})\b
Try with a very simple regex.
^([-0][0-1][0-9][0-9][0-9])$|^([-0]20[0-4][0-9])$|^([-0]205[0-5])$
Visual representation
It's very simple to understand.
group 1 [-0][0-1][0-9][0-9][0-9] will cover [-1999, 1999] values
group 2 [-0]20[0-4][0-9] will cover [-2000,-2049] and [2000,2049] values
group 3 [-0]205[0-5] will cover [-2050, -2055] and [2050, 2055] values
String.format("%05d", number) is doing very well done job here?
Sample code: (Read inline comments for more clarity.)
int[] numbers = new int[] { -10002, -3000, -2056, -2055, -2000, -1999, -20,
-1, 0, 1, 260, 1999, 2000, 2046, 2055, 2056, 2955,
3000, 10002, 123456 };
//valid range -2055 to 2055 inclusive
Pattern p = Pattern.compile("^([-0][0-1][0-9][0-9][0-9])$|^([-0]20[0-4][0-9])$|^([-0]205[0-5])$");
for (int number : numbers) {
String string = String.format("%05d", number);
Matcher m = p.matcher(string);
if (m.find()) {
System.out.println(number + " is in range.");
} else {
System.out.println(number + " is not in range.");
}
}
output:
-10002 is not in range.
-3000 is not in range.
-2056 is not in range.
-2055 is in range.
-2000 is in range.
-1999 is in range.
-20 is in range.
-1 is in range.
0 is in range.
1 is in range.
260 is in range.
1999 is in range.
2000 is in range.
2046 is in range.
2055 is in range.
2056 is not in range.
2955 is not in range.
3000 is not in range.
10002 is not in range.
123456 is not in range.
Try this:
^-?0*(1?[0-9]{1,3}|20[0-4][0-9]|205[0-5])$
The regex before the brackets matches an optional - and any leading 0s.
The first part in the brackets (1?[0-9]{1,3}) matches 0-1999.
The second part in the brackets (20[0-4][0-9]) matches 2000-2049.
The third part in the brackets (205[0-5]) matches 2050-2055.
Yet another -
# ^-?0*(?:20(?:[0-4][0-9]|5[0-5])|[0-9]{1,3})$
^
-?
0*
(?:
20
(?:
[0-4] [0-9]
|
5 [0-5]
)
|
[0-9]{1,3}
)
$

Create a regex range with two decimal number as optional number [duplicate]

My input number is an int. But the input number must be in a range from -2055 to 2055 and I want to check this by using regular expression.
So is there anyway to write a regular expression to check whether a number is in (-2055, 2055) or not ?
It is easier to use if statement to check whether the number is in range or not. But I'm writing an interpreter so I should use regex to check the input number
Using regular expressions to validate a numeric range
To be clear: When a simple if statement will suffice
if(num < -2055 || num > 2055) {
throw new IllegalArgumentException("num (" + num + ") must be between -2055 and 2055");
}
using regular expressions for validating numeric ranges is not recommended.
In addition, since regular expressions analyze strings, numbers must first be translated to a string before they can be tested. An exception is when the number happens to already be a string, such as when getting user input from the console.
(To ensure the string is a number to begin with, you could use org.apache.commons.lang3.math.NumberUtils#isNumber(s))
Despite this, figuring out how to validate number ranges with regular expressions is interesting and instructive.
(The links in this answer come from the Stack Overflow Regular Expressions FAQ.)
A one number range
Rule: A number must be exactly 15.
The simplest range there is. A regex to match this is
\b15\b
Word boundaries are necessary to avoid matching the 15 inside of 8215242.
A two number range
The rule: The number must be between 15 and 16. Here are three possible regexes:
\b(15|16)\b
\b1(5|6)\b
\b1[5-6]\b
(The groups are required for the "or"-ing, but they could be non-capturing: \b(?:15|16)\b)
A number range "mirrored" around zero
The rule: The number must be between -12 and 12.
Here is a regex for 0 through 12, positive-only:
\b(\d|1[0-2])\b
Free-spaced:
\b( //The beginning of a word (or number), followed by either
\d // Any digit 0 through 9
| //Or
1[0-2] // A 1 followed by any digit between 0 and 2.
)\b //The end of a word
Making this work for both negative and positive is as simple as adding an optional dash at the start:
-?\b(\d|1[0-2])\b
(This assumes no inappropriate characters precede the dash.)
To forbid negative numbers, a negative lookbehind is necessary:
(?<!-)\b(\d|1[0-2])\b
Leaving the lookbehind out would cause the 11 in -11 to match. (The first example in this post should have this added.)
Note: \d versus [0-9]
In order to be compatible with all regex flavors, all \d-s should be changed to [0-9]. For example, .NET considers non ASCII numbers, such as those in different languages, as legal values for \d. Except for in the last example, for brevity, it's left as \d.
(With thanks to #TimPietzcker)
Three digits, with all but the first digit equal to zero
Rule: Must be between 0 and 400.
A possible regex:
(?<!-)\b([1-3]?\d{1,2}|400)\b
Free spaced:
(?<!-) //Something not preceded by a dash
\b( //Word-start, followed by either
[1-3]? // No digit, or the digit 1, 2, or 3
\d{1,2} // Followed by one or two digits (between 0 and 9)
| //Or
400 // The number 400
)\b //Word-end
Another possibility that should never be used:
\b(0|1|2|3|4|5|6|7|8|9|10|11|12|13|14|15|16|17|18|19|20|21|22|23|24|25|26|27|28|29|30|31|32|33|34|35|36|37|38|39|40|41|42|43|44|45|46|47|48|49|50|51|52|53|54|55|56|57|58|59|60|61|62|63|64|65|66|67|68|69|70|71|72|73|74|75|76|77|78|79|80|81|82|83|84|85|86|87|88|89|90|91|92|93|94|95|96|97|98|99|100|101|102|103|104|105|106|107|108|109|110|111|112|113|114|115|116|117|118|119|120|121|122|123|124|125|126|127|128|129|130|131|132|133|134|135|136|137|138|139|140|141|142|143|144|145|146|147|148|149|150|151|152|153|154|155|156|157|158|159|160|161|162|163|164|165|166|167|168|169|170|171|172|173|174|175|176|177|178|179|180|181|182|183|184|185|186|187|188|189|190|191|192|193|194|195|196|197|198|199|200|201|202|203|204|205|206|207|208|209|210|211|212|213|214|215|216|217|218|219|220|221|222|223|224|225|226|227|228|229|230|231|232|233|234|235|236|237|238|239|240|241|242|243|244|245|246|247|248|249|250|251|252|253|254|255|256|257|258|259|260|261|262|263|264|265|266|267|268|269|270|271|272|273|274|275|276|277|278|279|280|281|282|283|284|285|286|287|288|289|290|291|292|293|294|295|296|297|298|299|300|301|302|303|304|305|306|307|308|309|310|311|312|313|314|315|316|317|318|319|320|321|322|323|324|325|326|327|328|329|330|331|332|333|334|335|336|337|338|339|340|341|342|343|344|345|346|347|348|349|350|351|352|353|354|355|356|357|358|359|360|361|362|363|364|365|366|367|368|369|370|371|372|373|374|375|376|377|378|379|380|381|382|383|384|385|386|387|388|389|390|391|392|393|394|395|396|397|398|399|400)\b
Final example: Four digits, mirrored around zero, that does not end with zeros.
Rule: Must be between -2055 and 2055
This is from a question on stackoverflow.
