Replace if else with Switch statement - c++

Question

I am working on the code below and trying to use switch statement instead of if/else.
The problem is that I cannot figure out how to get the switch to work.
A few things a tried:
I know that every time an expression is equal to the case constant, the code then will be executed. Example:
switch (expression)
{
case 1:
// code to be executed if
// expression is equal to 1;
break;
}
My code below has a similar concept, but I cannot get it display the calculation. There are no errors, but it does not display the total price.
#include <iostream>
#include <iomanip>
#include <string>
using namespace std;
int main()
{
const int CHEESE_PIZZA = 11;
const int SPINACH_PIZZA = 13;
const int CHICKEN_PIZZA = 14;
cout << " *********** MENU ***********" << endl;
cout << setw (9) << "ITEM" << setw (20) << "PRICE" << endl;
cout << " (1) Cheese Pizza" << setw (8) << "$"
<< CHEESE_PIZZA << endl;
cout << " (2) Spinach Pizza" << setw (7) << "$"
<< SPINACH_PIZZA << endl;
cout << " (3) Chicken Pizza" << setw (7) << "$"
<< CHICKEN_PIZZA << endl;
cout << endl;
cout << "What would you like? ";
int option;
cin >> option;
cout << "You picked pizza option " << option << endl;
cout << "How many orders? ";
int quantity;
cin >> quantity;
cout << "You choose quantity " << quantity << endl;
int price;
switch (option)
{
case 1:
price = CHEESE_PIZZA;
break;
case 2:
price = SPINACH_PIZZA;
break;
case 3:
price = CHICKEN_PIZZA;
break;
default:
cout << "Please select valid item from menu. " << endl;
}
return 1;
int amount = price * quantity;
cout << "Your Bill: $ " << amount << endl;
cout << endl;
return 0;
}
I am confused about the output for any input other than 1, 2, and 3 in case 4.
The if/else statement works:
int price;
if (option == 1) price = CHEESE_PIZZA;
else if (option == 2) price = SPINACH_PIZZA;
else if (option == 3) price = CHICKEN_PIZZA;
else {
cout << "Please select valid item from menu. " << endl;
return 1;
}

Answer 1

The problem, from eyeballing, appears to be because you return 1 outside the switch statement, which is why the code after it never gets run.
You should replace your case 4 with a default: label and move the return 1; into that case as well as add a break statement under case 3.