How to store and pass on my SAS result value? - sas

I would like to make decisions based on a dataset like this:
data cat;
input type ind;
datalines;
1 0
2 0
3 1
;
run;
The decision criterion are: if the minimum of ind is 0, then do action A; if the number of observations is 2, then do action B.
proc means data=cat N min;
var ind;
run;
Now I have printed out the N and min, which are what I want. But how to extract these values? In R, I can just use $, but in SAS it seems that I can only print them out in a table and store them as a dataset, not an independent variable.
Also, better not to use sql.

Thanks to #Reeza, I got my problem solved using macro symput.
proc means data=cat N min;
var ind;
output out=decider N=ntotal min=minimum;
run;
data _null_;
set decider;
call symput('ntotal', ntotal);
call symput('minimum',minimum);
run;

Related

SaS 9.4: How to use different weights on the same variable without datastep or proc sql

I can't find a way to summarize the same variable using different weights.
I try to explain it with an example (of 3 records):
data pippo;
a=10;
wgt1=0.5;
wgt2=1;
wgt3=0;
output;
a=3;
wgt1=0;
wgt2=0;
wgt3=1;
output;
a=8.9;
wgt1=1.2;
wgt2=0.3;
wgt3=0.1;
output;
run;
I tried the following:
proc summary data=pippo missing nway;
var a /weight=wgt1;
var a /weight=wgt2;
var a /weight=wgt3;
output out=pluto (drop=_freq_ _type_) sum()=;
run;
Obviously it gives me a warning because I used the same variable "a" (I can't rename it!).
I've to save a huge amount of data and not so much physical space and I should construct like 120 field (a0-a6,b0-b6 etc) that are the same variables just with fixed weight (wgt0-wgt5).
I want to store a dataset with 20 columns (a,b,c..) and 6 weight (wgt0-wgt5) and, on demand, processing a "summary" without an intermediate datastep that oblige me to create 120 fields.
Due to the huge amount of data (more or less 55Gb every month) I'd like also not to use proc sql statement:
proc sql;
create table pluto
as select sum(db.a * wgt1) as a0, sum(db.a * wgt1) as a1 , etc.
quit;
There is a "Super proc summary" that can summarize the same field with different weights?
Thanks in advance,
Paolo
I think there are a few options. One is the data step view that data_null_ mentions. Another is just running the proc summary however many times you have weights, and either using ods output with the persist=proc or 20 output datasets and then setting them together.
A third option, though, is to roll your own summarization. This is advantageous in that it only sees the data once - so it's faster. It's disadvantageous in that there's a bit of work involved and it's more complicated.
Here's an example of doing this with sashelp.baseball. In your actual case you'll want to use code to generate the array reference for the variables, and possibly for the weights, if they're not easily creatable using a variable list or similar. This assumes you have no CLASS variable, but it's easy to add that into the key if you do have a single (set of) class variable(s) that you want NWAY combinations of only.
data test;
set sashelp.baseball;
array w[5];
do _i = 1 to dim(w);
w[_i] = rand('Uniform')*100+50;
end;
output;
run;
data want;
set test end=eof;
i = .;
length varname $32;
sumval = 0 ;
sum=0;
if _n_ eq 1 then do;
declare hash h_summary(suminc:'sumval',keysum:'sum',ordered:'a');;
h_summary.defineKey('i','varname'); *also would use any CLASS variable in the key;
h_summary.defineData('i','varname'); *also would include any CLASS variable in the key;
h_summary.defineDone();
end;
array w[5]; *if weights are not named in easy fashion like this generate this with code;
array vars[*] nHits nHome nRuns; *generate this with code for the real dataset;
do i = 1 to dim(w);
do j = 1 to dim(vars);
varname = vname(vars[j]);
sumval = vars[j]*w[i];
rc = h_summary.ref();
if i=1 then put varname= sumval= vars[j]= w[i]=;
end;
end;
if eof then do;
rc = h_summary.output(dataset:'summary_output');
end;
run;
One other thing to mention though... if you're doing this because you're doing something like jackknife variance estimation or that sort of thing, or anything that uses replicate weights, consider using PROC SURVEYMEANS which can handle replicate weights for you.
You can SCORE your data set using a customized SCORE data set that you can generate
with a data step.
options center=0;
data pippo;
retain a 10 b 1.75 c 5 d 3 e 32;
run;
data score;
if 0 then set pippo;
array v[*] _numeric_;
retain _TYPE_ 'SCORE';
length _name_ $32;
array wt[3] _temporary_ (.5 1 .333);
do i = 1 to dim(v);
call missing(of v[*]);
do j = 1 to dim(wt);
_name_ = catx('_',vname(v[i]),'WGT',j);
v[i] = wt[j];
output;
end;
end;
drop i j;
run;
proc print;[enter image description here][1]
run;
proc score data=pippo score=score;
id a--e;
var a--e;
run;
proc print;
run;
proc means stackods sum;
ods exclude summary;
ods output summary=summary;
run;
proc print;
run;
enter image description here

