Good morning Stack Overflow,
I have a question, I do have a list of Timestamp, I believe there are Unix Time Stamp, I'd like to convert to datetime on PBI, but I'm getting an error, using the following formula :' #datetime(1957,1,1,0,0,0) + #duration(0,0,0,[Timestamp]) ' , Timestamp is the column that I'd like to convert.
Below a sample list of the data :
Is there a way to fix this issue?
You're close but you need to remember that Unix timestamps are recorded in milliseconds since 1970, not seconds since 1957. Try this instead
#datetime(1970, 1, 1, 0, 0, 0) + #duration(0, 0, 0, [Timestamp]/1000)
Make sure the column is a datetime data type.
Related
I would like to find time band of half hour.Suppose i have a time stamp :
2019-03-12 01:20:00 this exists between time band of 1:00-1:30, similarly
2019-03-12 04:33:00 this exists between time band of 4:30-5:00.
I have column of n number of timestamp.
Is there any dax function that i can write to find the time band or there is any other process?
Thanks in advance!!
Consider something like this:
TimeBand =
FORMAT(FLOOR(MyTable[Timestamp], 1/48),"h:mm")
& " - "
& FORMAT(CEILING(MyTable[Timestamp], 1/48),"h:mm")
Floor and Ceiling are very similar functions -- they essentially round to the nearest multiple. Floor picks the biggest multiple that is smaller, and ceiling picks the smallest multiple that is bigger. Usually we round to powers of 10, but with this function we can round to the nearest 5, or 7, or 1/3.
Combine this with the understanding that PowerBI values all datetimes as a special kind of number -- it is simply the count of days since 12/30/1899. (Try it, create a calculated column and set its value to 0, then display it as a date time). So in this system "1" is one day. That means 1/24 is one hour, and 1/24/60 is one minute. It follows, then, that 30/24/60 is 30 minutes, and that reduces to 1/48.
So now we can take Floor/Ceiling, give it a time, and have it round that datetime to the nearest half-hour -- either down or up depending on which function you choose.
Use format to convert everything to text, and you're all set.
Here's some sample data generated in Power Query:
let
Source = List.Generate(()=> #datetime(2020,3,1,0,0,0), each _ < #datetime(2020,3,1,0,0,0) + #duration(1,0,0,0) , each _ + #duration(0,0,5,0)),
#"Converted to Table" = Table.FromList(Source, Splitter.SplitByNothing(), {"Timestamp"}, null, ExtraValues.Error)
in
#"Converted to Table"
And the results of our DAX:
Hope it Helps!
I'm looking for a way to convert a decimal number into a valid HH:mm:ss format.
I'm importing data from an SQL database.
One of the columns in my database is labelled Actual Start Time.
The values in my database are stored in the following decimal format:
73758 // which translates to 07:27:58
114436 // which translates to 11:44:36
I cannot simply convert this Actual Start Time column into a Time format in my Power BI import as it returns errors for some values, saying it doesn't recognise 73758 as a valid 'time'. It needs to have a leading zero for cases such as 73758.
To combat this, I created a new Text column with the following code to append a leading zero:
Column = FORMAT([Actual Start Time], "000000")
This returns the following results:
073758
114436
-- which is perfect. Exactly what I needed.
I now want to convert these values into a Time.
Simply changing the data type field to Time doesn't do anything, returning:
Cannot convert value '073758' of type Text to type Date.
So I created another column with the following code:
Column 2 = FORMAT(TIME(LEFT([Column], 2), MID([Column], 3, 2), RIGHT([Column], 2)), "HH:mm:ss")
To pass the values 07, 37 and 58 into a TIME format.
This returns the following:
_______________________________________
| Actual Start Date | Column | Column 2 |
|_______________________________________|
| 73758 | 073758 | 07:37:58 |
| 114436 | 114436 | 11:44:36 |
Which is what I wanted but is there any other way of doing this? I want to ideally do it in one step without creating additional columns.
You could use a variable as suggested by Aldert or you can replace Column by the format function:
Time Format = FORMAT(
TIME(
LEFT(FORMAT([Actual Start Time],"000000"),2),
MID(FORMAT([Actual Start Time],"000000"),3,2),
RIGHT([Actual Start Time],2)),
"hh:mm:ss")
Edit:
If you want to do this in Power query, you can create a customer column with the following calculation:
Time.FromText(
if Text.Length([Actual Start Time])=5 then Text.PadStart( [Actual Start Time],6,"0")
else [Actual Start Time])
Once this column is created you can drop the old column, so that you only have one time column in the data. Hope this helps.
I, on purpose show you the concept of variables so you can use this in future with more complex queries.
