I have a vector with 2 elements a_destinations that represent the source and destination with two integers. 2 4 or 5 1...
I have a matrix test as follows:
0 15 15 15 13 13 15 15 13 13 15 15 15 13 15 15
2 1 2 2 2 2 2 2 2 2 10 2 2 2 10 2
6 1 2 3 3 3 6 6 6 6 6 6 6 6 6 6
7 2 2 3 4 4 2 7 7 7 7 7 7 7 7 7
8 3 3 3 4 5 3 3 8 8 3 3 3 8 3 3
9 4 4 4 4 5 4 4 4 9 4 4 4 9 4 4
7 2 2 2 2 2 6 7 7 7 11 11 7 7 11 7
12 6 6 3 3 3 6 7 8 8 12 12 12 12 12 12
9 7 7 7 4 4 7 7 8 9 7 7 7 9 7 7
13 8 8 8 8 5 8 8 8 9 13 13 13 13 13 13
14 1 11 11 11 11 11 11 11 11 10 11 11 11 14 14
12 6 6 12 12 12 6 12 12 12 10 11 12 12 10 12
15 7 7 7 7 7 7 7 7 13 11 11 12 13 11 15
0 12 12 12 9 9 12 12 9 9 12 12 12 13 12 12
15 10 10 10 10 10 10 10 10 10 10 10 10 10 14 15
0 12 12 12 12 12 12 12 12 12 14 12 12 12 14 15
where test[i][j] represents the path from i to j
each time test[i][j] != j we do the loop again
Example:
path from 2 to 4 >> test[2][4] = 3, test[3][4] = 4: we output: 2, 3, 4
path from 1 to 7 >> test[1][7] = 2, test[2][7] = 6 , test[6][7] = 7: we output 1, 2 ,6, 7
I tried as follows:
std::vector<vector<int>> test;
test = Graphe->P; // MATRIX IS FILLED like on top
vector< int > a_destinations; // Vector with the destinations: 2 4 or 5 10 or 1 4 ...
for ( unsigned i = 0; i < test.size(); i++){
for (unsigned j = 0; j< test.size(); j++){
for (unsigned k = 0; k < a_destinations->size() - 1 ; k ++){
if ( a_destinations->at(k) == i && a_destinations->at(k+1) == j ){
if (test[i][j] == a_destinations->at(k+1)){
cout << a_destinations->at(k) << ", " <<test[i][j];
} else {
cout << a_destinations->at(k) << ", " << test[a_destinations->at(k)][j];
}
cout << ", " << test[i][j];// << ", " << a_destinations->at(k+1);
}
}
}
}
But i end up with 2 destinations always.
Related
I was solving the puzzles in 2017 Advent of Code. It was necessary to fill in circular buffer using certain algorithm. For the buffer implementation I first used vector, and then I tried with deque. I am getting different results when printing values of the vector and the queue. Here's the code:
#include <iostream>
#include <vector>
void PrintBuffer(std::vector<int> a_CircularBuffer)
{
for (std::vector<int>::iterator it = a_CircularBuffer.begin(); it != a_CircularBuffer.end(); ++it) {
std::cout << *it << " ";
}
std::cout << std::endl;
}
int main()
{
std::vector<int> circularBuffer;
circularBuffer.reserve(20);
circularBuffer.push_back(0);
circularBuffer.push_back(1);
std::vector<int>::iterator currentPosition = circularBuffer.begin() + 1;
for (int i = 2; i < 20; ++i) {
int steps = 378;
if (steps >= i) {
steps = (steps % i);
}
if ((circularBuffer.end() - currentPosition) <= steps) {
currentPosition = circularBuffer.begin() + (((currentPosition - circularBuffer.begin()) + steps) % i);
circularBuffer.insert(currentPosition, i);
}
else {
currentPosition = currentPosition + steps;
circularBuffer.insert(currentPosition, i);
}
PrintBuffer(circularBuffer);
}
return 0;
}
This is the result when using vector:
0 2 1
0 3 2 1
0 3 2 4 1
0 5 3 2 4 1
0 6 5 3 2 4 1
0 7 6 5 3 2 4 1
0 7 6 8 5 3 2 4 1
0 7 6 9 8 5 3 2 4 1
0 10 7 6 9 8 5 3 2 4 1
0 10 7 6 9 11 8 5 3 2 4 1
0 10 7 6 9 11 8 5 3 2 4 12 1
0 10 7 6 9 11 8 5 3 2 4 12 13 1
0 10 7 6 9 11 8 5 3 2 4 12 14 13 1
15 0 10 7 6 9 11 8 5 3 2 4 12 14 13 1
...
and this is when using deque (just change "vector" to "deque" and comment out circularBuffer.reserve(20) line):
0 2 1
0 3 2 1
0 3 2 4 1
0 5 3 2 4 1
0 5 6 3 2 4 1
0 5 6 7 3 2 4 1
0 5 6 7 3 8 2 4 1
0 5 6 7 3 9 8 2 4 1
0 5 6 10 7 3 9 8 2 4 1
0 5 6 10 7 3 9 8 11 2 4 1
0 5 12 6 10 7 3 9 8 11 2 4 1
0 5 12 6 13 10 7 3 9 8 11 2 4 1
0 5 12 6 13 14 10 7 3 9 8 11 2 4 1
0 5 12 6 13 14 10 7 3 15 9 8 11 2 4 1
...
