So I'm trying to write a program that will read in ten whole numbers and outputs the sum of all numbers greater than zero, the sum of all numbers less than zero,
and the sum of all numbers, whether positive, negative, or zero.
Currently only the total sum and negative sum is adding correctly. My positive sum is always 1 or 0. Any tips to get me in the right direction would help.
Current Code:
#include <iostream>
using namespace std;
int main()
{
int N = 0;
int sum = 0;
int positiveSum = 0;
int negativeSum = 0;
cout << "Number 1" << endl;
cin >> N;
cout << "Number 2" << endl;
cin >> N;
cout << "Number 3" << endl;
cin >> N;
cout << "Number 4" << endl;
cin >> N;
cout << "Number 5" << endl;
cin >> N;
cout << "Number 6" << endl;
cin >> N;
cout << "Number 7" << endl;
cin >> N;
cout << "Number 8" << endl;
cin >> N;
cout << "Number 9" << endl;
cin >> N;
cout << "Number 10" << endl;
cin >> N;
for(int i=0;i<10;i++)
{
if (N >= 0 )
{
positiveSum += N;
}
else
{
negativeSum += N;
}
}
sum = positiveSum + negativeSum;
cout << "The positive sum is= " << positiveSum << endl;
cout << "the negative sum is= " << negativeSum << endl;
cout << "The total sum is= " << sum << endl;
return 0;
}
After entering all Ns and when entring to the loop, you have only the last N. because after assigning the first number to N you don't process the value but you assigning the next value to N again after asking the user to enter it and so on. Use something like the following
#include <iostream>
int main()
{
int N = 0;
int sum = 0;
int positiveSum = 0;
int negativeSum = 0;
for(int i=0;i<10;i++)
{
std::cout << "Number "<<i + 1<< std::endl;
std::cin >> N;
if (N >= 0 )
{
positiveSum += N;
}
else
{
negativeSum += N;
}
}
sum = positiveSum + negativeSum;
std::cout << "The positive sum is= " << positiveSum << std::endl;
std::cout << "the negative sum is= " << negativeSum << std::endl;
std::cout << "The total sum is= " << sum << std::endl;
return 0;
}
And see Why is "using namespace std;" considered bad practice?
Related
I am trying to add up all the values that have been stored into array b and have it display under the "total column" and don't know how to only have the scores add together.
#include <iostream>
#include <iomanip>
using namespace std;
int main()
{
int array[5][4];
int sum = 0;
cout<<"Enter grades for 4 exams for the 5 students \n";
for(int i=0;i<5;i++)
{
for(int b=1;b<=4;b++)
{
cout <<setw(8)<< "enter student "<< i << "'s grade for exam " << b << '\n';
cin >> array[i][b];
}
}
cout <<"ID"<<setw(11)<<"score 1"<<setw(11)<<"score 2"<<setw(11)<<"score 3"<<setw(11)<<"score 4"<<setw(11)<<"total"<<setw(11)<<"letter"<<endl;
cout <<"--------------------------------------------------------------------------------------------------------------\n";
for(int i=0;i<5;i++)
{
cout << i<< " ";
for(int b=1;b<=4;b++)
{
sum = sum + array[b];
cout <<setw(10)<<array[i][b]<<sum;
}
cout <<'\n';
}
cout <<"--------------------------------------------------------------------------------------------------------------\n";
return 0;
}
To be more specific around line 28
for(int i=0;i<5;i++)
{
cout << i<< " ";
for(int b=1;b<=4;b++)
{
sum = sum + array[b];
cout <<setw(10)<<array[i][b]<<sum;
}
cout <<'\n';
Arrays indexes start at 0, not 1. You are correctly looping through your array's 1st dimension, but not its 2nd dimension. You need to change the inner for loops from for(int b=1;b<=4;b++) to for(int b=0;b<4;b++)
Also, to handle the total column, you simply need to reset sum to 0 on each iteration of the 1st dimension, and then print the result after the iteration of the 2nd dimension.
