How can i initialize a set using loop in c++? - c++

I need to know can initialize a set using loop and how ?
What should i make in this code ?
#include <iostream>
#include <set>
using namespace std;
int main()
{
set <char>s;
for (auto it = s.begin(); it != s.end();it++){
cin >>*it;
}
return 0;
}

I'm going to assume you want to loop over all the user input. Note that the simplest way I have shown will ignore whitespace.
#include <iostream>
#include <set>
int main()
{
std::set<char> s;
char c; // input from user
while (std::cin >> c) { // read until end of input
s.insert(c);
}
// do something with s, I guess?
}
This: std:cin >> c will fail when the user finishes their input, which will terminate the loop. I'll repeat myself: std::cin >> skips whitespace. If you want to also read any whitespace characters the user inputs, I can show a way to do that too.
Iterators only let you access items that are already in the std::set (or other container), and in the case of std::set you can't assign to things once they are in there.
Please also note that using namespace std; is widely considered to be bad practice.

Related

How to shuffle an array in C++?

I have an array:
names[4]={john,david,jack,harry};
and i want to do it randomly shuffle, like:
names[4]={jack,david,john,harry};
I tried to use this but it just shuffled the letters of the first word in the array:
random_shuffle(names->begin(), names->end());
Here is the full code, it reads names from a .txt file and puts in an array:
#include <iostream>
#include <fstream>
#include <string>
#include <algorithm>
using namespace std;
int main() {
ifstream readName("names.txt");
string names[197];
int i = 0;
for (string line; getline(readName, line); ){
readName >> names[i];
i++;
}
readName.close();
random_shuffle(names->begin(), names->end());
for (int i = 0; i < 197; i++) {
cout << names[i] << endl;
}
return 0;
}
I tried few other things from different people but I couldn't manage to work it.. Anything helps, thank you!
Here's your code with what I felt were the smallest amount of changes. One could argue that I didn't need to change your first for loop as much, but I figure that if you have the prescience to know how many names you're reading, you might as well use the knowledge.
#include <algorithm>
#include <fstream>
#include <iostream>
#include <iterator> // std::begin(), std::end(); required for C-arrays
#include <random> // std::mt19937; needed to feed std::shuffle()
#include <string>
// using namespace std; // BAD PRACTICE
int main() {
constexpr int size = 4; // Give your magic number a name; only need to change
// a single location
std::ifstream readName("names.txt");
if (!readName) { // Always check that you successfully opened the file.
std::cerr << "Error opening file.\n";
return 1;
}
std::string names[size];
// int i = 0;
for (int i = 0; i < size; ++i) { // Retool the loop entirely
std::getline(readName, names[i]);
}
readName.close();
// This is a fragile solution. It's only working because the array is in
// scope
std::shuffle(std::begin(names), std::end(names),
std::mt19937{std::random_device{}()});
for (int i = 0; i < size; i++) {
std::cout << names[i]
<< '\n'; // Don't use std::endl unless you actually need it
}
return 0;
}
This is not ideal code, though. Any change to the size of the input file requires changing the code and re-compiling. The biggest single change was to get rid of std::random_shuffle and use std::shuffle() instead. std::random_shuffle was deprecated with C++14 and removed in C++17. It's bad to use it. std::shuffle() does add the requirement of providing a PRNG, but it's not so bad. It leads to better code if you have a PRNG that needs to randomize many different things in a bigger program. This is because it's good to have a single PRNG and let it live for the length of your program as opposed to constantly building new ones.
And the C-array just makes things a bit clunkier. Enter std::vector.
#include <algorithm>
#include <fstream>
#include <iostream>
#include <iterator>
#include <random> // std::mt19937; needed to feed std::shuffle()
#include <string>
#include <vector>
int main() {
std::ifstream readName("names.txt");
if (!readName) { // Always check that you successfully opened the file.
std::cerr << "Error opening file.\n";
return 1;
}
std::vector<std::string> names;
std::string name;
while (std::getline(readName, name)) { // Retool the loop entirely
names.push_back(name);
}
readName.close();
std::shuffle(std::begin(names), std::end(names),
std::mt19937{std::random_device{}()});
for (const auto& i : names) {
std::cout << i << '\n';
}
return 0;
}
The vector can grow as needed, so you see how much simpler the loop that reads the names becomes. It's also more flexible since you don't have to know ahead of time how many entries to expect. It will "just work." With the call to std::shuffle() I kept the std::begin(names) syntax because many consider this a best practice, but you could have also used names.begin() if you wanted since the vector class provides its own iterators.
