Hash multiple files - c++

I'm trying to hash multiple files, but there is an error.
My files name start from Cheque 083654.tif - 08365122.tif
My code:
for (int i = 4; i < 123; i++)
{
stringstream file;
file<< "C:/Users/user/Desktop/datasets/Cheque 08365" << i << ".tif";
string filename = file.str();
cout << filename << '\n';
unsigned char *sha256digest = calculateSHA256(filename);
char *sha256hash = (char *)malloc(sizeof(char) * 65);
sha256hash[65] = '\0';
for (int i = 0; i < SHA256_DIGEST_LENGTH; i++)
{
sprintf(&sha256hash[i * 2], "%02x", sha256digest[i]);
}
printf("SHA256 HASH: %s\n", sha256hash);
system("pause");
}
The error states that no suitable conversion function from string to char * exists at the filename in:
unsigned char *sha256digest = calculateSHA256(filename);
How can I solve this error?

If calculateSHA256 returns std::string, that assignment is illegal in more ways than one. char * is just a pointer to that storage, string returned by function is a temporal object, which stops existing after semicolon. First, you have to save that string, second, to access its data by appropriate member function. There is no way to convert string directly to a pointer.
Or don't use pointer at all. You would find it better to avoid using C idioms at all.
std::string sha256digest = calculateSHA256(filename);
// FORMATTED OUTPUT
std::stringstream hashstr;
hashstr << std::hex << std::setfill('0');
for( auto x : sha256digest ) // this would iterate through entirety of string
{
hashstr << std::setw(2) << static_cast<int>(static_cast<unsigned char>(x));
}
std::string output;
hashstr >> output;
std::cout << "SHA256 HASH: " << output;

You do not need a stringstream to construct the filename. Use std::to_sting().
I think most of the simplification can be done inside your own calculateSHA256() function. Let it return a std::vector or std::string instead of a char*.
Here's an example where I let it return a std::vector<std::uint8_t> instead:
#include <openssl/evp.h>
#include <openssl/sha.h>
#include <cstdint>
#include <cstdio>
#include <fstream>
#include <iomanip>
#include <iostream>
#include <iterator>
#include <stdexcept>
#include <string>
#include <vector>
// An EVP_MD_CTX helper class
class EvpMdCtx {
public:
explicit EvpMdCtx(const EVP_MD* type, ENGINE* impl = nullptr) : EvpMdCtx() {
if(init(type, impl) == 0)
throw std::runtime_error("EVP_DigestInit_ex failed");
}
EvpMdCtx() : ctx(EVP_MD_CTX_new()) {
if(ctx == nullptr) throw std::runtime_error("EVP_MD_CTX_new failed");
}
EvpMdCtx(const EvpMdCtx&) = delete;
EvpMdCtx& operator=(const EvpMdCtx&) = delete;
~EvpMdCtx() { EVP_MD_CTX_free(ctx); }
int init(const EVP_MD* type, ENGINE* impl = nullptr) {
return EVP_DigestInit_ex(ctx, type, impl);
}
int update(const void* d, size_t cnt) { return EVP_DigestUpdate(ctx, d, cnt); }
auto finalize() {
std::vector<std::uint8_t> md_value(EVP_MAX_MD_SIZE);
unsigned md_len;
if(EVP_DigestFinal_ex(ctx, md_value.data(), &md_len) == 0)
md_value.clear();
else
md_value.resize(md_len);
return md_value;
}
private:
EVP_MD_CTX* ctx;
};
std::vector<std::uint8_t> calculateSHA256(const std::string& filename) {
std::ifstream is(filename);
if(not is) return {};
EvpMdCtx ctx(EVP_sha256());
char buf[BUFSIZ]; // a buffer to fill
while(true) {
is.read(buf, std::size(buf));
auto len = is.gcount();
if(len > 0) {
if(ctx.update(buf, static_cast<size_t>(len)) == 0) return {};
} else {
break;
}
}
// finalize
return ctx.finalize();
}
int main() {
const std::string file = "C:/Users/user/Desktop/datasets/Cheque 08365";
for(int i = 4; i <= 122; ++i) {
std::string filename = file + std::to_string(i) + ".tif";
auto res = calculateSHA256(filename);
if(res.empty()) {
std::cout << "Failed: " << filename << '\n';
} else {
std::cout << std::hex << std::setfill('0');
for(auto v : res) {
std::cout << std::setw(2) << static_cast<int>(v);
}
std::cout << ' ' << filename << '\n';
}
}
}

Related

Collecting many printf calls in a single string

I am dealing with some code that performs RC4 encryption algorithm with some params passed into the function. From there I am trying to append the generated hash to an empty string but have failed with a few of my attempts. I had seen the use of snprintf() but how could I go about converting the code below to save what gets printed to a string?
for (size_t i = 0, len = strlen(plaintext); i < len; i++) {
printf("|x%02hhx| ", hash[i]);
}
Why not use C++.