Try this:
#include <iostream>
#include <iomanip>
using namespace std;
int main()
{
int array[5][4];
cout << "Enter grades for 4 exams for the 5 students \n";
for(int i = 0; i < 5; i++)
{
for(int b = 0; b < 4; b++)
{
cout << "Enter student " << i+1 << "'s grade for exam " << b+1 << '\n';
cin >> array[i][b];
}
}
cout << "ID" << setw(11) << "score 1" << setw(11) << "score 2" << setw(11) << "score 3" << setw(11) << "score 4" << setw(11) << "total" << setw(11) << "letter" << endl;
cout << "--------------------------------------------------------------------------------------------------------------\n";
for(int i = 0; i < 5; i++)
{
cout << setw(2) << left << i+1 << right;
int sum = 0;
for(int b = 0; b < 4; b++)
{
sum = sum + array[i][b];
cout << setw(11) << array[i][b];
}
cout << setw(11) << sum << '\n';
}
cout << "--------------------------------------------------------------------------------------------------------------\n";
return 0;
}
Online Demo
I'm new to coding. I wrote the below code in C++ and I am not allow to use array.
You will create a console C++ program that uses a nested loop to enter each archer's individual end scores and then displays the total score for each archer.
I am stuck at how to calculate the total end score:
#include <iomanip>
using namespace std;
int main()
{
int Rounds = 4;
int Archers = 3;
int endScore ;
int average;
for (int a = 1; a <= Archers ; a++)
{
cout << endl << "Number " << a << " score" << endl;
int tEndScore = 0 ;
for(int i=1; i <=Rounds ; i++)
{
cout << "Round " << i << " : " ;
cin >> endScore;
while(cin.fail())
{
cout << endl << "not enter an integer " << endl ;
cout << "Please enter an integer ";
cin >> endScore;
}
tEndScore += endScore;
}
cout << endl << "The total score for 4 ends of Archer Number " << a << " is " << tEndScore << endl;
average =(double) tEndScore/Rounds;
cout << setiosflags(ios::fixed) << setprecision(2) << endl << "The average score of 4 ends of Archer Number " << a << " is " << average << endl;
}
}
This is the result after running. It will only use the last value I entered as tEndScore:
You need to shift tEndScore =+ endScore; this line inside the second for loop as
for(int i=1; i <=Rounds ; i++)
{
...
...
tEndScore += endScore;
}
And it will be a good practice (And mandatory for your code...) to initialize the tEndScore for each player as
for (int a = 1; a <= Archers ; a++)
{
tEndScore = 0;
endScore = 0;
average = 0;
...
...
}
You need to replace totalEndScore to tEndScore and totalRounds to Rounds.
#include <iostream>
using namespace std;
int main()
{
int numint, sum, a, b, ctr;
cout << "Enter the number of intervals: ";
cin >> numint;
ctr = 0;
while (ctr != numint)
{
cout << "Enter the lower and upper bounds of the interval: ";
cin >> a;
cin >> b;
ctr++;
}
cout << "The sum of the " << numint << " intervals is: [" << a << "," << b << "]";
return 0;
}
I need to add the upper bounds of the interval (a) and lower bounds of the interval (b). This depends on the amt of intervals there are.
here:
cout << "The sum of the " << numint << " intervals is: [" << a << "," << b << ]";
you are not adding the values but instead just printing them
instead use some accumulator variable and do the math before printing it, like:
int main()
{
int numint,sum,a,b,ctr;
int result = 0;
cout << "Enter the number of intervals: ";
cin >> numint;
ctr=0;
while (ctr!=numint)
{
cout << "Enter the lower and upper bounds of the interval: ";
cin >> a;
cin >> b;
ctr++;
}
result = a + b ;
cout << "The sum of the " << numint << " is: " << result;
return 0;
}
As for what I understood from the question, you first need a int resultA=0 and another for b, and keep adding in the loop:
#include <iostream>
using namespace std;
int main()
{
int numint,sum,a,b,ctr;
int result = 0;
int resultA=0;
int resultB=0;
cout << "Enter the number of intervals: ";
cin >> numint;
ctr=0;
while (ctr!=numint)
{
cout << "Enter the lower and upper bounds of the interval: ";
cin >> a;
cin >> b;
resultA+=a;
resultB+=b;
ctr++;
}
result = resultA + resultB ;
cout << "The sum of the " << numint << " is: " << result;
return 0;
}
I think this is what you are looking for:
#include <iostream>
using namespace std;
int main() {
int numberOfIntervals;
int lowerBound;
int upperBound;
int counter;
int lowerBoundSum = 0;
int upperBoundSum = 0;
cout << "Enter the number of intervals: ";
cin >> numberOfIntervals;
counter = 0;
while (counter != numberOfIntervals) {
cout << "Enter the lower and upper bounds of interval "
<< counter << ": ";
cin >> lowerBound;
cin >> upperBound;
lowerBoundSum += lowerBound;
upperBoundSum += upperBound;
counter++;
}
cout << "The sum of the lower bounds is " << lowerBoundSum
<< endl;
cout << "The sum of the upper bounds is " << upperBoundSum
<< endl;
return 0;
}
C++ code where a user enters 2 integers, then the program outputs how many numbers were multiples of 3 between those integers, including both numbers, and how many numbers were divisible by 5.