Regex:
(-?\b(?:20(?:5[0-5]|[0-4][0-9])|1[0-9]{3}|[1-9][0-9]{0,2}|(?<!-)0+))\b
Debuggex Demo
Free-spaced:
( //Capture group for the entire number
-?\b //Optional dash, followed by a word (number) boundary
(?:20 //Followed by "20", which is followed by one of
(?:5[0-5] //50 through 55
| //or
[0-4][0-9]) //00 through 49
| //or
1[0-9]{3} //a one followed by any three digits
| //or
[1-9][0-9]{0,2} //1-9 followed by 0 through 2 of any digit
| //or
(?<!-)0+ //one-or-more zeros *not* preceded by a dash
) //end "or" non-capture group
)\b //End number capture group, followed by a word-bound
(With thanks to PlasmaPower and Casimir et Hippolyte for the debugging assistance.)
Final note
Depending on what you are capturing, it is likely that all sub-groups should be made into non-capture groups. For example, this:
(-?\b(?:20(?:5[0-5]|[0-4][0-9])|1?[0-9]{1,3})\b)
Instead of this:
-?\b(20(5[0-5]|[0-4][0-9])|1?[0-9]{1,3})\b
Example Java implementation
import java.util.Scanner;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
import org.apache.commons.lang.math.NumberUtils;
/**
<P>Confirm a user-input number is a valid number by reading a string an testing it is numeric before converting it to an it--this loops until a valid number is provided.</P>
<P>{#code java UserInputNumInRangeWRegex}</P>
**/
public class UserInputNumInRangeWRegex {
public static final void main(String[] ignored) {
int num = -1;
boolean isNum = false;
int iRangeMax = 2055;
//"": Dummy string, to reuse matcher
Matcher mtchrNumNegThrPos = Pattern.compile("(-?\\b(?:20(?:5[0-5]|[0-4][0-9])|1[0-9]{3}|[1-9][0-9]{0,2}|(?<!-)0+))\\b").matcher("");
do {
System.out.print("Enter a number between -" + iRangeMax + " and " + iRangeMax + ": ");
String strInput = (new Scanner(System.in)).next();
if(!NumberUtils.isNumber(strInput)) {
System.out.println("Not a number. Try again.");
} else if(!mtchrNumNegThrPos.reset(strInput).matches()) {
System.out.println("Not in range. Try again.");
} else {
//Safe to convert
num = Integer.parseInt(strInput);
isNum = true;
}
} while(!isNum);
System.out.println("Number: " + num);
}
}
Output
[C:\java_code\]java UserInputNumInRangeWRegex
Enter a number between -2055 and 2055: tuhet
Not a number. Try again.
Enter a number between -2055 and 2055: 283837483
Not in range. Try again.
Enter a number between -2055 and 2055: -200000
Not in range. Try again.
Enter a number between -2055 and 2055: -300
Number: -300
Original answer to this stackoverflow question
This is a serious answer that fits your specifications. It is similar to #PlasmaPower's answer.
(-?\b(?:20(?:5[0-5]|[0-4][0-9])|1[0-9]{3}|[1-9][0-9]{0,2}|(?<!-)0+))\b
Debuggex Demo
Don't ever use it, but this works. :)
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Check out this great tool which generates a regex for numeric ranges:
http://gamon.webfactional.com/regexnumericrangegenerator/
For the range requested by OP it generates: -?([0-9]{1,3}|1[0-9]{3}|20[0-4][0-9]|205[0-5])
Analyze the problem
If you "must" use a regex, break the problem down by analysing the accepted permutations.
"a range from -2055 to 2055" can be expressed as:
an optional -
optional leading zeros
followed by a number from 0 to 2055
"A number from 0 to 2055" can be one of a finite number of specific permutations:
one digit (0-9)
two digits (10-99)
three digits (100-999)
four digits starting with a 1 (1000-1999)
four digits starting with 20 (2000-204*9)
four digits starting with 205 (2050-2055*)
Note that for the purpose of this regex, it's not necessary to distinguish between the range "0-9" and "1-9", and only the last two ranges have any restrictions on the range of accepted digits/characters (indicated with a star).
Write component regex expressions
Each of the above component parts are easy to individually express as a regular expression:
-?
0*
[0-9]
[0-9][0-9]
[0-9][0-9][0-9]
1[0-9][0-9][0-9]
20[0-4][0-9]
205[0-5]
Put the expressions together
The relevant expression for the whole match would be:
-?0*([0-9]|[0-9][0-9]|[0-9][0-9][0-9]|1[0-9][0-9][0-9]|20[0-4][0-9]|205[0-5])
Or slightly more concisely:
-?0*([0-9]{1,3}|1[0-9]{3}|20[0-4][0-9]|205[0-5])
Assuming the input contains only "the number" and nothing else, the final regex is therefore:
^-?0*([0-9]{1,3}|1[0-9]{3}|20[0-4][0-9]|205[0-5])$
If it's necessary to allow for a leading plus sign, this becomes:
^[-+]?0*([0-9]{1,3}|1[0-9]{3}|20[0-4][0-9]|205[0-5])$
Here's a js fiddle demonstrating what passes and what would fails the last regex.
So many answers, but noone reads (or cares) about the OPs side question in the comments?
I'm writing an interpreter in OCaml .... how can i validate the input
number within the range without using regex ?? – Trung Nguyen Mar 2
at 17:30
As so many answers - correctly - pointed out that using regex is horrible for this scenario, lets think about other ways in OCaml! It is a while since I used OCaml, but with looking up a few constructs I was able to knock this together:
let isInRange i =
not (i < -2055 or i > 2055);;
let isIntAndInRange s =
try
let i = int_of_string s in
not (i < -2055 or i > 2055)
with
Failure "int_of_string" -> false;;
let () = print_string "type a number: " in
let s = read_line () in
isIntAndInRange s
If anything about is unclear, please read up on its syntax, type conversion functions and exception handling and input-output functions.
The user input part is only used to demonstrate. It might be more convenient to use the read_int function there. But the basic concept of handling the exception stays the same.
As of OCaml 4.02 this can be cleaned up a bit since exception handling can be done in a match.
let isIntAndInRange s =
match int_of_string s with
| i when i >= -2055 && i <= 2055 -> true
| _
| exception Failure _ -> false
As an alternate approach to the great expression offered by aliteralmind, here is one that is much longer but interesting in order to see what another approach might look like (and what not to do).
It's an interesting exercise, because you can think of two distinct method: roughly, you can either:
proceed by matching 4-char numbers, then 3-char numbers, etc.
or proceed by matching the thousands digit, then the hundreds digit, etc.
Without trying, how would you know which is best? It turns out that the first approach (aliteralmind's answer) is far more economical.
Lower, I include a series of tests in the PHP language in case you or someone else would like to check the output.
Below, I will give you the regex in "free-spacing mode", which allows comments inside the regex so you can easily understand what it does. However, not all regex engines support free-spacing mode, so before we start with the interesting part, here is the regex as a one-liner.
Note that your question mentions numbers from -2055 to 2055. I assumed that you wanted to match "normal numbers", without leading zeroes. This means that the regex will match 999 but not 0999. If you would like leading zeroes, let me know, that is a very easy tweak.
Also, if you are matching in utf-8 mode, the \d should be replaced by [0-9]. This is the more common form.
