GLSL for sprite sheet - opengl

I have a shader that renders a simple texture on the screen. But, consider that I have a sprite sheet (multiple frames for a sprite) and I want to render just a small portion of that sheet (a frame), how would I do that using GLSL?
I do not want to manipulate the vertex buffer since that would become extremely costly.
My vertex shader:
#version 330 core
layout (location = 0) in vec4 vertex; // <vec2 position, vec2 texCoords>
out vec2 TexCoords;
uniform mat4 model;
uniform mat4 projection;
void main()
{
TexCoords = vertex.zw;
gl_Position = projection * model * vec4(vertex.xy, 0.0, 1.0);
}
My fragment shader:
#version 330 core
in vec2 TexCoords;
out vec4 FragColor;
uniform sampler2D texture;
uniform vec4 color;
void main()
{
FragColor = texture(texture, TexCoords) * color;
}
Here is how I calculate where along the X the current animation frame is in the texture:
m_animationData.x = (m_animationData.width * m_currentFrame);
So consider if I have a 128x32 sprite sheet, and the size of the sprite is 32x32, that makes it have 4 frames of animation. Each frame would then have an X equivalent of
frame 0: 0
frame 1: 32
frame 2: 64
frame 3: 96
All that is missing is how to tell the shader to render just that portion of the texture.

Related

OpenGL jpg image loaded with SOIL is displayed slanted

When loading the jpg image using SOIL, the image is displayed slanted and the colors are not right (i don't know how to describe it, because it is in color, but it looks black and white)
The intended version
However, it is displayed like this
The shaders are:
vertex shader
#version 330 core
layout (location = 0) in vec3 position;
layout (location = 1) in vec3 color;
layout (location = 2) in vec2 texCoord;
out vec3 ourColor;
out vec2 TexCoord;
void main(){
gl_Position = vec4(position, 1.0f);
ourColor = color;
TexCoord = texCoord;
}
fragment shader
#version 330 core
in vec3 ourColor;
in vec2 TexCoord;
out vec4 color;
uniform sampler2D ourTexture;
void main(){
color = texture(ourTexture, TexCoord);
}
How to display it correctly, the intended way?
By default OpenGL assumes that the start of each row of an image is aligned with 4 bytes. This is because the GL_UNPACK_ALIGNMENT parameter by default is 4. If the format of the image is RGB and width*3 is not divisibly by 4, you must change the parameter before specifying the two-dimensional texture image (glTexImage2D):
glPixelStorei(GL_UNPACK_ALIGNMENT, 1);

Why do OpenGL resized images look pixelated?

I want to display 2 textures on 2 squares. Here's what it looks like.
left side 325x325 ( the same size as the image ), right side (100x100)
the image size is 325x325. How to make the texture of the right side more sharp.
the only way to get good quality is when I use textures and objects with the same size.
I'm using PNG images and the following GL methods.
gl::TexParameteri(gl::TEXTURE_2D, gl::TEXTURE_MAG_FILTER, gl::LINEAR as i32);
gl::TexParameteri(gl::TEXTURE_2D, gl::TEXTURE_MIN_FILTER, gl::LINEAR as i32);
My vertex
#version 430 core
layout(location = 0) in vec2 position;
layout(location = 1) in vec2 texCoord;
layout(location = 2) in float layer;
out vec2 uv;
out float layer_get;
uniform mat4 MVP;
void main()
{
gl_Position = MVP * vec4(position.x, position.y, 0.0, 1.0);
uv = texCoord;
layer_get = layer;
}
My fragment
#version 430 core
out vec4 color;
in vec2 uv;
in float layer_get;
layout (binding=0) uniform sampler2DArray textureArray;
void main()
{
color = texture(textureArray, vec3(uv.x,uv.y, 0));
}
thank you in advance
As mentioned in the comments and the linked question, you can improve the quality by trilinear filtering and generating Mipmaps.
Use one of the "mipmap" texture minifying functions gl::NEAREST_MIPMAP_NEAREST, gl::LINEAR_MIPMAP_NEAREST, gl::NEAREST_MIPMAP_LINEAR or gl::LINEAR_MIPMAP_LINEAR:
gl::TexParameteri(gl::TEXTURE_2D, gl::TEXTURE_MIN_FILTER, gl::LINEAR_MIPMAP_LINEAR as i32);
Generate the mip maps by gl::GenerateMipmap after specifying the two-dimensional texture image (after gl::TexImage2D):
gl::GenerateMipmap(gl::TEXTURE_2D)

