2 Forms on same model not saving as same user - Django - django

I'm creating a questionnaire / survey, and have two forms (Model Form) built on the same model. These forms are called on separate views, but when saved they appear as separate users in the database. I'm not sure how to get them so save as the same user, I am already using the ' post = form.save(commit=False), post.user = request.user, post.save()' method to save the forms.
EDIT: Added in an attempt to save to the same instance
Model:
class QuizTakers(models.Model):
user = models.ForeignKey(User, on_delete=models.CASCADE)
industry_choices = (
(1, 'Service'),
(2, 'Hospitality'),
(3, 'Wholesale/Retail'),
(4, 'Manufacturing'),
(5, 'Agriculture')
)
industry = MultiSelectField(choices=industry_choices, max_length=1, max_choices=1)
company_name = models.CharField( max_length=100)
email = models.EmailField(blank=True)
score = models.FloatField(default=0)
completed = models.BooleanField(default=False)
timestamp = models.DateTimeField(auto_now_add=True)
def __str__(self):
return self.company_name
Forms:
# Form for getting company name
class QuizTakerForm(forms.ModelForm):
class Meta:
model = QuizTakers
fields = ['company_name']
# Form for getting company industry
class QTIndustryForm(forms.ModelForm):
class Meta:
model = QuizTakers
fields = ['industry']
Views:
# view for getting company name
def start(request):
if request.method == 'POST':
# create a form instance and populate it with data from the request:
form = QuizTakerForm(request.POST)
# check whether it's valid:
if form.is_valid():
# process the data in form.cleaned_data as required
request.session['company_name'] = form.cleaned_data['company_name']
post = form.save(commit=False)
post.user = request.user
post.save()
# redirect to a new URL:
return HttpResponseRedirect('industry/')
# if a GET (or any other method) we'll create a blank form
else:
form = QuizTakerForm()
return render(request, 'ImpactCheck/start.html', {'form': form})
# view for getting industry
class IndustryView(FormView):
template_name = 'ImpactCheck/industry.html'
form_class = QTIndustryForm
success_url = '1/'
def get(self, request):
company_name = request.session['company_name']
this_user=QuizTakers.objects.filter(company_name=company_name).order_by('-timestamp').first()
form=self.form_class(instance=this_user)
company_name = request.session['company_name']
return render(request, 'ImpactCheck/industry.html', {'form': form, 'company_name': company_name})
def form_valid(self, form):
# This method is called when valid form data has been POSTed.
# It should return an HttpResponse.
post = form.save(commit=False)
post.user = self.request.user
post.save()
return HttpResponseRedirect('/1')

Firstly, in your def start(request) function, you should consider adding the ID to request.session instead of the company name. Something along the lines of
def start(request):
if request.method == 'POST':
# create a form instance and populate it with data from the request:
form = QuizTakerForm(request.POST)
# check whether it's valid:
if form.is_valid():
# process the data in form.cleaned_data as required
form.instance.user=request.user
form.save()
request.session['obj_id'] = post.id
# redirect to a new URL:
return HttpResponseRedirect('industry/')
Now you can use that id to get both the name of your company, as well as the object.
In your IndustryView(FormView), if you're having trouble with the form instances, it's better to use UpdateView instead of the FormView (Be sure to import UpdateView first)
class IndustryView(UpdateView):
template_name = 'ImpactCheck/industry.html'
model = QuizTakers
fields = ['industry']
success_url = '/1'
def get_object(self):
return QuizTakers.objects.get(pk=self.request.session.get('obj_id'))
def get_context_data(self, **kwargs):
ctx = super().get_context_data(**kwargs)
ctx['company_name'] = QuizTakers.objects.get(pk=self.request.session.get('obj_id'))
return ctx
We use the get_context_data method since you need the company_name in your template. The get_object method in this view, tells django which object is to be updated. By default, it grabs the pk from the url (as a url parameter). But since we store our id in the session, we need to explicitly define this function.
Also, since we switched to UpdateView, you no longer need the QTIndustryForm either.

Related

With Django, how do I reference an existing model in a form save method instead of creating a new instance?

