I have an xml with subelements and need to change one of the subelement to attribute using XSLT 1.0
<TransportationRequest>
<actionCode>01</actionCode>
<ContractConditionCode>DC</ContractConditionCode>
<ShippingTypeCode>17</ShippingTypeCode>
<MovementTypeCode>3</MovementTypeCode>
<DangerousGoodsIndicator>false</DangerousGoodsIndicator>
<DefaultCurrencyCode>SAR</DefaultCurrencyCode>
The Expected xml is as below using the XSLT code:
<TransportationRequest actionCode="01">
<ContractConditionCode>DC</ContractConditionCode>
<ShippingTypeCode>17</ShippingTypeCode>
<MovementTypeCode>3</MovementTypeCode>
<DangerousGoodsIndicator>false</DangerousGoodsIndicator>
<DefaultCurrencyCode>SAR</DefaultCurrencyCode>
First, close the root tag on your xml:
<TransportationRequest>
<actionCode>01</actionCode>
<ContractConditionCode>DC</ContractConditionCode>
<ShippingTypeCode>17</ShippingTypeCode>
<MovementTypeCode>3</MovementTypeCode>
<DangerousGoodsIndicator>false</DangerousGoodsIndicator>
<DefaultCurrencyCode>SAR</DefaultCurrencyCode>
</TransportationRequest>
then this xsl will do what you asked for:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="xml" encoding="UTF-8" />
<xsl:template match="/">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="#*|node()">
<!-- Copy every node as is -->
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="TransportationRequest">
<!-- transform the TransportationRequest node in a special way -->
<xsl:element name="TransportationRequest">
<xsl:attribute name="actionCode"><xsl:value-of select="actionCode" /></xsl:attribute>
<!-- don't transform the actionCode node (is in the attribute) -->
<xsl:apply-templates select="#*|node()[name()!='actionCode']"/>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
You could to it like this :
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="TransportationRequest">
<xsl:copy>
<xsl:attribute name="actionCode">
<xsl:value-of select="actionCode"/>
</xsl:attribute>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
<xsl:template match="actionCode"/>
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
See it working here : https://xsltfiddle.liberty-development.net/naZYrpW/1
Related
Is there a way for me to update the label element to Selma if "LastName" exists and if the label LastName doesn't exist then add the "LastName" and "label" elements to the XML?
<xml>
<udfs>
<udf>
<desc>FirstName</desc>
<label>Sam</label>
</udf>
<udf>
<desc>LastName</desc>
<label>Selman</label>
</udf>
</udfs>
</xml>
Here's what I have right now:
<xsl:stylesheet>
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="node()|#*" />
</xsl:copy>
</xsl:template>
<xsl:template match="udf[desc='LastName']/fieldValue">
<xsl:value-of select="'Selma'"/>
</xsl:template>
<xsl:template match="udf[not(desc='LastName')]">
<desc>LastName</desc>
<label>Selma</label>
</xsl:template>
</xsl:stylesheet>
I think you want to do:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- identity transform -->
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="udf[desc='LastName']/label">
<label>Selma</label>
</xsl:template>
<xsl:template match="udfs[not(udf/desc='LastName')]">
<xsl:copy>
<xsl:apply-templates/>
<udf>
<desc>LastName</desc>
<label>Selma</label>
</udf>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Thank you for taking the time to look at my question
I have a source xml that looks like so
<root>
<a>asdf</a>
<b>asdfdsaf</b>
<c>adfasd</c>
<d>asddf</d>
<e></e>
<others>
<foo>sdfd</foo>
<bar>hghg</bar>
</others>
</root>
I need to wrap certain elements Eg:a,b,c into a new parent and remove empty elements.
so output like so
<root>
<newparent>
<a>asdf</a>
<b>asdfdsaf</b>
<c>adfasd</c>
</newparent>
<d>asddf</d>
<others>
<foo>sdfd</foo>
<bar>hghg</bar>
</others>
</root>
I managed to remove the empty elements using this XSL -
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:strip-space elements="*"/>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="*[not(#*) and not(*) and (not(text()) or .=-1)]"/>
<xsl:template match="name">
</xsl:template>
</xsl:stylesheet>
Getting stuck at adding the newparent node. Any pointers/help is much appreciated.
