I want to read from stdin if that is within a size. How do I restrict that in this code?
std::cout << "Enter a string till end of line: " << std::endl;
std::isstreambuf_iterator<char> begin(std::cin), end;
std::string str(begin, end);
What I want is to restrict the read from stdin to maximum length of 10. If it is, then I would assign it to string str. Please help!
Read a line. Make sure it's not too big. Use the line.
Example:
std::cout << "Enter a string till end of line: " << std::endl;
std::string line;
if std::getline(std::cin, line)) // read in until end of line or end of stream
{
if (line.size <= maximum_size) // ensure line isn't too big
{
// process line here
}
}
else // read failed
{
// May need some clean-up to handle failed input stream
}
I'd suggest you to read char-by-char from cin. Use functions:
cin.get(...)
or
char c;
cin >> c;
By this way you would control length and end-of-line.
Related
I need to sort the input text document and write it into another test document. so that lines with an even number of words delete every second word, and lines with an odd number of words remain unchanged. The sorting should be performed as a function, the first pointer to the input of the string and the second pointer to the output.
I did the input and output, tried to do a sorting to begin with without a function, but nothing worked. can you tell me what I did not do the rule?
Example:
Input.txt
I do not like to go to school or study
I like to play games
Output.txt
I not to to or
I like to play games
string in, out;
cin >> in;
cin >> out;
ifstream input(in);
string str;
ofstream output(out);
string st;
while (getline(input, str))
{
do
{
int i = count(str.cbegin(), str.cend(), ' ');
if (i % 2 == 0)
st.append(str);
else
st.append(" ");
i++;
}
while (input);
output << st << endl;
}
The std::stringstream will be your friend.
Read about it here and especially for the useful std::istringstream here.
What can we do with this thing? We can put a string into it and then use the extraction operator >> like with any other stream.
So, counting words will become very simple. We read a line from the file as a std::string and then put it into a std::istringstream, Then we extract dummy words and increase a counter until the reading fails. Then we have the number of words.
Example:
// We read one line. Count the number of words
// Put the string in a stringstream to easily extract words
std::istringstream iss(line);
// Counter for words
unsigned int wordCount{};
// Dummy word
std::string tempWord{};
// Do the counting
while (iss >> tempWord) ++wordCount;
The stream tries too read until it cannot read any more (the stream is empty) and then sets a failbit. The failure of any stream can be checked with its bool operator or the !-operator. The while loop expects a boolean. And the extraction operation iss >> tempWord will return a reference to the stream and then its bool operator will be called and used as condition.
OK, understood, we can now count words. Next step is to skip words.
This is similar simple. In case of even number of words in a string, we will read always 2 words in a loop and simply throw the second one away.
Like this
std::string usedWord{};
// Read 2 words, ignore the second
while (iss >> usedWord >> tempWord)
result += (usedWord + ' ');
There are of course many other possible ways to solve that, but maybe the below solution can give you an idea.
#include <iostream>
#include <fstream>
#include <sstream>
#include <string>
int main() {
// First read the input filename
std::cout << "\nPlease enter the path for the input file:\n";
std::string inputFileName{};
std::getline(std::cin, inputFileName);
// next read the output filename
std::cout << "\nPlease enter the path for the output file:\n";
std::string outputFileName{};
std::getline(std::cin, outputFileName);
// Open now both files. If one file cannot be opened, then no need tocontinue
// Open input file and check, if it could be opened
std::ifstream inputFileStream(inputFileName);
if (inputFileStream) {
// Input file could be opened without error.