I'm trying to use a ModelChoiceField to display options populated from model, and when a user selects a choice, store that method in a different model.
I'm using a standard form instead of a ModelForm, because I wasn't able to get the form to display how I wanted to when using a Modelform.
My issue is that in my form save method, a new instance is created, which is not what I want.
Here are the relevant models:
class Client(models.Model):
client_email = models.EmailField(max_length = 254)
first_name = models.CharField(max_length=200)
last_name = models.CharField(max_length=200)
phone = PhoneField(blank=True)
assigned_manager = models.ForeignKey(Manager, on_delete=models.CASCADE, blank=True, null=True)
created_date = models.DateTimeField(default=timezone.now)
#property
def full_name(self):
return '{0} {1}'.format(self.first_name, self.last_name)
class Manager(models.Model):
first_name = models.CharField(max_length=200)
last_name = models.CharField(max_length=200)
manager_email = models.EmailField(max_length = 254)
username = models.OneToOneField(settings.AUTH_USER_MODEL, on_delete=models.CASCADE, blank=True, null=True)
#property
def full_name(self):
return '{0} {1}'.format(self.first_name, self.last_name)
My view:
def manageclient(request, urlid):
client = Client.objects.get(id=urlid)
form = AssignManagerForm()
if request.method == "POST":
form = AssignManagerForm(request.POST)
if form.is_valid():
form.save()
return render(request, 'mysite/manageclient.html', {})
else:
form = AssignManagerForm()
context = {
'client': client,
'urlid': urlid,
'form': form,
}
return render(request, 'mysite/manageclient.html', context)
And my forms.py
class AssignManagerForm(forms.Form):
full_name = forms.ModelChoiceField(queryset=Manager.objects.all())
def save(self):
data = self.cleaned_data
client = Client(assigned_manager=data['full_name'])
client.save()
What I need to do is pass the urlid in my view to my save method in my forms.py, but I am unsure how to do that. Even if i could do that, I'm not sure how to modify form save to use urlid to refer to a specific record and set only the assigned_manager record.
Additionally, while I want the meta field to be used to display the form, I know it isn't what should be being passed to the assigned_manager field. How would I pass a Manager of instance to establish the foreign key relationship?
edit: edited to correct queryset in forms.py as per comments
Here is a solution using a ModelForm, by using a ModelForm you no longer have to manually set attributes on save or provide initial values when updating an existing instance.
The field assigned_manager will still be named assigned_manager but it's label can be overridden to be whatever you want it to be by passing labels in the ModelForm.Meta
class AssignManagerForm(forms.ModelForm):
class Meta:
model = Client
fields = ['assigned_manager']
labels = {'assigned_manager': 'Full name'}
def manageclient(request, urlid):
client = Client.objects.get(id=urlid)
if request.method == "POST":
form = AssignManagerForm(request.POST, instance=client)
if form.is_valid():
client = form.save()
# The general convention is to redirect after a successful POST
else:
form = AssignManagerForm(instance=client)
context = {
'client': client,
'urlid': urlid,
'form': form,
}
return render(request, 'mysite/manageclient.html', context)
Instead of saving it in form, you can directly do this operation in view. For example:
def manageclient(request, urlid):
client = Client.objects.get(id=urlid)
if request.method == "POST":
form = AssignManagerForm(request.POST)
if form.is_valid():
client.assigned_manager = form.cleaned_data['full_name']
client.save()
return render(request, 'mysite/manageclient.html', {})

"Select a valid choice. <choice> is not one of the available choices" error when submitting ManyToMany ModelForm