Drawing smooth circle

I'm using OpenTK (C#) but OpenGL suggestions are welcome too.
I have a point list generated by iteration having 1 degrees per point around the center point which means there are 361 point including the center point. Point list can be different with different approaches, that's ok. I can draw the circle with the below simple Vertex and Fragment shaders. How can change the fragment and/or vertex shaders to have a smooth circle.
Vertex shader:
#version 330
in vec3 vPosition;
in vec4 vColor;
out vec4 color;
out vec4 fPosition;
uniform mat4 modelview;
void main()
{
fPosition = modelview * vec4(vPosition, 1.0);
gl_Position = fPosition;
color = vColor;
}
Fragment shader:
#version 330
in vec4 color;
in vec4 fPosition;
out vec4 outputColor;
void main()
{
outputColor = color;
}
C# code:
GL.DrawArrays(PrimitiveType.TriangleFan, 0, points.Length);
Hello what do you actually see ? Post a screenshot. Anyway for smooth edges we have what's called anti alising.
Use this line for your glControl to enable it
glControl = new GLControl(new OpenTK.Graphics.GraphicsMode(32, 24, 0, 8));

OpenGL: Terrain deformation using a heightmap in the vertex shader

I have been trying to implement a heightmap to my terrain shader, but the terrain remains flat. The texture is properly loaded in the vertex shader, and I try to use the greyscale values of the texture based on the mesh's uvs to adjust the vertex height:
//DIFFUSE VERTEX SHADER
#version 330
uniform mat4 projectionMatrix;
uniform mat4 viewMatrix;
uniform mat4 modelMatrix;
in vec3 vertex;
in vec3 normal;
in vec2 uv;
uniform sampler2D heightmap;
out vec2 texCoord;
void main( void ){
vec3 _vertex = vertex;
_vertex.y = texture(heightmap, uv).r * 2.f;
gl_Position = projectionMatrix * viewMatrix * modelMatrix * vec4(_vertex, 1.f);
texCoord = uv;
}
Fragment: (the splatmap works so ignore that)
uniform sampler2D splatmap;
uniform sampler2D diffuse1;
uniform sampler2D diffuse2;
uniform sampler2D diffuse3;
uniform sampler2D diffuse4;
in vec2 texCoord;
out vec4 fragment_color;
void main( void ) {
///Loading the splatmap and the diffuse textures
vec4 splatTexture = texture2D(splatmap, texCoord);
vec4 diffuseTexture1 = texture2D(diffuse1, texCoord);
vec4 diffuseTexture2 = texture2D(diffuse2, texCoord);
vec4 diffuseTexture3 = texture2D(diffuse3, texCoord);
vec4 diffuseTexture4 = texture2D(diffuse4, texCoord);
//Interpolate between the different textures using the splatmap's rgb values (works)
diffuseTexture1 *= splatTexture.r;
diffuseTexture2 = mix (diffuseTexture1, diffuseTexture2, splatTexture.g);
diffuseTexture3 = mix (diffuseTexture2,diffuseTexture3, splatTexture.b);
vec4 outcolor = mix (diffuseTexture3, diffuseTexture4, splatTexture.a);
fragment_color = outcolor;
}
Some additional info:
All textures are loaded like this in my terrain material and passed to the shader (works properly):
glActiveTexture(GL_TEXTURE0);
glBindTexture(GL_TEXTURE_2D, heightMap->getId());
glUniform1i (_shader->getUniformLocation("heightMap"),0);
...
The plane mesh uvs are mapped like this:
(0,1) (1,1)
(0,0) (1,0)
I guess I am doing something horribly wrong, but I can't figure out what. Any help is appreciated!
Does your writing this:
The plane mesh uvs are mapped like this:
(0,1) (1,1)
(0,0) (1,0)
… mean that your mesh consists of just 4 vertices? If so, then that's your problem right there: The Vertex shader can not magically create "new" vertices, so your heightmap texture is sampled at only 4 points (and nothing in between).
And because you sample the texture coordinates at integer values and your texture coordinates and are at 0 and 1, you're effectively sampling the very same texture coordinate, so you're going to see the same displacement for all four vertices.
Solution: Tesselate your base mesh so that there are actually vertices available to displace. A tesselation shader is perfectly fine for that.
EDIT:
BTW, you can simplyfiy your vertex shader a bit: For the attributes make it a
in vec2 vertex;
which requires just 2/3 of the space of vec3, since you're not using the z component anyway.
float y = texture(heightmap, uv).r * 2.f;
gl_Position =
projectionMatrix
* viewMatrix
* modelMatrix
* vec4(vertex.x, y, vertex.y, 1.f);

