Can i add more line in 1 decision like that picture? we can have more input in condition flowchart
for example:
for(int i = 0; i < 10; i++){
if( condition ){
some process...
some process...
some process...
}
else {
some process...
some process...
some process...
if(condition){
some process...
some process...
}
}
}
some process...
some process...
some process...
or should we combine the line? like this picture?
ok, from Berk Ozturk answer:
Can i add more line in 1 decision like that picture? we can have more input in condition flowchart.
You should be able to redirect another input flow to this condition.
In the picture, it seems like there are already 3 inputs to the if
condition. Adding more inputs should be possible.
can i combine lines? like picture 2
Yes, you can combine like this what matters is where the direction of
the arrow is pointing to decide if it is an input or output. It
doesn't matter where you put the arrows.
Related
Is there a way to make a loop that checks user input but doesn't stop if the user doesn't input anything?
For example:
while(condition){
...
selection = _getch();// the or an equivalent of getch()
...
}
But without the loop stopping and waiting for the user to input something.
I'm on VS if it matters.
I found an answer right after posting this, so I'll make it an answer:
Using kbhit() like so will solve it (at least on VS):
while(condition){
if (_kbhit()) {
char ch = _getch();
...
Yeah. So, I'm trying to make a code for a guessing game. In this game, there's a hard mode. In hard mode, you have 15 guesses, and have to guess between 1 and 500. But my problem is this:
I'm trying to have hard mode save & display your wins/losses, but when it outputs the contents of wins.txt it outputs something like this:
Wins: 0x7fffee26df78
Losses: 0x7fffee26e178
It's really confusing me. Here's the part of the code I have for that:
ifstream losses_var("losses.txt");
ifstream wins_var("wins.txt");
losses_var>> loss;
wins_var>> win;
wins_var.close();
losses_var.close();
Then it gets called with:
cout<<"Wins: "<< wins <<"\nLosses: "<< losses <<"\n"
If you would like to see the full source code, it's here: http://pastebin.com/gPT37uBJ
My second problem:
Hard mode won't display when you win. That's pretty much the whole problem. In my code, the loop for asking users for input uses
while (guess != randNum)
So at the end bracket I have what I want the code to display when a user wins, but it just doesn't run. It just stops. I would like it if someone could help me with this. The line that has the bug is line 97 through 105. Again, source code is here: http://pastebin.com/gPT37uBJ
You've got your variable names confused
cout<<"Wins: "<< wins <<"\nLosses: "<< losses <<"\n";
should be
cout<<"Wins: "<< win <<"\nLosses: "<< loss <<"\n";
It's important to pick good variable names. One reason is so that you don't confuse yourself about what your variables mean (if you confuse yourself think how it's going to be for someone else looking at your code).
Others have already answered the output problem (win vs. wins). The other problem is probably in your logic of while loop nesting. The outer loop (while (guess != randNum)) starts, but its body contains the entire inner loop (while (guesses_left != 0)). This means that the outer condition is not checked again until the inner loop terminates, which means you've run out of guesses. Also note that if you guess correctly, inner loop will never terminate. You probably want something like this:
while (guesses_left > 0) {
// input user's guess
if (guess < randNum) {
// process it
} else if (guess > randNum) {
// process it
} else {
// it's equal, user won
// do what's necessary for a win
return 0;
}
}
// ran out of guesses
// do what's necessary for a loss
return 0;
You are not writing your variables win and loss to cout. From your pasted code, I can see that wins and losses are ofstream objects, which means you are probably seeing addresses there. I would advise you to choose more informative variable names to avoid hard to spot mistakes like this.
I'm a rookie programmer, so please be polite.
Well i'm trying to write a simple Terminal Backgammon game, just for fun, but i have a problem.
The entire game runs in a while loop which keeps re running as long as nobody moved all their bricks to the end of the board.
A simple integer controls whatever it is black or white who plays.
I wrote a function to check for any possible moves, cause i want to program to skip the turn in case absolutely no moves can be made.
Well, i want this function to run and in case it returns false(No possible moves) then i want the rest of the code to skip and change the turn to the next player. For example if the dice combination gives no possible moves for black, then i want the program to skip black and go to white.
So i sort of want to break the rest of the while loop, but keep it running.
It's a little complicated for me to explain the issue, but i hope you guys understand.
Thanks alot
- Martin
It sounds like you want to use continue:
while (someCondition)
{
doSomething();
if (someOtherCondition)
continue;
doSomethingElse();
}
In this example, if someOtherCondition is true, the continue statement will cause the program to jump back to the top of the loop rather than continuing to execute the following statements. If someOtherCondition is false, doSomethingElse() will get run as normal.
I think this is roughly what you want to know.
Hope it helps.
while( keepRunning )
{
bool noPossibleMoves = checkForPossibleMoves();
setup for each loop iteration
Do things here that are always necessary.
if( noPossibleMoves )
{
continue; // This will go to the top of the while loop
}
wait for user input etc...
...
...
}
I have a function that creates and insert some numbers in a vector.
if(Enemy2.dEnemy==true)
{
pt.y=4;
pt.x=90;
pt2.y=4;
pt2.x=125;
for(int i=0; i<6; i++)
{
Enemy2.vS1Enemy.push_back(pt);
Enemy2.vS2Enemy.push_back(pt2);
y-=70;
pt.y=y;
pt2.y=y;
}
Enemy2.dEnemy=false;
Enemy3.cEnemy=0;
}
It should insert 6 numbers in two vectors, the only problem is that it doesn't - it actually inserts more.
