I am trying to convert datatime20. from numeric to character value.
Currently I have numeric values like this: 01Jan200:00:00:00 and I need to convert it to character values and received output like: 2020-01-01 00:00:00.0
What format and informat should be used in aboved ?
I have tried used PUT function to convert numeric to character and tried many option, each time receiving other format. Should be also use DHMS function before PUT ?
There is not a native format that produces that string exactly. But it it not hard to build it in steps using existing formats. Or you could use PICTURE statement in PROC FORMAT to build your own format.
If you don't really care about the time of day part of the datetime value then this is an easy and clearly understand way to convert the numeric variable DT with number of seconds into a new character variable in that style. Use DATEPART() to get the date (number of days) from the datetime value and then use the YYMMDD format to generate the 10 character string for the date and then just append the constant string of the formatted zeros.
length dt_string $21.;
dt_string = put(datepart(dt),yymmdd10.)||' 00:00:00.0';
If you need the time of day part then you could also use the TOD format.
dt_string = put(datepart(dt),yymmdd10.)||put(dt,tod11.1);
Or you could use the format E8601DT21.1 and then change the letter T between the date and time to a space instead.
dt_string = translate(put(dt,E8601DT21.1),' ','T');
If you want to figure out what formats exist for datetime values and what the formatted results look like you could run a little program to pull the formats from the meta data and apply them to a specific datetime value.
data datetime_formats;
length format $50 string $80 ;
set sashelp.vformat;
where fmttype='F';
where also fmtinfo(fmtname,'cat')='datetime';
keep format string fmtname maxw minw maxd ;
format=cats(fmtname,maxw,'.','-L');
string=putn('01Jan2020:01:02:03'dt,format);
run;
A custom format can be defined to return the result of a user defined function. Docs
proc format;
value <format-name> (default=<width>)
other = [<function-name>()]
;
run;
Example:
options cmplib=(sasuser.functions);
proc fcmp outlib=sasuser.functions.temporal;
function E8601DTS (datetime) $21;
return (
translate (putn(datetime,'E8601DT21.1'),' ','T')
);
endsub;
run;
proc format;
value E8601DTS (default=21)
other = [E8601DTS()]
;
run;
data have;
do dt = '01jan2020:0:0'dt to '10jan2020:0:0'dt by '60:00't;
output;
end;
format dt datetime16.;
run;
ods html file='function-based-format.html';
proc print data=have(obs=4); title 'stock E8601DT';
proc print data=have(obs=4); title 'custom E8601DTS';
format dt E8601DTS.;
run;
ods html close;
Related
First I had to format all of the categories to numbers and I used the code below to do that and was successful. I need to convert the type from character to numerical so that I can run analysis. I have tried the input function but that has not worked either. Any help would be greatly appreciated.
Proc Format;
Value $gender_num 'Male'=0 'Female'=1;
Value $att 'Yes'=0 'No'=1;
Value $bustrav 'Non-Travel'=1 'Travel_Frequently'=2 'Travel_Rarely'=3;
Value $dpt 'Research & Development'=1 'Human Resources'=2 'Sales'=3;
Value $edfd 'Life Sciences'=1 'Human Resources'=2 'Marketing'=3 'Medical'=4 'Technical Degree'=5 'Other'=6;
Value $ot 'Yes'=0 'No'=1;
Value $ms 'Divorced'=1 'Married'=2 'Single'=3;
Value $jr 'Healthcare Representative'=1 'Human Resources'=2 'Laboratory Technician'=3 'Manager'=4
'Manufacturing Director'=5 'Research Director'=6 'Research Scientist'=7 'Sales Executive'=8 'Sales
Representative'=9;
Run;
Proc Print data=work.empatt;
format gender $gender_num.;
format attrition $att.;
format businesstravel $bustrav.;
format department $dpt.;
format educationfield $edfd.;
format overtime $ot.;
format maritalstatus $ms.;
format jobrole $jr.;
Run;
You're mixing Formats with Informats.
Format: "How do I display a number on the screen for you?"
Informat: "How do I convert text to a number?"
Your code in the first step above should be invalues. Then you use input to translate. You also need to assign that to a new variable - you can't just associate the informat with the variable and magically get a numeric.
proc format;
invalue sexi
'Male'=1
'Female'=2
;
quit;
data want;
set have;
sex_n = input(sex,sexi.);
run;
You can, if you want, keep the same variable name; I'll show that in the next step, also adding a format so the value "looks" right.
proc format;
invalue sexi
'Male'=1
'Female'=2
;
value sexf
1 = 'Male'
2 = 'Female'
;
quit;
data want;
set have;
sex_n = input(sex,sexi.);
format sex_n sexf.;
drop sex;
rename sex_n = sex;
run;
You drop the original one, then rename the new one to the original name. I use the _n suffix to make it clear what I'm doing, but it's not required; nor are the 'i' and 'f' suffixes in the format/informat (and in fact you could use the identical name if you wanted to), again just a pattern I use to make it easier to distinguish.