opengl glsl bug in which model goes invisible if i use glsl texture function with different parameters

I want to replicate a game. The goal of the game is to create a path between any 2 squares that have the same color.
Here is the game: www.mypuzzle.org/3d-logic-2
The cube has 6 faces. Each faces has 3x3 squares.
The cube has different square types: empty squares(reflect the environment), wall squares(you cant color them), start/finish squares(which have a black square in the middle but the rest of it is the colored).
I've close to finishing my project but i'm stuck with a bug. I used c++,sfml,opengl,glm.
The problem is in the shaders.
Vertex shader:
#version 330 core
layout (location = 0) in vec3 vPosition;
layout (location = 1) in vec3 vColor;
layout (location = 2) in vec2 vTexCoord;
layout (location = 3) in float vType;
layout (location = 4) in vec3 vNormal;
out vec3 Position;
out vec3 Color;
out vec2 TexCoord;
out float Type;
out vec3 Normal;
uniform mat4 model;
uniform mat4 view;
uniform mat4 projection;
void main()
{
gl_Position = projection * view * model * vec4(vPosition, 1.0f);
Position = vec3(model * vec4(vPosition, 1.0f));
Color=vColor;
TexCoord=vTexCoord;
Type=vType;
Normal = mat3(transpose(inverse(model))) * vNormal;
}
Fragment shader:
#version 330 core
in vec3 Color;
in vec3 Normal;
in vec3 Position;
in vec2 TexCoord;
in float Type;
out vec4 color;
uniform samplerCube skyboxTexture;
uniform sampler2D faceTexture;
uniform sampler2D centerTexture;
void main()
{
color=vec4(0.0,0.0,0.0,1.0);
if(Type==0.0)
{
vec3 I = normalize(Position);
vec3 R = reflect(I, normalize(Normal));
if(texture(faceTexture, TexCoord)==vec4(1.0,1.0,1.0,1.0))
color=mix(texture(skyboxTexture, R),vec4(1.0,1.0,1.0,1.0),0.3);*/
}
else if(Type==1.0)
{
if(texture(centerTexture, TexCoord)==vec4(1.0,1.0,1.0,1.0))
color=vec4(Color,1.0);
}
else if(Type==-1.0)
{
color=vec4(0.0,0.0,0.0,1.0);
}
else if(Type==2.0)
{
if(texture(faceTexture, TexCoord)==vec4(1.0,1.0,1.0,1.0))
color=mix(vec4(Color,1.0),vec4(1.0,1.0,1.0,1.0),0.5);
}
}
/*
Type== 0 ---> blank square(reflects light)
Type== 1 ---> start/finish square
Type==-1 ---> wall square
Type== 2 ---> colored square that was once a black square
*/
In the fragment shader i draw the pixels of a square that has a certain type, so the shader only enters in 1 of the 4 if's for each square. The program works fine if i only use the glsl function texture with the same texture. If i use this function 2 times with different textures ,in 2 differents if's ,my model goes invisible. Why is that happening?
https://postimg.org/image/lximpl0bz/
https://postimg.org/image/5dzvqz2r7/
The red square is of type 1. I've modified code in the type==0 if and then my model went invisible.
Texture sampler in OpenGL should only be accessed in (at least) dynamically uniform control flow. This basically means, that all invocations of a shader execute the same code path. If this is not the case, then no automatic gradients are available and mipmapping or anisotropic filtering will fail.
In your program this problem happens exactly when you try to use multiple textures. One solution might be not to use anything that requires gradients. There are also a number of other options, for example, patching all textures together in a texture atlas and just selecting the appropriate uv-coordinates in the shader or drawing each quad separately and providing the type through a uniform variable.