So the question requires us to check if the entered elements in an array form a palindrome or not.
For eg, if an array has 134, 21, 12, 431, the output should declare that this is a palindrome.
I tried my best to keep my program simple and the logic used looks right to me. But it still isn't giving me the correct output. For eg, I input the size as 4 and then entered 134, 21, 12, 431. As per my code, I think it should print "It is a palindrome." but instead there's no ouput on the console.
would be great if somebody can help me with this.
#include <iostream>
using namespace std;
int main()
{
int size;
cout << "Enter the size of array: " << endl;
cin >> size;
int arr[size];
cout << "Enter the element: " << endl;
for (int i=0; i<size; i++)
{
cin >> arr[i];
}
int arr2[size/2];
for (int i=0; i<((size/2)-1); i++)
{
int reverse=0;
while (arr[i]!=0)
{
int rem;
rem = arr[i]%10;
reverse=((reverse*10)+rem);
arr[i]=arr[i]/10;
}
arr2[i]=reverse;
}
for (int i=0; i<((size/2)-1); i++)
{
if(arr2[i]==arr[size-1-i])
{
if(i==(size/2)-1)
{
cout << "It is a palindrome." << endl;
}
}
else
{
cout << "Array is not a palindrome." << endl;
}
}
}
You can check whether the count of non-repeated couples is 1 or 0.
bool isPalindrome(std::vector<int>& vec) {
int max = *(std::max_element(vec.begin(), vec.end()));
std::vector<int> tmp(max + 1, 0);
for (int i = 0; i < vec.size(); ++i) {
++tmp[vec[i]];
}
int odd = 0;
for (int i = 0; i < tmp.size(); ++i) {
if (tmp[i] % 2 == 1) {
++odd;
}
}
return (odd == 1 || odd == 0);
}
Related
I'm a C++ newb. I need to insert numbers to an array and then display first the odd numbers and then the even numbers in a single array. I've managed to create two separate arrays with the odd and even numbers but now I don't know how to sort them and put them back in a single array. I need your help to understand how to do this with basic C++ knowledge, so no advanced functions. Here's my code:
#include <iostream>
using namespace std;
int main()
{
int N{ 0 }, vector[100], even[100], odd[100], unify[100], i{ 0 }, j{ 0 }, k{ 0 };
cout << "Add the dimension: " << endl;
cin >> N;
cout << "Add the elements: " << endl;
for (int i = 0; i < N; i++) {
cout << "v[" << i << "]=" << endl;
cin >> vector[i];
}
for (i = 0; i < N; i++) {
if (vector[i] % 2 == 0) {
even[j] = vector[i];
j++;
}
else if (vector[i] % 2 != 0) {
odd[k] = vector[i];
k++;
}
}
cout << "even elements are :" << endl;
for (i = 0; i < j; i++) {
cout << " " << even[i] << " ";
cout << endl;
}
cout << "Odd elements are :" << endl;
for (i = 0; i < k; i++) {
cout << " " << odd[i] << " ";
cout << endl;
}
return 0;
}
If you don't need to store the values then you can simply run through the elements and print the odd and the even values to different stringstreams, then print the streams at the end:
#include <sstream>
#include <stddef.h>
#include <iostream>
int main () {
std::stringstream oddStr;
std::stringstream evenStr;
static constexpr size_t vecSize{100};
int vec[vecSize] = {10, 5, 7, /*other elements...*/ };
for(size_t vecIndex = 0; vecIndex < vecSize; ++vecIndex) {
if(vec[vecIndex] % 2 == 0) {
evenStr << vec[vecIndex] << " ";
} else {
oddStr << vec[vecIndex] << " ";
}
}
std::cout << "Even elements are:" << evenStr.rdbuf() << std::endl;
std::cout << "Odd elements are:" << oddStr.rdbuf() << std::endl;
}
Storing and sorting the elements are always expensive.
Basically, it would be better to sort them first.