Lets have a look at you main question:
I tried to use this but it just shuffled the letters of the first word in the array:
random_shuffle(names->begin(), names->end());
The reason that it only shuffles the first word is because of the types and usage.
So names is an array of strings.
string names[197];
The problem stems from the C world. Were arrays decay into pointers exceedingly easily (just by being used in an expression). So here names-> has decayed into a pointer to the first element of the array. This allows you to use the -> operator which normally only works on pointers. So you are calling the functions begin() and end() on the pointer to the first element in the array. Thus only the first name is being shuffled.
The fix this problem use std::begin() method.
// here std::begin / std::end find the beginning and end
// of the array. So you are shuffling the array.
random_shuffle(std::begin(names), std::end(names));
But I would note that random_shuffle() is outdated. As mentioned by #sweenish you should use std::shuffle() See his answer for details.
A couple of things we can improve:
You use C array to store the names. Sure it works, but it is susceptible to a couple of issues because it can not be re-sized (and unless you think the file is never going to be changed that may be an issue). Potentially a hidden issue to a far distant maintainer.
std::vector<std::string> names; // resizeable container.
I would note that the current implementation ignores the first line. Then reads the first word from each subsequent line. There is also a slight issue that the last line may be empty and you read an empty name into the last element of the array (but you don't track how many names you read so unless you use all elements in the array you may never notice that).
I would change that. As it is not obvious. I would delibrately and seprately ignore the first line. Then I would simply read all the first words into a vector (so you know the size).
std::string line
std::getline(file, line); // Ignore the first line.
std::string word
while(file >> word) {
names.push_back(word);
std::getline(file, line); // ignore the rest of the line.
}
We could get fancy. Use iterators to simply create the array directly.
class Line
{
std::string firstWord;
friend std::istream& operator>>(std::istream& stream, Line& data) {
stream >> data.firstWord;
stream.ignore(std::numeric_limits<std::streamsize>::max(), '\n'); retrun stream;
}
operator std::string() const {
return firstWord;
}
};
Now you can create and load the vector in one line:
std::vector<std::string> names(std::istream_iterator<Line>(file),
std::istream_iterator<Line>{});
Then finally copy the names out can be made easier using foreach loop. Also don't use std::endl in a loop like this. It forces a flush of the underlying bugger after each new line. This is very ineffecient.
for(auto const& name: names) {
std::cout << name << "\n";
}
So the result is:
#include <iostream>
#include <fstream>
#include <string>
#include <vector>
#include <iterator>
#include <algorithm>
class Line
{
std::string firstWord;
friend std::istream& operator>>(std::istream& stream, Line& data) {
stream >> data.firstWord;
stream.ignore(std::numeric_limits<std::streamsize>::max(), '\n'); return stream;
}
operator std::string() const {
return firstWord;
}
};
int main()
{
std::ifstream file("names.txt");
std::string line
std::getline(file, line); // Ignore the first line.
std::vector<std::string> names(std::istream_iterator<Line>(file),
std::istream_iterator<Line>{});
random_shuffle(std::begin(names), std::end(names));
for(auto const& name: names) {
std::cout << name << "\n";
}
}

how to fill a set in C++ with input from user

how can we fill a set in C++ from user input in one liner
I know we can store input in a variable and then use
set.insert(some_variable)
but cant we take input from user directly?
like set.insert(cin>>set[i])?
I am just a beginner.
You can copy the values into a std::set with std::copy_n. (Please see here)
The source will be the std::istream_iterator (described here) and the destination will be the std::inserter wrapper (described here).
Please see:
#include <iostream>
#include <set>
#include <iterator>
#include <algorithm>
int main() {
// Our set
std::set<int> s{};
// How many values do we want to read
const size_t numberOfUserInputs{ 3 };
// Copy values from std::cin to set
std::copy_n(std::istream_iterator<int>(std::cin), numberOfUserInputs, std::inserter(s, s.begin()));
// Debug output
for (int i : s) std::cout << i << '\n';
return 0;
}
no, you can't do this.
things that go with vector like
std::vector<int> he;
auto endf = he.end();
*he.insert(endf, 1) = 5;
will not go with set. insert returns const_iterator.