// Now open output file and check, if it could be opened
std::ofstream outputFileStream(outputFileName);
if (outputFileStream) {
// Now, both input and output file streams are open
// Read lines
std::string line{};
while (std::getline(inputFileStream, line)) {
// We read one line. Count the number of words
// Put the string in a stringstream to easily extract words
std::istringstream iss(line);
// Counter for words
unsigned int wordCount{};
// Dummy word
std::string tempWord{};
// Do the counting
while (iss >> tempWord) ++wordCount;
// if the number of words is even then
if ((wordCount % 2) == 0) {
// Rinitialize stringstream
iss.clear(), iss.str(line);
// Here we store the resulting sentence
std::string result{};
// Now extract the word that we will keep and the other one that we will throw away
std::string usedWord{};
// Read 2 words, ignore the second
while (iss >> usedWord >> tempWord)
result += (usedWord + ' ');
// Write result to output
outputFileStream << result << '\n';
}
else
outputFileStream << line << '\n';
}
}
else std::cerr << "\n*** Error: could not open output file '" << outputFileName << "'\n\n";
}
else std::cerr << "\n*** Error: could not open input file '" << inputFileName << "'\n\n";
}
I am trying to read a line of string characters with numbers (e.g "30 40 50 20") and put them into a vector. I also need to avoid empty space and newlines. But when I read the input, it doesn't see the string "30", it sees the characters "3" and "4".
void Input() {
getline(cin,line, '\n');
for (int i = 0; i < line.length(); i++) {
if (! (isspace(line[i]))) {
cout << line[i] << ", ";
scores.push_back(line[i]);//(atoi(input));
}
}
cout << scores.size() << "! ";
}
A line like "30 40 50" won't give a vector size of 3, it will give a size of 6.
What are the optimal ways to get around this issue?
EDIT: I should have clarified in the original message that this is for a challenge, in which I am unable to include the string stream library in the original case.
I think you're doing the right thing grabbing the whole line before parsing, otherwise you get into a bit of a pickle. But you do actually have to do some parsing. Right now you're just pulling out individual characters.
The following isn't optimal but it'll get you started — continue using formatted stream extraction, but isolated to this line from the file.
So:
void Input()
{
getline(cin, line, '\n');
istringstream ss(line);
int val;
while (ss >> val)
scores.push_back(val);
cout << scores.size() << "! ";
}
Read the line and put into a std::istringstream, then read as "normally" using the >> operator from the string stream.
Putting the line into a std::istringstream and extracting the numbers from that is the best way.
Here's an alternative to a manual loop using the standard library:
std::istringstream numbers(line);
std::copy(std::istream_iterator<int>(numbers),
std::istream_iterator<int>(),
std::back_inserter(scores));
It is probably best to take advantage of an input stringsteam, example: http://www.cplusplus.com/reference/sstream/stringstream/stringstream/.
The extraction operator allows you to parse data from the stream to some variable of datatype T. Another advantage of input stringstreams is the ability to query whether the pass was successful, and in your case ignore whitespace characters by setting the skipws format flag.
Example:
int main () {
std::istringstream ss("30 40 50");
float val = 0.0f;
while( ss >> std::skipws >> val )
{
std::cout << val << "\n";
}
return 0;
}
Out: 30 40 50
Only the first call to getline() appears to read anything in from std::cin. Is the fact that buffer contains something a problem - why doesn't getline() just overwrite the contents of buffer?
How can I get the second call to getline() to read something in?
My code:
const int recordLen = 20;
// truncate the input to 20 chars
void getText(char line[])
{
std::cout << "Enter something for getText: ";
std::cin.getline(line, recordLen+1);
for(int i = std::strlen(line); i < recordLen; i++)
{
line[i] = ' ';
}
line[recordLen] = '\0';
}
int main()
{
char buffer[340];
getText(buffer);
std::cout << buffer;
std::cout << "Now enter some more text:";
// put more text into buffer
std::cin.getline(buffer, 30);
std::cout << "you entered : " << buffer << std::endl;
return 0;
}
So - example output of program:
Enter something for getText: alskdjfalkjsdfljasldkfjlaksjdf
alskdjfalkjsdfljasldNow enter some more text:you entered :
After the display of "Now enter some more text:", the program immediately displays "you entered:". It does not give me the opportunity to enter more text, neither does it display any characters that were truncated from the previous call to getline().
std::cin.getline(line, recordLen+1);
Here, if the input is longer than recordLen chars, the remaining characters will not be read and will remain in the stream. The next time you read from cin, you'll read those remaining characters. Note that, in this case, cin will raise its failbit, which is probably what you're experiencing.
If your first input is exactly recordLen chars long, only the newline will remain in the stream and the next call to getline will appear to read an empty string.
Other than that, getline does overwrite the buffer.