#include <iostream>
using namespace std;
int main()
{
int numbers[5];
int mergedArrays[5];
int evenNumbers[5];
int oddNumbers[5];
for(int i=0;i<5;i++){
cin>>numbers[i];
}
int temp=numbers[0];
//bubble sort
for(int i = 0; i<5; i++)
{
for(int j = i+1; j<5; j++)
{
if(numbers[j] < numbers[i])
{
temp = numbers[i];
numbers[i] = numbers[j];
numbers[j] = temp;
}
}
}
int nEvens=0;
int nOdds=0;
for(int i = 0; i<5; i++)
{
if(numbers[i]%2==0)
{
evenNumbers[nEvens]=numbers[i];
nEvens++;
}
else if(numbers[i]%2!=0)
{
oddNumbers[nOdds]=numbers[i];
nOdds++;
}
}
int lastIndex=0;
//copy evens
for(int i = 0; i<nEvens; i++)
{
mergedArrays[i]=evenNumbers[i];
lastIndex=i;
}
//copy odds
for(int i =lastIndex; i<nOdds; i++)
{
mergedArrays[i]=oddNumbers[i];
}
return 0;
}
If you have to just output the numbers in any order, or the order given in the input then just loop over the array twice and output first the even and then the odd numbers.
If you have to output the numbers in order than there is no way around sorting them. And then you can include the even/odd test in the comparison:
std::ranges::sort(vector, [](const int &lhs, const int &rhs) {
return ((lhs % 2) < (rhs % 2)) || (lhs < rhs); });
or using a projection:
std::ranges::sort(vector, {}, [](const int &x) {
return std::pair<bool, int>{x % 2 == 0, x}; });
If you can't use std::ranges::sort then implementing your own sort is left to the reader.
I managed to find the following solution. Thanks you all for your help.
#include <iostream>
using namespace std;
int main()
{
int N{0}, vector[100], even[100], odd[100], merge[100], i{0}, j{0}, k{0}, l{0};
cout << "Add the dimension: " << endl;
cin >> N;
cout << "Add the elements: " << endl;
for (int i = 0; i < N; i++)
{
cout << "v[" << i << "]=" << endl;
cin >> vector[i];
}
for (i = 0; i < N; i++)
{
if (vector[i] % 2 == 0)
{
even[j] = vector[i];
j++;
}
else if (vector[i] % 2 != 0)
{
odd[k] = vector[i];
k++;
}
}
cout << "even elements are :" << endl;
for (i = 0; i < j; i++)
{
cout << " " << even[i] << " ";
cout << endl;
}
cout << "Odd elements are :" << endl;
for (i = 0; i < k; i++)
{
cout << " " << odd[i] << " ";
cout << endl;
}
for (i = 0; i < k; i++)
{
merge[i] = odd[i];
}
for (int; i < j + k; i++)
{
merge[i] = even[i - k];
}
for (int i = 0; i < N; i++)
{
cout << merge[i] << endl;
}
return 0;
}
You can use Bubble Sort Algorithm to sort whole input. After sorting them using if and put odd or even numbers in start of result array and and others after them. like below:
//Bubble Sort
void bubbleSort(int arr[], int n)
{
int i, j;
for (i = 0; i < n - 1; i++)
// Last i elements are already
// in place
for (j = 0; j < n - i - 1; j++)
if (arr[j] > arr[j + 1])
swap(arr[j], arr[j + 1]);
}
// Insert In array
int result[100];
if(odd[0]<even[0])
{
for (int i = 0; i < k; i++)
{result[i] = odd[i];}
for (int i = 0; i < j; i++)
{result[i+k] = even[i];}
}else
{
for (int i = 0; i < j; i++)
{result[i] = even[i];}
for (int i = 0; i < k; i++)
{result[i+k] = odd[i];}
}
I have a problem with this piece of code, I'm trying to print the EVEN and ODD numbers, but there is a problem when it comes to show them, the vectors don't save the numbers as I'm expecting.
#include <iostream>
using namespace std;
int main() {
int n;
cin >> n;
int vect[n], even[n], odd[n]; // CREATING VECTORS LIMIT AFTER "n"
for(int i = 1; i <= n; ++i) { // ENTERING The ELEMENS IN VECTOR
cin >> vect[i];
}
for(int i = 1; i <= n; ++i) {
if(vect[i] % 2 != 0) {
odd[i] = vect[i]; // I think that here's the problem, the vectors don't save the right numbers.
} /// VERIFYING IF THE NUMBER IS ODD OR EVEN.
else if (vect[i] % 2 == 0) {
even[i] == vect[i];
}
}
for(int i = 1; i <= n; ++i) {
cout << even[i] << " " << endl; /// PRINTING THE ODD AND EVEN numbers.
cout << odd[i] << " " << endl;
}
return 0;x
}
I have fixed the problem, thanks all for help.