Try it this way:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- identity transform -->
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="/root">
<xsl:copy>
<newparent>
<xsl:apply-templates select="a|b|c"/>
</newparent>
<xsl:apply-templates select="*[not(self::a or self::b or self::c)]"/>
</xsl:copy>
</xsl:template>
<xsl:template match="*[not(#* or node())]"/>
</xsl:stylesheet>
<xsl:template match="root">
<xsl:copy>
<newparent>
<xsl:copy-of select="a|b|c"/>
</newparent>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
<xsl:template match="*[.= '' or name() ='a' or name()='b' or name()='c']"/>
check it if it is fullfill your requirement.
For XML Transformation, i have to transform XML in such a way in adds counter value to all child node attribute Below is my xml sample
<hs>
<hscode>
<hsdetail>
<Name>Shirt</Name>
<ItemPrice>30</ItemPrice>
</hsdetail>
<hsdetail>
<Name>Shirt</Name>
<ItemPrice>30</ItemPrice>
</hsdetail>
</hscode>
</hs>
Using Xslt i want to apply counter on each child nodes of , id there are multiple hsdetails, each attribute in this node will use counter, and so on, Theconverted xml looks like below
<hs>
<hscode>
<hsdetail>
<Name1>Shirt</Name1>
<ItemPrice1>30</ItemPrice1>
</hsdetail>
<hsdetail>
<Name2>Shirt</Name2>
<ItemPrice2>30</ItemPrice2>
</hsdetail>
</hscode>
</hs>
I am using xsl but does not seems to be working when applying transformation
Any help on this? The xsl is as follows:
<xsl:stylesheet xmlns:xsl="w3.org/1999/XSL/Transform" version="1.0">
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()" />
</xsl:copy>
</xsl:template>
<xsl:template match="hsdetail/*">
<xsl:element
name="{name()}{count(preceding-sibling::*[name() = name(current())]) + 1}">
<xsl:apply-templates select="#*|node()" />
</xsl:element>
</xsl:template> </xsl:stylesheet>
How about:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<!-- identity transform -->
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="hsdetail">
<xsl:variable name="i" select="position()" />
<xsl:copy>
<xsl:for-each select="*">
<xsl:element name="{name()}{$i}">
<xsl:apply-templates select="#*|node()"/>
</xsl:element>
</xsl:for-each>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
I am trying to filter out elements, and rename element value, but I can't get it to work:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output encoding="UTF-8" indent="yes" method="xml"/>
<xsl:template match="xml">
<xsl:copy>
<xsl:for-each select="product[matches(code, 'C17.*[^V]$')]">
<xsl:copy>
<xsl:copy-of select="#*|node()"/>
</xsl:copy>
</xsl:for-each>
</xsl:copy>
</xsl:template>
<xsl:template match="title">
<xsl:copy>
<xsl:value-of select="replace(.,'Apple','Carrot')"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Example input data:
<?xml version="1.0" encoding="UTF-8"?>
<xml>
<product>
<code>C17020</code>
<title>Apple</title>
</product>
<product>
<code>C1723V</code>
<title>Samsung</title>
</product>
</xml>
I want to leave <product>'s starting with C17, but not ending to V. I use C17.*[^V]$ regex for this. This part is working.
The problem is with renaming title function. If I add this step to a new XSLT with code:
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
at the begin, then it works.
What I am doing wrong here?
The problem is you are doing <xsl:copy-of select="#*|node()"/> in your template matching xml. This will copy the attributes and child nodes, buy will not apply any templates. So your template matching title is just not used.