is there any way to define dynamic array without Determine the size of it

I need a dynamic array that I don't have to scale(Determine) to a fixed number like the following
string* s;
I have this code so far, but obviously it doesn't work.
#include <iostream>
#include <string>
#include <fstream>
using namespace std;
int main()
{
fstream f;
f.open("resa.txt");
string* s;
int i = 0;
while (f.good())
{
f >> *(s + i);
i++;
}
return 0;
}
This is my task:
Now we change the class definitions a bit. No static arrays can occur anymore. The fact that the arrays instead become dynamic means that some class methods need to be modified, and that some / some of the classes need copy constructors and assignment methods (or superimposed assignment operator). [...]"
This means, that I just can't use data structures.
It's not automatic, you have to allocate more memory every time you want to resize, copy elements into new array and delete the old one. Fortunately, standard library got you covered with std::vector - an automatically resizable array.
#include <iostream>
#include <string>
#include <fstream>
#include <vector>
using namespace std;
int main()
{
fstream f;
f.open("resa.txt");
string temp;
std::vector<std::string> s;
while (f >> temp)
{
s.push_back(temp);
}
return 0;
}
I also fixed your input reading - see Why is iostream::eof inside a loop condition (i.e. while (!stream.eof())) considered wrong? (applies to good() as well).
Alternatively, you can use std::istream_iterator to initialize vector in one line instead of using loop (credit to Ayxan):
vector<string> s{ istream_iterator<string>{f}, {} };

How to traverse a char among the vector elements?

enter image description here
Is there any built-in function that exists to allow programmers to find a single char in a string vector(elements)?
There is no built-in function that checks for a character in a string among a vector of strings.
However, there are built-in functions for various sub-tasks involved in the process, which you can adjoin together to achieve your goal.
A simple way to achieve what you want would be to iterate over the vector of strings and use std::find() on each string to search for the element you desire:
#include <iostream>
#include <vector>
int main()
{ std::vector<std::string> s;
s.push_back("Stack");
s.push_back("Overflow");
char c;
std::cin>>c;
for(std::string& e:s)
{
if(e.find(c))
{ std::cout<<"found";
break;
}
}
return 0;
}

Storing a string into a vector

The error says that no matching function to call for push_back().
I included <vector> so I don't understand why this error is occurring. If you could also show me how to take in a string and store it into a vector that would be really helpful!
#include <iostream>
#include <string>
#include <vector>
using namespace std;
int main()
{
vector<string> list;
char input;
while(cin>>input)
{
list.push_back(input);
}
for(int i=0;list.size();i--)
{
cout<<list[99-i];
}
}
Since your list is a vector of string, pushing single chars into it wouldn't work: you should either make it a vector of chars, or read strings:
string input;
while(cin>>input) {
list.push_back(input);
}
Note that list[99-i] is rather suspicious: it will work only if the list has exactly 99 elements, and only if you change i-- for i++. Otherwise, you would get undefined behavior either on accessing elements past the end of the vector, or accessing elements at negative indexes.
If you would like to print the list from the back, use list[list.size()-1-i] instead, and use i++ instead of i--, because otherwise the loop would not stop.
Well, the error is correct. It helps, though, to read all of it!
The class vector<string> has a function push_back(const string&).
It does not have a function push_back(char).
I don't know why you're extracting individual chars but storing whole strings; don't do that.
Because you are trying to put in char into a string vector.
Change input to string.
#include<bits/stdc++.h>
using namespace std;
int main()
{
int n;
cin>>n;
string v;
vector<string> s;
for(int i=0;i<n;i++)
{
cin>>v;
s.push_back(v);
}
sort(s.begin(),s.end());
for(int i=0;i<n;i++)
{
cout<<s[i]<<endl;;
}
return 0;
}