Error making tuple containing a unique_ptr - c++

Question

I am trying to create a function func that returns an std::tuple of an std::unique_ptr<A> and a double. However, when I try to create the tuple I receive errors. The code follows:
#include <tuple>
#include <memory>
class A {
public:
A() : data (3){}
private:
double data;
};
std::tuple<std::unique_ptr<A>, double> func(double num) {
std::unique_ptr<A> a = std::make_unique<A>();
std::tuple<std::unique_ptr<A>, double> temp = std::make_tuple(a, num); // ERROR MESSAGE C
return temp;
}
int main() {
return 0;
}
This code produces the following 4 errors in Visual Studio.
Error message A:
tuple(827,18): error C2440: '<function-style-cast>': cannot convert from 'initializer list' to '_Ttype'
Error message B:
tuple(825,83): message : No constructor could take the source type, or constructor overload resolution was ambiguous
Error message C:
Source.cpp(14): message : see reference to function template instantiation 'std::tuple<std::unique_ptr<A,std::default_delete<A>>,double> std::make_tuple<std::unique_ptr<A,std::default_delete<A>>&,double&>(std::unique_ptr<A,std::default_delete<A>> &,double &)' being compiled
Error message D:
tuple(827,12): error C2064: term does not evaluate to a function taking 2 arguments
First, what is the cause of this error? Second, is the A associated with a being placed on the heap?

Answer 1

A std::unique_ptr is not copyable. You are attempting to copy a std::unique_ptr to the tuple, and that will not work. The compiler error message is kind of cryptic, IMO, but that is basically what seems to be the problem.
However, a std::unique_ptr is moveable, thus you can use std::move:
std::tuple<std::unique_ptr<A>, double> temp = std::make_tuple(std::move(a), num);