#include <iomanip>
#include <iostream>
#include <sstream>
#include <cstring>
int main() {
char plaintext[] = "12345";
char hash[] = "123\xf0\x0f";
std::stringstream out;
for (size_t i = 0, len = strlen(plaintext); i < len; i++) {
out << "|x"
<< std::setfill('0') << std::setw(2) << std::setbase(16)
// ok, maybe this is the reason.
<< 0xff & hash[i]
<< "| ";
}
std::cout << out.str();
}
Just work with std::string::data after determining the size of the output of std::snprintf:
template<class...Args>
std::string PrintFToString(char const* format, Args...args)
{
std::string result;
char c;
int requiredSize = std::snprintf(&c, 1, format, args...);
if (requiredSize < 0)
{
throw std::runtime_error("error with snprintf");
}
result.resize(requiredSize);
int writtenSize = std::snprintf(result.data(), requiredSize+1, format, args...);
assert(writtenSize == requiredSize);
return result;
}
template<class...Args>
void AppendPrintFToString(std::string& target, char const* format, Args...args)
{
char c;
int requiredSize = std::snprintf(&c, 1, format, args...);
if (requiredSize < 0)
{
throw std::runtime_error("error with snprintf");
}
auto const oldSize = target.size();
target.resize(oldSize + requiredSize);
int writtenSize = std::snprintf(target.data() + oldSize, requiredSize+1, format, args...);
assert(writtenSize == requiredSize);
}
int main() {
std::cout << PrintFToString("|x%02hhx| ", 33) << '\n';
std::string output;
for (int i = 0; i != 64; ++i)
{
AppendPrintFToString(output, "|x%02hhx| ", i);
output.push_back('\n');
}
std::cout << output;
}
Note: If you know a reasonable upper bound for the number of characters of the output, you could use a char array allocated on the stack for output instead of having to use 2 calls to std::snprintf...

parsing text and output "time of appearance" of some lines [closed]

Closed. This question needs debugging details. It is not currently accepting answers.
Edit the question to include desired behavior, a specific problem or error, and the shortest code necessary to reproduce the problem. This will help others answer the question.
Closed 3 years ago.
Improve this question
So I got file that look like:
$GPGGA,124613.90,5543.3221231,N,03739.1368442,E,1,15,0.69,147.0851,M,14.4298,M,,*54
$GPGSV,3,1,10,27,12,078,41,05,31,308,49,16,25,043,44,02,11,268,44*7E
$GPGSV,3,2,10,26,03,031,39,07,74,216,52,09,58,121,52,30,39,234,48*71
$GPGSV,3,3,10,23,30,116,46,04,37,114,47*79
$GLGSV,2,1,07,84,17,338,43,78,15,212,48,85,12,032,46,67,84,223,53*67
$GLGSV,2,2,07,77,67,195,47,76,50,047,54,66,32,144,52*5C
$GPGGA,124614.00,5543.3221239,N,03739.1368445,E,1,15,0.69,147.0864,M,14.4298,M,,*53
$GPGSV,3,1,10,27,12,078,41,05,31,308,49,16,25,043,43,02,11,268,44*79
$GPGSV,3,2,10,26,03,031,39,07,74,216,52,09,58,121,52,30,39,234,48*71
$GPGSV,3,3,10,23,30,116,46,04,37,114,47*79
$GLGSV,2,1,07,84,17,338,43,78,15,212,48,85,12,032,46,67,84,223,53*67
$GLGSV,2,2,07,77,67,195,47,76,50,047,54,66,32,144,52*5C
My cod is checking check sum of string and output some values in strings.
In $GPGGA line "124614.00" is time. 12 hours 46 minutes 14.00 sec. I need to output time of "appearance" $GPGSV lines. I`ve tried subtract first value and the following ones through the pointer, but I must have messed up somewhere.