The Regex as a One-Liner
^(?!-0$)-?(?:(?=\d{4}$)[12])?(?:(?=\d{3}$)(?:(?:(?<=^)|(?<=^-)|(?<=1)|(?<=-1))\d|(?:(?<=2)|(?<=-2))0))?(?:(?=\d{2}$)(?:(?:(?<=^)|(?<=^-)|(?<=^\d)|(?<=^-\d)|(?<=^\d{2})(?<!20)|(?<=^-\d{2})(?<!-20))\d|(?:(?<=20)|(?<=-20))[0-5]))?(?:(?=\d$)(?:(?:(?<=^)|(?<=^-)|(?<=^\d)|(?<=^-\d)|(?<=^\d{2})|(?<=^-\d{2})|(?<=^\d{3})(?<!205)|(?<=^-\d{3})(?<!-205))\d|(?:(?<=205)|(?<=-205))[0-5]))$
The Regex in Free-Spacing Mode
(?x) # free-spacing mode
^ # anchor at beginning of string.
(?!-0$)-? # optional minus sign, but not for -0
(?: # OPTIONAL THOUSANDS DIGIT
(?=\d{4}$)[12] # assert that the number is 4-digit long, match 1 or 2
)? # end optional thousands digit
(?: # OPTIONAL HUNDREDS DIGIT
(?=\d{3}$) # assert that there are three digits left
(?: # non-capturing group
(?:(?<=^)|(?<=^-)|(?<=1)|(?<=-1))\d # if preceding chars are 1, -1 or head of string: value can be any digit
| # or
(?:(?<=2)|(?<=-2))0 # if preceding chars are 2 or -2: value must be 0
) # close non-capturing group
)? # end optional hundreds digits
(?: # OPTIONAL TENS DIGIT
(?=\d{2}$) # assert that there are two digits left
(?: # start non-capturing group
# if preceding char is head of string, single digit,
# or two digits that are not 20
# (with or without a minus)
# value can be any digit
(?:(?<=^)|(?<=^-)|(?<=^\d)|(?<=^-\d)|
(?<=^\d{2})(?<!20)|(?<=^-\d{2})(?<!-20))\d
| # or
(?:(?<=20)|(?<=-20))[0-5] # if preceding chars are 20 or -20: value can be from 0 to 5
) # end non-capturing group
)? # close optional tens digits
(?: # FINAL DIGIT (non optional)
(?=\d$) # assert that there is only one digit left
(?: # start non-capturing group
# if preceding char is head of string, single digit,
# two digits, or three digits that are not 205
# (with or without a minus)
# value can be any digit
(?:(?<=^)|(?<=^-)|(?<=^\d)|(?<=^-\d)|
(?<=^\d{2})|(?<=^-\d{2})|
(?<=^\d{3})(?<!205)|(?<=^-\d{3})(?<!-205))
\d
| # or
(?:(?<=205)|(?<=-205))[0-5] # if preceding chars are 205 or -205: value can be from 0 to 5
) # end non-capturing group
) # end final digit
$
Series of Tests
These tests try to match against numbers from -100000 to 100000. They produce the following output:
Successful test: matches from -2055 to 2055
Successful test: NO matches from -100000 to -2056
Successful test: NO matches from 2056 to 100000
Here is the code:
<?php
$regex="~^(?!-0$)-?(?:(?=\d{4}$)[12])?(?:(?=\d{3}$)(?:(?:(?<=^)|(?<=^-)|(?<=1)|(?<=-1))\d|(?:(?<=2)|(?<=-2))0))?(?:(?=\d{2}$)(?:(?:(?<=20)|(?<=-20))[0-5]|(?:(?<=^)|(?<=^-)|(?<=^\d)|(?<=^-\d)|(?<=^\d{2})(?<!20)|(?<=^-\d{2})(?<!-20))\d))?(?:(?=\d$)(?:(?:(?<=205)|(?<=-205))[0-5]|(?:(?<=^)|(?<=^-)|(?<=^\d)|(?<=^-\d)|(?<=^\d{2})|(?<=^-\d{2})|(?<=^\d{3})(?<!205)|(?<=^-\d{3})(?<!-205))\d))$~";
// Test 1
$success="Successful test: matches from -2055 to 2055";
for($i=-2055;$i<=2055;$i++) {
$chari = sprintf("%d",$i);
if (! preg_match($regex,$chari)) {
$success="Failed test: matches from -2055 to 2055";
echo $chari.": No Match!<br />";
}
}
echo $success."<br />";
// Test 2
$success="Successful test: NO matches from -100000 to -2056";
for($i=-100000;$i<=-2056;$i++) {
$chari = sprintf("%d",$i);
if (preg_match($regex,$chari)) {
$success="Failed test: NO matches from -100000 to -2056";
echo $chari.": Match!<br />";
}
}
echo $success."<br />";
// Test 3
$success="Successful test: NO matches from 2056 to 100000";
for($i=2056;$i<=100000;$i++) {
$chari = sprintf("%d",$i);
if (preg_match($regex,$chari)) {
$success="Failed test: NO matches from 2056 to 100000";
echo $chari.": Match!<br />";
}
}
echo $success."<br />";
?>
Speed Tests
Here is the output of my simple speed test, matching from -1M to +1M. As Casimir pointed out, if aliteralmind's expression were anchored, instead of being slower it would be faster by 25%!
zx81: 3.796217918396
aliteralmind: 3.9922280311584
difference: 5.1632998151294 percent longer
Here is the test code:
$regex="~(?x)^(?!-0$)-?(?:(?=\d{4}$)[12])?(?:(?=\d{3}$)(?:(?:(?<=^)|(?<=^-)|(?<=1)|(?<=-1))\d|(?:(?<=2)|(?<=-2))0))?(?:(?=\d{2}$)(?:(?:(?<=^)|(?<=^-)|(?<=^\d)|(?<=^-\d)|(?<=^\d{2})(?<!20)|(?<=^-\d{2})(?<!-20))\d|(?:(?<=20)|(?<=-20))[0-5]))?(?:(?=\d$)(?:(?:(?<=^)|(?<=^-)|(?<=^\d)|(?<=^-\d)|(?<=^\d{2})|(?<=^-\d{2})|(?<=^\d{3})(?<!205)|(?<=^-\d{3})(?<!-205))\d|(?:(?<=205)|(?<=-205))[0-5]))$~";
$regex2 = "~(-?\b(?:20(?:5[0-5]|[0-4][0-9])|1[0-9]{3}|[1-9][0-9]{0,2}|(?<!-)0+))\b~";
$start=microtime(TRUE);
for ($i=-1000000;$i<1000000;$i++) preg_match($regex,$i);
$zxend=microtime(TRUE);
for ($i=-1000000;$i<1000000;$i++) preg_match($regex2,$i);
$alitend=microtime(TRUE);
$zx81 = $zxend-$start;
$alit = $alitend-$zxend;
$diff = 100*($alit-$zx81)/$zx81;
echo "zx81: ".$zx81."<br />";
echo "aliteralmind: ".$alit."<br />";
echo "difference: ".$diff." percent longer<br />";
Why use Regex only to check a number?
int n = -2000;
if(n >= -2055 && n <= 2055)
//Do something
else
//Do something else
Try this:
\-?\b0*(205[0-5]|20[0-4]\d|1?\d{3}|\d{1,2})\b
Try with a very simple regex.
^([-0][0-1][0-9][0-9][0-9])$|^([-0]20[0-4][0-9])$|^([-0]205[0-5])$
Visual representation
It's very simple to understand.
group 1 [-0][0-1][0-9][0-9][0-9] will cover [-1999, 1999] values
group 2 [-0]20[0-4][0-9] will cover [-2000,-2049] and [2000,2049] values
group 3 [-0]205[0-5] will cover [-2050, -2055] and [2050, 2055] values
String.format("%05d", number) is doing very well done job here?