I want to limit the choices of a ManyToManyField to those matching a ForeignKey. The form displays properly, but upon saving results in an error Select a valid choice. <choice> is not one of the available choices.
Before I was trying to limit the queryset by passing a parameter in the view to the form, and then using that parameter to filter the queryset.
Models:
class VenueEventTimeslot(models.Model):
venue = models.ForeignKey(Venue)
name = models.CharField(max_length=255)
class VenueEvent(models.Model):
venue = models.ForeignKey(Venue)
event_timeslots = models.ManyToManyField(VenueEventTimeslot)
class VenueEventForm(ModelForm):
event_timeslots = ModelMultipleChoiceField(queryset=None, widget=CheckboxSelectMultiple())
def __init__(self, *args, **kwargs): # limit timeslots to those of the venue only
venue_obj = kwargs.pop('venue_obj',None)
super(VenueEventForm, self).__init__(*args,**kwargs)
self.fields['event_timeslots'].queryset=VenueEventTimeslot.objects.filter(venue=venue_obj)
class Meta:
model = VenueEvent
fields = ['event_timeslots']
Views:
#login_required
def calendar(request, pk):
venue = Venue.objects.get(pk = pk)
if request.method == "POST":
form = VenueEventForm(request.POST)
if form.is_valid():
# form stuff
else:
form = VenueEventForm(venue_obj = venue)
context = {'venue':venue, 'form':form}
return render(request, ... , context)
However, if I pass the queryset from the view, it works perfectly.
Models:
class VenueEventTimeslot(models.Model):
# same as above
class VenueEvent(models.Model):
# same as above
class VenueEventForm(ModelForm):
class Meta:
model = VenueEvent
fields = ['date','client_name','event_timeslots']
widgets = {
'date': SelectDateWidget(),
'event_timeslots': CheckboxSelectMultiple(),
}
Views:
#login_required
def calendar(request, pk):
venue = Venue.objects.get(pk = pk)
if request.method == "POST":
form = VenueEventForm(request.POST)
if form.is_valid():
# form stuff
else:
form = VenueEventForm()
form.fields['event_timeslots'].queryset=VenueEventTimeslot.objects.filter(venue=venue)
context = {'venue':venue, 'form':form}
return render(request, ..., context)
Would anyone be able to shed some light on this?
I just solved a problem similar to this yesterday which is right here, How To Exclude A Value In A ModelMultipleChoiceField?, but I think the issue with your init function is the way it is formatted. Instead of venue=venue_obj, you need to change it to pk=venue_obj because it appear you are getting the pk of venue in the view instead of the venue attribute of VenueEvent , and I reformatted your form a bit to make it look cleaner.
forms.py
class VenueEventForm(ModelForm):
def __init__(self, *args, **kwargs): # limit timeslots to those of the venue only
venue_obj = kwargs.pop('venue_obj')
super(VenueEventForm, self).__init__(*args,**kwargs)
self.fields['event_timeslots'] = forms.ModelMultipleChoiceField(widget=forms.CheckboxSelectMultiple(), queryset=VenueEventTimeslot.objects.filter(pk=venue_obj))
class Meta:
model = VenueEvent
fields = ['event_timeslots']
views.py
#login_required
def calendar(request, pk):
venue = Venue.objects.get(pk = pk)
if request.method == "POST":
form = VenueEventForm(request.POST, venue_obj=venue)
if form.is_valid():
# form stuff
else:
print VenueEventForm.errors
else:
form = VenueEventForm(venue_obj=venue)
context = {'venue':venue, 'form':form}
return render(request, ... , context)

Adding a new field to django form

I am totally new in Django and I'm trying to use django forms for the first time. I have searched for this but I still haven't exactly found the answer. Basically I have a view like this:
def pay(request):
if request.method == 'POST':
form = PaymentForm(request.POST)
if form.is_valid():
# I have to calculate the checksum here
myModel = form.save()
else:
print form.errors
else: # The request is GET
form = PaymentForm()
return render_to_response('payment/payment.html', {'form':form})
and I want add an additional field, checksum to the form from the inputs I got from the form So when the user submits the entries the checksum should be added and added to the form and the form should be sent to an external server. But I don't know how to do that (I have defined checksum in my Model). Could anyone help me on this?
My model looks like this:
class PaymentModel(models.Model):
alphanumeric = RegexValidator(r'^[0-9a-zA-Z]*$', 'Only alphanumeric characters are allowed!')
secret_key = '6cd118b1432bf22942d93d784cd17084'
pid = models.CharField(primary_key=True, max_length=50, validators=[alphanumeric])
sid = models.CharField(primary_key=True, max_length=50, validators=[alphanumeric])
amount = models.DecimalField(max_digits=9, decimal_places=2)
success_url = 'http://localhost:8000/success'
cancel_url = 'http://localhost:8000/cancel'
error_url = 'http://localhost:8000/error'
checksum = 0
def calc_checksum(self):
checksumstr = "pid=%s&sid=%s&amount=%s&token=%s"% (self.pid, self.sid, self.amount, self.secret_key)
m = md5(checksumstr)
checksum = m.hexdigest()
return checksum
def __unicode__(self): #returns the unicode representation of the object
return self.name
and my form looks like this:
class PaymentForm(ModelForm):
class Meta:
model = PaymentModel
You can use the commit=False keyword argument to form.save():
def pay(request):
if request.method == 'POST':
form = PaymentForm(request.POST)
if form.is_valid():
# Will not save it to the database
myModel = form.save(commit=False)
# keep your business logic out of the view and put it on the form or model
# so it can be reused
myModel.checksum = form.calculate_checksum()
myModel.save()
else:
print form.errors
else: # The request is GET
form = PaymentForm()
return render_to_response('payment/payment.html', {'form':form})
Django form.save() documentation.