You need to use xsl:apply-templates here, but also include the identity template (the template you mention using in your new XSLT code) which ensures code gets copied too
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output encoding="UTF-8" indent="yes" method="xml"/>
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="xml">
<xsl:copy>
<xsl:for-each select="product[matches(code, 'C17.*[^V]$')]">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:for-each>
</xsl:copy>
</xsl:template>
<xsl:template match="title">
<xsl:copy>
<xsl:value-of select="replace(.,'Apple','Carrot')"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Note you can actually simplify your XSLT. Rather than being explicit in what you want to copy, by using the identity template you can instead have templates to remove what you don't want to copy....
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output encoding="UTF-8" indent="yes" method="xml"/>
<xsl:strip-space elements="*" />
<xsl:template match="node()|#*">
<xsl:copy>
<xsl:apply-templates select="node()|#*"/>
</xsl:copy>
</xsl:template>
<xsl:template match="product[not(matches(code, 'C17.*[^V]$'))]" />
<xsl:template match="title">
<xsl:copy>
<xsl:value-of select="replace(.,'Apple','Carrot')"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Another thing to note is that matches and replace is for XSLT 2.0 only.
Input file:
<?xml version="1.0" encoding="UTF-8"?>
<ns0:root xmlns:ns0="http://xyz.com/separate">
<ns0:root1>
<ns3:Detail xmlns:ns3="http://POProject/Details">
<DetailLines>
<ItemID>
<ItemDescription/>
</DetailLines>
</ns3:Detail>
</ns0:root1>
</ns0:root>
Output file:
<?xml version="1.0" encoding="UTF-8"?>
<ns0:Detail xmlns:ns0="http://POProject/Details">
<DetailLines>
<ItemID>
<ItemDescription/>
</DetailLines>
</ns0:Detail>
Question: I have to remove the root1 and root nodes and need to do small
changes in Detail node. How to write a xslt code to achieve this?
This...
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:ns0="http://xyz.com/separate"
xmlns:ns3="http://POProject/Details">
<xsl:output method="xml" indent="yes"/>
<xsl:strip-space elements="*" />
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="/">
<xsl:apply-templates select="*/*/ns3:Detail" />
</xsl:template>
<xsl:template match="ns3:Detail">
<xsl:apply-templates select="." mode="copy-sans-namespace" />
</xsl:template>
<xsl:template match="*" mode="copy-sans-namespace">
<xsl:element name="{name()}" namespace="{namespace-uri()}">
<xsl:copy-of select="#*"/>
<xsl:apply-templates mode="copy-sans-namespace" />
</xsl:element>
</xsl:template>
</xsl:stylesheet>
...will yield this...
<?xml version="1.0" encoding="utf-8"?>
<ns3:Detail xmlns:ns3="http://POProject/Details">
<DetailLines>
<ItemID />
<ItemDescription />
</DetailLines>
</ns3:Detail>
I'm not sure it is possible to control the prefix. The XDM data model does not consider it to be significant information.
UDPATE
To get the prefix rename, I thought you would have to go to an XML 1.1 supporting XSLT processor (allowing prefix undefine), but I found a way to do it with XML 1.0 . Try this ...
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:ns0="http://xyz.com/separate">
<xsl:output method="xml" indent="yes"/>
<xsl:strip-space elements="*" />
<xsl:template match="#*|node()">
<xsl:copy>
<xsl:apply-templates select="#*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="/" xmlns:ns3="http://POProject/Details">
<xsl:apply-templates select="*/*/ns3:Detail" />
</xsl:template>
<xsl:template match="ns0:Detail" xmlns:ns0="http://POProject/Details">
<ns0:Detail xmlns:ns0="http://POProject/Details">
<xsl:apply-templates select="*" mode="copy-sans-namespace" />
</ns0:Detail>
</xsl:template>
<xsl:template match="*" mode="copy-sans-namespace">
<xsl:element name="{name()}" namespace="{namespace-uri()}">
<xsl:copy-of select="#*"/>
<xsl:apply-templates mode="copy-sans-namespace" />
</xsl:element>
</xsl:template>
</xsl:stylesheet>