#include <iostream>
#include <fstream>
#include <string>
#include <stdlib.h>
#include <numeric>
#include <cstdlib>
#include <cstring>
#include <stdio.h>
int checksum(const char* s) {
int c = 0;
while (*s)
c ^= *s++;
return c;
}
int main() {
char linec_h[200];
int k, key;
int* hour = NULL;
int* minute = NULL;
float* sec = NULL;
std::string line, key_s;
std::ifstream logs_("C:/Users/Olya/Desktop/broken.txt");
std::ofstream pout("C:/Users/Olya/Desktop/outLOG.txt");
if (logs_.is_open()) {
while (getline(logs_, line)) {
key_s = line.substr(line.length() - 2, 2);
key = strtol(key_s.c_str(), NULL, 16);
line = line.substr(1, line.length() - 4);
strcpy_s(linec_h, line.c_str());
if (key != checksum(linec_h))
pout << "Line is corrupted!" << std::endl;
else {
k = 0;
if (line.substr(0, 5) == "GPGGA") {
if (hour, minute, sec) {
*hour = stoi(line.substr(5, 2)) - *hour;
*minute = stoi(line.substr(7, 2)) - *minute;
*sec = stof(line.substr(9, 4)) - *sec;
}
else {
hour = new int;
minute = new int;
sec = new float;
*hour = stoi(line.substr(5, 2));
*minute = stoi(line.substr(7, 2));
*sec = stof(line.substr(9, 4));
}
} else if (line.substr(0, 5) == "GPGSV") {
for (size_t i = 0, SNR = 7, N = 4; i < line.size(); i++) {
if (line[i] == ',')
k++;
if (k == N) {
pout << "Satellite number -- " << line.substr(i + 1, 2) << " ";
if ((N += 4) > 16)
;
} else if (k == SNR) {
pout << "SNR -- " << line.substr(i + 1, 2) << " time -- " << hour
<< "." << minute << "." << sec << std::endl;
if ((SNR += 4) > 19)
break;
}
}
}
}
delete hour;
delete minute;
delete sec;
}
logs_.close();
std::cout << "Success" << std::endl;
} else
std::cout << "File is not open" << '\n';
pout.close();
return 0;
}
Just for the FUn of it. I created a complete solution which parses your GPS NMEA format completely and put all results in structs. So you can get ALL satellite data.
However. I show only the values that you used in your example.
I adapted my coding style to yours. In C++ I would do things completel different. Anyway.
Please find attached an complete example:
#include <string>
#include <ctime>
#include <cstring>
#include <iostream>
#include <fstream>
#include <iomanip>
constexpr size_t NumberOfFixQualityStrings = 9;
constexpr size_t NumberOfSatellitesPerGSVSentencePart = 4;
constexpr size_t MaxNumberOfPartsInSentence = 10;
constexpr size_t MaxTokensInSentence = 64;
constexpr size_t NumberOfFieldsInGGA = 12;
std::string fixQualityString[NumberOfFixQualityStrings]{
"invalid", "GPS fix (SPS)", "DGPS fix", "PPS fix", "Real Time Kinematic", "Float RTK",
"estimated (dead reckoning", "Manual input mode", "Simulation mode" };
// essential fix data which provide 3D location and accuracy data
struct GGA {
// Time of last satellite fix
unsigned int fixTimeInUtcHours{};
unsigned int fixTimeInUtcMinutes{};
unsigned int fixTimeInUtcSeconds{};
unsigned int fixTimeInUtcMilliSeconds{};
// Position: Lattitude
unsigned int lattitudeInDegree{};
double lattitudeInMinutes{};
std::string lattitideDirection{};
// Position: Longitude
unsigned int longitudeInDegree{};
double longitudeInMinutes{};
std::string longitudeDirection{};
// FixQuality // see dteails as string above
unsigned int fixQuality{};
std::string fixQualityString{};
// Number of satellites being tracked (can be more than shown in GSV, not all are beeing used for calculation)
unsigned int numberOfTrackedSatellites{};
// Horizontal dilution of position
double horizontalDilution{};
// Altitude, Meters, above mean sea level
double altitude{};
std::string altitudeDimension{};
// Height of geoid (mean sea level) above WGS84 ellipsoid
double goidHight{};
std::string goidHightDimension{};
};
// Detail information for satellites in satellit view (GSV)
struct SatelliteData {
std::string satellitePRNnumber{};
double elevationInDegress{};
double azimuthInDegrees{};
double snr{}; // signal noise ratio
};
// Part of a GSV sentence
struct GSVSentencePart {
size_t numberOfSentencesForFullData{};
