Let's say my controller is taking an object parameter without [FromBody], how do I post the data using Postman? I tried this way but it doesn't reach the endpoint.
I think in this case, since you're not using [fromBody] your object should be in the URL and not in the Request Body.
in Postman, this can be done using the Query Params as the screenshot shows.
Yet, I don't think you could pass an object in the query params like that. I think you should instead turn it into a query string like this format
"User=abc&Pass=abc"
Multiple ways to achieve this can be found here
If your controller is taking an object parameter without [FromBody] then you must send the data as URL parameter:
POST http://localhost:44364/login?object={"User":"abc","Pass":"abc"}
Note: replace "object" by the name of the parameter in your controller. Also you have to know that Postman should converts special characters { " : , to %XX format and you have to manage that in your service.
If you want to send it in the body, then include [FromBody]
I use Postman for REST API testing and parametrize tests with global variables.
I should put a phone number into GET request: /path/get?phone={{phone}} but leading + sign in the phone number is interpreted as a space.
What is the syntax to URL encode global variables in Postman? Is it possible to run JS encodeURIComponent() on variable in URL?
I am late but still worth it:
Just highlight and right click the part of url you want to encode. Select encodeURIComponent
That's it.
Use the Pre-request scripts (it's next to body) for this:
var encoded = encodeURIComponent({{phone number}});
or
var encoded = encodeURIComponent(pm.environment.get("phone number"));
and to proceed, use:
pm.environment.set("encoded phone number", encoded);
And set your URL to /path/get?phone={{encoded phone number}}
Just a shortcut to Mohhamad Hasham' answer.
You can encode and decode direct in the Params Value field:
The trick is to get your environment variable in the pre-request script and then set it after encoding it
var encoded = encodeURIComponent(pm.environment.get("phone"));
pm.environment.set("encoded phone number", encoded);
This will work as well:
var encoded = encodeURIComponent(pm.request.url.query.get("phone"));
pm.request.url.query.remove("phone");
pm.request.url.query.insert("phone", encoded);
I came across this question looking for an answer to a similar question. For me, the variable was a JSON object. The endpoint I needed to hit was expecting an object list as a query parameter and I have no way to change that to be the request body.
As much as some of the answers helped, I ended up coming up with a combined solution. Also, some of the code given in other answers is outdated as Postman has updated their API over the years, so this uses methods that work on 7.22.1.
pm.environment.set("basicJSON", '[{"key1":"value1","key2":"value2"},{"key1":"value1","key2":"value2"}]')
var encoded = encodedURIComponent(pm.environment.get("basicJSON"))
pm.environment.set("encodedJSON", encoded)
This solution requires that both basicJSON and encodedJSON exist as environment variables. But what was important for me was the ease of editing the object. I didn't want to have to decode/encode constantly to change values, and I didn't want to have to open the environment variables dialogue. Also, it's important to note the single-quotes around the object. Excluding them or using double-quotes would cause Postman to send something like "[object Object]" which is useless to an endpoint expecting actual JSON.
I had similar problem with braces { and } in query parameter.
By turning off the following setting it started working for me.
For the postman version 9.28.4 ==>
You can use 2 methods:
By selecting the part of the url in url bar -> right click -> EncodeURLComponent. (screenshot attached)
You can also use "pre-request script" tab of postman and write the script for the variable manually. (screenshot attached)
The problem with right-click => Encode URI Component is that it destroys the raw value of that parameter. You can use the following pre-request script to overcome this (which also works for cases where you have disabled that param):
// queryParam is of type https://www.postmanlabs.com/postman-collection/QueryParam.html
if ((queryParam = pm.request.url.query.one("name_of_your_query_param")) !== undefined
&& queryParam.disabled !== true) {
queryParam.value = encodeURIComponent(queryParam.value);
}
Click the Params button to open the data editor for URL parameters. When you add key-value pairs, Postman combines everything in the query string above. If your URL already has parameters - for example, if you are pasting a URL from some other source. Postman splits the URL into pairs automatically.
https://www.getpostman.com/docs/v6/postman/sending_api_requests/requests
POSTMAN's documentation on building requests in the section "sending parameters" is helpful here. You can encode path data by simply encoding the URL with a colon, listing the key name of the encoded element, and then a new section will appear below the query parameters allowing you to customize values and add a description, just as we do with query params. Here's an example of encoding the URL for a GET request:
https://somesite-api-endpoint/:record/get
And here's what the display looks like after you add path data. Any value you add in the path variables section will automagically update the URL with your data.
I am trying to pass an encrypted token from an external application into Application Express. I want to read and work with this token in a custom authentication scheme as a way to authenticate the user into the application.
What is the best way to do this? At first, I was trying to just append the token onto the URL, eg:
/pls/apex/f?p=999:1&Token=XXXXXXXX
But then Apex returns a 404.
So then, I was trying to use the Application Express session values to send in the token, creating a URL like this:
f?p=999:1:::::TOKEN:XXXXXXXX
And then my sentry function I would do something like:
v_token := V('TOKEN')
To get it. However, this isn't working either, and I think's because the session isn't established yet when the sentry function executes? And is it even possible to do it this way? (Since there would be no item with this name, and no page yet to create it on...)
Is there a better approach to doing what I'm trying to do? If I had this added as a HTTP Header upstream, can I read that somehow in the sentry function? Maybe with owa_util.get_cgi_env? Does that work to read HTTP Headers from the request?
Thank you
If anyone else runs into something like this - I figured out a workaround.
Just put the token in the "value" session variables section of the URL, like so
f?p=999:1::::::XXXXXXXX
Then in the "sentry function" I can get the entire query string like this:
v_query_str := owa_util.get_cgi_env('QUERY_STRING');
And then I can split v_query_str by : and get the 8th token, which is what I need.
I found some examples using apex_util.string_to_table to split the string, which works nicely.
I want to insert a URL filter and I would like the URL to be hard to dechiffre.
For example .*porn\.* in a way maybe that it uses the ASCII code for the letters in hex form .
Of course, the example is obvious and I definately will leave that one as it is ;)
But for the others I would like them to be hard to read!
Thx!
You can use the $_GET function in PHP to pull an ID out of the URL and display it that way, similar to Youtube with their "watch?v=". I recently did one using "?id=49" (I only have a few pages ATM, I will have about 70 soon). What I did is use a database with a song_id to index the information. I use the same basic layout, but you can use the ID to access information wrapped in PHP so that it doesnt get sent to the browser but will still display the page you want.
Or if you really want it to look crazy, you could use a database using the SHA() or MD5() function to encrypt it.
and your display will look like /page.php?id=21a57f2fe765e1ae4a8bf15d73fc1bf2a533f547f2343d12a499d9c0592044d4.
i'm trying to get full path of the requested url in Django. I use a such url pattern:
('^', myawesomeview),
It works good for domain.com/hello, domain.com/hello/sdfsdfsd and even for domain.com/hello.php/sd""^some!bullshit.index.aspx (although, "^" is replaced with "%5E")
But when I try to use # in request (ex. http://127.0.0.1:8000/solid#url) it returns only "/sold". Is there any way to get the full path without ANY changes or replacements?
BTW, I'getting url with return HttpResponse(request.path)
Thanks in advance.
The part of URI separated by '#' sign is called a fragment identifier. Its sense is to be processed on client side only, and not to be passed to server. So if you really need this, you have to process it with JS, for example, and pass it as a usual parameter. Otherwise, this information will never be sent to Django.