Now it works perfectly.
#include <iostream>
using namespace std;
int main() {
int n;
cin >> n;
int vect[n], even[n], odd[n], z = 0, x = 0; // CREATING VECTORS LIMIT AFTER "n"
for(int i = 1; i <= n; ++i) { // ENTERING The ELEMENS IN VECTOR
cin >> vect[i];
}
for(int i = 1; i <= n; ++i) {
if(vect[i] % 2 != 0) {
odd[1+z] = vect[i];
z++;
// I think that here's the problem, the vectors don't save the right numbers.
} /// VERIFYING IF THE NUMBER IS ODD OR EVEN.
else if (vect[i] % 2 == 0) {
even[1+x] = vect[i];
x++;
}
}
for(int i = 1; i <= x; i++) {
cout << even[i] << " ";
}
cout << endl;
for(int i = 1; i <= z; i++) {
cout << odd[i] << " ";
}
return 0;
}
Considering the hints of the comments, your program shall be changed into this:
#include <iostream>
#include <vector>
using namespace std;
int main() {
int n, number;
cin >> n;
vector<int> vect, even, odd; // CREATING DYNAMIC VECTORS
for(int i = 0; i < n; ++i) { // ENTERING THE ELEMENTS IN VECTOR
cin >> number;
vect.push_back(number);
}
for(int i = 0; i < n; ++i) {
if(vect[i] % 2 != 0) { /// VERIFYING IF THE NUMBER IS ODD OR EVEN.
odd.push_back(vect[i]);
}
else {
even.push_back(vect[i]);
}
}
for (int i = 0; i < n; ++i)
cout << vect[i] << " ";
cout << endl;
/// PRINTING THE ODD AND EVEN NUMBERS.
for (auto& val : odd)
cout << val << " ";
cout << endl;
for (auto& val : even)
cout << val << " ";
cout << endl;
return 0;
}
It uses the vector container of STL for your arrays, start the indexing at 0 and prints out the resulting arrays separately, as the number of odd and of even entries might be different.
Hope it helps?
With standard, you might use std::partition (or stable version) to solve your problem:
void print_even_odd(std::vector<int> v)
{
auto limit = std::stable_partition(v.begin(), v.end(), [](int n){ return n % 2 == 0; });
std::cout << "Evens:";
// Pre-C++20 span:
// for (auto it = v.begin(); it != limit; ++it) { int n = *it;
for (int n : std::span(v.begin(), limit)) {
std::cout << " " << n;
}
std::cout << std::endl;
std::cout << "Odds:";
for (int n : std::span(limit, v.end())) {
std::cout << " " << n;
}
std::cout << std::endl;
}
Demo
having a trouble with a condition which tells if an element of a multidimensional array
as example arr[row][col] is exactly arr[col][row] then automatically assign the value of arr[col][row] to the same value of arr[row][col] without letting user enter it manually
That should be an example of the output
example[4][4] =
{
// 0 1 2 3
{ 0, 10, 15, 18}, // 0
{ 10, 0, 20, 14}, // 1
{ 15, 20, 0, 90}, // 2
{ 18, 14,90, 0}, // 3
here's my code
` int size;
int arr[size][size];
cout<<"Choose size of your multidimensional array [matrix]: ",cin>>size;
cout<<"Now enter your data [Respectively] \n";
for(int d=0 ; d<size ; d++)
{
for(int j=0; j<size; j++)
{
if (d==j)
{
arr[d][j]=0 ;
}
else if(arr[d][j]!=0 ) //there should be the problem
{
arr[j][d]=arr[d][j];
}
else
{
cin>>arr[d][j]; // Filling matrix
}
}
} `
Here is a Minimum Working Example (MWE) that should solve your issues:
#include <iostream>
using namespace std;
int main()
{
cout << "Choose size of your multidimensional array [matrix]: ";
int size;
cin >> size;
int arr[size][size];
cout << "Now enter your data [Respectively] \n";
for(int d=0; d<size; d++)
{
for(int j=d+1; j<size; j++)
{
if (d==j)
{
arr[d][j] = 0;
}
else if(j<d) // here laid the problem
{
arr[d][j] = arr[j][d];
}
else
{
cin >> arr[d][j]; // Filling matrix
}
}
}
// print matrix
for(int d=0; d<size; d++) {
for(int j=0; j<size; j++)
cout << arr[d][j] << " ";
cout << '\n';
}
return 0;
}
This below is even cleaner, gets rid of the conditional inside the inner loop, thank you #ThomasSablik
#include <iostream>
using namespace std;
int main()
{
cout << "Choose size of your multidimensional array [matrix]: ";
int size;
cin >> size;
int arr[size][size];
cout << "Now enter your data [Respectively] \n";
for(int d=0 ; d<size ; d++)
{
arr[d][d]=0;
for(int j=d+1; j<size; j++)
{
cin >> arr[d][j];
arr[j][d]=arr[d][j];
}
}
// print matrix
for(int d=0; d<size; d++) {
for(int j=0; j<size; j++)
cout << arr[d][j] << " ";
cout << '\n';
}
return 0;
}
This question already has answers here:
How to make cin take only numbers
(2 answers)
Closed 6 years ago.