Sample code: (Read inline comments for more clarity.)
int[] numbers = new int[] { -10002, -3000, -2056, -2055, -2000, -1999, -20,
-1, 0, 1, 260, 1999, 2000, 2046, 2055, 2056, 2955,
3000, 10002, 123456 };
//valid range -2055 to 2055 inclusive
Pattern p = Pattern.compile("^([-0][0-1][0-9][0-9][0-9])$|^([-0]20[0-4][0-9])$|^([-0]205[0-5])$");
for (int number : numbers) {
String string = String.format("%05d", number);
Matcher m = p.matcher(string);
if (m.find()) {
System.out.println(number + " is in range.");
} else {
System.out.println(number + " is not in range.");
}
}
output:
-10002 is not in range.
-3000 is not in range.
-2056 is not in range.
-2055 is in range.
-2000 is in range.
-1999 is in range.
-20 is in range.
-1 is in range.
0 is in range.
1 is in range.
260 is in range.
1999 is in range.
2000 is in range.
2046 is in range.
2055 is in range.
2056 is not in range.
2955 is not in range.
3000 is not in range.
10002 is not in range.
123456 is not in range.
Try this:
^-?0*(1?[0-9]{1,3}|20[0-4][0-9]|205[0-5])$
The regex before the brackets matches an optional - and any leading 0s.
The first part in the brackets (1?[0-9]{1,3}) matches 0-1999.
The second part in the brackets (20[0-4][0-9]) matches 2000-2049.
The third part in the brackets (205[0-5]) matches 2050-2055.
Yet another -
# ^-?0*(?:20(?:[0-4][0-9]|5[0-5])|[0-9]{1,3})$
^
-?
0*
(?:
20
(?:
[0-4] [0-9]
|
5 [0-5]
)
|
[0-9]{1,3}
)
$

limit string in preg_match on php

Thanks for visit or just see my question.
I try to catch some pattern in string on php.
pattern :
min char = 100
max char = 100
contains [a-z] and [A-Z] and [0-9] and "#" and "-" and "=" and "+"
It's return TRUE if all on pattern match and founds in string.
else it will return FALSE.
$string = "jhJH#KJNkj-HJV=+0ksdbscasdJNKajcajnacakjBKBKjbidcubiISABUIhsdbchdsiweucIBHbhbHBUJHBjhJHBIYBHBCwJHBdcd";
if (preg_match("/^.*(?=.{100,100})(?=.*\d)(?=.*[a-z])(?=.*[A-Z])(?=.*[#])(?=.*[-])(?=.*[=])(?=.*[+]).*$/", $string)){
$result1 = true;
} else {
$result1 = false;
}
This works if the 100 char, But this is return TRUE too if the string length more than 100 digits.
I want return TRUE if string length not below 100 digits and not more than 100 digits and it should be contains a pattern.
Maybe any suggestions, in the pattern?
Thanks in advances
You failed to actually set the min and max length as you allow 0+ any chars other than a newline before actually requiring 100 chars in the string. You need to use
'/^(?=\D*\d)(?=[^a-z]*[a-z])(?=[^A-Z]*[A-Z])(?=[^#]*#)(?=[^-]*-)(?=[^=]*=)(?=[^+]*[+]).{0,100}$/s'
^^^^^^^
Here, the pattern will match 0 to 100 any chars incl. a newline (as /s allows . to match a newline) and requiring at least 1 digit, 1 lowercase, 1 uppercase, 1 #, 1-, 1 = and one +.
Actually, there are 7 conditions with specific requirements, so in fact, the minimum will be 7 chars. You need to adjust this pattern to what you really need.

How do you find 3 UNIQUE digits in a string of digits?

I am trying to write a regex that is very specific. I want to find 3 digits in a list. The issue comes because I do not care about repeating digits (5, 555, and 55555555555555 are seen as 5). Also, within the 3 digits, they need to be 3 different digits (123 = good, 311 = bad).
Here is what I have so far to find 3 digits, ignoring repeats but it does not specify 3 unique digits.
^(?:([0]{1,}|[1]{1,}|[2]{1,}|[3]{1,}|[4]{1,}|[5]{1,}|[6]{1,}|[7]{1,}|[8]{1,}|[9]{1,}|[0]{1,})(?!.*\\1)){3}$<p>
Here is an example of the types of data I see.
Matching:
458
3333335555111
2222555111
222255558888
111147
9533333333
And not matching:
999999999
222252
888887
Right now my regex will find all of these. How can I ignore any that do not have 3 unique digits?
If your regex-tool of choice supports look-behinds, back-references and possesive matching you could use
^(\d)\1*+(?!.*\1)(\d)\2*+(\d)\3*+$
^ and $ are anchors to ensure, that we check the whole string
(\d) matches a digit into a first capturing group, with \1*+ we possesively match any following occurences of this digit and use the lookbehind (?!.*\1) to ensure, that it doesn't end with that number.
(\d)\2*+ then matches the next different digit, again matching any following occurences possesively (check 122 without the possesive matching to see, why I use it here)
(\d)\3*+ matches the last digit with any following occurences.
Without possesive matching you could make more use of look-behinds, like ^(\d)\1*(?!.*\1)(\d)\2*(?!.*\2)(\d)\3*+$
See https://regex101.com/r/pV2tB2/2 for a demo.
Site Note: Regex might not be the best for this, but as you specifically asked for it - here you are.
This can be done with regex, but it's not the best tool for your work.
Instead of a regex-only approach, you can easily achieve this using Python.
Example:
strings = ['458', '3333335555111', '2222555111', '222255558888', '111147', '9533333333', '955555555', '12222211']
for s in strings:
if len(set(list(s))) == 3:
print "Ok :", s
else:
print "Error :", s
Output:
>> Ok : 458
>> Ok : 3333335555111
>> Ok : 2222555111
>> Ok : 222255558888
>> Ok : 111147
>> Ok : 9533333333
>> Error : 955555555
>> Error : 12222211
I've used the following commands while iterating over the strings inside that list:
list()
set()
len()
Using negative lookahead, this should match any string of digits that contains at least 3 unique digits /^(\d)\1*(?!\1)(\d)(?:\2|\1)*(?!\2|\1)(\d)+$/
(\d) - Match a digit
\1* - Allow that digit to repeat
(?!\1) - Make sure that's followed by a digit that does not match the first match
(\d) - Match the new digit
(?:\2|\1)* - Allow repeats of either the first or second digit
(?!\2|\1) - Make sure that's followed by a digit that does not match the first or second match
(\d)+ - Capture the third unique digit, then allow any number of digits of any kind to follow
I'm not sure if an awk script will do it for you, but here it goes:
awk '
function match_func(num) {
if (match_array[num] == 0)
match_array[num] = 1;
}
{
for (i = 0; i < length($1); i++)
match_func(substr($1, i, 1));
for (i = 0; i < 10; i++)
if (match_array[i] == 1) match_sum++;
if (match_sum == 3)
print $1;
}'

RegEx Numerical Range 0-35 [duplicate]

My input number is an int. But the input number must be in a range from -2055 to 2055 and I want to check this by using regular expression.
So is there anyway to write a regular expression to check whether a number is in (-2055, 2055) or not ?