size_t sentencePartNumber{};
size_t numberOfSatellitesInView{};
size_t numberOfSatellitesInThisPart{};
SatelliteData satelliteData[NumberOfSatellitesPerGSVSentencePart];
};
struct GSV
{
GSVSentencePart gsvSentencePart[MaxNumberOfPartsInSentence];
size_t numberOfParts{};
};
bool checksumTest(std::string& line) {
bool result{ false };
// Check, if there is a 2 digt checksum at the end and convert it to decimal
if (size_t pos{}, checkSumGiven{ std::stoul(line.substr(line.size() - 2), &pos, 16) }; pos == 2)
{
// Strip off checksum part
line = line.substr(1,line.size() - 4);
// Calculate checksum
unsigned char calculatedChecksum{ 0U }; for (const unsigned char c : line) calculatedChecksum ^= c;
// Get result
result = (calculatedChecksum == checkSumGiven);
}
return result;
}
// Split all strings into a tokens
size_t splitIntoTokens(std::string& s, std::string (&tokens)[MaxTokensInSentence]) {
// Number of converted tokens
size_t numberOfTokens{ 0 };
// First check checksum
if (checksumTest(s)) {
// Now split along each comma
for (size_t i{ 0U }, startpos{ 0U }; i < s.size(); ++i) {
// So, if there is a comma or the end of the string
if ((s[i] == ',') || (i == (s.size() - 1))) {
// Copy substring
tokens[numberOfTokens++] = s.substr(startpos, i - startpos);
startpos = i + 1;
}
}
}
return numberOfTokens;
}
GGA convertStringToGGA(std::string& s) {
GGA gga;
// Split string into tokens and check, if it worked
if (std::string tokens[MaxTokensInSentence]; splitIntoTokens(s, tokens) > NumberOfFieldsInGGA && tokens[0] == "GPGGA") {
gga.fixTimeInUtcHours = std::stoul(tokens[1].substr(0, 2));
gga.fixTimeInUtcMinutes = std::stoul(tokens[1].substr(2, 2));
gga.fixTimeInUtcSeconds = std::stoul(tokens[1].substr(4, 2));
gga.fixTimeInUtcMilliSeconds = std::stod(tokens[1].substr(6, 2))*1000.0;
gga.lattitudeInDegree = std::stoul(tokens[2].substr(0, 2));
gga.lattitudeInMinutes = std::stod(tokens[2].substr(2));
gga.lattitideDirection = tokens[3];
gga.longitudeInDegree = std::stoul(tokens[4].substr(0, 2));
gga.longitudeInMinutes = std::stod(tokens[4].substr(2));
gga.longitudeDirection = tokens[5];
gga.fixQuality = std::stoul(tokens[6]);
gga.fixQualityString = (gga.fixQuality < NumberOfFixQualityStrings) ? fixQualityString[gga.fixQuality] : fixQualityString[0];
gga.numberOfTrackedSatellites = std::stoul(tokens[7]);
gga.horizontalDilution = std::stod(tokens[8]);
gga.altitude = std::stod(tokens[9]);
gga.altitudeDimension = tokens[10];
gga.goidHight = std::stod(tokens[11]);
gga.goidHightDimension = tokens[12];
}
return gga;
}
GSVSentencePart convertToGSVSentencePart(std::string& s) {
GSVSentencePart gsvsp;
// Split string into tokens and check, if it worked
std::string tokens[MaxTokensInSentence];
if (size_t numberOfCOnvertedTokens = splitIntoTokens(s, tokens); numberOfCOnvertedTokens > 0 && tokens[0] == "GPGSV") {
gsvsp.numberOfSentencesForFullData = std::stoul(tokens[1]);
gsvsp.sentencePartNumber = std::stoul(tokens[2]);
gsvsp.numberOfSatellitesInView = std::stoul(tokens[3]);
gsvsp.numberOfSatellitesInThisPart = 0;
for (size_t currentToken = 4; currentToken < numberOfCOnvertedTokens; currentToken += 4) {
gsvsp.satelliteData[gsvsp.numberOfSatellitesInThisPart].satellitePRNnumber = tokens[currentToken];
gsvsp.satelliteData[gsvsp.numberOfSatellitesInThisPart].elevationInDegress = stod(tokens[currentToken + 1]);
gsvsp.satelliteData[gsvsp.numberOfSatellitesInThisPart].azimuthInDegrees= stod(tokens[currentToken + 2]);
gsvsp.satelliteData[gsvsp.numberOfSatellitesInThisPart].snr = stod(tokens[currentToken + 3]);
++gsvsp.numberOfSatellitesInThisPart;
}
}
return gsvsp;
}
std::string calculateElapsedTime(const GGA& previousGGA, const GGA& nextGGA) {
std::tm tmPrevious{}, tmNext{};
tmPrevious.tm_year = 100; tmPrevious.tm_mon = 1; tmPrevious.tm_mday = 1;
tmNext.tm_year = 100; tmNext.tm_mon = 1; tmNext.tm_mday = 1;
tmPrevious.tm_hour = previousGGA.fixTimeInUtcHours;
