find the longest word in a vector c++ - c++

Question

So i have a c++ vector which contains about 106 thousand words which are stored on vector<string>words i need to find the longest word in this vector and i also need to get the location at which the word is, for example (1,2,3) in my vector. I need this location because i have two other vectors which has the meaning and the type for the words. vector<string>definition, vector<string>type
Please help
My current code
this code is not working at all
copy_if(words.begin(), words.end(), back_inserter(length), [](const string& x) { return x.length() > 40; });// looks for words longer than 7 letters
for (const string& s : length)
{
cout << "found!!" << endl;
auto i = find(words.begin(), words.end(), s);//looks for the word in the words vector
if (i != words.end())
{
auto pos = i - words.begin();
//displays the word, type and the definition of the word that the user has entered
cout << "Word : " << words[pos] << '\n';
cout << "Type : " << definitions[pos] << '\n';
cout << "Definition: " << types[pos] << '\n';
cout << '\n';
}
else
cout << "word not found" << endl;
}

Answer 1

You could use the standard algorithm std::max_element to search through the vector<string>.
Example:
#include <algorithm> // max_element
#include <iostream>
#include <iterator> // distance
#include <string>
#include <vector>
int main() {
std::vector<std::string> words{"a", "bb", "ccc"};
auto it = std::max_element(words.begin(), words.end(),
[](const auto& a, const auto& b) {
return a.size() < b.size();
});
std::cout << "The longest word is " << *it << " at (zero-based) pos "
<< std::distance(words.begin(), it) << '\n';
}
Output:
The longest word is ccc at (zero-based) pos 2

Answer 2

I would prefer thinking simply: just check length of elements according to each indice and update information according to that.
std::vector<std::string> length;
// initialize the vector length
size_t max_length = 0; // the length of longest word(s)
std::vector<size_t> max_indice; // the indice of longest word(s)
for (size_t i = 0; i < length.size(); i++) {
size_t this_len = length[i].length();
if (this_len > max_length) {
// new record
max_length = this_len;
max_indice.clear();
max_indice.push_back(i);
} else if (this_len == max_length) {
// tie
max_indice.push_back(i);
}
}
for (size_t pos : max_indice) {
cout << "Word : " << words[pos] << '\n';
cout << "Type : " << definitions[pos] << '\n';
cout << "Definition: " << types[pos] << '\n';
cout << '\n';
}