If you want to ignore anything beyond the first recordLen chars on the same line, you can call istream::clear to clear the failbit and istream::ignore to ignore the rest of the line, after istream::getline:
std::cin.getline(line, recordLen+1);
std::cin.clear();
std::cin.ignore( std::numeric_limits<streamsize>::max(), '\n' );
For example, when parsing a text file, some times this file have stuff like this:
keyword a string here
keyword another string
keyword
keyword again a string
Note that the 3th line have an empty string (nothing or white spaces).. The thing is that when you do stringstream>>laststring, and stringstream have an empty string (null or just white space), it will not overwrite the "laststring", it will do nothing. Theres anyway to check this situation before hand? I dont want to create a temp empty string just to check it is still empty after stringstream>>, seems lame.
When you cannot read from stream - its state changes, so when casting to bool, it returns false:
bool read = static_cast<bool>(ss >> laststring);
Or - in if-expr:
if (ss >> laststring)
cout << "Just read: " << laststring;
See example
You can only know after trying to read whether there was something or not. What you might be able to do is to skip whitespace and see if there is a non-space in the next location:
if ((in >> std::ws).peek() != std::char_traits<char>::eof()) {
...
}
Given that empty strings are cheap to create, I wouldn't bother and try read the string. Note, however, that reading from streams isn't line based, i.e., in your case above you need to split the lines first or use something like std::getline() to read the second part of line.
You can use getline, to read a line from the file. Then, copy the line into a string stream and read words from the string stream one at a time. The streams will automatically stop reading when they run out of lines / words.
// open file
std::ifstream fin("text.txt");
// 'iterate' through all the lines in the file
unsigned lineCount = 1;
std::string line;
while (std::getline(fin, line))
{
// print the line number for debugging
std::cout << "Line " << lineCount << '\n';
// copy line into another stream
std::stringstream lineStream(line);
// 'iterate' through all the words in the line
unsigned wordCount = 1;
std::string word;
while (lineStream >> word)
{
// print the words for debugging
std::cout << '\t' << wordCount++ << ' ' << word << '\n';
}
}
You need to include iostream, fstream, sstream and string.
For checking if string is empty, use foo.size() == 0.
For checking if string stream is empty fooStream.rdbuf()->in_avail() == 0
How do I run the while loop until the end of line or null character reached.
Here is my code
#include<iostream>
using namespace std;
main()
{
char input[20];
cout<<"Enter a line: ";
cin>>input;
while(input!='\0')
{
cout<<"This is a text";
}
system("pause");
}
If you want to read until either a newline or a NUL, read one character at a time inside the loop.
#include<iostream>
int main()
{
char input;
std::cout << "Enter a line: " << std::flush;
while(std::cin >> input && input != '\n' && input != 0) {
std::cout << "This is a test\n";
}
}
Notes:
main requires a return type
Never, ever, say "using namespace std;"
Don't forget to flush if you want cout to appear immediately.
Notice the compound test in the while condition:
First, did the read succeed?
Next, is it not '\n' (one of your conditions).
Next, is it not NUL (the other of your conditions).
The body of the loop will be executed once per input character -- is that what you wanted?
But, consider if you have correctly specified your requirement. It is an unusual requirement -- why would there be a NUL in a text file, and why would you want to process each character individually?
In idiomatic C++, you can read the input file in a line at a time using std::getline:
std::string myString;
while(std::getline(std::cin, myString)) {
// process myString
}
If you just want to read in a single line:
std::string myString;
if(std::getline(std::cin, myString)) {
// process myString
}
Finally, if you want to read a line, and ignore its contents:
std::cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
try something like:
i = 0;
while ((input[i] != '\0') && i < 20)
{
cout<<"This is a text";
i++;
}
Like this:
std::string line;
if (std::getline(std::cin, line))
{
std::cout << "Thank you, you said, \"" << line << "\".\n";
}
else
{
// error, e.g. EOF
}
If you want to read multiple lines, use a while loop instead:
while (std::getline(std::cin, line))
{
std::cout << "Thank you, you said, \"" << line << "\".\n";
}
The issue is that you're reading an entire chunk of text at once and then printing it until the input is '\0'. However, you're never actually updating this inside the loop. You can either use cin inside the loop to get the input, OR if you're trying to output each character, you can index the char array.