I would like to get only date and time separately from 01JAN13:08:29:00
Format & Infomat available in Dataset is:
Date Num 8 DATETIME.(format) ANYDTDTM40(informat)
And If I run datepart() on 01JAN13:08:29:00 I get output as 19359 (I don't want it.)
The DATEPART function extracts the date value from a datetime value. The date value as you have seen is simply a number. A date format must be applied to a variable holding a date value. Base SAS variables have only two value types, character and numeric.
data want;
now_dtm = datetime();
now_dt = datepart(now_dtm);
now_dt_unformatted = now_dt;
format now_dtm datetime.;
format now_dt date9.; * <----- this is what you need, format stored in data set header information;
run;
proc print data=want;
run;
* you can change the format temporarily during a proc step;
proc print data=want;
format now_dt yymmdd10.; * <---- changes format for duration of proc step;
format now_dt_unformatted mmddyy10.;
run;
Actually 19,359 is exactly the value you want. You started with the number of seconds since 1960 and converted it to the number of days since 1960.
data x ;
dt = '01JAN13:08:29:00'dt ;
date = datepart(dt);
time = timepart(dt);
put (dt date time) (=);
run;
Results
dt=1672648140 date=19359 time=30540
You just need to attach a format to your new variable so that SAS will display the value in a format that humans will recognize. You could use a format like DATE9. to have it show 19,359 as 01JAN2013. Similarly you need to attach a format to the time part to make it print in format that human's will interpret as a time.
format date date9. time time8. ;
I am working with a huge number of observations in different tables in different versions.
I will use a date %let date_to_view = "20JAN2014:16:10"dt;
But how to convert this date into SAS format?
I knew how to Convert SAS data type (use proc sql):
dhms("01JAN1970'd,3,0,i.valid_dttm/1000) format datetime20.
I see date 20JAN2014:16:34:10 is 1390224849927 but how to convert it into code?
In your formula dhms("01JAN1970'd,3,0,i.valid_dttm/1000) you are converting a number that represents the number of milliseconds since 01JAN1970 to a SAS datetime value that represents the number of seconds since 01JAN1960. You also appear to be adding 3 hours.
So it sounds like your question is how to convert a SAS DATETIME value into a Unix timestamp value. So just reverse the arithmetic.
Your formula to convert from a Unix timestamp to a SAS datetime was:
sasdt2 = '01JAN1970:00:00'dt + '03:00't + unix_timestamp2/1000 ;
So to convert from a SAS datetime value to a Unix timestamp use:
unix_timestamp1 = 1000*(sasdt1 - '01JAN1970:00:00'dt - '03:00't) ;
"20JAN2014:16:10"dt is already in the correct SAS date (datetime) format, but as a date literal. SAS stores this as a number, representing the number of seconds since 01JAN1960:00:00:00.
If you just want the date component of the datetime, use the datepart() function, and format the result accordingly, e.g. date9..
data want ;
dt = "20JAN2014:16:10"dt ;
date = datepart(dt) ;
format dt datetime19. date date9. ;
/* To have 'date' show as the unformatted value, simply remove the format */
format date best32. ;
run ;
I'm trying to put a number eg 20141001 into a date9. format eg 01OCT14.
I've tried to use the input function with an input format of yymmddn8. but SAS throws out 'informat could not be found or loaded'
Any ideas how to get around this? (Sample code below)
data _null_;
date=20141001;
output=input(date,yymmddn8.);
format output date9.;
put output=;
run;
You are almost there. Although there is a YYMMDDN format there is not an informat of the same name. Use the YYMMDD informat. The Input function is expecting a character string i.e. the DATE variable. Redefine DATE as a character variable e.g.
data _null_;
date='20141001';
output=input(date,yymmdd8.);
format output date9.;
put output=;
run;
Alternatively you could have used these assignments:
output = input('20141001',yymmdd8.);
or
output = '01oct2014'd;
I've got a dataset that's full of data all in character format.
Now I want to create another dataset from this one, put put everything it it's correct decimal or date or character format.
Here's what I'm trying.
data work.testout;
attrib account_open_date informat = mmddyy10.;
do i = 1 to nobs;
set braw.accounts point = i nobs = nobs;
output;
end;
stop;
run;
this gives me:
Variable 'account_open_date' from data set braw.accounts (at line 7 column 21) has a different type (character) to the variable type on the data vector (numeric)
What's the best way of doing this?
You cannot use an informat to convert a variable directly from character to numeric. At least in SAS proper, you cannot convert a variable from character to numeric, period, without using an intermediary. You must do something along the lines of the following:
data want;
set have(rename=varwant=temp);
varwant=input(temp,MMDDYY10.);
drop temp;
run;
There you rename the (character) variable to a temporary name, then convert it to numeric using INPUT.