It is easier to use if statement to check whether the number is in range or not. But I'm writing an interpreter so I should use regex to check the input number
Using regular expressions to validate a numeric range
To be clear: When a simple if statement will suffice
if(num < -2055 || num > 2055) {
throw new IllegalArgumentException("num (" + num + ") must be between -2055 and 2055");
}
using regular expressions for validating numeric ranges is not recommended.
In addition, since regular expressions analyze strings, numbers must first be translated to a string before they can be tested. An exception is when the number happens to already be a string, such as when getting user input from the console.
(To ensure the string is a number to begin with, you could use org.apache.commons.lang3.math.NumberUtils#isNumber(s))
Despite this, figuring out how to validate number ranges with regular expressions is interesting and instructive.
(The links in this answer come from the Stack Overflow Regular Expressions FAQ.)
A one number range
Rule: A number must be exactly 15.
The simplest range there is. A regex to match this is
\b15\b
Word boundaries are necessary to avoid matching the 15 inside of 8215242.
A two number range
The rule: The number must be between 15 and 16. Here are three possible regexes:
\b(15|16)\b
\b1(5|6)\b
\b1[5-6]\b
(The groups are required for the "or"-ing, but they could be non-capturing: \b(?:15|16)\b)
A number range "mirrored" around zero
The rule: The number must be between -12 and 12.
Here is a regex for 0 through 12, positive-only:
\b(\d|1[0-2])\b
Free-spaced:
\b( //The beginning of a word (or number), followed by either
\d // Any digit 0 through 9
| //Or
1[0-2] // A 1 followed by any digit between 0 and 2.
)\b //The end of a word
Making this work for both negative and positive is as simple as adding an optional dash at the start:
-?\b(\d|1[0-2])\b
(This assumes no inappropriate characters precede the dash.)
To forbid negative numbers, a negative lookbehind is necessary:
(?<!-)\b(\d|1[0-2])\b
Leaving the lookbehind out would cause the 11 in -11 to match. (The first example in this post should have this added.)
Note: \d versus [0-9]
In order to be compatible with all regex flavors, all \d-s should be changed to [0-9]. For example, .NET considers non ASCII numbers, such as those in different languages, as legal values for \d. Except for in the last example, for brevity, it's left as \d.
(With thanks to #TimPietzcker)
Three digits, with all but the first digit equal to zero
Rule: Must be between 0 and 400.
A possible regex:
(?<!-)\b([1-3]?\d{1,2}|400)\b
Free spaced:
(?<!-) //Something not preceded by a dash
\b( //Word-start, followed by either
[1-3]? // No digit, or the digit 1, 2, or 3
\d{1,2} // Followed by one or two digits (between 0 and 9)
| //Or
400 // The number 400
)\b //Word-end
Another possibility that should never be used:
\b(0|1|2|3|4|5|6|7|8|9|10|11|12|13|14|15|16|17|18|19|20|21|22|23|24|25|26|27|28|29|30|31|32|33|34|35|36|37|38|39|40|41|42|43|44|45|46|47|48|49|50|51|52|53|54|55|56|57|58|59|60|61|62|63|64|65|66|67|68|69|70|71|72|73|74|75|76|77|78|79|80|81|82|83|84|85|86|87|88|89|90|91|92|93|94|95|96|97|98|99|100|101|102|103|104|105|106|107|108|109|110|111|112|113|114|115|116|117|118|119|120|121|122|123|124|125|126|127|128|129|130|131|132|133|134|135|136|137|138|139|140|141|142|143|144|145|146|147|148|149|150|151|152|153|154|155|156|157|158|159|160|161|162|163|164|165|166|167|168|169|170|171|172|173|174|175|176|177|178|179|180|181|182|183|184|185|186|187|188|189|190|191|192|193|194|195|196|197|198|199|200|201|202|203|204|205|206|207|208|209|210|211|212|213|214|215|216|217|218|219|220|221|222|223|224|225|226|227|228|229|230|231|232|233|234|235|236|237|238|239|240|241|242|243|244|245|246|247|248|249|250|251|252|253|254|255|256|257|258|259|260|261|262|263|264|265|266|267|268|269|270|271|272|273|274|275|276|277|278|279|280|281|282|283|284|285|286|287|288|289|290|291|292|293|294|295|296|297|298|299|300|301|302|303|304|305|306|307|308|309|310|311|312|313|314|315|316|317|318|319|320|321|322|323|324|325|326|327|328|329|330|331|332|333|334|335|336|337|338|339|340|341|342|343|344|345|346|347|348|349|350|351|352|353|354|355|356|357|358|359|360|361|362|363|364|365|366|367|368|369|370|371|372|373|374|375|376|377|378|379|380|381|382|383|384|385|386|387|388|389|390|391|392|393|394|395|396|397|398|399|400)\b
Final example: Four digits, mirrored around zero, that does not end with zeros.
Rule: Must be between -2055 and 2055
This is from a question on stackoverflow.
Regex:
(-?\b(?:20(?:5[0-5]|[0-4][0-9])|1[0-9]{3}|[1-9][0-9]{0,2}|(?<!-)0+))\b
Debuggex Demo
Free-spaced:
( //Capture group for the entire number
-?\b //Optional dash, followed by a word (number) boundary
(?:20 //Followed by "20", which is followed by one of
(?:5[0-5] //50 through 55
| //or
[0-4][0-9]) //00 through 49
| //or
1[0-9]{3} //a one followed by any three digits
| //or
[1-9][0-9]{0,2} //1-9 followed by 0 through 2 of any digit
| //or
(?<!-)0+ //one-or-more zeros *not* preceded by a dash
) //end "or" non-capture group
)\b //End number capture group, followed by a word-bound
(With thanks to PlasmaPower and Casimir et Hippolyte for the debugging assistance.)
Final note
Depending on what you are capturing, it is likely that all sub-groups should be made into non-capture groups. For example, this:
(-?\b(?:20(?:5[0-5]|[0-4][0-9])|1?[0-9]{1,3})\b)
Instead of this:
-?\b(20(5[0-5]|[0-4][0-9])|1?[0-9]{1,3})\b
Example Java implementation
import java.util.Scanner;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
import org.apache.commons.lang.math.NumberUtils;
/**
<P>Confirm a user-input number is a valid number by reading a string an testing it is numeric before converting it to an it--this loops until a valid number is provided.</P>
<P>{#code java UserInputNumInRangeWRegex}</P>
**/
public class UserInputNumInRangeWRegex {
public static final void main(String[] ignored) {
int num = -1;
boolean isNum = false;
int iRangeMax = 2055;
//"": Dummy string, to reuse matcher
Matcher mtchrNumNegThrPos = Pattern.compile("(-?\\b(?:20(?:5[0-5]|[0-4][0-9])|1[0-9]{3}|[1-9][0-9]{0,2}|(?<!-)0+))\\b").matcher("");
do {
System.out.print("Enter a number between -" + iRangeMax + " and " + iRangeMax + ": ");
String strInput = (new Scanner(System.in)).next();
if(!NumberUtils.isNumber(strInput)) {
System.out.println("Not a number. Try again.");
} else if(!mtchrNumNegThrPos.reset(strInput).matches()) {
System.out.println("Not in range. Try again.");
} else {
//Safe to convert
num = Integer.parseInt(strInput);
isNum = true;
}
} while(!isNum);
System.out.println("Number: " + num);
}
}
Output
[C:\java_code\]java UserInputNumInRangeWRegex
Enter a number between -2055 and 2055: tuhet
Not a number. Try again.
Enter a number between -2055 and 2055: 283837483
Not in range. Try again.
Enter a number between -2055 and 2055: -200000
Not in range. Try again.
