Is there a way to exclude a value from set precision? - c++

Question

How would I modify code, like the code shown below, to exclude the constant VALUE_1 when using setprecision(2) so that it will display 3 decimals instead of 2 like the others?
#include <iostream>
#include <iomanip>
using namespace std;
const double VALUE_1 = .011;
int main(void)
{
double value2;
double value3;
value2 = 2.362;
value3 = 5;
cout << fixed << setprecision(2);
cout << value2 << endl;
cout << VALUE_1 << endl;
cout << value3 << endl;
return 0;
}
I tried the following fix and it works fine, but is there anything else that doesn't look so improvised? Or is this the intended method?
cout << value_2 << endl;
cout << setprecision (3) << value_1 << endl;
cout << setprecision (2) << value_3 << endl;

Answer 1

I would probably do it by writing my own manipulator to at least combine the steps of setting fixed format and the width I wanted:
class fixed {
int width;
public:
fixed(int width) : width(width) {}
friend std::ostream &operator<<(std::ostream &os, fixed const &f) {
return os << std::fixed << std::setw(width);
}
};
Then you'd write out your numbers like:
std::cout << fixed(3) << value2 << '\n'
<< fixed(2) << VALUE_1 << '\n'
<< fixed(2) << value3 << '\n';
Admittedly, not a drastic improvement, but seems at least a little better to me.
Oh and avoid std::endl unless you really need it (which is pretty much never).