Combing/Collapsing binary variables into a single row by patient ID in SAS

I am trying to collapse my multiple rows of binary variables into a single row per patient id as depicted in my illustration. Could someone please help me with the SAS code to do this? Thanks
If the rule is that to set it to 1 if it is ever 1 then take the MAX. If the rule is to set it to one only if all of them are one then take the MIN.
proc summary data=have nway ;
by id;
output out=want max= ;
run;
Update trick
data want;
update have(obs=0) have;
by id;
run;
Or
proc sql;
create table want as
select ID, max('2018'n) as Y2018, max('2019'n) as Y2019, max('2020'n) as Y2020
from have
group by ID
order by ID;
quit;
Untested because you provided data as images, please post as text, preferably as a data step.
Here is a data step-based solution. Certainly more complex than the above answers, but it does show ways you can use arrays, first. and last. processing, and the retain statement.
Use a retained temporary array to hold the values of 2018-2020 until the last observation of each id group. On the last value of each id, check if each held value is 1 and set each value of the year to a 1 or 0.
data want;
set have;
by id;
array year[3] '2018'n--'2020'n;
array hold[3] _TEMPORARY_;
retain hold;
if(first.id) then call missing(of hold[*]);
do i = 1 to dim(year);
if(year[i] = 1) then hold[i] = 1;
end;
if(last.id) then do;
do i = 1 to dim(year);
year[i] = (hold[i] = 1);
end;
output;
end;
drop i;
run;

SAS averaging into groups

Ive got 50 columns of data, with 4 different measurements in each, as well as designation tags (groups C, D, and E). Ive averaged the 4 measurements... So every data point now has an average. Now, I am supposed to take the average of all the data points averages of each specific group.
So I want all the data in group C to be averaged, and so on for D and E.... and I dont know how to do that.
avg1=(MEAS1+MEAS2+MEAS3+MEAS4)/4;
avg_score=round(avg1, .1);
run;
proc print;
run;
This is what I have so far.
There are several procedures, and SQL that can average values over a group.
I'll guess you meant to say 50 rows of data.
Example:
Proc MEANS
data have;
call streaminit(314159);
do _n_ = 1 to 50;
group = substr('CDE', rand('integer',3),1);
array v meas1-meas4;
do _i_ = 1 to dim(v);
num + 2;
v(_i_) = num;
end;
output;
end;
drop num;
run;
data rowwise_means;
set have;
avg_meas = mean (of meas:);
run;
* group wise means of row means;
proc means noprint data=rowwise_means nway;
class group;
var avg_meas;
output out=want mean=meas_grandmean;
run;
rowwise_means
want (grandmean, or mean of means)

SAS: Using Do/Loop in a Proc Transpose

I'm not very familiar with Do Loops in SAS and was hoping to get some help. I have data that looks like this:
Product A: 1
Product A: 2
Product A: 4
I'd like to transpose (easy) and flag that Product A: 3 is missing, but I need to do this iteratively to the i-th degree since the number of products is large.
If I run the transpose part in SAS, my first column will be 1, second column will be 2, and third column will be 4 - but I'd really like the third column to be missing and the fourth column to be 4.
Any thoughts? Thanks.
Get some sample data:
proc sort data=sashelp.iris out=sorted;
by species;
run;
Determine the largest column we will need to transpose to. Depending on your situation you may just want to hardcode this value using a %let max=somevalue; statement:
proc sql noprint;
select cats(max(sepallength)) into :max from sorted;
quit;
%put &=max;
Transpose the data using a data step:
data want;
set sorted;
by species;
retain _1-_&max;
array a[1:&max] _1-_&max;
if first.species then do;
do cnt = lbound(a) to hbound(a);
a[cnt] = .;
end;
end;
a[sepallength] = sepallength;
if last.species then do;
output;
end;
keep species _1-_&max;
run;
Notice we are defining an array of columns: _1,_2,_3,..._max. This happens in our array statement.
We then use by-group processing to populate these newly created columns for a single species at a time. For each species, on the first record, we clear the array. For each record of the species, we populate the appropriate element of the array. On the final record for the species output the array contents.
You need a way to tell SAS that you have 4 products and the values are 1-4. In this example I create dummy ID with the needed information then transpose using ID statement to name new variables using the value of product.
data product;
input id product ##;
cards;
1 1 1 2 1 4
2 2 2 3
;;;;
run;
proc print;
run;
data productspace;
if 0 then set product;
do product = 1 to 4;
output;
end;
stop;
run;
data productV / view=productV;
set productspace product;
run;
proc transpose data=productV out=wide(where=(not missing(id))) prefix=P;
by id;
var product;
id product;
run;
proc print;
run;

How to sum a variable and record the total in the last row using SAS

I have a dataset looks like the following:
Name Number
a 1
b 2
c 9
d 6
e 5.5
Total ???
I want to calculate the sum of variable Number and record the sum in the last row (corresponding with Name = 'total'). I know I can do this using proc means then merge the output backto this file. But this seems not very efficient. Can anyone tell me whether there is any better way please.
you can do the following in a dataset:
data test2;
drop sum;
set test end = last;
retain sum;
if _n_ = 1 then sum = 0;
sum = sum + number;
output;
if last then do;
NAME = 'TOTAL';
number = sum;
output;
end;
run;
it takes just one pass through the dataset
It is easy to get by report procedure.
data have;
input Name $ Number ;
cards;
a 1
b 2
c 9
d 6
e 5.5
;
proc report data=have out=want(drop=_:);
rbreak after/ summarize ;
compute after;
name='Total';
endcomp;
run;
The following code uses the DOW-Loop (DO-Whitlock) to achieve the result by reading through the observations once, outputting each one, then lastly outputting the total:
data want(drop=tot);
do until(lastrec);
set have end=lastrec;
tot+number;
output;
end;
name='Total';
number=tot;
output;
run;
For all of the data step solutions offered, it is important to keep in mind the 'Length' factor. Make sure it will accommodate both 'Total' and original values.
proc sql;
select max(5,length) into :len trimmed from dictionary.columns WHERE LIBNAME='WORK' AND MEMNAME='TEST' AND UPCASE(NAME)='NAME';
QUIT;
data test2;
length name $ &len;
set test end=last;
...
run;