Hough transform old opencv convert into new opencv - c++

i am trying to make hough transformation to parallel programming this is a code that i found online and i am new in using opencv2 in c++ anyone know how to convert this code into new open cv code?
//Next do the Canney and Hough transforms on the smaller image
IplImage* src;
src=cvLoadImage(fileName, 0);
IplImage* dst = cvCreateImage( cvGetSize(src), 8, 1 );
IplImage* color_dst = cvCreateImage( cvGetSize(src), 8, 3 );
IplImage* final_dst = cvCreateImage( cvGetSize(src), 8, 1 );
CvMemStorage* storage = cvCreateMemStorage(0);
CvSeq* lines = 0;
int i;
cvCanny( src, dst, 50, 200, 3 );
cvCvtColor( dst, color_dst, CV_GRAY2BGR );
lines = cvHoughLines2( dst,
storage,
CV_HOUGH_STANDARD,
1,
CV_PI/180,
100,
0,
0 );
for( i = 0; i < MIN(lines->total,100); i++ )
{
float* line = (float*)cvGetSeqElem(lines,i);
float rho = line[0];
float theta = line[1];
CvPoint pt1, pt2;
double a = cos(theta), b = sin(theta);
double x0 = a*rho, y0 = b*rho;
pt1.x = cvRound(x0 + 1000*(-b));
pt1.y = cvRound(y0 + 1000*(a));
pt2.x = cvRound(x0 - 1000*(-b));
pt2.y = cvRound(y0 - 1000*(a));
cvLine( color_dst, pt1, pt2, CV_RGB(255,0,0), 2, 8 );
}
cvCvtColor(color_dst, final_dst, CV_BGR2GRAY);
cvSaveImage(fileName, final_dst);
i have tried a bit but i think i fail
//Next do the Hough transforms on the smaller image
cv::Mat src = cv::imread(fileName);
cv::Mat dst;
cv::Mat color_dst;
cv::Mat final_dst;
//IplImage src;
//src=cvLoadImage(fileName, 0);
//IplImage* dst = cvCreateImage( cvGetSize(src), 8, 1 );
//IplImage* color_dst = cvCreateImage( cvGetSize(src), 8, 3 );
//IplImage* final_dst = cvCreateImage( cvGetSize(src), 8, 1 );
//CvMemStorage* storage = cvCreateMemStorage(0);
cv::namedWindow(CW_IMG_ORIGINAL, cv::WINDOW_NORMAL);
cv::resizeWindow(CW_IMG_ORIGINAL, 1280, 720);
cv::moveWindow(CW_IMG_ORIGINAL, 10, 10);
cv::Mat lines;
//CvSeq* lines = 0;
//cv::Seq<linesTp>;
int i;
cvHoughLines2;
cv::Canny( src, dst, 50, 200, 3 );
cv::cvtColor( dst, color_dst, CV_GRAY2BGR );
cv::HoughLines( dst,lines,
CV_HOUGH_STANDARD,
1,
CV_PI/180,
100,
0,
0 );
for( i = 0; i < 100; i++ )
{
//float* line = (float*)cv::getSeqElem(lines, i);
float* line = lines.at(i);
float rho = line[0];
float theta = line[1];
cv::Point pt1, pt2;
double a = cos(theta), b = sin(theta);
double x0 = a*rho, y0 = b*rho;
pt1.x = cvRound(x0 + 1000*(-b));
pt1.y = cvRound(y0 + 1000*(a));
pt2.x = cvRound(x0 - 1000*(-b));
pt2.y = cvRound(y0 - 1000*(a));
cv::line(color_dst, pt1, pt2, CV_RGB(255, 0, 0), 2, 8);
}
cv::cvtColor(color_dst, final_dst, CV_BGR2GRAY);
cv::imshow(CW_IMG_ORIGINAL,final_dst);
I fail due to i dono how to implement the hough lines into the line to do the iteration of the formula previously using cvhoughlines2 but cvhoughlines2 need to insert as cvArr but the cvLoadImage is not currently working in opencv4.1.2 so that I cant use IplImage and cvLoadImage to run this code.