Enter a number between -2055 and 2055: -300
Number: -300
Original answer to this stackoverflow question
This is a serious answer that fits your specifications. It is similar to #PlasmaPower's answer.
(-?\b(?:20(?:5[0-5]|[0-4][0-9])|1[0-9]{3}|[1-9][0-9]{0,2}|(?<!-)0+))\b
Debuggex Demo
Don't ever use it, but this works. :)
\b(-2055|-2054|-2053|-2052|-2051|-2050|-2049|-2048|-2047|-2046|-2045|-2044|-2043|-2042|-2041|-2040|-2039|-2038|-2037|-2036|-2035|-2034|-2033|-2032|-2031|-2030|-2029|-2028|-2027|-2026|-2025|-2024|-2023|-2022|-2021|-2020|-2019|-2018|-2017|-2016|-2015|-2014|-2013|-2012|-2011|-2010|-2009|-2008|-2007|-2006|-2005|-2004|-2003|-2002|-2001|-2000|-1999|-1998|-1997|-1996|-1995|-1994|-1993|-1992|-1991|-1990|-1989|-1988|-1987|-1986|-1985|-1984|-1983|-1982|-1981|-1980|-1979|-1978|-1977|-1976|-1975|-1974|-1973|-1972|-1971|-1970|-1969|-1968|-1967|-1966|-1965|-1964|-1963|-1962|-1961|-1960|-1959|-1958|-1957|-1956|-1955|-1954|-1953|-1952|-1951|-1950|-1949|-1948|-1947|-1946|-1945|-1944|-1943|-1942|-1941|-1940|-1939|-1938|-1937|-1936|-1935|-1934|-1933|-1932|-1931|-1930|-1929|-1928|-1927|-1926|-1925|-1924|-1923|-1922|-1921|-1920|-1919|-1918|-1917|-1916|-1915|-1914|-1913|-1912|-1911|-1910|-1909|-1908|-1907|-1906|-1905|-1904|-1903|-1902|-1901|-1900|-1899|-1898|-1897|-1896|-1895|-1894|-1893|-1892|-1891|-1890|-1889|-1888|-1887|-1886|-1885|-1884|-1883|-1882|-1881|-1880|-1879|-1878|-1877|-1876|-1875|-1874|-1873|-1872|-1871|-1870|-1869|-1868|-1867|-1866|-1865|-1864|-1863|-1862|-1861|-1860|-1859|-1858|-1857|-1856|-1855|-1854|-1853|-1852|-1851|-1850|-1849|-1848|-1847|-1846|-1845|-1844|-1843|-1842|-1841|-1840|-1839|-1838|-1837|-1836|-1835|-1834|-1833|-1832|-1831|-1830|-1829|-1828|-1827|-1826|-1825|-1824|-1823|-1822|-1821|-1820|-1819|-1818|-1817|-1816|-1815|-1814|-1813|-1812|-1811|-1810|-1809|-1808|-1807|-1806|-1805|-1804|-1803|-1802|-1801|-1800|-1799|-1798|-1797|-1796|-1795|-1794|-1793|-1792|-1791|-1790|-1789|-1788|-1787|-1786|-1785|-1784|-1783|-1782|-1781|-1780|-1779|-1778|-1777|-1776|-1775|-1774|-1773|-1772|-1771|-1770|-1769|-1768|-1767|-1766|-1765|-1764|-1763|-1762|-1761|-1760|-1759|-1758|-1757|-1756|-1755|-1754|-1753|-1752|-1751|-1750|-1749|-1748|-1747|-1746|-1745|-1744|-1743|-1742|-1741|-1740|-1739|-1738|-1737|-1736|-1735|-1734|-1733|-1732|-1731|-1730|-1729|-1728|-1727|-1726|-1725|-1724|-1723|-1722|-1721|-1720|-1719|-1718|-1717|-1716|-1715|-1714|-1713|-1712|-1711|-1710|-1709|-1708|-1707|-1706|-1705|-1704|-1703|-1702|-1701|-1700|-1699|-1698|-1697|-1696|-1695|-1694|-1693|-1692|-1691|-1690|-1689|-1688|-1687|-1686|-1685|-1684|-1683|-1682|-1681|-1680|-1679|-1678|-1677|-1676|-1675|-1674|-1673|-1672|-1671|-1670|-1669|-1668|-1667|-1666|-1665|-1664|-1663|-1662|-1661|-1660|-1659|-1658|-1657|-1656|-1655|-1654|-1653|-1652|-1651|-1650|-1649|-1648|-1647|-1646|-1645|-1644|-1643|-1642|-1641|-1640|-1639|-1638|-1637|-1636|-1635|-1634|-1633|-1632|-1631|-1630|-1629|-1628|-1627|-1626|-1625|-1624|-1623|-1622|-1621|-1620|-1619|-1618|-1617|-1616|-1615|-1614|-1613|-1612|-1611|-1610|-1609|-1608|-1607|-1606|-1605|-1604|-1603|-1602|-1601|-1600|-1599|-1598|-1597|-1596|-1595|-1594|-1593|-1592|-1591|-1590|-1589|-1588|-1587|-1586|-1585|-1584|-1583|-1582|-1581|-1580|-1579|-1578|-1577|-1576|-1575|-1574|-1573|-1572|-1571|-1570|-1569|-1568|-1567|-1566|-1565|-1564|-1563|-1562|-1561|-1560|-1559|-1558|-1557|-1556|-1555|-1554|-1553|-1552|-1551|-1550|-1549|-1548|-1547|-1546|-1545|-1544|-1543|-1542|-1541|-1540|-1539|-1538|-1537|-1536|-1535|-1534|-1533|-1532|-1531|-1530|-1529|-1528|-1527|-1526|-1525|-1524|-1523|-1522|-1521|-1520|-1519|-1518|-1517|-1516|-1515|-1514|-1513|-1512|-1511|-1510|-1509|-1508|-1507|-1506|-1505|-1504|-1503|-1502|-1501|-1500|-1499|-1498|-1497|-1496|-1495|-1494|-1493|-1492|-1491|-1490|-1489|-1488|-1487|-1486|-1485|-1484|-1483|-1482|-1481|-1480|-1479|-1478|-1477|-1476|-1475|-1474|-1473|-1472|-1471|-1470|-1469|-1468|-1467|-1466|-1465|-1464|-1463|-1462|-1461|-1460|-1459|-1458|-1457|-1456|-1455|-1454|-1453|-1452|-1451|-1450|-1449|-1448|-1447|-1446|-1445|-1444|-1443|-1442|-1441|-1440|-1439|-1438|-1437|-1436|-1435|-1434|-1433|-1432|-1431|-1430|-1429|-1428|-1427|-1426|-1425|-1424|-1423|-1422|-1421|-1420|-1419|-1418|-1417|-1416|-1415|-1414|-1413|-1412|-1411|-1410|-1409|-1408|-1407|-1406|-1405|-1404|-1403|-1402|-1401|-1400|-1399|-1398|-1397|-1396|-1395|-1394|-1393|-1392|-1391|-1390|-1389|-1388|-1387|-1386|-1385|-1384|-1383|-1382|-1381|-1380|-1379|-1378|-1377|-1376|-1375|-1374|-1373|-1372|-1371|-1370|-1369|-1368|-1367|-1366|-1365|-1364|-1363|-1362|-1361|-1360|-1359|-1358|-1357|-1356|-1355|-1354|-1353|-1352|-1351|-1350|-1349|-1348|-1347|-1346|-1345|-1344|-1343|-1342|-1341|-1340|-1339|-1338|-1337|-1336|-1335|-1334|-1333|-1332|-1331|-1330|-1329|-1328|-1327|-1326|-1325|-1324|-1323|-1322|-1321|-1320|-1319|-1318|-1317|-1316|-1315|-1314|-1313|-1312|-1311|-1310|-1309|-1308|-1307|-1306|-1305|-1304|-1303|-1302|-1301|-1300|-1299|-1298|-1297|-1296|-1295|-1294|-1293|-1292|-1291|-1290|-1289|-1288|-1287|-1286|-1285|-1284|-1283|-1282|-1281|-1280|-1279|-1278|-1277|-1276|-1275|-1274|-1273|-1272|-1271|-1270|-1269|-1268|-1267|-1266|-1265|-1264|-1263|-1262|-1261|-1260|-1259|-1258|-1257|-1256|-1255|-1254|-1253|-1252|-1251|-1250|-1249|-1248|-1247|-1246|-1245|-1244|-1243|-1242|-1241|-1240|-1239|-1238|-1237|-1236|-1235|-1234|-1233|-1232|-1231|-1230|-1229|-1228|-1227|-1226|-1225|-1224|-1223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Check out this great tool which generates a regex for numeric ranges:
http://gamon.webfactional.com/regexnumericrangegenerator/
For the range requested by OP it generates: -?([0-9]{1,3}|1[0-9]{3}|20[0-4][0-9]|205[0-5])
Analyze the problem
If you "must" use a regex, break the problem down by analysing the accepted permutations.