tmPrevious.tm_min = previousGGA.fixTimeInUtcMinutes;
tmPrevious.tm_sec = previousGGA.fixTimeInUtcSeconds;
std::time_t previousTime = std::mktime(&tmPrevious);
tmNext.tm_hour = nextGGA.fixTimeInUtcHours;
tmNext.tm_min = nextGGA.fixTimeInUtcMinutes;
tmNext.tm_sec = nextGGA.fixTimeInUtcSeconds;
std::time_t nextTime = std::mktime(&tmNext);
double diff = std::difftime(nextTime, previousTime);
diff = diff + 1.0*nextGGA.fixTimeInUtcMilliSeconds/1000.0- 1.0*previousGGA.fixTimeInUtcMilliSeconds/1000.0;
return std::to_string(diff);
}
int main() {
// Open file and check, if it is open
if (std::ifstream nmeaFile("r:\\log.txt"); nmeaFile) {
GGA previousGGA;
GGA nextGGA;
GSV gsv;
size_t state{ 0 };
for (std::string line{}; std::getline(nmeaFile, line); ) {
switch ( state) {
case 0: // wait for first GGA data
if (line.substr(0, 6) == "$GPGGA") {
previousGGA = nextGGA;
nextGGA = convertStringToGGA(line);
state = 1;
gsv = {};
}
break;
case 1: // wait for GSV
if (line.substr(0, 6) == "$GPGSV") {
gsv.gsvSentencePart[gsv.numberOfParts] = convertToGSVSentencePart(line);
if (gsv.gsvSentencePart[gsv.numberOfParts].numberOfSentencesForFullData ==
gsv.gsvSentencePart[gsv.numberOfParts].sentencePartNumber) {
state = 0;
++gsv.numberOfParts;
// Now all data are available in reable and structed format.
// You can do, what you want with them
// For example, we can print all Satellite Data:
size_t counter{ 0 };
for (size_t i = 0; i < gsv.numberOfParts; ++i) {
for (size_t j = 0; j < gsv.gsvSentencePart[i].numberOfSatellitesInThisPart; j++) {
std::cout << "Satellite: " << std::setw(2) << ++counter << " Satellite name: " <<
std::setw(3) << gsv.gsvSentencePart[i].satelliteData[j].satellitePRNnumber <<
" SNR: " << std::setw(8) << gsv.gsvSentencePart[i].satelliteData[j].snr <<
" Elapsed time: "<< calculateElapsedTime(previousGGA, nextGGA)<< " s\n";
}
}
--gsv.numberOfParts;
}
++gsv.numberOfParts;
}
break;
}
}
}
return 0;
}
I can see bugs like if (hour, minute, sec) { and many C-Style code, operating with pointers or so. I do not want to debug you code.
As a samll hint for you, I created a parser that reads all source lines, splits tem into tokens and checks the checksum.
Only a few lines of code will do the trick. From that on you can develop further.
#include <iostream>
#include <regex>
#include <vector>
#include <iterator>
#include <string>
#include <utility>
#include <algorithm>
#include <functional>
#include <numeric>
#include <fstream>
const std::regex re{ R"(\$(.*)\*[abcdefABCDEF\d]{2})" };
const std::regex delimiter{ "," };
using Tokens = std::vector<std::string>;
std::tuple<bool, Tokens> checkString(const std::string& str) {
// Return value of the function. Assume that string is not ok
std::tuple<bool, std::vector<std::string>> result(false, {});
// We want to find a string in the given format
std::smatch sm{};
if (std::regex_match(str, sm, re)) {
// OK, found. Validate checksum
if (std::string s = sm[1]; std::stoul(str.substr(str.size() - 2), nullptr, 16) == std::accumulate(s.begin(), s.end(), 0U, std::bit_xor<unsigned char>())) {
// Tokenize string
Tokens tokens(std::sregex_token_iterator(str.begin(), str.end(), delimiter, -1), {});
// Build return value
result = std::make_tuple(true, std::move(tokens));
}
}
return result;
}
int main() {
std::vector<Tokens> csvData{};
// Open file and check if it is open
if (std::ifstream logs("r:\\log.txt"); logs) {
// Read all lines of files
for (std::string line{}; std::getline(logs, line);) {
if (const auto& [ok, data] = checkString(line); ok) {
csvData.push_back(std::move(data));
}
else {
std::cerr << "**** Coruppted: " << line << "\n";
}
}
}
// So, now we have read all csv data
// Show eight column of GPGSV data
for (const Tokens& t : csvData) {
if (t[0] == "$GPGGA") {
std::cout << "$GPGGA -->" << t[1] << "\n";
}
else if (t[0] == "$GPGSV") {
std::cout << "$GPGSV -->" << t[4] << " " << t[7] << "\n";
}
}
return 0;
}
Of course there are many other possibilities . .