Related

opencv road line detection with HoughLines

Hello I have an image simple street image
I want to detect road lines like here
but so far I just can do this
I don't understand what I am doing wrong this is my code, I need to this HoughLines
#include "opencv2/imgcodecs.hpp"
#include "opencv2/highgui.hpp"
#include "opencv2/imgproc.hpp"
using namespace cv;
using namespace std;
int main(int argc, char** argv)
{
// Declare the output variables
Mat dst, cdst, cdstP;
// Loads an image
Mat src = imread( "/Users/user/Desktop/opencv_tests/street_scene.png", IMREAD_COLOR );
Canny(src, dst, 700, 500, 3);
// Copy edges to the images that will display the results in BGR
cvtColor(dst, cdst, COLOR_GRAY2BGR);
cdstP = cdst.clone();
// Standard Hough Line Transform
vector<Vec2f> lines; // will hold the results of the detection
HoughLines(dst, lines, 1, CV_PI/30, 75, 0, 0 );
// Draw the lines
for( size_t i = 0; i < lines.size(); i++ )
{
float rho = lines[i][0], theta = lines[i][1];
Point pt1, pt2;
double a = cos(theta), b = sin(theta);
double x0 = a*rho;
double y0 = b*rho;
pt1.x = cvRound(x0 + 1000*(-b));
pt1.y = cvRound(y0 + 1000*(a));
pt2.x = cvRound(x0 - 1000*(-b));
pt2.y = cvRound(y0 - 1000*(a));
line( src, pt1, pt2, Scalar(0,0,255), 3, LINE_AA);
}
imshow("Source", src);
waitKey();
return 0;
}

Rotate an image using OpenCV with C++ on interface

I'm developing Rotate an image using OpenCV in C++ on interface project.So, I have some problems with this code.Is there any way to solve this code...?
IplImage* source_image = cvLoadImage(ip, 1);
IplImage *rotate_image = cvCreateImage(cvGetSize(source_image), IPL_DEPTH_8U, 1);
cvNamedWindow("rotate_image", CV_WINDOW_FREERATIO);
int angle = 180;
cvCreateTrackbar("Angle", rotate_image,&angle,360);
int image_height = source_image.rows / 2;
int image_width = source_image.cols / 2;
IplImage *rotatetion = cvCreateImage(cvGetSize(source_image), IPL_DEPTH_8U, 1);
rotatetion = cv2DRotationMatrix(Point(image_height,image_width),(angle - 180), 1);
IplImage *rotated_image = cvCreateImage(cvGetSize(rotatetion), IPL_DEPTH_8U, 1);
cvWarpAffine(dialateImage,Rotated_Image,Rotatetion,dialateImage.size());
cvShowImage("rotateImage", rotated_image);
From https://docs.opencv.org/2.4/doc/tutorials/imgproc/imgtrans/warp_affine/warp_affine.html
Mat rot_mat( 2, 3, CV_32FC1 );
Mat warp_mat( 2, 3, CV_32FC1 );
Mat src, warp_dst, warp_rotate_dst;
/// Load the image
src = imread( argv[1], 1 );
/// Set the dst image the same type and size as src
warp_dst = Mat::zeros( src.rows, src.cols, src.type() );
/// Compute a rotation matrix with respect to the center of the image
Point center = Point( warp_dst.cols/2, warp_dst.rows/2 );
double angle = -50.0;
double scale = 0.6;
/// Get the rotation matrix with the specifications above
rot_mat = getRotationMatrix2D( center, angle, scale );
/// Rotate the warped image
warpAffine( warp_dst, warp_rotate_dst, rot_mat, warp_dst.size() );
Don't use obsolete C api like #Miki said and ask a clear question, not "this code no worky".
try this.worked.
IplImage* source_image;
IplImage *dest = cvCloneImage(source_image);
CvPoint2D32f center;
center.x = dest->width / 2;
center.y = dest->height / 2;
CvMat *mapMatrix = cvCreateMat(2, 3, CV_32FC1);
double angle = System::Convert::ToDouble(numericUpDown1->Value);
cv2DRotationMatrix(center, angle, 1.0, mapMatrix);
cvWarpAffine(source_image, dest, mapMatrix, CV_INTER_LINEAR + CV_WARP_FILL_OUTLIERS, cvScalarAll(0));
cvReleaseMat(&mapMatrix);
cvShowImage("Rotated", dest);

How to get Hough transform matrix ,theta and rho value of hough transformation in opencv cpp

I have matlab code to get Hough transform matrix, theta and rho values.
[H,T,R] = hough(EdgeImage);
How to get H, T, R values in OpenCV?
In OpenCV, you call the HT as:
vector<Vec2f> lines;
HoughLines(edges, lines, 1, CV_PI/180.0, 100);
where edge is your binary input image, and lines is a std::vector of Vec2f, i.e. a vector of 2 float values: the first value is rho, the second one is theta.
OpenCV doesn't output the H parameter space, if you need also that you need to write some code yourself and adapt HoughLines to output also the H value. However, this is rarely needed in practice.
This is a simple example on how to use standard Hough Transform, adapted from OpenCV tutorials:
#include <opencv2\opencv.hpp>
#include <vector>
using namespace std;
using namespace cv;
int main()
{
// Load image
Mat3b img = imread("path_to_image");
Mat3b res = img.clone();
// Convert to grayscale
Mat1b gray;
cvtColor(img, gray, COLOR_BGR2GRAY);
// Compute edges
Mat1b edges;
Canny(gray, edges, 100, 400);
vector<Vec2f> lines;
HoughLines(edges, lines, 1, CV_PI/180.0, 100);
for (size_t i = 0; i < lines.size(); i++)
{
// rho and theta values
float rho = lines[i][0];
float theta = lines[i][1];
// Draw the line
Point pt1, pt2;
double a = cos(theta), b = sin(theta);
double x0 = a*rho, y0 = b*rho;
pt1.x = cvRound(x0 + 1000 * (-b));
pt1.y = cvRound(y0 + 1000 * (a));
pt2.x = cvRound(x0 - 1000 * (-b));
pt2.y = cvRound(y0 - 1000 * (a));
line(res, pt1, pt2, Scalar(0, 0, 255), 2);
}
imshow("Input", img);
imshow("Output", res);
waitKey();
return 0;
}
Input:
Output:

