Jmeter - find with regex and replace part of XML body using groovy - regex

Question

I'm trying to replace part an XML response data with something else.
Here is an example:
?xml version="1.0" encoding="UTF-8"?>
<trustedDevices><trustedDevice><id>1942</id><name>BksQ9LKwWuNOHpn</name></trustedDevice><trustedDevice><id>1944</id><name>6f4srs4PkJk1j36</name></trustedDevice><trustedDevice><id>1943</id><name>7cGYVAlmQoXaVrf</name></trustedDevice></trustedDevices>
I'm trying to get all the <name>(.+?)<\/name> data and replace it with something else (timestamp or random string)
so far, my groovy post processor code looks like this:
String trustedDevices = prev.getResponseDataAsString()
log.info('Response: ' + trustedDevices)
def nameFind = "/<name>(.+?)<\/name>/"
def newTrustedDevices = trustedDevices.replaceAll(nameFind, "test")
log.info('New response: ' + newTrustedDevices)
Unfortunately it seems that replaceAll requires String or Long to work, and won't work with regex.

Answer 1

You regex just need a correct escaping:
def nameFind = "<name>(.+?)<\\/name>"

Answer 2

Replacing values in XML using regular expressions is not the best option as it will be fragile and very sensitive to any markup change.
I would suggest going for Groovy's XML parsing capabilities instead
Example code:
def trustedDevices = new XmlSlurper().parseText(prev.getResponseDataAsString())
trustedDevices.trustedDevice.findAll().each {
it.name = 'test'
}
def newTrustedDevices = new StreamingMarkupBuilder().bind { mkp.yield trustedDevices }.toString()
More information on Groovy scripting in JMeter: Apache Groovy - Why and How You Should Use It