How to insert an integer with leading zeros into a std::string?

In a C++14 program, I am given a string like
std::string s = "MyFile####.mp4";
and an integer 0 to a few hundred. (It'll never be a thousand or more, but four digits just in case.) I want to replace the "####" with the integer value, with leading zeros as needed to match the number of '#' characters. What is the slick C++11/14 way to modify s or produce a new string like that?
Normally I would use char* strings and snprintf(), strchr() to find the "#", but figure I should get with modern times and use std::string more often, but know only the simplest uses of it.
What is the slick C++11/14 way to modify s or produce a new string like that?
I don't know if it's slick enough but I propose the use of std::transform(), a lambda function and reverse iterators.
Something like
#include <string>
#include <iostream>
#include <algorithm>
int main ()
{
std::string str { "MyFile####.mp4" };
int num { 742 };
std::transform(str.rbegin(), str.rend(), str.rbegin(),
[&](auto ch)
{
if ( '#' == ch )
{
ch = "0123456789"[num % 10]; // or '0' + num % 10;
num /= 10;
}
return ch;
} // end of lambda function passed in as a parameter
); // end of std::transform()
std::cout << str << std::endl; // print MyFile0742.mp4
}
I would use regex since you're using C++14:
#include <iostream>
#include <regex>
#include <string>
#include <iterator>
int main()
{
std::string text = "Myfile####.mp4";
std::regex re("####");
int num = 252;
//convert int to string and add appropriate number of 0's
std::string nu = std::to_string(num);
while(nu.length() < 4) {
nu = "0" + nu;
}
//let regex_replace do it's work
std::regex_replace(std::ostreambuf_iterator<char>(std::cout),
text.begin(), text.end(), re, nu);
std::cout << std::endl;
return 0;
}
WHy not use std::stringstream and than convert it to string.
std::string inputNumber (std::string s, int n) {
std::stringstream sstream;
bool numberIsSet = false;
for (int i = 0; i < s; ++i) {
if (s[i] == '#' && numberIsSet == true)
continue;
else if (s[i] == '#' && numberIsSet == false) {
sstream << setfill('0') << setw(5) << n;
numberIsSet = true;
} else
sstream << s[i];
}
return sstream.str();
}
I would probably use something like this
#include <iostream>
using namespace std;
int main()
{
int SomeNumber = 42;
std:string num = std::to_string(SomeNumber);
string padding = "";
while(padding.length()+num.length()<4){
padding += "0";
}
string result = "MyFile"+padding+num+".mp4";
cout << result << endl;
return 0;
}
Mine got out of control while I was playing with it, heh.
Pass it patterns on its command line, like:
./cpp-string-fill file########.jpg '####' test###this### and#this
#include <string>
#include <iostream>
#include <sstream>
std::string fill_pattern(std::string p, int num) {
size_t start_i, end_i;
for(
start_i = p.find_first_of('#'), end_i = start_i;
end_i < p.length() && p[end_i] == '#';
++end_i
) {
// Nothing special here.
}
if(end_i <= p.length()) {
std::ostringstream os;
os << num;
const std::string &ns = os.str();
size_t n_i = ns.length();
while(end_i > start_i && n_i > 0) {
end_i--;
n_i--;
p[end_i] = ns[n_i];
}
while(end_i > start_i) {
end_i--;
p[end_i] = '0';
}
}
return p;
}
int main(int argc, char *argv[]) {
if(argc<2) {
exit(1);
}
for(int i = 1; i < argc; i++) {
std::cout << fill_pattern(argv[i], 1283) << std::endl;
}
return 0;
}
I would probably do something like this:
using namespace std;
#include <iostream>
#include <string>
int main()
{
int SomeNumber = 42;
string num = std::to_string(SomeNumber);
string guide = "myfile####.mp3";
int start = static_cast<int>(guide.find_first_of("#"));
int end = static_cast<int>(guide.find_last_of("#"));
int used = 1;
int place = end;
char padding = '0';
while(place >= start){
if(used>num.length()){
guide.begin()[place]=padding;
}else{
guide.begin()[place]=num[num.length()-used];
}
place--;
used++;
}
cout << guide << endl;
return 0;
}

Taking Each Individual Word From a String in C++

I am writing a method in C++ which will take a string of 2 or more words and output each individual word of the string separated by a second or so, using the sleep() method. I am trying to do this using a for loop and substrings. I am unsure also of the regexs which should be used, and how they should be used, to achieve the desired output.