So the requirements for this program is to be able to increment arrays of the same size (size from 5 to 15 indexes) and increment each element in the array by one using for and while loops. The last task is to take values from the first array and put them in reverse order and assign them to the second array.
So everything works as normal, and the program rejects invalid inputs and does not go into an infinite loop. However, the program accepts some inputs that are not wanted.
For example, I would input something like '12 a' or '7 asdfkla;j lasnfg jasklgn asfg' and it would go through. It is interesting too because the code registers only 12 or 7 and completely ignores the rest. I think it is because once it hits a non-integer character, it would stop ignore the rest.
Why is it ignoring the rest of the input? And is there a way to catch this error from going through?
Also, if you see anything that catches your eye, feel free to critique c: I am always looking to improving.
#include <iostream>
#include <cstdlib>
#include <ctime>
using namespace std;
int main() {
srand(time(NULL));
int x;
int j = 0;
bool not_valid = true;
system("color f");
cout << "Program will ask for an input for the size of an array.\n"
<< "With the array size defined, program will generate semi-\n"
<< "true random integers from 0 to 8. First array will then\n"
<< "be assigned to the second in reverse (descending) order.\n\n";
do {
cout << "Enter array size (0 - 15): ";
cin >> x;
if (x >= 5 && x <= 15) {
not_valid = false;
cout << "\nArray size: " << x << endl;
}
else {
cout << "Invalid input.\n\n";
cin.clear();
cin.ignore(numeric_limits<streamsize>::max(), '\n');
}
} while (not_valid);
int *arr0;
int *arr1;
arr0 = new int[x];
arr1 = new int[x];
for (int i = 0; i < x; i++) {
arr0[i] = rand() % 9;
}
for (int i = 0; i < x; i++) {
arr1[i] = rand() % 9;
}
cout << "\nARRAY 0 (unmodified, for):\n";
for (int i = 0; i < x; i++) {
cout << arr0[i] << "\t";
}
cout << "\n\nARRAY 0 (modified, for):\n";
for (int i = 0; i < x; i++) {
arr0[i]++;
cout << arr0[i] << "\t";
}
cout << "\n\nARRAY 1 (unmodified, while):\n";
for (int i = 0; i < x; i++) {
cout << arr1[i] << "\t";
}
cout << "\n\nARRAY 1 (modified, while):\n";
while (j < x) {
arr1[j]++;
cout << arr1[j] << "\t";
j++;
}
int second = x - 1;
for (int i = 0; i < x; i++) {
arr1[second] = arr0[i];
second--;
}
j = 0;
cout << "\n\nARRAY 1 (array 0, descending):\n";
while (j < x) {
cout << arr1[j] << "\t";
j++;
}
cout << endl << endl;
system("pause");
return 0;
}
Take input in string and then check if it's a number or not.
Example:
#include<iostream>
#include<sstream>
#include <string>
using namespace std;
int main()
{
string line;
int n;
bool flag=true;
do
{
cout << "Input: ";
getline(cin, line);
stringstream ss(line);
if (ss >> n)
{
if (ss.eof())
{
flag = false;
}
else
{
cout << "Invalid Input." << endl;
}
}
}while (flag);
cout << "Yo did it !";
}
I am Having Problem with Passing a 2D array to a c++ Function. The function is supposed to print the value of 2D array. But getting errors.
In function void showAttributeUsage(int)
Invalid types for int(int) for array subscript.
I know the problem is with the syntax in which I am passing the particular array to function but I don't know how to have this particular problem solved.