Here is my code. I think I am not calling the if statements correctly. Maybe I need a switch?
#include <iostream>
#include <cmath>
using namespace std;
int main() {
int numb1, numb2;
int sentinel;
int counter = 0;
int mult3 = 0;
int mult5 = 0;
cout << "Enter an integer:";
cin >> numb1;
cout << "Enter another integer:";
cin >> numb2;
cout << endl;
sentinel = (abs(numb2-numb1)+1);
if(numb1 % 3 == 0 && counter <= sentinel) {
mult3++;
numb1++;
counter++;
}
else {
numb1++;
counter++;
}
cout << endl;
counter = 0;
if(numb1 % 5 == 0 && counter <= sentinel) {
mult5++;
numb1++;
}
else {
numb1++;
counter++;
}
cout << endl;
cout << mult3 << " " << "numbers are divisible by 3 in between your entered integers." << endl;
cout << mult5 << " " << "numbers are divisible by 5 in between your entered integers.";
cout << endl;
return 0;
}
A short version for your code is given below. Checkout the while loop(not ran, just from top of my head).
#include <iostream>
#include <cmath>
using namespace std;
int main() {
int numb1, numb2;
int sentinel;
int counter = 0;
int mult3 = 0;
int mult5 = 0;
cout << "Enter an integer:";
cin >> numb1;
cout << "Enter another integer:";
cin >> numb2;
cout << endl;
while(numb1 <= numb2){
mult3 += (numb1%3)==0?1:0; // (numb1%3)?0:1
mult5 += (numb1%5)==0?1:0;
++counter;
++numb1;
}
cout << endl;
cout << mult3 << " " << "numbers are divisible by 3 in between your entered integers." << endl;
cout << mult5 << " " << "numbers are divisible by 5 in between your entered integers.";
cout << endl;
return 0;
}
You're not looping it at all, so this will only execute once.
while(counter < sentinel)
{
//run your tests and increment the appropriate variables if the numbers are divisible by 3 or 5
counter++;
}
start by evaluating the lowest of the 2 entered numbers + counter % 3 == 0
I got it. I had to use 3 separate while loops. One for <, one for >, and one for =. When I just had a <= and >=, the first loop would feed into the second. I took out the sentinel and the counter thanks to Avezan's help. Thanks everyone.
The program output should look like this:
Enter an even number: 23
The number is not a positive even number.
Enter an even number: -6
The number is not a positive even number.
Enter an even number: 4
20 20.25 20.50 20.75 21
The sum is 102.5
program doesn't run properly. the odd/ even numbers are identified, but the loop to increment the variables (20 + 1 / (even number entered)) does not work right.
#include <iostream>
int main(int argc, char *argv[])
{
float val, sum, incr;
int num;
cout << "Enter an even number: ";
cin >> num;
if (num % 2 != 0)
cout << "The number " << num << " is not a positive even number." << endl;
else
cout << num << " is even!" << endl << endl;
incr = 1 / num;
for (val = 20.0F; val <= 21.0; val += incr)
{
cout << val;
sum += val;
}
cout << "The sum is " << sum << endl;
return 0;
}
If you divide one integer 1 between another num the result is an integer that as chris said is 0.
You should do:
incr = 1.0F / (float)num;
And for exiting for wrong introduced values you should return from main
#include <iostream>
int main() {
float val, sum, incr;
int num;
cout << "Enter an even number: ";
cin >> num;
if (num < 0 || num % 2 != 0){
cout << "The number " << num << " is not a positive even number." << endl;
return -1;
}
else {
cout << num << " is even!" << endl << endl;
}
incr = 1.0 / num;
for (val = 20.0F; val <= 21.0; val += incr) {
cout << val << " ";
sum += val;
}
cout << "The sum is " << sum << endl;
return 0;
}