I have reviewed this and this and find my question differs since I am trying to do this in a loop, and not store the individual substrings.
Input:
"This is an example"
Desired output:
"This " (pause) "is " (pause) "an " (pause) "example."
Use std::stringstream, no regular expressions required:
#include <iostream>
#include <sstream>
using namespace std;
int main() {
stringstream ss("This is a test");
string s;
while (ss >> s) {
cout << s << endl;
}
return 0;
}
Also, see How do I tokenize a string in C++?
Here are a pair of implementations that don't involve creating any extraneous buffers.
#include <boost/range/adaptor/filtered.hpp>
#include <boost/range/algorithm/copy.hpp> //for boost::copy
#include <chrono>
#include <iostream>
#include <string>
#include <experimental/string_view> //in clang or gcc; or use boost::string_ref in boost 1.53 or later; or use boost::iterator_range<char*> in earlier version of boost
#include <thread>
void method_one(std::experimental::string_view sv)
{
for(auto b = sv.begin(), e = sv.end(), space = std::find(b, e, ' ')
; b < e
; b = space + 1, space = std::find(space + 1, e, ' '))
{
std::copy(b, space, std::ostreambuf_iterator<char>(std::cout));
std::cout << " (pause) "; //note that this will spit out an extra pause the last time through
std::this_thread::sleep_for(std::chrono::seconds(1));
}
}
void method_two(std::experimental::string_view sv)
{
boost::copy(
sv | boost::adaptors::filtered([](const char c) -> bool
{
if(c == ' ')
{
std::cout << " (pause) "; //note that this spits out exactly one pause per space character
std::this_thread::sleep_for(std::chrono::seconds(1));
return false;
}
return true;
})
, std::ostreambuf_iterator<char>(std::cout)
);
}
int main() {
const std::string s{"This is a string"};
method_one(s);
std::cout << std::endl;
method_two(s);
std::cout << std::endl;
return 0;
}
Live on coliru, if you're into that.
you can implement your own method:
//StrParse.h
#pragma once
#include <iostream>
static counter = 0;
char* strPar(char* pTxt, char c)
{
int lenAll = strlen(pTxt);
bool strBeg = false;
int nWords = 0;
for(int i(0); i < lenAll; i++)
{
while(pTxt[i] != c)
{
strBeg = true;
i++;
}
if(strBeg)
{
nWords++;
strBeg = false;
}
}
int* pLens = new int[nWords];
int j = 0;
int len = 0;
for(i = 0; i < lenAll; i++)
{
while(pTxt[i] != c)
{
strBeg = true;
i++;
len++;
}
if(strBeg)
{
pLens[j] = len;
j++;
strBeg = false;
len = 0;
}
}
char** pStr = new char*[nWords + 1];
for(i = 0; i < nWords; i++)
pStr[i] = new char[pLens[i] + 1];
int k = 0, l = 0;
for(i = 0; i < lenAll; i++)
{
while(pTxt[i] != c)
{
strBeg = true;
pStr[k][l] = pTxt[i];
l++;
i++;
}
if(strBeg)
{
pStr[k][l] = '\0';
k++;
l = 0;
strBeg = false;
}
}
counter++;
if(counter <= nWords)
return pStr[counter - 1];
else
return NULL;
}
//main.cpp
#include "StrParse.h"
void main()
{
char* pTxt = " -CPlusPlus -programming -is -a - superb thing ";
char* pStr1 = NULL;
int i = 1;
char sep;
std::cout << "Separator: ";
sep = std::cin.get();
std::cin.sync();
while(pStr1 = strPar(pTxt, sep))
{
std::cout << "String " << i << ": " << pStr1 << std::endl;
delete pStr1;
i++;
}
std::cout << std::endl;
}

How to insert spaces in a big number to make it more readable?

I came up with this, since other examples provided on stackoverflow were in C#
string number_fmt(ulong n)
{
// cout << "(" << n << ")" << endl;
char s[128];
sprintf(s, "%lu", n);
string r(s);
reverse(r.begin(), r.end());
int space_inserted = 0;
size_t how_many_spaces = r.length() / 3;
if(r.length() % 3 != 0)
how_many_spaces += 1;
for(int i = 1; i < how_many_spaces; ++i)
{
r.insert(3 * i + space_inserted, " ");
space_inserted += 1;
}
reverse(r.begin(), r.end());
return r;
}
Do you know any better solution ?
I don't know about "better", but this version uses std::locale, etc.