I don't think the snippet will run unless Enemy2.dEnemy == true, and it won't stay true for ever.
The first time the snippet runs, then Enemy2.dEnemy is set to false and it shouldn't run again.
I don't set Enemy2.dEnemy to true anywhere except when the window is created.
If I insert a break point any where in the snippet, the program will work fine - it will insert ONLY 6 numbers in the two vectors.
Any ideas what's wrong here?
ok so i did some debugging.
i found that Enemy2.dEnemy=false; is being skipped for some reason.
i tried to do this to see if it was.
if(Enemy2.dEnemy)
{
pt.y=4;
pt.x=90;
pt2.y=4;
pt2.x=125;
for(int i=0; i<6; i++)
{
Enemy2.vS1Enemy.push_back(pt);
Enemy2.vS2Enemy.push_back(pt2);
y-=70;
pt.y=y;
pt2.y=y;
}
TCHAR s[244];
Enemy2.dEnemy=false;
if(Enemy2.dEnemy)
{
MessageBox(hWnd, _T("0"), _T(""), MB_OK);
}
else
{
MessageBox(hWnd, _T("1"), _T(""), MB_OK);
}
Enemy3.cEnemy=0;
}
well the message box popped saying 1 and my code worked fine. it seems that Enemy2.dEnemy=false; doesn't have time to run ;/
blahblahblahblahblahblahblahblahblahblahblahblahblahblahblahblah!
ok i found where is the real problem which was causing to insert more than 6 numbers..
it was where i was asigning Enemy2.dEnemy=true;
if(Enemy2.e1)
{
Enemy2.now=time(NULL);
Enemy2.tEnemy=Enemy2.now+4;
Enemy2.e1=false;
}
if(Enemy2.tEnemy==time(NULL))
{
check=1;
Enemy2.aEnemy=0;
Enemy2.dEnemy=true;
}
the problem seems that the second if runs more than one time, which is weird!
First things first: get rid of that abominable if (Enemy2.dEnemy == true) - it should be:
if (Enemy2.dEnemy)
(I also prefer to name my booleans as a readable sentence segments like Enemy2.isABerserker or Enemy3.hasHadLeftLegCutOffThreeInchesBelowTheKnee but that's just personal preference).
Other than that, the only thing I can suggest is a threading problem. There's nothing wrong with that code per se, but there is a window in which two threads could enter the if statement and both start pushing values into your vector.
In other words, if thread 1 is doing the pushing when thread 2 encounters the if statement, thread 2 will also start pushing values, since thread 1 has yet to set dEnemy to true. And don't think you can just move the assignment to the top of the if block - that will reduce but not remove the window.
My advice is to print out the contents of the vectors in the situation where they have more than six entries and that may give a clue as to what's happened (post the output here if you wish).
Re your update that the second if below is running twice:
if(Enemy2.e1)
{
Enemy2.now=time(NULL);
Enemy2.tEnemy=Enemy2.now+4;
Enemy2.e1=false;
}
if(Enemy2.tEnemy==time(NULL))
{
check=1;
Enemy2.aEnemy=0;
Enemy2.dEnemy=true;
}
If this code is executed twice in the same second (and that's not beyond the bounds of possibility), the second if statement will run twice.
That's because time(NULL) give you the number of seconds since the epoch so, until that second is over, you may well be executing the contents of that if thousands of times (or more).
If this problem disappears when you put in a breakpoint or a diagnostic output message, that's a strong clue that the problem is undefined behavior, which is usually caused by something like dereferencing an uninitialized pointer or careless use of const_cast.
The cause of the problem probably has nothing to do with the code you're looking at. It's caused somewhere else and just happens to show up here. It's like someone being hit by a falling brick: the obvious symptom is a man lying unconscious on the sidewalk, but the real problem has nothing to do with the man or the sidewalk, it's several stories up.
If you want to find the cause of the error, remove your diagnostics until the problem reappears, then start removing everything else. Prune away all of the other code. Whenever the error stops, back up until it starts again; if you don't see the cause of the error, start pruning somewhere else. Eventually the bug will have nowhere to hide.
I am trying to find an error in my code. The problem is the error occurs in a loop. But the loop iterates about 500 times. Instead of clicking through the loop. Is it possible to skip over a certain amount of the loop ??
VS allows you to set a condition on a breakpoint in terms of variables that are in scope. So, in your case, you can test against the loop counter.
Here is a crude answer:
if ((iter % 10) == 0) {
int stop = 1;
}
Then place a break-point at "int stop = 1;". Perhaps, there is a better way in VS but this is what I do from time-to-time.
You can assign new values to variables during debug session. Step through the loop statements as many times as you like, then set your loop counter (or whatever other vars maintain loop condition) to terminate the loop.
Just put the breakpoint in the loop like indicated below >>. Use F5 to get to the condition that causes failure so you can loop through the individual pass. How to know where to break is up to you.
for (int i = 0; i < LOOPMAX; i++) {
>>some_proc(i);
some_other_proc(i);
some_third_proc(i);
}
By pressing F5 it'll continue running till it gets to the next breakpoint (the next pass through the code). Sure you'll have to hit it 500 times, but that beats some thousands of times. Combine this with #Troubador code above.
PS: This answer IS really simple, but some people don't know they can do this.