Code:
#include <iostream>
using namespace std;
void showAttributeUsage(int);
int main()
{
int qN, aN;
cout << "Enter Number of Queries : ";
cin >> qN;
cout << "\nEnter Number of Attributes : ";
cin >> aN;
int attVal[qN][aN];
cout << "\nEnter Attribute Usage Values" << endl;
for(int n = 0; n < qN; n++) { //for looping in queries
cout << "\n\n***************** COLUMN " << n + 1 << " *******************\n\n";
for(int i = 0; i < aN; i++) { //for looping in Attributes
LOOP1:
cout << "Use(Q" << n + 1 << " , " << "A" << i + 1 << ") = ";
cin >> attVal[n][i];
cout << endl;
if((attVal[n][i] > 1) || (attVal[n][i] < 0)) {
cout << "\n\nTHE VALUE MUST BE 1 or 0 . Please Re-Enter The Values\n\n";
goto LOOP1; //if wrong input value
}
}
}
showAttributeUsage(attVal[qN][aN]);
cout << "\n\nYOUR ATTRIBUTE USAGE MATRIX IS\n\n";
getch();
return 0;
}
void showAttributeUsage(int att)
{
int n = 0, i = 0;
while(n != '\0') {
while(i != '\0') {
cout << att[n][i] << " ";
i++;
}
cout << endl;
n++;
}
}
I really suggest to use std::vector : live example
void showAttributeUsage(const std::vector<std::vector<int>>& att)
{
for (std::size_t n = 0; n != att.size(); ++n) {
for (std::size_t i = 0; i != att.size(); ++i) {
cout << att[n][i] << " ";
}
cout << endl;
}
}
And call it that way:
showAttributeUsage(attVal);
Looking at your code, I see no reason why you can't use std::vector.
First, your code uses a non-standard C++ extension, namely Variable Length Arrays (VLA). If your goal is to write standard C++ code, what you wrote is not valid standard C++.
Second, your initial attempt of passing an int is wrong, but if you were to use vector, your attempt at passing an int will look almost identical if you used vector.
#include <iostream>
#include <vector>
#include <algorithm>
#include <iterator>
typedef std::vector<int> IntArray;
typedef std::vector<IntArray> IntArray2D;
using namespace std;
void showAttributeUsage(const IntArray2D&);
int main()
{
int qN, aN;
cout << "Enter Number of Queries : ";
cin >> qN;
cout << "\nEnter Number of Attributes : ";
cin >> aN;
IntArray2D attVal(qN, IntArray(aN));
//... Input left out ...
showAttributeUsage(attVal);
return 0;
}
void showAttributeUsage(const IntArray2D& att)
{
for_each(att.begin(), att.end(),
[](const IntArray& ia) {std::copy(ia.begin(), ia.end(), ostream_iterator<int>(cout, " ")); cout << endl;});
}
I left out the input part of the code. The vector uses [] just like a regular array, so no code has to be rewritten once you declare the vector. You can use the code given to you in the other answer by molbdnilo for inputing the data (without using the goto).
Second, just to throw it into the mix, the showAttributeUsage function uses the copy algorithm to output the information. The for_each goes throw each row of the vector, calling std::copy for the row of elements. If you are using a C++11 compliant compiler, the above should compile.
You should declare the function like this.
void array_function(int m, int n, float a[m][n])
{
for (int i = 0; i < m; i++)
for (int j = 0; j < n; j++)
a[i][j] = 0.0;
}
where you pass in the dimensions of array.
This question has already been answered here. You need to use pointers or templates. Other solutions exists too.
In short do something like this:
template <size_t rows, size_t cols>
void showAttributeUsage(int (&array)[rows][cols])
{
for (size_t i = 0; i < rows; ++i)
{
std::cout << i << ": ";
for (size_t j = 0; j < cols; ++j)
std::cout << array[i][j] << '\t';
std::cout << std::endl;
}
}
You're using a compiler extension that lets you declare arrays with a size determined at runtime.
There is no way to pass a 2D array with such dimensions to a function, since all but one dimension for an array as a function parameter must be known at compile time.