TimeC =
var timeStr = FORMAT([Actual Start Time], "000000")
return FORMAT(TIME(LEFT([timeStr], 2), MID([timeStr], 3, 2), RIGHT([timeStr], 2)), "HH:mm:ss")
I'm trying to investigate the Python time striptime method to decompose a time represented as 11:49:57.74. The standard %H, %M, %S are able to decompose the hour , minute , second. However, since the data is a string ( which is taken in python pandas column as datatype object, the Milliseconds after the decimal second is left uninterpreted. Hence, I get an error. Could someone please advise how to parse the example so that the seconds and microseconds are correctly interpreted from the time string ?
I would then use them to find the time delta between two time stamps.
I don't know if I had correctly understood your question.
So, to convert that string time to datetime and calculate the timedelta between two times you need to do as follow:
timedelta = str() #declare an empty string where save the timedelta
my_string = '11:49:57.74' # first example time
another_example_time = '13:49:57.74' #second example time, invented by me for the example
first_time = datetime.strptime(my_string, "%H:%M:%S.%f") # extract the first time
second_time = datetime.strptime(another_example_time , "%H:%M:%S.%f") # extract the second time
#calculate the time delta
if(first_time > second_time):
timedelta = first_time - second_time
else:
timedelta = second_time - first_time
print "The timedelta between %s and %s is: %s" % (first_time, second_time, timedelta)
Here obviusly you don't have any date, so the datetime library as default use 1900-01-01 as you can see in the result of the print:
The timedelta between 1900-01-01 11:49:57.740000 and 1900-01-01 13:49:57.740000 is: 2:00:00
I hope this solution is what you need. Next time provide a little bit more information please, or share an example with the code that you have tried to write.
I am trying to convert UTC timestamp to simple binary encoded message.
Would like to achieve what is mentioned in example here.
Binary Encoding Example
The following timestamp:
UTC timestamp 14:17:22 Friday, October 4, 2024
is expressed in binary code (nanoseconds since Unix epoch) this way:
007420bf8838fb17 (8 bytes in nanoseconds since Unix epoch synced to a master clock to microsecond accuracy.
What I have done so far is,
import struct
from datetime import datetime
dt = datetime(2024, 10, 4, 14, 17, 22, 0)
timestamp = (dt - datetime(1970, 1, 1)).total_seconds() * 1000000000
utc_timestamp = struct.pack('d', timestamp)
Output I see on CLI is '\xf4\x02\x82\xa1E\xfb\xb7C' but, as per example in shared link, expected is 007420bf8838fb17
TL;DR: I think there's either an error in linked example, or the description of the representation is incorrect or incomplete.
import struct
from datetime import datetime, timedelta, timezone
utc_tz = timezone(timedelta(0))
t = datetime(2024, 10, 4, 14, 17, 22, 0, utc_tz)
nanos = int(t.timestamp()) * 1_000_000_000
print(hex(timestamp))
This gives the result of 0x17fb45a18202f400, not the quoted 0x17fb3888bf297400 (as presented, I think it's a little-endian byte string, so this value has the order of bytes reversed).
The quoted answer, converted to decimal seconds (dividing by 1_000_000_000) is 1728037042.0005898. That value obviously has a sub-second quantity, which the source datetime does NOT have.
Decoding the seconds component of the quoted answer:
import time
answer = 0x17fb3888bf297400
secs = int(answer / 1_000_000_000)
print(time.gmtime(secs))
gives:
time.struct_time(tm_year=2024, tm_mon=10, tm_mday=4, tm_hour=10, tm_min=17, tm_sec=22, tm_wday=4, tm_yday=278, tm_isdst=0)
which looks almost correct, save that the hour component is 4 hours earlier. So ... my guess is that this is actually a US/Eastern timestamp (not UTC), and contains a sub-second component of 5898ns, and the example is misleading.
If the schema you're using is encoding timestamps as a 64-bit number of nanoseconds since the Unix epoch (midnight 1 January 1970), then I think your example code has only one error: use format <q (or <Q) rather than d, and you'll get a little-endian 64-bit integer as required. You will also need to convert the timestamp to an integer to have struct.pack() accept it.
13:20:06.037
13:20:06.038
13:20:06.039
I want to read the timestamps from a file using python and compare the difference between adjacent values. Below is the code I used for this.
h, m, s = str(diff).split(':')
v,w = str(s).split('.')
I tried to split the diff in to hours,minutes and seconds using split(':'). In s, there is seconds and milliseconds value. When I try to run the second line of code, I get the error:" ValueError: need more than 1 value to unpack".
If you would like to convert string records from a file then You should try:
--put here Your code, that retrieves time records from file--
format = '%H:%M:%S.%f'
time_string = '09:54:11.001'
time = datetime.strptime(time_string, format)
This function does the job with displaying time, as You wanted to:
strftime("%H:%M:%S.%f", *put your time variable here*)
And this code snippet shows how to get a difference between two dates in Your format:
time1 = '09:54:11.001'
time2 = '10:32:43.837'
format = '%H:%M:%S.%f'
difference = datetime.strptime(time2, format) - datetime.strptime(time1, format)
You can read more about time functions in Python docs: https://docs.python.org/2/library/time.html
Regards.