Opencv: Cannot load new frame while detecting Hough lines

I'm trying to detect Hough Lines in video captured by cam. The problem is that to load a new frame, I have to close current window and after that, a new window with a new frame is opened automatically. I just want to get rid of closing windows to load new frames. How can I play the video in single window without closing it?
#include <opencv2/highgui/highgui.hpp>
#include <opencv2/imgproc/imgproc.hpp>
#include <iostream>
using namespace cv;
using namespace std;
int main()
{
VideoCapture stream(0);
if(!stream.isOpened()){
cout << "\nCannot open video camera";
} else {
//CAPTURING FRAMES FROM CAMERA
while( true ){
Mat src;
stream.read(src);
//Mat src = imread("D:/LineDetection.png", 0);
Mat dst, cdst;
Canny(src, dst, 50, 200, 3);
cvtColor(dst, cdst, CV_GRAY2BGR);
vector<Vec2f> lines;
// detect lines
HoughLines(dst, lines, 1, CV_PI/180, 150, 0, 0 );
// draw lines
for( size_t i = 0; i < lines.size(); i++ )
{
float rho = lines[i][0], theta = lines[i][1];
Point pt1, pt2;
double a = cos(theta), b = sin(theta);
double x0 = a*rho, y0 = b*rho;
pt1.x = cvRound(x0 + 1000*(-b));
pt1.y = cvRound(y0 + 1000*(a));
pt2.x = cvRound(x0 - 1000*(-b));
pt2.y = cvRound(y0 - 1000*(a));
line( cdst, pt1, pt2, Scalar(0,0,255), 3, CV_AA);
}
imshow("source", src);
imshow("detected lines", cdst);
if( waitKey() == 32 )
break;
}
}
return 0;
}
Change waitKey() to waitKey(10).
waitKey() - will wait for keypress infinite time.

Draw the lines detected by cv::HoughLines

On this site(tutorial), it show us how to draw the lines detected by cv::HoughLines,but I can't understand how could it find out the Point between the lines.
for( size_t i = 0; i < lines.size(); i++ )
{
float rho = lines[i][0], theta = lines[i][1];
Point pt1, pt2;
double a = cos(theta), b = sin(theta);
double x0 = a*rho, y0 = b*rho;
pt1.x = cvRound(x0 + 1000*(-b)); //??
pt1.y = cvRound(y0 + 1000*(a)); //??
pt2.x = cvRound(x0 - 1000*(-b)); //??
pt2.y = cvRound(y0 - 1000*(a)); //??
line( cdst, pt1, pt2, Scalar(0,0,255), 3, CV_AA);
}
Example from the openCV cookbook, I could understand the reason these codes
but it is more verbose
for(auto const &data : lines){
float const rho = data[0];
float const theta = data[1];
if((theta < PI/4. || theta > 3. * PI/4.)){
cv::Point pt1(rho / std::cos(theta), 0);
cv::Point pt2( (rho - result.rows * std::sin(theta))/std::cos(theta), result.rows);
cv::line(result, pt1, pt2, cv::Scalar(255), 1);
}else if{
cv::Point pt1(0, rho / std::sin(theta));
cv::Point pt2(result.cols, (rho - result.cols * std::cos(theta))/std::sin(theta));
cv::line(result, pt1, pt2, cv::Scalar(255), 1);
}
}
Hough Line transform returns Polar coordinates. To display the lines on 2D picture, coordinates have to be converted do Cartesian coordinates. Here is some more info about this: http://www.mathsisfun.com/polar-cartesian-coordinates.html
Lines, returned from Hough Transform have only one Cartesian point (intersect between blue and red line):
So to display the line author converts the coordinates to Cartesian and then calculates start and end points which are set to fixed position -1000 and +1000 pixels from the converted point:
pt1.x = cvRound(x0 + 1000*(-b)); //??
pt1.y = cvRound(y0 + 1000*(a)); //??
pt2.x = cvRound(x0 - 1000*(-b)); //??
pt2.y = cvRound(y0 - 1000*(a)); //??
One option to find intersection between returned lines is to use this equation:
For more information about implementation of this see this tutorial.