"a range from -2055 to 2055" can be expressed as:
an optional -
optional leading zeros
followed by a number from 0 to 2055
"A number from 0 to 2055" can be one of a finite number of specific permutations:
one digit (0-9)
two digits (10-99)
three digits (100-999)
four digits starting with a 1 (1000-1999)
four digits starting with 20 (2000-204*9)
four digits starting with 205 (2050-2055*)
Note that for the purpose of this regex, it's not necessary to distinguish between the range "0-9" and "1-9", and only the last two ranges have any restrictions on the range of accepted digits/characters (indicated with a star).
Write component regex expressions
Each of the above component parts are easy to individually express as a regular expression:
-?
0*
[0-9]
[0-9][0-9]
[0-9][0-9][0-9]
1[0-9][0-9][0-9]
20[0-4][0-9]
205[0-5]
Put the expressions together
The relevant expression for the whole match would be:
-?0*([0-9]|[0-9][0-9]|[0-9][0-9][0-9]|1[0-9][0-9][0-9]|20[0-4][0-9]|205[0-5])
Or slightly more concisely:
-?0*([0-9]{1,3}|1[0-9]{3}|20[0-4][0-9]|205[0-5])
Assuming the input contains only "the number" and nothing else, the final regex is therefore:
^-?0*([0-9]{1,3}|1[0-9]{3}|20[0-4][0-9]|205[0-5])$
If it's necessary to allow for a leading plus sign, this becomes:
^[-+]?0*([0-9]{1,3}|1[0-9]{3}|20[0-4][0-9]|205[0-5])$
Here's a js fiddle demonstrating what passes and what would fails the last regex.
So many answers, but noone reads (or cares) about the OPs side question in the comments?
I'm writing an interpreter in OCaml .... how can i validate the input
number within the range without using regex ?? – Trung Nguyen Mar 2
at 17:30
As so many answers - correctly - pointed out that using regex is horrible for this scenario, lets think about other ways in OCaml! It is a while since I used OCaml, but with looking up a few constructs I was able to knock this together:
let isInRange i =
not (i < -2055 or i > 2055);;
let isIntAndInRange s =
try
let i = int_of_string s in
not (i < -2055 or i > 2055)
with
Failure "int_of_string" -> false;;
let () = print_string "type a number: " in
let s = read_line () in
isIntAndInRange s
If anything about is unclear, please read up on its syntax, type conversion functions and exception handling and input-output functions.
The user input part is only used to demonstrate. It might be more convenient to use the read_int function there. But the basic concept of handling the exception stays the same.
As of OCaml 4.02 this can be cleaned up a bit since exception handling can be done in a match.
let isIntAndInRange s =
match int_of_string s with
| i when i >= -2055 && i <= 2055 -> true
| _
| exception Failure _ -> false
As an alternate approach to the great expression offered by aliteralmind, here is one that is much longer but interesting in order to see what another approach might look like (and what not to do).
It's an interesting exercise, because you can think of two distinct method: roughly, you can either:
proceed by matching 4-char numbers, then 3-char numbers, etc.
or proceed by matching the thousands digit, then the hundreds digit, etc.
Without trying, how would you know which is best? It turns out that the first approach (aliteralmind's answer) is far more economical.
Lower, I include a series of tests in the PHP language in case you or someone else would like to check the output.
Below, I will give you the regex in "free-spacing mode", which allows comments inside the regex so you can easily understand what it does. However, not all regex engines support free-spacing mode, so before we start with the interesting part, here is the regex as a one-liner.
Note that your question mentions numbers from -2055 to 2055. I assumed that you wanted to match "normal numbers", without leading zeroes. This means that the regex will match 999 but not 0999. If you would like leading zeroes, let me know, that is a very easy tweak.
Also, if you are matching in utf-8 mode, the \d should be replaced by [0-9]. This is the more common form.
The Regex as a One-Liner
^(?!-0$)-?(?:(?=\d{4}$)[12])?(?:(?=\d{3}$)(?:(?:(?<=^)|(?<=^-)|(?<=1)|(?<=-1))\d|(?:(?<=2)|(?<=-2))0))?(?:(?=\d{2}$)(?:(?:(?<=^)|(?<=^-)|(?<=^\d)|(?<=^-\d)|(?<=^\d{2})(?<!20)|(?<=^-\d{2})(?<!-20))\d|(?:(?<=20)|(?<=-20))[0-5]))?(?:(?=\d$)(?:(?:(?<=^)|(?<=^-)|(?<=^\d)|(?<=^-\d)|(?<=^\d{2})|(?<=^-\d{2})|(?<=^\d{3})(?<!205)|(?<=^-\d{3})(?<!-205))\d|(?:(?<=205)|(?<=-205))[0-5]))$
The Regex in Free-Spacing Mode
(?x) # free-spacing mode
^ # anchor at beginning of string.