You can use fixed dimensions and use the values read as limits that you pass to the function:
const int max_queries = 100;
const int max_attributes = 100;
void showAttributeUsage(int array[max_queries][max_attributes], int queries, int attributes);
int main()
{
int attVal[max_queries][max_attributes];
int qN = 0;
int aN = 0;
cout << "Enter Number of Queries (<= 100) : ";
cin >> qN;
cout << "\nEnter Number of Attributes (<= 100) : ";
cin >> aN;
cout << "\nEnter Attribute Usage Values" << endl;
for (int n = 0; n < qN; n++)
{
cout << "\n\n***************** COLUMN " << n + 1 <<" *******************\n\n";
for (int i = 0; i < aN; i++)
{
bool bad_input = true;
while (bad_input)
{
bad_input = false; // Assume that input will be correct this time.
cout << "Use(Q" << n + 1 << " , " << "A" << i + 1 << ") = ";
cin >> attVal[n][i];
cout << endl;
if (attVal[n][i] > 1 || attVal[n][i] < 0)
{
cout << "\n\nTHE VALUE MUST BE 1 or 0 . Please Re-Enter The Values\n\n";
bad_input = true;
}
}
}
}
cout << "\n\nYOUR ATTRIBUTE USAGE MATRIX IS\n\n";
showAttributeUsage(attVal, qN, aN);
getch();
return 0;
}
void showAttributeUsage(int att[max_queries][max_attributes], int queries, int attributes)
{
for (int i = 0; i < queries; i++)
{
for (int j = 0; j < attributes; j++)
{
cout << att[i][j] << " ";
}
cout << endl;
}
}
For comparison, the same program using std::vector, which is almost identical but with no size limitations:
void showAttributeUsage(vector<vector<int> > att);
int main()
{
cout << "Enter Number of Queries (<= 100) : ";
cin >> qN;
cout << "\nEnter Number of Attributes (<= 100) : ";
cin >> aN;
vector<vector<int> > attVal(qN, vector<int>(aN));
cout << "\nEnter Attribute Usage Values"<<endl;
for (int n = 0; n < qN; n++)
{
cout<<"\n\n***************** COLUMN "<<n+1<<" *******************\n\n";
for (int i = 0; i < aN; i++)
{
bool bad = true;
while (bad)
{
bad = false;
cout << "Use(Q" << n + 1 << " , " << "A" << i + 1 << ") = ";
cin >> attVal[n][i];
cout << endl;
if (attVal[n][i] > 1 || attVal[n][i] < 0)
{
cout << "\n\nTHE VALUE MUST BE 1 or 0 . Please Re-Enter The Values\n\n";
bad = true;
}
}
}
}
cout << "\n\nYOUR ATTRIBUTE USAGE MATRIX IS\n\n";
showAttributeUsage(attVal);
getch();
return 0;
}
void showAttributeUsage(vector<vector<int> > att);
{
for (int i = 0; i < att.size(); i++)
{
for (int j = 0; j < att[i].size(); j++)
{
cout << att[i][j] << " ";
}
cout << endl;
}
}
The Particular Logic worked for me. At last found it. :-)
int** create2dArray(int rows, int cols) {
int** array = new int*[rows];
for (int row=0; row<rows; row++) {
array[row] = new int[cols];
}
return array;
}
void delete2dArray(int **ar, int rows, int cols) {
for (int row=0; row<rows; row++) {
delete [] ar[row];
}
delete [] ar;
}
void loadDefault(int **ar, int rows, int cols) {
int a = 0;
for (int row=0; row<rows; row++) {
for (int col=0; col<cols; col++) {
ar[row][col] = a++;
}
}
}
void print(int **ar, int rows, int cols) {
for (int row=0; row<rows; row++) {
for (int col=0; col<cols; col++) {
cout << " | " << ar[row][col];
}
cout << " | " << endl;
}
}
int main () {
int rows = 0;
int cols = 0;
cout<<"ENTER NUMBER OF ROWS:\t";cin>>rows;
cout<<"\nENTER NUMBER OF COLUMNS:\t";cin>>cols;
cout<<"\n\n";
int** a = create2dArray(rows, cols);
loadDefault(a, rows, cols);
print(a, rows, cols);
delete2dArray(a, rows, cols);
getch();
return 0;
}
if its c++ then you can use a templete that would work with any number of dimensions
template<typename T>
void func(T& v)
{
// code here
}
int main()
{
int arr[][7] = {
{1,2,3,4,5,6,7},
{1,2,3,4,5,6,7}
};
func(arr);
char triplestring[][2][5] = {
{
"str1",
"str2"
},
{
"str3",
"str4"
}
};
func(triplestring);
return 0;
}