Why there are different results for vector and deque?
You get undefined behaviour when you insert an element causing reallocation, and then use the old iterator again.
Anything can happen.
Use index to store current position and it'll work the same way.
Output should be like this
10 10 10 10 10 10 10 10 10 10
9 9 9 9 9 9 9 9 9
8 8 8 8 8 8 8 8
7 7 7 7 7 7 7
.
.
.
1
tyr it dear
l = [1,2,3,4,5,6,7,8,9,10]
d = []
for i in l:
d.extend([i]*i)
print d[::-1]
I have a 50 x 50 matrix having certain values from 1 to 50. I need to plot a color map for the same using OpenCV .
I have already done this in MATLAB (with help from this answer):
>> A = randi([10,60],100,100);
>> colormap('hot')
>> imagesc(A)
>> colorbar
And the output comes like .
I would like to do the same using openCV.
How do I proceed for this ?
I am unable to understand how do I implement the function of "hot" which appears like this (see only hot)
:
Additionally I would also be interested in putting a color bar as shown in the first image.
Update (Final code I am running)
Unfortunately still I am unable to plot the correct color map: Here is the MATLAB code:
Note : A is a 10 by 100 matrix.
A=[0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 ;
0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9;
0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9;
0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9;
0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9;
0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9;
0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9;
0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9;
0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9;
0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9;
]
colormap('hot');
imagesc(A)
colorbar
And here is the output:
Now I created a text file with same data, and my text file looks like this:
And used the following code to achieve the same result as of MATLAB:
int main()
{
ifstream Read("myfile.txt");
vector<int> nums;
while ( !Read.eof() ) {
int n;
Read >> n;
nums.push_back(n);
}
// now make a Mat from the vector:
Mat mat(nums);
cout<<mat<<endl; //for testing
Mat mat1d(nums);
Mat mat2d = mat1d.reshape(1, 10);
//
Mat image; //create an empty image. (you can leave it empty ;)
//// Apply the colormap, but on the 2d mat, not on the 2d vector, please:
applyColorMap( mat2d, image, COLORMAP_JET );
// Show the result:
imshow("colormap", image);
waitKey(0);
return 0;
}
But the output from the above is meaningless.
I need to match the results from MATLAB and Opencv.
you will have to reshape the 1d vector, to a 2d mat :
//
// before doing anything else, CLEAN UP YOUR DAMN TXTFILE.
// it should contain nothing than numbers and spaces.
ifstream Read("m.txt");
// be extra picky about the type here.
// we are reading in a 8bit grayscale map.
vector<uchar> nums;
for (int i=0; (i<100*10)&&(!Read.eof()); i++ ) {
int n;
Read >> n;
nums.push_back(n);
}
// now make a Mat from the vector:
Mat mat1d(nums);
Mat mat2d = mat1d.reshape(1, 10);
// your data is in the [0..9] range, so scale up to [0..255] uchar range
mat2d *= (255/10);
cout<<mat2d<<endl; //for testing
//
Mat image; //create an empty image. (you can leave it empty ;)
//// Apply the colormap, but on the 2d mat, not on the 2d vector, please:
applyColorMap( mat2d, image, COLORMAP_HOT );
// Show the result:
imshow("colormap", image);
waitKey(0);
How to pick the best uniformed 1d array from the 2d arrays ?
I have two 2d array of : 11 x 10
Example :
4 8 12 12 12 14 16 18 4 1 0
5 7 11 12 13 11 15 18 3 2 1
8 3 12 14 18 19 20 21 8 5 4 ,
8 2 11 12 17 17 19 20 7 4 3 ,
4 7 11 11 11 15 17 19 5 1 1 ,
3 8 11 13 11 15 14 17 4 1 0 ,
4 7 12 13 13 14 16 19 3 1 1 ,
5 9 11 12 13 15 17 19 5 0 1 ,
9 7 25 22 24 18 23 17 3 3 3 ,
4 8 13 13 13 15 17 17 5 2 0 ,
here we have 2d arrays of size 11x10 - Need to analysis and have to find out the common 1d array which has common like.
find the best closing number and its difference- and keep doing for all the corresponding columns in an array .