#include <iostream>
#include <locale>
#include <sstream>
template<class Char>
class MyFacet : public std::numpunct<Char> {
public:
std::string do_grouping() const { return "\3"; }
Char do_thousands_sep() const { return ' '; }
};
std::string number_fmt(unsigned long n)
{
std::ostringstream oss;
oss.imbue(std::locale(oss.getloc(), new MyFacet<char>));
oss << n;
return oss.str();
}
int main() {
std::cout << number_fmt(123456789) << "\n";
}
EDIT: Of course, if your final goal is to print the values on an ostream, you can skip storing them in a string altogether.
#include <iostream>
#include <locale>
#include <sstream>
#include <cwchar>
template <class Char>
class MyFacet : public std::numpunct<Char> {
public:
std::string do_grouping() const { return "\3"; }
Char do_thousands_sep() const { return ' '; }
};
int main(int ac, char **av) {
using std::locale;
using std::cout;
// Show how it works to start with
cout << 123456789 << "\n";
// Switch it to spacey mode
locale oldLoc =
cout.imbue(locale(cout.getloc(), new MyFacet<char>));
// How does it work now?
cout << 456789123 << "\n";
// You probably want to clean up after yourself
cout.imbue(oldLoc);
// Does it still work?
cout << 789123456 << "\n";
}
This is already done by the locale.
The default local is "C" which does no formatting. But you can set it to your current language-specific local (as defined by your computer's setting by setting the current local as the first line of main).
int main()
{
std::locale::global(std::locale("")); // Set the default local of the machine
// Will be used by all streams.
// The "" will find the machine specific local
// and use that instead of the "C" locale
// Note: The C local should only be used for programmers.
// Alternatively you can imbue particular stream with the local
// To achieve a localized effect
// std::cout.imbue(std::locale(""));
// Now all you do is print the number.
std::cout << "123456789\n"; // This will print the number according to your local
} // For me US-en this is 123,456,789
// Your may very.
If you want to do something explicitly then you can set a facet in the local for printing numbers.
#include <iostream>
#include <locale>
#include <string>
template<typename CharT>
struct Sep : public std::numpunct<CharT>
{
virtual std::string do_grouping() const {return "\003";}
virtual CharT do_thousands_sep() const {return ':';}
};
int main()
{
std::cout.imbue(std::locale(std::cout.getloc(), new Sep <char>()));
std::cout << 123456789 << "\n"; // this prints 123:456:789
}
This one is different, but better is subjective. I think it's very succinct and clear what it's doing though:
string number_fmt(unsigned long long n, char sep = ',') {
stringstream fmt;
fmt << n;
string s = fmt.str();
s.reserve(s.length() + s.length() / 3);
// loop until the end of the string and use j to keep track of every
// third loop starting taking into account the leading x digits (this probably
// can be rewritten in terms of just i, but it seems more clear when you use
// a seperate variable)
for (int i = 0, j = 3 - s.length() % 3; i < s.length(); ++i, ++j)
if (i != 0 && j % 3 == 0)
s.insert(i++, 1, sep);
return s;
}
Using it like
cout << number_fmt(43615091387465) << endl;
prints
43,615,091,387,465
Admittedly, if one wanted to have the most possible efficient version and didn't mind specializing it for the case at hand, using a local char buffer can help a lot.
#include <iostream>
#include <string>
std::string format(unsigned long long i) {
char buffer[128]; // can be adapted more tightly with std::numeric_limits
char* p = buffer + 128;
*(--p) = '\0';
unsigned char count = 0;
while (i != 0) {
*(--p) = '0' + (i % 10);
i /= 10;
if (++count == 3) { count = 0; *(--p) = ' '; }
}
return p;
}
int main() {
std::cout << format(1234567890) << '\n';
}
In action at ideone:
1 234 567 890
(Key point: for number printing, go backward)
Not very optimal but small
QString str = QString::number(d);
for (int i = 3; str.size() > i; i += 4)
str.insert(str.size() - i, ' ');
If "better" means more efficient, you should:
use reserve on the output string (you know its size...)
avoid the insert in the middle of the string, because you have to copy a big part of the string each time you do that.
I would say something like this (untested):
std::string number_fmt (ulong n)
{
std::ostringstream buff;
buff << n;
std::string without_spaces = buff.str ();
std::string with_spaces;
with_spaces.reserve ((without_spaces.size () * 4) / 3);
std::size_t nb_inserted = 0;
for (auto it = without_spaces.rbegin (); it != without_spaces.rend (); ++it)
{
if (nb_inserted % 3 == 0 && nb_inserted != 0)
{
with_spaces.push_back (' ');
}
++ nb_inserted;
with_spaces.push_back (*it);
}
std::reverse (with_spaces.begin (), with_spaces.end ());
return with_spaces;
}