django forms - how to filter number of available options in a form

I'm trying to limit number of "categories" that user have available when entering new "feed" only to categories that he owns and he created. The way it works now is that user can add "feed" to other users' "categories" as this is what the form displays. How can I fix it ?
thanks!
-M
models.py
from django.db import models
from django.contrib.auth.models import User
class Category(models.Model):
name = models.CharField(max_length=50)
user = models.ForeignKey(User)
class Feed(models.Model):
url = models.URLField()
name = models.CharField(max_length=50)
created = models.DateTimeField(auto_now_add=True)
description = models.TextField(blank=True)
category = models.ForeignKey(Category)
user = models.ForeignKey(User)
forms.py
class FeedForm(forms.ModelForm):
class Meta:
model = Feed
exclude = ['user']
views.py
def addfeed(request, user):
user = request.user
page_title = "Add feed"
instance = Category.objects.filter(user=request.user)
if request.method == 'POST':
form = FeedForm(request.POST, instance=instance)
if form.is_valid():
feed = form.save(commit=False)
feed.user = request.user
feed.save()
return HttpResponseRedirect("/user/" + user.username + "/manage")
else:
form = FeedForm()
return render(request, "form_manage.html", {
'page_title': page_title,
'form': form,
})
Set the queryset attribute of the field somewhere. Because it depends on your user, it's something you have to set during or after instantiating the form. For instance, here's how to do it in the view:
def addfeed(request, user):
user = request.user # why does this view take user as an arg and then reassign?
page_title = "Add feed"
categories = Category.objects.filter(user=request.user)
if request.method == 'POST':
form = FeedForm(request.POST)
form.fields['category'].queryset = categories
if form.is_valid():
feed = form.save(commit=False)
feed.user = request.user
feed.save()
return HttpResponseRedirect("/user/" + user.username + "/manage")
else:
form = FeedForm()
form.fields['category'].queryset = categories
return render(request, "form_manage.html", {
'page_title': page_title,
'form': form,})
I removed the instance argument to your POST case's form construction because that's meant for passing in an existing Feed instance, not a categories queryset.
You could also do this in the form's __init__ if you pass in the correct categories queryset.
I use javascript to do this. For example, you could pass a list of the relevant categories as extra context in your view then use javascript in your template to empty the pre-populated option field in the form and replace it with your extra context.

want to get currently logged user's id (using django-registration )

I'm using django-registration for registration and login purpose. My Models and Forms.py are working fine. The problem is I want to store the currently logged user's id in the user field of the following Model:
MALE = 1
FEMALE = 2
SEX_CHOICES = (
(MALE,'Male'),
(FEMALE,'Female'),
)
class UserProfile(models.Model):
#user = models.IntegerField() # update : Changed to ForeignKey.
user = models.ForeignKey(User)
gender = models.IntegerField(choices = SEX_CHOICES,null=True, blank=True)
zip_code = models.CharField(max_length=100,null=True, blank=True)
language = models.ManyToManyField(Category)
My ModelForm:
class UserProfileForm(forms.ModelForm):
class Meta:
model = UserProfile
widgets = {'language': forms.CheckboxSelectMultiple}
Update 2: Here is my view:
def some_view(request):
if request.method == 'POST':
form = UserProfileForm(request.POST)
if form.is_valid():
form.save()
else:
form = UserProfileForm()
Update: I can get currently logged in user's using {{ user.id }} in template. But now How do i pass this id to user field?
Well, in you view you can access the currently logged user via request.user.
Make this user initial data in your Form :
#login_required
def my_view(request):
logged_user = request.user
initial = {'user': logged_user}
form = MyForm(request.POST or None, initial=initial)
# Here your logical code
# ...
return HttpResponse(...)
And if you are using a ModelForm:
#login_required
def my_view(request):
logged_user = request.user
form = MyUserProfileModelForm(
request.POST or None,\
instance=logged_user.get_profile())
# Here your logical code
# ...
return HttpResponse(...)
Note: get_profile() is a OneToOneField and may raise a DoesNotExist exception if your database is screwed (which may happen if you have tried different things here).