below answer should be like - finding the corresponding very column and comparing with the next row column - if it has some difference below ( 5 ) take the both column of two rows are same and process for next column of the same row..process untill finding the 1 row where it has at least nearby matches of 5
4 8 11 12 13 13 15 18 4 1 0
why don't you do something like this
int[] count(int[][] array)
int result[11];
for(int x = o; x<= 11;x++)
{
int temp[10];
for(int y = o; y<= 10;y++)
{
temp[y] = array[y][x];
}
result[x] = getHighest(temp);
}
return result;
}
int getHighest(int[] array)
{
int size = array.length;
int[size][1] temp;
for(int x; x<= size;x++)
{
int z = array[x];
temp[z][0]++;
}
int highest = -1;
for(int z; z<= size;z++)
{
int z = array[x];
int h = temp[z][0];
if(h > highest)
{
highest = h;
}
}
return highest;
}
Something like this, but my C++ has gotten a bit of rusty so sorry if there are any mistakes.
#include<iostream>
#include<time.h>
#include<list>
#include<stdlib.h>
#include<fstream>
using namespace std;
typedef struct diskBtNode
{
int parent; //-1 if NULL
//int size;
int leaf;
int arr[20];
};
int main()
{
fstream myfile;
srand(time(NULL));
myfile.open("btree.txt",ios::in | ios::out | ios::binary | ios::trunc);
long nodesize=256;
long currentpos=0;
if(myfile.fail())
{
std::cout<<"Error opening the file "<<std::endl;
}
currentpos=0;
for(int i=0;i<10;i++)
{
diskBtNode node;
node.parent=rand()%10;
node.leaf=rand()%1;
int n=rand()%19;
int j;
for(j=0;j<n;j++)
{
node.arr[j]=n;
}
node.arr[j]=-1;
cout<<node.parent<<" "<<node.leaf<<" ";
j=0;
while(node.arr[j]!=-1)
{
cout<<node.arr[j]<<" ";
j++;
}
cout<<node.arr[j]<<std::endl;
myfile.seekp(currentpos*nodesize,ios::beg);
myfile.write(reinterpret_cast<char *>(&node),nodesize);
currentpos++;
// p=p+1;
}
cout<<"******************* "<<std::endl;
currentpos--;
long p=0;
while(currentpos>=0)
{
std::cout<<currentpos<<" &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& "<<p<<" "<<std::endl;
diskBtNode node;
myfile.seekg(currentpos*nodesize,ios::beg);
myfile.read(reinterpret_cast<char *>(&node),nodesize);
currentpos--;
p--; //decrementing p
cout<<node.parent<<" "<<node.leaf<<" ";
int j=0;
while(node.arr[j]!=-1)
{
cout<<node.arr[j]<<" ";
j++;
}
cout<<node.arr[j]<<std::endl;
}
myfile.close();
}
This code simply reads and writes to a binary file. In the first part it writes to a file and in the second part it reads from the same file. While reading I was trying to read any random blocks from a file for a finite number of time. But when I am using p variable as a counter, it doesn't work. It's value is decremented in the first iteration directly to -1. I used debugger to track where it changes. Apparently it changes after the read statement is executed. Can somebody please help me with this? The output of the above program is this
8 0 8 8 8 8 8 8 8 8 -1
5 0 8 8 8 8 8 8 8 8 -1
3 0 15 15 15 15 15 15 15 15 15 15 15 15 15 15 15 -1
5 0 1 -1
4 0 -1
9 0 13 13 13 13 13 13 13 13 13 13 13 13 13 -1
4 0 11 11 11 11 11 11 11 11 11 11 11 -1
6 0 6 6 6 6 6 6 -1
6 0 8 8 8 8 8 8 8 8 -1
2 0 2 2 -1
*******************
9 &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& 0
2 0 2 2 -1
8 &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& -1
6 0 8 8 8 8 8 8 8 8 -1
7 &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& -1
6 0 6 6 6 6 6 6 -1
6 &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& -1
4 0 11 11 11 11 11 11 11 11 11 11 11 -1
5 &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& -1
9 0 13 13 13 13 13 13 13 13 13 13 13 13 13 -1
4 &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& -1
4 0 -1
3 &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& -1
5 0 1 -1
2 &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& -1
3 0 15 15 15 15 15 15 15 15 15 15 15 15 15 15 15 -1
1 &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& -1
5 0 8 8 8 8 8 8 8 8 -1
0 &&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&&& -1
8 0 8 8 8 8 8 8 8 8 -1
The problem comes from this line :
myfile.read(reinterpret_cast<char *>(&node),nodesize);
nodesizeequals 256, while you structure's size if 88byte ( 22 * 4 bytes int ).
The read is writing memory over the structure, which happens to be the other stack variables.
Use sizeof( node ) when you both write and read the struct to the file.
Not clear what you are trying to achieve, but in your code you have specified.
long p=0;
while(currentpos>=0)
{
....
p--; // this will make p = -1
}
so the p will print as -1 all through the while statement. Are you forgetting to initialize the p variable?