(?!-0$)-? # optional minus sign, but not for -0
(?: # OPTIONAL THOUSANDS DIGIT
(?=\d{4}$)[12] # assert that the number is 4-digit long, match 1 or 2
)? # end optional thousands digit
(?: # OPTIONAL HUNDREDS DIGIT
(?=\d{3}$) # assert that there are three digits left
(?: # non-capturing group
(?:(?<=^)|(?<=^-)|(?<=1)|(?<=-1))\d # if preceding chars are 1, -1 or head of string: value can be any digit
| # or
(?:(?<=2)|(?<=-2))0 # if preceding chars are 2 or -2: value must be 0
) # close non-capturing group
)? # end optional hundreds digits
(?: # OPTIONAL TENS DIGIT
(?=\d{2}$) # assert that there are two digits left
(?: # start non-capturing group
# if preceding char is head of string, single digit,
# or two digits that are not 20
# (with or without a minus)
# value can be any digit
(?:(?<=^)|(?<=^-)|(?<=^\d)|(?<=^-\d)|
(?<=^\d{2})(?<!20)|(?<=^-\d{2})(?<!-20))\d
| # or
(?:(?<=20)|(?<=-20))[0-5] # if preceding chars are 20 or -20: value can be from 0 to 5
) # end non-capturing group
)? # close optional tens digits
(?: # FINAL DIGIT (non optional)
(?=\d$) # assert that there is only one digit left
(?: # start non-capturing group
# if preceding char is head of string, single digit,
# two digits, or three digits that are not 205
# (with or without a minus)
# value can be any digit
(?:(?<=^)|(?<=^-)|(?<=^\d)|(?<=^-\d)|
(?<=^\d{2})|(?<=^-\d{2})|
(?<=^\d{3})(?<!205)|(?<=^-\d{3})(?<!-205))
\d
| # or
(?:(?<=205)|(?<=-205))[0-5] # if preceding chars are 205 or -205: value can be from 0 to 5
) # end non-capturing group
) # end final digit
$
Series of Tests
These tests try to match against numbers from -100000 to 100000. They produce the following output:
Successful test: matches from -2055 to 2055
Successful test: NO matches from -100000 to -2056
Successful test: NO matches from 2056 to 100000
Here is the code:
<?php
$regex="~^(?!-0$)-?(?:(?=\d{4}$)[12])?(?:(?=\d{3}$)(?:(?:(?<=^)|(?<=^-)|(?<=1)|(?<=-1))\d|(?:(?<=2)|(?<=-2))0))?(?:(?=\d{2}$)(?:(?:(?<=20)|(?<=-20))[0-5]|(?:(?<=^)|(?<=^-)|(?<=^\d)|(?<=^-\d)|(?<=^\d{2})(?<!20)|(?<=^-\d{2})(?<!-20))\d))?(?:(?=\d$)(?:(?:(?<=205)|(?<=-205))[0-5]|(?:(?<=^)|(?<=^-)|(?<=^\d)|(?<=^-\d)|(?<=^\d{2})|(?<=^-\d{2})|(?<=^\d{3})(?<!205)|(?<=^-\d{3})(?<!-205))\d))$~";
// Test 1
$success="Successful test: matches from -2055 to 2055";
for($i=-2055;$i<=2055;$i++) {
$chari = sprintf("%d",$i);
if (! preg_match($regex,$chari)) {
$success="Failed test: matches from -2055 to 2055";
echo $chari.": No Match!<br />";
}
}
echo $success."<br />";
// Test 2
$success="Successful test: NO matches from -100000 to -2056";
for($i=-100000;$i<=-2056;$i++) {
$chari = sprintf("%d",$i);
if (preg_match($regex,$chari)) {
$success="Failed test: NO matches from -100000 to -2056";
echo $chari.": Match!<br />";
}
}
echo $success."<br />";
// Test 3
$success="Successful test: NO matches from 2056 to 100000";
for($i=2056;$i<=100000;$i++) {
$chari = sprintf("%d",$i);
if (preg_match($regex,$chari)) {
$success="Failed test: NO matches from 2056 to 100000";
echo $chari.": Match!<br />";
}
}
echo $success."<br />";
?>
Speed Tests
Here is the output of my simple speed test, matching from -1M to +1M. As Casimir pointed out, if aliteralmind's expression were anchored, instead of being slower it would be faster by 25%!
zx81: 3.796217918396
aliteralmind: 3.9922280311584
difference: 5.1632998151294 percent longer
Here is the test code:
$regex="~(?x)^(?!-0$)-?(?:(?=\d{4}$)[12])?(?:(?=\d{3}$)(?:(?:(?<=^)|(?<=^-)|(?<=1)|(?<=-1))\d|(?:(?<=2)|(?<=-2))0))?(?:(?=\d{2}$)(?:(?:(?<=^)|(?<=^-)|(?<=^\d)|(?<=^-\d)|(?<=^\d{2})(?<!20)|(?<=^-\d{2})(?<!-20))\d|(?:(?<=20)|(?<=-20))[0-5]))?(?:(?=\d$)(?:(?:(?<=^)|(?<=^-)|(?<=^\d)|(?<=^-\d)|(?<=^\d{2})|(?<=^-\d{2})|(?<=^\d{3})(?<!205)|(?<=^-\d{3})(?<!-205))\d|(?:(?<=205)|(?<=-205))[0-5]))$~";
$regex2 = "~(-?\b(?:20(?:5[0-5]|[0-4][0-9])|1[0-9]{3}|[1-9][0-9]{0,2}|(?<!-)0+))\b~";
$start=microtime(TRUE);
for ($i=-1000000;$i<1000000;$i++) preg_match($regex,$i);
$zxend=microtime(TRUE);
for ($i=-1000000;$i<1000000;$i++) preg_match($regex2,$i);
$alitend=microtime(TRUE);
$zx81 = $zxend-$start;
$alit = $alitend-$zxend;
$diff = 100*($alit-$zx81)/$zx81;
echo "zx81: ".$zx81."<br />";
echo "aliteralmind: ".$alit."<br />";
echo "difference: ".$diff." percent longer<br />";
Why use Regex only to check a number?
int n = -2000;
if(n >= -2055 && n <= 2055)
//Do something
else
//Do something else
Try this:
\-?\b0*(205[0-5]|20[0-4]\d|1?\d{3}|\d{1,2})\b
Try with a very simple regex.
^([-0][0-1][0-9][0-9][0-9])$|^([-0]20[0-4][0-9])$|^([-0]205[0-5])$
Visual representation
It's very simple to understand.
group 1 [-0][0-1][0-9][0-9][0-9] will cover [-1999, 1999] values
group 2 [-0]20[0-4][0-9] will cover [-2000,-2049] and [2000,2049] values
group 3 [-0]205[0-5] will cover [-2050, -2055] and [2050, 2055] values
String.format("%05d", number) is doing very well done job here?
Sample code: (Read inline comments for more clarity.)
int[] numbers = new int[] { -10002, -3000, -2056, -2055, -2000, -1999, -20,
-1, 0, 1, 260, 1999, 2000, 2046, 2055, 2056, 2955,
3000, 10002, 123456 };
//valid range -2055 to 2055 inclusive
Pattern p = Pattern.compile("^([-0][0-1][0-9][0-9][0-9])$|^([-0]20[0-4][0-9])$|^([-0]205[0-5])$");
for (int number : numbers) {
String string = String.format("%05d", number);
Matcher m = p.matcher(string);
if (m.find()) {
System.out.println(number + " is in range.");
} else {
System.out.println(number + " is not in range.");
}
}
output:
-10002 is not in range.
-3000 is not in range.
-2056 is not in range.
-2055 is in range.
-2000 is in range.
-1999 is in range.
-20 is in range.
-1 is in range.
0 is in range.
1 is in range.
260 is in range.
1999 is in range.
2000 is in range.
2046 is in range.
2055 is in range.
2056 is not in range.
2955 is not in range.
3000 is not in range.
10002 is not in range.
123456 is not in range.
Try this:
^-?0*(1?[0-9]{1,3}|20[0-4][0-9]|205[0-5])$
The regex before the brackets matches an optional - and any leading 0s.
The first part in the brackets (1?[0-9]{1,3}) matches 0-1999.
The second part in the brackets (20[0-4][0-9]) matches 2000-2049.
The third part in the brackets (205[0-5]) matches 2050-2055.
Yet another -
# ^-?0*(?:20(?:[0-4][0-9]|5[0-5])|[0-9]{1,3})$
^
-?
0*
(?:
20
(?:
[0-4] [0-9]
|
5 [0-5]
)
|
[0-9]{1,3}
)
$